Couldnt print out the Hexadecimal value of the string [closed] - python

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string = "Karma police, arrest this man, he talks in maths"
byte_string = string.encode("utf-8")
hex_string = byte_string.hex()
print("Hex: ".format(hex_string))
I am trying to print out the hexadecimal value of the string, but the output is empty
ouput-> Hex:
What should I change in order to print out the hexadecimal value?


You forgot placeholder for .format()
string = "Karma police, arrest this man, he talks in maths"
byte_string = string.encode("utf-8")
hex_string = byte_string.hex()
print("Hex: {}".format(hex_string))

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Python 3 str.format with decimal place [closed]

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Closed 2 years ago.
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def ShowData(data = (x)):
for r in data:
print (“{:}, {:.2f}”.format(x, x))
keep getting this error:
File "<ipython-input-10-9963f96f39ca>", line 8
print (“{:}, {:.2f}”.format(x, x))
^
SyntaxError: invalid character in identifier

Replace the “ charachter with this " ?
# data is a list of lists
def ShowData(data = (x)):
for r in data:
print ("{:}, {:.2f}".format(x, x))

"starts with" does not work (python regex) [closed]

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Closed 3 years ago.
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I have this string:
m = 'Film/6702-BRINGING-UP-BABY" da'
and the following regax, that tries to find words that start with 'd':
movie = re.findall(r'^d.*', m)
print(movie)
the result is:
[]
and I can not understand why - there is a match in the string('da'), so why wont it find it?
I an working with pycharm, python 3.6

Using \b as boundary character we can find the words starting with specific character
import re
m = 'Film/6702-BRINGING-UP-BABY" da'
movie = re.findall(r'\bd.*', m)
print(movie)
output
['da']

How do I avoid printing certain data that contains "None" as a value? [closed]

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Closed 3 years ago.
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In my code below, the times variable prints data in calendar and business time. Some of the data have numbers and others print the value 'None'. I would like to only print data that does not have the value 'None'. When I run my code I still get all of the data printed.
for ticket1 in ticket_list1:
for ticket2 in ticket_list2:
times = ticket2['reply_time_in_minutes']
ticket_id = ticket2['ticket_id']
assignee = ticket1['assignee_id']
priority = ticket1['priority']
if ticket1['assignee_id'] != ticket1['requester_id']:
if times['calendar'] != 'None':
print("%s %20s %20s %20s" % (times, ticket_id,
assignee, priority))

Remove the quotes around none. None is actually a value - of <type 'NoneType'>. So it cannot be compared to a string.
if times['calendar'] != None:

Python: Compare sliced string to another string with "==" [closed]

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Closed 5 years ago.
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I thought that the following would return True but that was not the case.
"Hey guys"[:4] == "Hey"
Printing both "Hey guys"[:4] and "Hey" prints out Hey. So I don't understand why would it be False under the == operator.

"Hey guys"[:4] means you want the first 4 characters of "Hey guys" which includes the space. You only want the first 3 characters so it should be "Hey guys"[:3].

Python bytearray.fromhex fails when string has "16" [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
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In Python 2.7, the function bytearray.fromhex(string) gives:
ValueError: non-hexadecimal number found in fromhex() arg at position x
when the string has '16' in it, like in for example:
0200FF001603000E30D03, 0200FF001603004401A03
It's like failing if it was decimal and was '84102' just for having '10', the base, in it.
How can I avoid that error?

There is no problem with 16 existed in the string, the problem is that you try to encode odd length strings - try any valid string with even length and you will see that it is works.

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