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I thought that the following would return True but that was not the case.
"Hey guys"[:4] == "Hey"
Printing both "Hey guys"[:4] and "Hey" prints out Hey. So I don't understand why would it be False under the == operator.
"Hey guys"[:4] means you want the first 4 characters of "Hey guys" which includes the space. You only want the first 3 characters so it should be "Hey guys"[:3].
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import math
import random
possibility_1=0
possibility_2=0
while True:
list = [0, 1]
number_1=random.choice(list)
number_2=random.choice(list)
number_3=random.choice(list)
number_total=str(number_1)+","+str(number_2)+","+str(number_3)
if number_total==(1,1,0) or number_total==(0,0,1):
possibility_1 +=1
if number_total==(1,1,1) or number_total==(0,0,0):
possibility_2 +=1
print(str(number_total)+" possibility_11= "+ str(possibility_1)+" possibility_12= "+ str(possibility_2))
guys the possibility_1 and possibility_2 doesn!t changing. Please help me I want to make a heads or tails code and simulate it then check the possibilities.
Looks like number_total is a string so the output would be "1,1,0" you are comparing with a tuple. This means the if statements will not be invoked.
if number_total=="1,1,0" or number_total=="0,0,1":
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string = "Karma police, arrest this man, he talks in maths"
byte_string = string.encode("utf-8")
hex_string = byte_string.hex()
print("Hex: ".format(hex_string))
I am trying to print out the hexadecimal value of the string, but the output is empty
ouput-> Hex:
What should I change in order to print out the hexadecimal value?
You forgot placeholder for .format()
string = "Karma police, arrest this man, he talks in maths"
byte_string = string.encode("utf-8")
hex_string = byte_string.hex()
print("Hex: {}".format(hex_string))
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def ShowData(data = (x)):
for r in data:
print (“{:}, {:.2f}”.format(x, x))
keep getting this error:
File "<ipython-input-10-9963f96f39ca>", line 8
print (“{:}, {:.2f}”.format(x, x))
^
SyntaxError: invalid character in identifier
Replace the “ charachter with this " ?
# data is a list of lists
def ShowData(data = (x)):
for r in data:
print ("{:}, {:.2f}".format(x, x))
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In Python 2.7, the function bytearray.fromhex(string) gives:
ValueError: non-hexadecimal number found in fromhex() arg at position x
when the string has '16' in it, like in for example:
0200FF001603000E30D03, 0200FF001603004401A03
It's like failing if it was decimal and was '84102' just for having '10', the base, in it.
How can I avoid that error?
There is no problem with 16 existed in the string, the problem is that you try to encode odd length strings - try any valid string with even length and you will see that it is works.
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Closed 7 years ago.
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I'm trying to sort each string inside a list. For example, if I have the list ['bca', 'fed'] then I want my function to return ['abc', 'def'].
Currently trying to do this like so:
lines = [''.join.(sorted(e)) for e in lines]
What's wrong with this syntax?
Just remove the redundant dot (.):
lines = [''.join(sorted(e)) for e in lines]