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I need a program on raspberry pi, in which I can change the value of a variable delay while the program is running and is not interrupted by any input(). I came up with only one solution: read a value from a text file and change it using another program. But my solution doesn't work very well... When I overwrite a value in a text file, sometimes it happens that the program can't convert it to a float... sometimes it works well and sometimes it prints this error:
ValueError: could not convert string to float: ''
But the value in the text file seems to be fine...
So, this is main program:
def pause():
file = open('delay.txt', 'r')
pause = file.readline()
return pause
delay = float(pause())
while True:
GPIO.output(STEP, GPIO.HIGH)
delay = float(pause())
sleep(delay)
GPIO.output(STEP, GPIO.LOW)
delay = float(pause())
sleep(delay)
And this is the program, which is changing value in the text file:
while True:
rpm = float(input('RPM: '))
delay = (1/(rpm*60))/800
file = open('delay.txt', 'w')
file.write(str(delay))
file.close()
I really can't move with this... I'll be grateful for any advice and help in solving it.
You don't have to stick to my idea with a text file, maybe there is a better solution, but I couldn't think of anything better.
I'd suggest you use threading for this. I've made a small code example for you to get you started:
import threading
from time import sleep
import logging
logging.basicConfig(level=logging.DEBUG, filename="thread_output.txt", format='%(asctime)s %(levelname)-8s [%(filename)s:%(lineno)d] %(message)s')
running = True
delay = 1
def worker(delay, running):
while running():
logging.debug(1)
sleep(delay())
logging.debug(0)
sleep(delay())
x = threading.Thread(target=worker, args=(lambda: delay, lambda: running))
x.start()
while running:
code = input("""
Make a choice:
1) Set delay
2) quit
""")
code = int(code)
if code == 1:
try:
val = input("Give up the desired delay between 0 and 10 seconds:")
val = int(val)
assert val >= 0 and val <= 10
delay = val
except ValueError:
print("Invalid input! Returning to home menu")
continue
elif code == 2:
running = False
else:
print("invalid option! Returning to home menu")
continue
print("quiting...")
x.join()
The part that helps you here is the fact that you pass the value of delay (and in the example also of running) as a lambda function. This means that every time the value is used, the value refetched. If you then were to change the value of the variable, it would get passed on :)
Hit me up if you have more questions!
So I would like to run two programs, a timer and a math question. But always the input seems to be stopping the timer funtion or not even run at all. Is there any ways for it to get around that?
I'll keep the example simple.
import time
start_time = time.time()
timer=0
correct = answer
answer = input("9 + 9 = ")
#technically a math question here
#so here until i enter the input prevents computer reading the code
while True:
timer = time.time() - start_time
if timer > 3:
#3 seconds is the limit
print('Wrong!')
quit()
So recap i would like the player to answer the question in less than 3 seconds.
after the 3 seconds the game will print wrong and exit
if the player answer within three seconds the timer would be 'terminated' or stopped before it triggers 'wrong' and quit
hope you understand, and really appreciate your help
On Windows you can use the msvcrt module's kbhit and getch functions (I modernized this code example a little bit):
import sys
import time
import msvcrt
def read_input(caption, timeout=5):
start_time = time.time()
print(caption)
inpt = ''
while True:
if msvcrt.kbhit(): # Check if a key press is waiting.
# Check which key was pressed and turn it into a unicode string.
char = msvcrt.getche().decode(encoding='utf-8')
# If enter was pressed, return the inpt.
if char in ('\n', '\r'): # enter key
return inpt
# If another key was pressed, concatenate with previous chars.
elif char >= ' ': # Keys greater or equal to space key.
inpt += char
# If time is up, return the inpt.
if time.time()-start_time > timeout:
print('\nTime is up.')
return inpt
# and some examples of usage
ans = read_input('Please type a name', timeout=4)
print('The name is {}'.format(ans))
ans = read_input('Please enter a number', timeout=3)
print('The number is {}'.format(ans))
I'm not sure what exactly you have to do on other operating systems (research termios, tty, select).
Another possibility would be the curses module which has a getch function as well and you can set it to nodelay(1) (non-blocking), but for Windows you first have to download curses from Christopher Gohlke's website.
import time
import curses
def main(stdscr):
curses.noecho() # Now curses doesn't display the pressed key anymore.
stdscr.nodelay(1) # Makes the `getch` method non-blocking.
stdscr.scrollok(True) # When bottom of screen is reached scroll the window.
# We use `addstr` instead of `print`.
stdscr.addstr('Press "q" to exit...\n')
# Tuples of question and answer.
question_list = [('4 + 5 = ', '9'), ('7 - 4 = ', '3')]
question_index = 0
# Unpack the first question-answer tuple.
question, correct_answer = question_list[question_index]
stdscr.addstr(question) # Display the question.
answer = '' # Here we store the current answer of the user.
# A set of numbers to check if the user has entered a number.
# We have to convert the number strings to ordinals, because
# that's what `getch` returns.
numbers = {ord(str(n)) for n in range(10)}
start_time = time.time() # Start the timer.
while True:
timer = time.time() - start_time
inpt = stdscr.getch() # Here we get the pressed key.
if inpt == ord('q'): # 'q' quits the game.
break
if inpt in numbers:
answer += chr(inpt)
stdscr.addstr(chr(inpt), curses.A_BOLD)
if inpt in (ord('\n'), ord('\r')): # Enter pressed.
if answer == correct_answer:
stdscr.addstr('\nCorrect\n', curses.A_BOLD)
else:
stdscr.addstr('\nWrong\n', curses.A_BOLD)
if timer > 3:
stdscr.addstr('\nToo late. Next question.\n')
if timer > 3 or inpt in (ord('\n'), ord('\r')):
# Time is up or enter was pressed; reset and show next question.
answer = ''
start_time = time.time() # Reset the timer.
question_index += 1
# Keep question index in the correct range.
question_index %= len(question_list)
question, correct_answer = question_list[question_index]
stdscr.addstr(question)
# We use wrapper to start the program.
# It handles exceptions and resets the terminal after the game.
curses.wrapper(main)
Use time.time(), it returns the epoch time (that is, the number of seconds since January 1, 1970 UNIX Time). You can compare it to a start time to get the number of seconds:
start = time.time()
while time.time() - start < 60:
# stuff
You can have a timer pull you out of your code at any point (even if the user is inputting info) with signals but it is a little more complicated. One way is to use the signal library:
import signal
def timeout_handler(signal, frame):
raise Exception('Time is up!')
signal.signal(signal.SIGALRM, timeout_handler)
This defines a function that raises an exception and is called when the timeout occurs. Now you can put your while loop in a try catch block and set the timer:
signal.alarm.timeout(60)
try:
while lives > 0
# stuff
except:
# print score
in python, is there a way to, while waiting for a user input, count time so that after, say 30 seconds, the raw_input() function is automatically skipped?
The signal.alarm function, on which #jer's recommended solution is based, is unfortunately Unix-only. If you need a cross-platform or Windows-specific solution, you can base it on threading.Timer instead, using thread.interrupt_main to send a KeyboardInterrupt to the main thread from the timer thread. I.e.:
import thread
import threading
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
timer = threading.Timer(timeout, thread.interrupt_main)
astring = None
try:
timer.start()
astring = input(prompt)
except KeyboardInterrupt:
pass
timer.cancel()
return astring
this will return None whether the 30 seconds time out or the user explicitly decides to hit control-C to give up on inputting anything, but it seems OK to treat the two cases in the same way (if you need to distinguish, you could use for the timer a function of your own that, before interrupting the main thread, records somewhere the fact that a timeout has happened, and in your handler for KeyboardInterrupt access that "somewhere" to discriminate which of the two cases occurred).
Edit: I could have sworn this was working but I must have been wrong -- the code above omits the obviously-needed timer.start(), and even with it I can't make it work any more. select.select would be the obvious other thing to try but it won't work on a "normal file" (including stdin) in Windows -- in Unix it works on all files, in Windows, only on sockets.
So I don't know how to do a cross-platform "raw input with timeout". A windows-specific one can be constructed with a tight loop polling msvcrt.kbhit, performing a msvcrt.getche (and checking if it's a return to indicate the output's done, in which case it breaks out of the loop, otherwise accumulates and keeps waiting) and checking the time to time out if needed. I cannot test because I have no Windows machine (they're all Macs and Linux ones), but here the untested code I would suggest:
import msvcrt
import time
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
finishat = time.time() + timeout
result = []
while True:
if msvcrt.kbhit():
result.append(msvcrt.getche())
if result[-1] == '\r': # or \n, whatever Win returns;-)
return ''.join(result)
time.sleep(0.1) # just to yield to other processes/threads
else:
if time.time() > finishat:
return None
The OP in a comment says he does not want to return None upon timeout, but what's the alternative? Raising an exception? Returning a different default value? Whatever alternative he wants he can clearly put it in place of my return None;-).
If you don't want to time out just because the user is typing slowly (as opposed to, not typing at all!-), you could recompute finishat after every successful character input.
I found a solution to this problem in a blog post. Here's the code from that blog post:
import signal
class AlarmException(Exception):
pass
def alarmHandler(signum, frame):
raise AlarmException
def nonBlockingRawInput(prompt='', timeout=20):
signal.signal(signal.SIGALRM, alarmHandler)
signal.alarm(timeout)
try:
text = raw_input(prompt)
signal.alarm(0)
return text
except AlarmException:
print '\nPrompt timeout. Continuing...'
signal.signal(signal.SIGALRM, signal.SIG_IGN)
return ''
Please note: this code will only work on *nix OSs.
The input() function is designed to wait for the user to enter something (at least the [Enter] key).
If you are not dead set to use input(), below is a much lighter solution using tkinter. In tkinter, dialog boxes (and any widget) can be destroyed after a given time.
Here is an example :
import tkinter as tk
def W_Input (label='Input dialog box', timeout=5000):
w = tk.Tk()
w.title(label)
W_Input.data=''
wFrame = tk.Frame(w, background="light yellow", padx=20, pady=20)
wFrame.pack()
wEntryBox = tk.Entry(wFrame, background="white", width=100)
wEntryBox.focus_force()
wEntryBox.pack()
def fin():
W_Input.data = str(wEntryBox.get())
w.destroy()
wSubmitButton = tk.Button(w, text='OK', command=fin, default='active')
wSubmitButton.pack()
# --- optionnal extra code in order to have a stroke on "Return" equivalent to a mouse click on the OK button
def fin_R(event): fin()
w.bind("<Return>", fin_R)
# --- END extra code ---
w.after(timeout, w.destroy) # This is the KEY INSTRUCTION that destroys the dialog box after the given timeout in millisecondsd
w.mainloop()
W_Input() # can be called with 2 parameter, the window title (string), and the timeout duration in miliseconds
if W_Input.data : print('\nYou entered this : ', W_Input.data, end=2*'\n')
else : print('\nNothing was entered \n')
from threading import Timer
def input_with_timeout(x):
def time_up():
answer= None
print('time up...')
t = Timer(x,time_up) # x is amount of time in seconds
t.start()
try:
answer = input("enter answer : ")
except Exception:
print('pass\n')
answer = None
if answer != True: # it means if variable have somthing
t.cancel() # time_up will not execute(so, no skip)
input_with_timeout(5) # try this for five seconds
As it is self defined... run it in command line prompt , I hope you will get the answer
read this python doc you will be crystal clear what just happened in this code!!
A curses example which takes for a timed math test
#!/usr/bin/env python3
import curses
import curses.ascii
import time
#stdscr = curses.initscr() - Using curses.wrapper instead
def main(stdscr):
hd = 100 #Timeout in tenths of a second
answer = ''
stdscr.addstr('5+3=') #Your prompt text
s = time.time() #Timing function to show that solution is working properly
while True:
#curses.echo(False)
curses.halfdelay(hd)
start = time.time()
c = stdscr.getch()
if c == curses.ascii.NL: #Enter Press
break
elif c == -1: #Return on timer complete
break
elif c == curses.ascii.DEL: #Backspace key for corrections. Could add additional hooks for cursor movement
answer = answer[:-1]
y, x = curses.getsyx()
stdscr.delch(y, x-1)
elif curses.ascii.isdigit(c): #Filter because I only wanted digits accepted
answer += chr(c)
stdscr.addstr(chr(c))
hd -= int((time.time() - start) * 10) #Sets the new time on getch based on the time already used
stdscr.addstr('\n')
stdscr.addstr('Elapsed Time: %i\n'%(time.time() - s))
stdscr.addstr('This is the answer: %s\n'%answer)
#stdscr.refresh() ##implied with the call to getch
stdscr.addstr('Press any key to exit...')
curses.wrapper(main)
under linux one could use curses and getch function, its non blocking.
see getch()
https://docs.python.org/2/library/curses.html
function that waits for keyboard input for x seconds (you have to initialize a curses window (win1) first!
import time
def tastaturabfrage():
inittime = int(time.time()) # time now
waitingtime = 2.00 # time to wait in seconds
while inittime+waitingtime>int(time.time()):
key = win1.getch() #check if keyboard entry or screen resize
if key == curses.KEY_RESIZE:
empty()
resize()
key=0
if key == 118:
p(4,'KEY V Pressed')
yourfunction();
if key == 107:
p(4,'KEY K Pressed')
yourfunction();
if key == 99:
p(4,'KEY c Pressed')
yourfunction();
if key == 120:
p(4,'KEY x Pressed')
yourfunction();
else:
yourfunction
key=0
This is for newer python versions, but I believe it will still answer the question. What this does is it creates a message to the user that the time is up, then ends the code. I'm sure there's a way to make it skip the input rather than completely end the code, but either way, this should at least help...
import sys
import time
from threading import Thread
import pyautogui as pag
#imports the needed modules
xyz = 1 #for a reference call
choice1 = None #sets the starting status
def check():
time.sleep(15)#the time limit set on the message
global xyz
if choice1 != None: # if choice1 has input in it, than the time will not expire
return
if xyz == 1: # if no input has been made within the time limit, then this message
# will display
pag.confirm(text = 'Time is up!', title = 'Time is up!!!!!!!!!')
sys.exit()
Thread(target = check).start()#starts the timer
choice1 = input("Please Enter your choice: ")
i manipulate a sensor : HC SR04 to capture a distance.
I'm a newbie in Python and RPI. My code work, I capture distance during a time but one moment the script stop...
My code :
GPIO.setmode(GPIO.BCM)
GPIO_TRIGGER = 23
GPIO_ECHO = 24
GPIO.setup(GPIO_TRIGGER, GPIO.OUT)
GPIO.setup(GPIO_ECHO, GPIO.IN)
def main():
global state
print("ultrasonic")
while True:
print "1s second refresh.."
time.sleep(1)
i = 0
datas = []
average = 0
while i< 1:
GPIO.output(GPIO_TRIGGER, False)
time.sleep(C.time['count'])
GPIO.output(GPIO_TRIGGER, True)
time.sleep(0.00001)
GPIO.output(GPIO_TRIGGER, False)
while GPIO.input(GPIO_ECHO) == 0:
start = time.time()
while GPIO.input(GPIO_ECHO) == 1:
stop = time.time()
distance = (stop-start) * 17000
print "Distance : %.1f" % distance
average = F.getAverage(datas)
print "Average: %.1f" % average
GPIO.cleanup()
The code stop here
while GPIO.input(GPIO_ECHO) == 0:
start = time.time()
THE SOLUTION : with a sample timeout :
now = time()
while GPIO.input(self.gpio_echo) == 0 and time()-now<waitTime:
pass
I am also mucking about with this sensor. My code executes similar to yours and I need no timeout for it to work.
The one difference I can find is this:
while i< 1:
GPIO.output(GPIO_TRIGGER, False)
time.sleep(C.time['count'])
I don't know how long the sleep time is here, but it might be that that's causing the problem. If it would be similar to mine setting the Trigger to false would be directly after the setup of the in/out pins instead, and then there's a two second wait to eliminate noise. Your wait time might be lower, I can't tell. There should be no need to set the trigger to false again just before you send the pulse and, I don't know, but it might be causing a false start. I would change it to this to work similarly to mine and then remove the setting to false in the while loop.
GPIO.setup(GPIO_TRIGGER, GPIO.OUT)
GPIO.setup(GPIO_ECHO, GPIO.IN)
GPIO.output(GPIO_TRIGGER, False)
print("Waiting for sensor to settle\n")
time.sleep(2)
I'm not sure if this will solve the issue without the need for a timeout, but I don't seem to need one.
I've written a module for making an object of the sensor which then allows for some more readable scripting. I'm also quite new to python and not at all an experienced programmer so fun errors might be there somewhere, but it's here below if you want to use it or just compare code:
#! /usr/bin/python3
# dist.py this is a module for objectifying an ultrasonic distance sensor.
import RPi.GPIO as GPIO
import time
class Distancer(object):
#init takes an input of one GPIO for trigger and one for echo and creates the object,
#it searches for a calibration file in the working directory (name)Const.txt, if none
#is found it will initiate a calibration
def __init__(self, trig, cho, name):
self.trigger = trig
self.echo = cho
self.name = name
self.filename = self.name + 'Const.txt'
GPIO.setup(self.trigger, GPIO.OUT)
GPIO.setup(self.echo, GPIO.IN)
GPIO.output(self.trigger, False)
print("Waiting for sensor to calm down")
time.sleep(2)
try:
with open(self.filename, "r") as inConst:
self.theConst = int(inConst.read())
except (OSError, IOError) as e:
print("Not calibrated, initializing calibration")
self.calibrate()
with open(self.filename, "r") as inConst:
self.theConst = int(inConst.read())
#Returns the echo time
def measureTime(self):
GPIO.output(self.trigger, True)
time.sleep(0.00001)
GPIO.output(self.trigger, False)
while GPIO.input(self.echo) == 0:
pulse_start = time.time()
while GPIO.input(self.echo) == 1:
pulse_end = time.time()
pulse_duration = pulse_end - pulse_start
return pulse_duration
#Returns a distance in cm
def measure(self):
return self.measureTime() * self.theConst
#Makes you set up the sensor at 3 different distances in order to find the
#relation between pulse time and distance, it creates the file (name)Const.txt
#in the working directory and stores the constant there.
def calibrate(self):
ten = []
thirty = []
seventy = []
print("Make distance 10 cm, enter when ready")
input()
for i in range(30):
ten.append(10/self.measureTime())
time.sleep(0.2)
print("Make distance 30 cm, enter when ready")
input()
for i in range(30):
thirty.append(30/self.measureTime())
time.sleep(0.2)
print("Make distance 70 cm, enter when ready")
input()
for i in range(30):
seventy.append(70/self.measureTime())
time.sleep(0.2)
allTime = ten + thirty + seventy
theOne = 0.0
for i in range(90):
theOne = theOne + allTime[i]
theOne = theOne / 90
with open(self.filename, "w") as inConst:
inConst.write(str(round(theOne)))
#Will continually check distance with a given interval until something reaches the
#treshold (cm), takes an argument to set wether it should check for something being
#nearer(near) or farther(far) than the treashold. Returns True when treshold is reached.
def distWarn(self, nearfar, treashold):
if nearfar.lower() == "near":
while True:
if self.measure() < treashold:
return True
break
time.sleep(0.2)
if nearfar.lower() == "far":
while True:
if self.measure() > treashold:
return True
break
time.sleep(0.2)
#Will measure with a second interval and print the distance
def keepGoing(self):
while True:
try:
print(str(round(self.measure())) + ' cm')
time.sleep(1)
except KeyboardInterrupt:
print("Won't keep going")
break
I've run it with the code below to test it and everything seems to work. First time it's run it will prompt you to calibrate the sensor by putting it at different distances from something.
#! /usr/bin/python3
import RPi.GPIO as GPIO
import time
import dist as distancer
GPIO.setmode(GPIO.BOARD)
TRIG = 16
ECHO = 18
dist = distancer.Distancer(TRIG, ECHO, 'dist')
def main():
global dist
print(str(round(dist.measureTime(),5)) + ' s')
print(str(round(dist.measure())) + ' cm')
dist.distWarn('near', 10)
print('Warning, something nearer than 10 cm at ' + time.asctime( time.localtime(time.time()) ))
dist.distWarn('far', 10)
print('Warning, something further than 10 cm at ' + time.asctime( time.localtime(time.time()) ))
dist.keepGoing()
GPIO.cleanup()
print('Fin')
if __name__ == "__main__":
try:
main()
except KeyboardInterrupt:
GPIO.cleanup()
print("Exiting")
time.sleep(1)
I am pretty sure you want
while GPIO.input(GPIO_ECHO)==GPIO.LOW:
start = time.time()
while GPIO.input(GPIO_ECHO) == GPIO.HIGH:
stop = time.time()
I don't think GPIO.input naturally returns zeros or ones, you can test that though.
Not really, I think that i lost the signal, i'll try a timeout in
while GPIO.input(GPIO_ECHO)==GPIO.LOW:
start = time.time()
I think that my program wait indefinitely a signal but he stay to 0
I know this is an old question. The cause of the problem was described in this question https://raspberrypi.stackexchange.com/questions/41159/...
The solution is to add a timeout, like the OP did, to the while loops similar to this:
# If a reschedule occurs or the object is very close
# the echo may already have been received in which case
# the following will loop continuously.
count=time.time()
while GPIO.input(GPIO_ECHO)==0 and time.time()-count<0.1:
start = time.time()
...
# if an object is not detected some devices do not
# lower the echo line in which case the following will
# loop continuously.
stop = time.time()
count=time.time()
while GPIO.input(GPIO_ECHO)==1 and time.time()-count<0.1:
stop = time.time()
in python, is there a way to, while waiting for a user input, count time so that after, say 30 seconds, the raw_input() function is automatically skipped?
The signal.alarm function, on which #jer's recommended solution is based, is unfortunately Unix-only. If you need a cross-platform or Windows-specific solution, you can base it on threading.Timer instead, using thread.interrupt_main to send a KeyboardInterrupt to the main thread from the timer thread. I.e.:
import thread
import threading
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
timer = threading.Timer(timeout, thread.interrupt_main)
astring = None
try:
timer.start()
astring = input(prompt)
except KeyboardInterrupt:
pass
timer.cancel()
return astring
this will return None whether the 30 seconds time out or the user explicitly decides to hit control-C to give up on inputting anything, but it seems OK to treat the two cases in the same way (if you need to distinguish, you could use for the timer a function of your own that, before interrupting the main thread, records somewhere the fact that a timeout has happened, and in your handler for KeyboardInterrupt access that "somewhere" to discriminate which of the two cases occurred).
Edit: I could have sworn this was working but I must have been wrong -- the code above omits the obviously-needed timer.start(), and even with it I can't make it work any more. select.select would be the obvious other thing to try but it won't work on a "normal file" (including stdin) in Windows -- in Unix it works on all files, in Windows, only on sockets.
So I don't know how to do a cross-platform "raw input with timeout". A windows-specific one can be constructed with a tight loop polling msvcrt.kbhit, performing a msvcrt.getche (and checking if it's a return to indicate the output's done, in which case it breaks out of the loop, otherwise accumulates and keeps waiting) and checking the time to time out if needed. I cannot test because I have no Windows machine (they're all Macs and Linux ones), but here the untested code I would suggest:
import msvcrt
import time
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
finishat = time.time() + timeout
result = []
while True:
if msvcrt.kbhit():
result.append(msvcrt.getche())
if result[-1] == '\r': # or \n, whatever Win returns;-)
return ''.join(result)
time.sleep(0.1) # just to yield to other processes/threads
else:
if time.time() > finishat:
return None
The OP in a comment says he does not want to return None upon timeout, but what's the alternative? Raising an exception? Returning a different default value? Whatever alternative he wants he can clearly put it in place of my return None;-).
If you don't want to time out just because the user is typing slowly (as opposed to, not typing at all!-), you could recompute finishat after every successful character input.
I found a solution to this problem in a blog post. Here's the code from that blog post:
import signal
class AlarmException(Exception):
pass
def alarmHandler(signum, frame):
raise AlarmException
def nonBlockingRawInput(prompt='', timeout=20):
signal.signal(signal.SIGALRM, alarmHandler)
signal.alarm(timeout)
try:
text = raw_input(prompt)
signal.alarm(0)
return text
except AlarmException:
print '\nPrompt timeout. Continuing...'
signal.signal(signal.SIGALRM, signal.SIG_IGN)
return ''
Please note: this code will only work on *nix OSs.
The input() function is designed to wait for the user to enter something (at least the [Enter] key).
If you are not dead set to use input(), below is a much lighter solution using tkinter. In tkinter, dialog boxes (and any widget) can be destroyed after a given time.
Here is an example :
import tkinter as tk
def W_Input (label='Input dialog box', timeout=5000):
w = tk.Tk()
w.title(label)
W_Input.data=''
wFrame = tk.Frame(w, background="light yellow", padx=20, pady=20)
wFrame.pack()
wEntryBox = tk.Entry(wFrame, background="white", width=100)
wEntryBox.focus_force()
wEntryBox.pack()
def fin():
W_Input.data = str(wEntryBox.get())
w.destroy()
wSubmitButton = tk.Button(w, text='OK', command=fin, default='active')
wSubmitButton.pack()
# --- optionnal extra code in order to have a stroke on "Return" equivalent to a mouse click on the OK button
def fin_R(event): fin()
w.bind("<Return>", fin_R)
# --- END extra code ---
w.after(timeout, w.destroy) # This is the KEY INSTRUCTION that destroys the dialog box after the given timeout in millisecondsd
w.mainloop()
W_Input() # can be called with 2 parameter, the window title (string), and the timeout duration in miliseconds
if W_Input.data : print('\nYou entered this : ', W_Input.data, end=2*'\n')
else : print('\nNothing was entered \n')
from threading import Timer
def input_with_timeout(x):
def time_up():
answer= None
print('time up...')
t = Timer(x,time_up) # x is amount of time in seconds
t.start()
try:
answer = input("enter answer : ")
except Exception:
print('pass\n')
answer = None
if answer != True: # it means if variable have somthing
t.cancel() # time_up will not execute(so, no skip)
input_with_timeout(5) # try this for five seconds
As it is self defined... run it in command line prompt , I hope you will get the answer
read this python doc you will be crystal clear what just happened in this code!!
A curses example which takes for a timed math test
#!/usr/bin/env python3
import curses
import curses.ascii
import time
#stdscr = curses.initscr() - Using curses.wrapper instead
def main(stdscr):
hd = 100 #Timeout in tenths of a second
answer = ''
stdscr.addstr('5+3=') #Your prompt text
s = time.time() #Timing function to show that solution is working properly
while True:
#curses.echo(False)
curses.halfdelay(hd)
start = time.time()
c = stdscr.getch()
if c == curses.ascii.NL: #Enter Press
break
elif c == -1: #Return on timer complete
break
elif c == curses.ascii.DEL: #Backspace key for corrections. Could add additional hooks for cursor movement
answer = answer[:-1]
y, x = curses.getsyx()
stdscr.delch(y, x-1)
elif curses.ascii.isdigit(c): #Filter because I only wanted digits accepted
answer += chr(c)
stdscr.addstr(chr(c))
hd -= int((time.time() - start) * 10) #Sets the new time on getch based on the time already used
stdscr.addstr('\n')
stdscr.addstr('Elapsed Time: %i\n'%(time.time() - s))
stdscr.addstr('This is the answer: %s\n'%answer)
#stdscr.refresh() ##implied with the call to getch
stdscr.addstr('Press any key to exit...')
curses.wrapper(main)
under linux one could use curses and getch function, its non blocking.
see getch()
https://docs.python.org/2/library/curses.html
function that waits for keyboard input for x seconds (you have to initialize a curses window (win1) first!
import time
def tastaturabfrage():
inittime = int(time.time()) # time now
waitingtime = 2.00 # time to wait in seconds
while inittime+waitingtime>int(time.time()):
key = win1.getch() #check if keyboard entry or screen resize
if key == curses.KEY_RESIZE:
empty()
resize()
key=0
if key == 118:
p(4,'KEY V Pressed')
yourfunction();
if key == 107:
p(4,'KEY K Pressed')
yourfunction();
if key == 99:
p(4,'KEY c Pressed')
yourfunction();
if key == 120:
p(4,'KEY x Pressed')
yourfunction();
else:
yourfunction
key=0
This is for newer python versions, but I believe it will still answer the question. What this does is it creates a message to the user that the time is up, then ends the code. I'm sure there's a way to make it skip the input rather than completely end the code, but either way, this should at least help...
import sys
import time
from threading import Thread
import pyautogui as pag
#imports the needed modules
xyz = 1 #for a reference call
choice1 = None #sets the starting status
def check():
time.sleep(15)#the time limit set on the message
global xyz
if choice1 != None: # if choice1 has input in it, than the time will not expire
return
if xyz == 1: # if no input has been made within the time limit, then this message
# will display
pag.confirm(text = 'Time is up!', title = 'Time is up!!!!!!!!!')
sys.exit()
Thread(target = check).start()#starts the timer
choice1 = input("Please Enter your choice: ")