Develop Reference

Creating a search function in a list from a text file

everyone. I have a Python assignment that requires me to do the following:
Download this CSV fileLinks to an external site of female Oscar winners (https://docs.google.com/document/d/1Bq2T4m7FhWVXEJlD_UGti0zrIaoRCxDfRBVPOZq89bI/edit?usp=sharing) and open it into a text editor on your computer
Add a text file to your sandbox project named OscarWinnersFemales.txt
Copy and paste several lines from the original file into your sandbox file. Make sure that you include the header.
Write a Python program that does the following:
Open the file and store the file object in a variable
Read the entire contents line by line into a list and strip away the newline character at the end of each line
Using list slicing, print lines 4 through 7 of your file
Write code that will ask the user for an actress name and then search the list to see if it is in there. If it is it will display the record and if it is not it will display Sorry not found.
Close the file
Below is the code I currently have. I've already completed the first three bullet points but I can't figure out how to implement a search function into the list. Could anyone help clarify it for me? Thanks.
f = open('OscarsWinnersFemales.txt')
f = ([x.strip("\n") for x in f.readlines()])
print(f[3:7])
Here's what I tried already but it just keeps returning failure:
def search_func():
actress = input("Enter an actress name: ")
for x in f:
if actress in f:
print("success")
else:
print("failure")
search_func()

I hate it when people use complicated commands like ([x.strip("\n") for x in f.readlines()]) so ill just use multiple lines but you can do what you like.
f = open("OscarWinnersFemales.txt")
f = f.readlines()
f.close()
data = {} # will list the actors and the data as their values
for i, d in enumerate(data):
f[i] = d.strip("\n")
try:
index, year, age, name, movie = d.split(",")
except ValueError:
index, year, age, name, movie, movie2 = d.split(",")
movie += " and " + movie2
data[name] = f"{index}-> {year}-{age} | {movie}"
print(f[3:7])
def search_actr(name):
if name in data: print(data[name])
else: print("Actress does not exist in database. Remember to use captols and their full name")
I apologize if there are any errors, I decided not to download the file but everything I wrote is based off my knowledge and testing.

I have figured it out
file = open("OscarWinnersFemales.txt","r")
OscarWinnersFemales_List = []
for line in file:
stripped_line = line.strip()
OscarWinnersFemales_List.append(stripped_line)
file.close()
print(OscarWinnersFemales_List[3:7])
print()
actress_line = 0
name = input("Enter An Actress's Name: ")
for line in OscarWinnersFemales_List:
if name in line:
actress_line = line
break
if actress_line == 0:
print("Sorry, not found.")
else:
print()
print(actress_line)

How to save all user input from for loop into text file

I have the following task:
We will write a program called ​student_register.py that allows students to register for an exam venue. 
First, ask the user how many students are registering. 
Create a ​for loop​ that runs for that amount of students 
Each loop asks for the student to enter their ID number. 
Write each of the ID numbers to a Text File called ​reg_form.txt 
This will be used as an attendance register that they will sign when they arrive at the exam venue. 
I think the following code I have is close as it saves the text file but only saves the first inputted ID number and does not display the others.
students = int(input("Please enter the amount of students registered."))
id_number = ""
for a in range (0, students):
id_number = (int(input("Please enter student ID numbers.")))
id_number = id_number + 1
reg_form = open('reg_form.txt', 'w')
reg_form.write("Student ID numbers: \n" + str(id_number))
print ("Thank you, ID numbers saved to txt file reg_form")

You are re-opening the file every loop, and you are opening it in write mode. This means you are overwriting any data in the file every loop.
A simple fix would be to open the file in append mode using 'a', alternatively you could store the results in a list and then write everything in one go at the end which would be nicer.
It's also good practise to close a file after you've finished with it, see Why Should I close files with Python. Whilst you can do this using reg_form.close() a better approach would be to use a context manager as this guarantees the file is always closed:
with open("reg_form.txt", "w") as my_file:
my_file.write("some data")

It is not saving because you are not closing the file stream.
I suggest that you use it with with keyword, it handles the opening and closing of your file and saving the data.
students = int(input("Please enter the amount of students registered."))
id_number = ""
for a in range (0, students):
id_number = (int(input("Please enter student ID numbers.")))
id_number = id_number + 1
with open('reg_form.txt', 'w') as file:
file.write("Student ID numbers: \n" + str(id_number))
print ("Thank you, ID numbers saved to txt file reg_form")

Multiple Word Search not Working Correctly (Python)

I am working on a project that requires me to be able to search for multiple keywords in a file. For example, if I had a file with 100 occurrences of the word "Tomato", 500 for the word "Bread", and 20 for "Pickle", I would want to be able to search the file for "Tomato" and "Bread" and get the number of times it occurs in the file. I was able to find people with the same issue/question, but for other languages on this site.
I a working program that allows me to search for the column name and tally how many times something shows up in that column, but I want to make something a bit more precise. Here is my code:
def start():
location = raw_input("What is the folder containing the data you like processed located? ")
#location = "C:/Code/Samples/Dates/2015-06-07/Large-Scale Data Parsing/Data Files"
if os.path.exists(location) == True: #Tests to see if user entered a valid path
file_extension = raw_input("What is the file type (.txt for example)? ")
search_for(location,file_extension)
else:
print "I'm sorry, but the file location you have entered does not exist. Please try again."
start()
def search_for(location,file_extension):
querylist = []
n = 5
while n == 5:
search_query = raw_input("What would you like to search for in each file? Use'Done' to indicate that you have finished your request. ")
#list = ["CD90-N5722-15C", "CD90-NB810-4C", "CP90-N2475-8", "CD90-VN530-22B"]
if search_query == "Done":
print "Your queries are:",querylist
print ""
content = os.listdir(location)
run(content,file_extension,location,querylist)
n = 0
else:
querylist.append(search_query)
continue
def run(content,file_extension,location,querylist):
for item in content:
if item.endswith(file_extension):
search(location,item,querylist)
quit()
def search(location,item,querylist):
with open(os.path.join(location,item), 'r') as f:
countlist = []
for search in querylist: #any search value after the first one is incorrectly reporting "0"
countsearch = 0
for line in f:
if search in line:
countsearch = countsearch + 1
countlist.append(search)
countlist.append(countsearch) #mechanism to update countsearch is not working for any value after the first
print item, countlist
start()
If I use that code, the last part (def search) is not working correctly. Any time I put a search in, any search after the first one I enter in returns "0", despite there being up to 500,000 occurrences of the search word in a file.
I was also wondering, since I have to index 5 files with 1,000,000 lines each, if there was a way I could write either an additional function or something to count how many times "Lettuce" occurs over all the files.
I cannot post the files here due to their size and content. Any help would be greatly appreciated.
Edit
I also have this piece of code here. If I use this, I get the correct count of each, but it would be much better to have a user be able to enter as many searches as they want:
def check_start():
#location = raw_input("What is the folder containing the data you like processed located? ")
location = "C:/Code/Samples/Dates/2015-06-07/Large-Scale Data Parsing/Data Files"
content = os.listdir(location)
for item in content:
if item.endswith("processed"):
countcol1 = 0
countcol2 = 0
countcol3 = 0
countcol4 = 0
#print os.path.join(currentdir,item)
with open(os.path.join(location,item), 'r') as f:
for line in f:
if "CD90-N5722-15C" in line:
countcol1 = countcol1 + 1
if "CD90-NB810-4C" in line:
countcol2 = countcol2 + 1
if "CP90-N2475-8" in line:
countcol3 = countcol3 + 1
if "CD90-VN530-22B" in line:
countcol4 = countcol4 + 1
print item, "CD90-N5722-15C", countcol1, "CD90-NB810-4C", countcol2, "CP90-N2475-8", countcol3, "CD90-VN530-22B", countcol4

You are trying to iterate over your file more than once. After the first time, the file pointer is at the end so subsequent searches will fail because there's nothing left to read.
If you add the line:
f.seek(0), this will reset the pointer before every read:
def search(location,item,querylist):
with open(os.path.join(location,item), 'r') as f:
countlist = []
for search in querylist: #any search value after the first one is incorrectly reporting "0"
countsearch = 0
for line in f:
if search in line:
countsearch = countsearch + 1
countlist.append(search)
countlist.append(countsearch) #mechanism to update countsearch is not working for any value after the first
f.seek(0)
print item, countlist
PS. I've guessed at the indentation... You really shouldn't use tabs.

I'm not sure I get your question completely, but how about something like this?
def check_start():
raw_search_terms = raw_input('Enter search terms seperated by a comma:')
search_term_list = raw_search_terms.split(',')
#location = raw_input("What is the folder containing the data you like processed located? ")
location = "C:/Code/Samples/Dates/2015-06-07/Large-Scale Data Parsing/Data Files"
content = os.listdir(location)
for item in content:
if item.endswith("processed"):
# create a dictionary of search terms with their counts (initialized to 0)
search_term_count_dict = dict(zip(search_term_list, [0 for s in search_term_list]))
for line in f:
for s in search_term_list:
if s in line:
search_term_count_dict[s] += 1
print item
for key, value in search_term_count_dict.iteritems() :
print key, value

Python name to/from file

I want the text to display the users name if they have entered it before. I have this working in c++ but wanted to practice python. the output will continue to do the "else" statement. I have tried having the if statement search for a string such as "noname" or "empty" and it would still do the else statement.
fr = open('sample.txt','r')
name = fr.read()
fr.close()
if name is None:
fw = open('sample.txt','w')
stuff = raw_input("enter name:")
fw.write(stuff)
fw.close()
else:
print(name)

If you have a blank file without any data in it, f.read() doesn't return None, it returns an empty string.
So rather than do if name is None you could write if name == '' or, to be certain, if name in (None, '').
You might also want to make sure you add a newline character when you write the names to your file, so you should do:
f.write(name + '\n')
for example.
Edit: As Cat Plus Plus mentioned, you can just do if name:, because both None and an empty string will evaluate to False. I just thought it was less clear for this particular question.

Use with to open files, it closes them automtically:
with open('sample.txt','a+') as names: # if file does not exist, "a" will create it
lines = names.read()
if lines: # if file has data
print("Hello {}".format(lines))
else: # else file is empty, ask for name and write name to file
name = raw_input("enter name:")
names.write(name)
To check if the name exists before writing:
with open('sample.txt','a+') as names:
lines = names.read()
name = raw_input("enter name:")
if name in lines:
print("Hello {}".format(name))
else:
names.write(name)

Need help writing function ticker

I'm currently trying to write a function ticker() that will open a file read it and ask the user to input a company name. When the user inputs the company name it will return the ticker symbol of that company.
Also a data file is given, which is formatted in this way:
Name of Company #1
Ticker Symbol of Company #1
Name of Company #2
Ticker Symbol of Company #2
...
The view that I need is something like this:
ticker('test.txt')
Enter Company Name: YAHOO
Ticker: YHOO
My current code is:
def ticker(x):
d = {}
infile = open(x,'r')
content = infile.readlines()
for line in (x):
file = line.split('\n')
But now I'm completely lost as how to compute this.

I'm not sure what the format of the file you're reading in is, but the following code will read in the file and break it up into non-blank lines.
def ticker(filename):
lines = open(filename).read().split('\n')
lines = [x in lines if x]

Either change your fileformat, or try this:
ticker = {}
for company, ticker in (x):
ticker[company] = ticker
This will give you a dictionary, which can ba accessed in a manner like dictionary[key] and return its value. I am sure if you google for getting user input you can get this to work. Maybe apply a case conversion, so that the capitalization of the user input does not matter.
If this does not take you far enough consider trying harder/hiring a consultant or asking questions that show that you acctually put effort into it.

Below is a very raw and simple implementation, you can improve it.
def ticker(filename):
name = raw_input("Enter Company Name:")
f = open(filename, "r")
l = f.readline()
ticker = ''
while l:
if l.strip() == name:
ticker = f.readline().strip()
break
else:
l = f.readline()
if ticker:
print "Ticker: %s" % ticker
else:
print "Ticker not found!"
ticker("1.txt")

If you're sure about the format of your data file, you can use code bellow, But always remember that working with files without handling possible exceptions is not a good idea.
def ticker(filename):
with open(filename, 'r') as f:
lines = [line.strip() for line in f.readlines()]
return dict(zip(lines[::2], lines[1::2]))
data = ticker('test')
name = raw_input('Enter Company Name: ')
print 'Ticker:', data.get(name.strip(), 'Not Found!')