Develop Reference

Creating a search function in a list from a text file

everyone. I have a Python assignment that requires me to do the following:
Download this CSV fileLinks to an external site of female Oscar winners (https://docs.google.com/document/d/1Bq2T4m7FhWVXEJlD_UGti0zrIaoRCxDfRBVPOZq89bI/edit?usp=sharing) and open it into a text editor on your computer
Add a text file to your sandbox project named OscarWinnersFemales.txt
Copy and paste several lines from the original file into your sandbox file. Make sure that you include the header.
Write a Python program that does the following:
Open the file and store the file object in a variable
Read the entire contents line by line into a list and strip away the newline character at the end of each line
Using list slicing, print lines 4 through 7 of your file
Write code that will ask the user for an actress name and then search the list to see if it is in there. If it is it will display the record and if it is not it will display Sorry not found.
Close the file
Below is the code I currently have. I've already completed the first three bullet points but I can't figure out how to implement a search function into the list. Could anyone help clarify it for me? Thanks.
f = open('OscarsWinnersFemales.txt')
f = ([x.strip("\n") for x in f.readlines()])
print(f[3:7])
Here's what I tried already but it just keeps returning failure:
def search_func():
actress = input("Enter an actress name: ")
for x in f:
if actress in f:
print("success")
else:
print("failure")
search_func()

I hate it when people use complicated commands like ([x.strip("\n") for x in f.readlines()]) so ill just use multiple lines but you can do what you like.
f = open("OscarWinnersFemales.txt")
f = f.readlines()
f.close()
data = {} # will list the actors and the data as their values
for i, d in enumerate(data):
f[i] = d.strip("\n")
try:
index, year, age, name, movie = d.split(",")
except ValueError:
index, year, age, name, movie, movie2 = d.split(",")
movie += " and " + movie2
data[name] = f"{index}-> {year}-{age} | {movie}"
print(f[3:7])
def search_actr(name):
if name in data: print(data[name])
else: print("Actress does not exist in database. Remember to use captols and their full name")
I apologize if there are any errors, I decided not to download the file but everything I wrote is based off my knowledge and testing.

I have figured it out
file = open("OscarWinnersFemales.txt","r")
OscarWinnersFemales_List = []
for line in file:
stripped_line = line.strip()
OscarWinnersFemales_List.append(stripped_line)
file.close()
print(OscarWinnersFemales_List[3:7])
print()
actress_line = 0
name = input("Enter An Actress's Name: ")
for line in OscarWinnersFemales_List:
if name in line:
actress_line = line
break
if actress_line == 0:
print("Sorry, not found.")
else:
print()
print(actress_line)

Find line with specific string in a file with Python

I'm trying to print the category and the number of pages from a text file with python.
This is the code I wrote so far:
search = input("Which book are you looking for: ")
file = open("books.txt","r")
line_num = 0
reading = file.readlines()
# for line in file:
# if search in file:
# NOT SURE HOW TO WRITE TO GET THE LINE NUMBER OF WHAT THE USER IS LOOKING FOR
book_category = line_num + 1
book_pages = line_num + 2
print(reading[book_category] , " " , reading[book_pages])
file.close()
And here is the file (books.txt)
Book one
Horror
300
Book two
Fantasy
150
Book three
Mystery
400
Book four
Romance
100

Try this:
with open('books.txt') as fin :
lines = fin.readlines()
line_num = -1
for k,line in enumerate(lines) :
if line.find( search ) != -1 :
line_num = k
The code above will search for the user input in the book titles, for example, if user inputs "Gob", all following books will match: "The Goblin", "The Life of Richard Gobbler" etc.
If you need an exact match, use:
if line.lower().strip() == search.lower().strip() :

One way to go about this problem is break the string / book into two parts everything before your target and after. Then split all of the stuff before your target by new line and count how many lines there are.
def line_no(inp, target):
inp = inp.split(target)
#inp[0] = everything before your target
line_no = len(inp[0].split('\n')) #split everything before your target by line and get a count
#-1 for zero index
return line_no
statement = '''Hello
World
I
Am
A
Statement'''
line_no(statement, 'Am')

Code is not properly searching text file

#
# Obtain user input for file name, and open it
#
inFile = open(input("Enter file name: "), "r")
#
# Process data and address possible errors
#
countDinner = 0
countLodging = 0
countConference = 0
valueDinner = 0
valueLodging = 0
valueConference = 0
done = False
while not done :
line = inFile.readline()
try :
s = line
serviceAmount = ';'.join(s.split(';')[1:-1]) #Removes date and name regardless of format
serviceAmount.split(";")
s.lower()
if "dinner" in s :
countDinner = countDinner + 1
valueDinner = valueDinner + int(filter(str.isdigit, s))
print("Dinners: ", countDinner, "Value of Dinner sales: ", valueDinner)
elif "lodging" in s :
countLodging = countLodging + 1
valueLodging = valueLodging + int(filter(str.isdigit, s))
print("Lodging: ", countLodging, "Value of Lodging sales: ", valueLodging)
elif "conference" in s :
countConference = countConference + 1
valueConference = valueConference + int(filter(str.isdigit, s))
print("Conferences: ", countConference, "Value of Conference sales: ", valueConference)
elif line == "" :
done = True
else :
print("Invalid file format.")
except FileNotFoundError :
print("Unable to find file.")
finally :
done = True
inFile.close()
Returns "Invalid file format" even when the document is set up specifically for this code. I'm not getting a syntax error, so I'm not sure whats wrong.
The document contains the text:
John;Lodging;123;050617
Tyler;Conference;123;081497
Taylor;Dinner;453;041798

There are a lot of things you aren't doing quite right here. I tried to not only fix the issue you posted about, but also write some code that should be more clear and easier to use. I left comments to explain things.
# Don't open the file here, just get the file name. We will open in later
fname = input("Enter file name: ")
# I think using dicts is more clearn and organized. Having so many variables I think makes the code messy
counts = {"Dinner": 0,
"Lodging": 0,
"Conference": 0}
values = {"Dinner": 0,
"Lodging": 0,
"Conference": 0}
# Lets try to open the file
try:
with open(fname, 'r') as inFile: # Use "with", this way the file is closed automatically when we are done reading it
for linenum, line in enumerate(inFile): # I want to enumerate each line. If there is an error on a line, we can display the line nmber this way
line = line.lower().split(';')[1:-1] # lets make it all lower case, then split and drop as needed
print(line)
if "dinner" in line :
counts["Dinner"] += 1 # x += 1 is the same as x = x + 1, but cleaner
values["Dinner"] += int(line[1])
print("Dinners: {} Value of Dinner sales: {}".format(counts["Dinner"], values["Dinner"]))
elif "lodging" in line :
counts["Lodging"] += 1
values["Lodging"] += int(line[1])
print("Lodging: {} Value of Dinner sales: {}".format(counts["Lodging"], values["Lodging"]))
elif "conference" in line :
counts["Conference"] += 1
values["Conference"] += int(line[1])
print("Conference: {} Value of Dinner sales: {}".format(counts["Conference"], values["Conference"]))
else :
print("Invalid file format on line {}".format(linenum)) # Here is why we used enumerate in the for loop
except FileNotFoundError:
print("Unable to find file.")

Here is your problem:
serviceAmount = ';'.join(s.split(';')[1:-1]) #Removes date and name regardless of format
serviceAmount.split(";")
You should do:
serviceAmount = ';'.join(s.lower().split(';')[1:-1])
You are checking against lower case strings, but not actually lower casing your input.
It is also important to note that s.lower() doesn't actually change s, it just returns a string where all the letters of s have been switched to lower case. Same thing for split (as in not changing the string its called on, not that it returns a string).
Another problem you are going to run into is getting the numbers from your strings.
int(filter(str.isdigit, s))
Won't work. You can use split again like you did earlier (or just not re-join since you only care about the first element in the comparisons).
int(serviceAmount.split(';')[1])
The last thing is the
finally:
done = True
inFile.close()
finally always runs when exiting a try, meaning that you are always done after each loop (and close the file after you read the first line).
If you remove the finally and add inFile.close() inside the elif line == "" it will close, and set done only when you've reached the end of the file.

It could be done as simple as
categories = {}
filename = input("Enter file name: ")
with open(filename, "r") as file:
name, category, value, date = file.readline().split(";")
if category not in categories:
categories[category] = {"count": 0, "value": 0}
categories[category]["count"] += 1
categories[category]["value"] += int(value)
At the end, you'll have a dict with categories, their count, and value, and also their names are not hard-coded.

Trying to only look at specific lines in txt file TypeError: 'in <string>' requires string as left operand, not dict raises when I try

ask questions for clarification
I think it would be best if I just posted my code for better understanding. So first I just simply ask the user to input a file name, just to see if it exists. And if it doesn't it exits the program.
I have a separate file containing a list of keywords, which I put into a dict
then I check if another file exists... similar to before. and with this file, Im checking to see if the keywords in the first file are contained in the second one. and calculating the sentiment value. But this is not what I need help with I just wanted to explain a little before hand
So my question is, in the section below:
for line in open('tweets.txt'):
line = line.split(" ")
lat = float(line[0][1:-1]) #Stripping the [ and the ,
long = float(line[1][:-1]) #Stripping the ]
if eastern.contains(lat, long):
eastScore += score(line)
elif central.contains(lat, long):
centralScore += score(line)
elif mountain.contains(lat, long):
mountainScore += score(line)
elif pacific.contains(lat, long):
pacificScore += score(line)
else:
continue
how would I be able to focus on only lines in the file that contain keywords and not the entire file?
like you see in this part where I ignore lines without values?
with open('tweets.txt') as f:
for line in f:
values = Counter(word for word in line.split() if word in sentiments)
if not values:
continue
I tried methods such as creating a new file and writing the lines that contain keywords into the new file, but that raised
TypeError: 'in <string>' requires string as left operand, not dict
but it wasnt really what I wanted to do anyways. So my first question is, how would I be able to focus on only lines that contain keywords for that section above?
[41.923916200000001, -88.777469199999999] 6 2011-08-28 19:24:18 My life is a moviee.
from collections import Counter
try:
keyW_Path = input("Enter file named keywords: ")
keyFile = open(keyW_Path, "r")
except IOError:
print("Error: file not found.")
exit()
# Read the keywords into a list
keywords = {}
wordFile = open('keywords.txt', 'r')
for line in wordFile.readlines():
word = line.replace('\n', '')
if not(word in keywords.keys()): #Checks that the word doesn't already exist.
keywords[word] = 0 # Adds the word to the DB.
wordFile.close()
# Read the file name from the user and open the file.
try:
tweet_path = input("Enter file named tweets: ")
tweetFile = open(tweet_path, "r")
except IOError:
print("Error: file not found.")
exit()
#Calculating Sentiment Values
with open('keywords.txt') as f:
sentiments = {word: int(value) for word, value in (line.split(",") for line in f)}
with open('tweets.txt') as f:
for line in f:
values = Counter(word for word in line.split() if word in sentiments)
if not values:
continue
happyScore_Tweet = (sum(values[word]*sentiments[word] for word in values)) // (len(values))
print(happyScore_Tweet)
def score(tweet):
total = 0
for word in tweet:
if word in sentiments:
total += 1
return total
#Classifying the regions
class Region:
def __init__(self, lat_range, long_range):
self.lat_range = lat_range
self.long_range = long_range
def contains(self, lat, long):
return self.lat_range[0] <= lat and lat < self.lat_range[1] and\
self.long_range[0] <= long and long < self.long_range[1]
eastern = Region((24.660845, 49.189787), (-87.518395, -67.444574))
central = Region((24.660845, 49.189787), (-101.998892, -87.518395))
mountain = Region((24.660845, 49.189787), (-115.236428, -101.998892))
pacific = Region((24.660845, 49.189787), (-125.242264, -115.236428))
eastScore = 0
centralScore = 0
pacificScore = 0
mountainScore = 0
happyScoreE = 0
for line in open('tweets.txt'):
line = line.split(" ")
lat = float(line[0][1:-1]) #Stripping the [ and the ,
long = float(line[1][:-1]) #Stripping the ]
if eastern.contains(lat, long):
eastScore += score(line)
elif central.contains(lat, long):
centralScore += score(line)
elif mountain.contains(lat, long):
mountainScore += score(line)
elif pacific.contains(lat, long):
pacificScore += score(line)
else:
continue

Use regex to extract the lat and long.
import re
text = open(filename, 'r')
matches = re.findall("(\-?\d+\.\d+?),\s*(\-?\d+\.\d+)", text.read())
Matches will return a list of strings containing only your lat and long.
Also, there are some very good tools in python you can use for spatial queries, you should look them up.

Python: Print Result Only

import os
def find_method(name):
i = 0
found_dic = { "$_GET":[], "$_POST":[], "include":[], "require":[], "mysql_query":[], "SELECT":[], "system":[], "exec":[], "passthru":[], "readfile":[], "fopen":[], "eval":[] }
for x in file(name, "r"):
i += 1
for key in found_dic:
if x.strip().find(key) != -1:
found_dic[key].append("LINE:"+str(i)+":" + x.strip())
print "="*20, name, "="*20
for key in found_dic:
if found_dic[key]:
print " ", "-"*10, key, "-"*10
for r in found_dic[key]:
print " ",r
def search(dirname):
flist = os.listdir(dirname)
for f in flist:
next = os.path.join(dirname, f)
if os.path.isdir(next):
search(next)
else:
doFileWork(next)
def doFileWork(filename):
ext = os.path.splitext(filename)[-1]
#if ext == '.html': print filename
if ext == '.php':
# print "target:" + filename
find_method(filename)
how can I print only results. its prints all name of file eventhough file doesn't have any result in it. I want to make print file name if its has any result in it
this is about searching word, but it shows every word include like (seaching for include) then it also finds word in sentence and prints all sentence I want to find only word "include" not included in sentence. it's really hard to explain.. I hope to understand.. srry

It looks like there may be a problem with the indentation of the first print command, you are printing 'name', but it is outside of the for loop.
Try populating your dictionary, and then printing the dictionary, along the lines of:
with open(your_file) as f:
found_dic = {}
key = 'your_key'
# populate the dictionary
found_dic[key] = [i for i in f if key in i and i not in found_dic]
With this as a starting point, hopefully you can format the result to the dictionary as you need it. Only lines that include the 'key' will be in the found_dic, so you should be able to print these out in any format you like.
Hope this helps

I hope that's what you asked for:
for i, line in enumerate(file(name, "r")):
found = False
for key in found_dic:
if key in line.strip():
found_dic[key].append("LINE:"+str(i)+":" + key)
found = True
if found:
print "="*20, name, "="*20
for key in found_dic:
if found_dic[key]:
print " ", "-"*10, key, "-"*10
for r in found_dic[key]:
print " ",r
You have to check if you found something if you only want to print the name when you actually found something. Also, you only concatenate key in line 5, because key is what you search. And you only want to add what you search.
Further changes:
I used the enumerate function in line i, its far easier and more readable than incrementing you own i.
I also changed the condition in line 10. Using the in keyword here is the more simple and readable way...