I have a homework to draw a spiral(from inside to outside) in python with turtle, but I cant think of a way to do that, beside what I did its need to be like this:
I tried to do it like that, but its not working properly.
import turtle
turtle.shape ('turtle')
d = 20 #Distance
a = 1 #StartingAngle
x = 200 #Num of loops
for i in range (x):
turtle.left(a)
turtle.forward(d)
a = a + 5
You are increasing the wrong variable in your loop.
A spiral is like a "circunference whose radius increases over time".
You should increase the d variable over time, and not the angle a. The amount of the increase of each loop will be essential to determine the appearance of your spiral, but you can obtain a good value for the increase with some calculation or by trial and error.
import turtle
from math import sin,cos,pi
t=turtle.Turtle()
t.speed(0)
n=50 #number of spirals
d=10 #distance between 2 spirals
r=0 #radius
x,y = 0, 0
cur_r = r
for i in range(n):
for a in range(1,360, 4):
r = cur_r + d*a/360.0
a *= pi/180.0
y = r*sin(a)
x = r*cos(a)
turtle.goto(x,y)
cur_r += d
import turtle
i=0
while i<4:
turtle.speed(0)
turtle.pensize(1+i)
turtle.forward(1+i)
t.color("blue")
turtle.bgcolor("pink")
t.lt(3)
i+=0.003
If you are using program other than IDLE(such as pycharm), add
turtle.mainloop()
at the end of the code
import turtle as t
for i in range(360):
t.circle(i,20)
Source: Explained here
Related
I have to make a change to this specific code, which produces a square grid of circles, I have to change the code to make a triangle grid of circles.
import turtle
window = turtle.Screen()
my_boi = turtle.Turtle()
my_boi.speed(0)
for y in range(-200,200,50):
for x in range(-200,200,50):
my_boi.penup()
my_boi.setposition(x,y)
my_boi.pendown()
my_boi.circle(20)
window.exitonclick()
I'm sure there is a smarter approach, but this is one way to do it:
import turtle
window = turtle.Screen()
my_boi = turtle.Turtle()
my_boi.speed(0)
for (i,y) in enumerate(range(-200,200,50)):
for x in range(-200+(25*i),200-(25*i),50):
my_boi.penup()
my_boi.setposition(x,y)
my_boi.pendown()
my_boi.circle(20)
window.exitonclick()
turtle.done()
In the second for-loop the range is iteratively decreased by 1/2 of the circle diameter in each side.
I'd simplify things somewhat:
from turtle import Screen, Turtle
window = Screen()
my_boi = Turtle()
my_boi.speed('fastest')
my_boi.penup()
for y in range(1, 9):
my_boi.setposition(-25 * y + 25, 50 * y - 250)
for x in range(y):
my_boi.pendown()
my_boi.circle(20)
my_boi.penup()
my_boi.forward(50)
my_boi.hideturtle()
window.exitonclick()
Only the starting position of each row has to be calculated and placed via setposition(). The column positions can be a simple forward() statement.
I know this is an old post, but I was looking for the answer and managed to figure it out, so to help everyone else out, All you need to do is change the stop range in the nested loop to be y. I switched the x and y variables because I wanted the triangle to be flat, but if you need it the other way that also works.
import turtle
window = turtle.Screen()
my_boi = turtle.Turtle()
my_boi.speed(0)
for x in range(-200,200,50):
for y in range(-200,x,50):
my_boi.penup()
my_boi.setposition(x,y)
my_boi.pendown()
my_boi.circle(20)
window.exitonclick()
Link to the Exercises can be accessed here - Case Study: Interface Design, Exercise Section 4.3
Quoting the question, it seems I have to implement an arc() function:
Make a more general version of circle called arc that takes an additional parameter angle, which determines what fraction of a circle to draw. angle is in units of degrees, so when angle=360, arc should draw a complete circle.
The code I've written so far:
import turtle
import math
bob = turtle.Turtle()
def polygon(t, n, length):
for i in range(n):
t.fd(length)
t.lt(360/n)
def circle(t, r):
circumference = 2 * math.pi * r
n = int(circumference/3) + 1
length = circumference/n
polygon(t, n, length)
def arc(t, r, angle):
arc_length = 2 * math.pi * r * (angle/360)
n = (arc_length/4) + 1
arc(bob, 1000, 45)
turtle.mainloop()
I'm intending to call the circle() function within arc() just as polygon() was called within circle(), but I'm confused on how I should do that. Apart from that, the arc() function does not draw anything, rather just shows me a stationary Turtle.
I believe that the Turtle object bob isn't receiving any of the movement instructions assigned within polygon(). Thus all that it's doing is displaying the Turtle object!
I could be wrong, and this where I need clarification. Should I call circle() within arc() as well as make the Turtle object move? Are there easier alternatives? Calling functions within a function is still confusing for me, so more resources to learn about them would be great as well!
import turtle
bob=turtle.Turtle()
import math
def arc(t,radius,angle):
circumference = 2.0*math.pi*radius
frac = angle/360.0
arclength = circumference*frac
n = 50 # pick a number
len = arclength/n;
turnang = angle/n
for i in range(n):
t.fd(len)
t.lt(turnang)
arc(bob, 130,360)
turtle.done()
I'm trying to ... call the circle() function
within arc() just as polygon() was called within circle()
You've got this backward. The problem states:
Make a more general version of circle called arc
Just as you could draw a circle with the more general function polygon(), you should be able to draw a circle with the more general function arc(). Here's a skeletal program for thinking about this:
from turtle import Screen, Turtle
from math import pi
def polygon(turtle, sides, length):
outside_angle = 360 / sides
for _ in range(sides):
turtle.forward(length)
turtle.left(outside_angle)
def circle_using_polygon(turtle, radius):
circumference = 2 * pi * radius
sides = min(60, int(circumference / 3))
length = circumference / sides
polygon(turtle, sides, length)
def arc(turtle, radius, angle):
# implement arc not by calling *circle() nor by
# calling polygon() but rather by borrowing code
# from both and adding one more step to reduce
# the number of sides based on the arc angle
def circle_using_arc(turtle, radius):
arc(turtle, radius, 360)
bob = Turtle(visible=False)
# Draw overlapping circles three different ways:
bob.color("green")
circle_using_polygon(bob, 100)
for color in ['cyan', 'magenta', 'yellow', 'black']:
bob.color(color)
arc(bob, 100, 90)
bob.color("blue")
circle_using_arc(bob, 100)
screen = Screen()
screen.mainloop()
import tkinter
import swampy
from swampy.TurtleWorld import *
def polygon(n, t, length, angle):
print(t)
k= angle/360
for i in range(0,int(n*k)):
fd(t, length)
p= 360
lt(t,p/n)
t.delay
world = TurtleWorld()
bob = Turtle()
#def circle(r):
#l1= 2*3.14*r
#l= l1/60
#polygon(30, bob, l)
polygon(60, bob, 10, 180)
I need to model a spring in Python for one of my classes at the university and it doesn't really work. I've the second order differential equation and I translated it in 2 first order ones to have a system.
Can someone look my code and give me an idea about what could I do? For me, the equations are good, I just don't know how to draw it...
from math import pi
from time import sleep
from turtle import *
k=1
m=1
def main():
L = 5
total_time = 0
vo = 0 #Vitesse angulaire initial (rad/s)
time_step = 0.05
while total_time < 100:
total_time += time_step
vo += (-k/m) * L * time_step
L += vo * time_step
if draw(L): break
sleep(time_step)
def init():
setup()
mode('logo')
radians()
speed(0)
tracer(False)
hideturtle()
def draw(L):
if speed() != 0: return True
clear()
pendown()
setheading(L)
penup()
pensize(5)
pencolor('red')
dot(L * 10)
home
update()
if __name__ == '__main__':
init()
main()
Your equations are good, as far as I remember from my physic lessons, but the L variable is varying from -5 to +5, not from 0 to +5.
The dot(radius) function draws a circle. The radius needs to be positive.
Just replace :
dot(L * 10)
by :
dot(51 + L * 10)
(I put "51" instead of "50" to be sure to avoid errors due to crappy approximation of float numbers)
Some little tip : when you don't understand what happens, try to determine the current values of your variables.
You could have guessed that L varies from -5 to +5 by adding print("vo:", vo, "L:", L, "total_time:", total_time) in the loop of the main function.
How can I play with a turtle and how can I use a turtle?
I have trouble getting the thing to work as in the picture shown below (ignore the colors).
from turtle import *
from math import *
def formulaX(R, r, p, t):
x = (R-r)*cos(t) - (r + p)*cos((R-r)/r*t)
def formulaY(R, r, p, t):
y = (R-r)*sin(t) - (r + p)*sin((R-r)/r*t)
def t_iterating(R, r, p):
t = 2*pi
up()
goto(formulaX, formulaY)
down()
while (True):
t = t + 0.01
formulaX(R, r, p, t)
formulaY(R, r, p, t)
def main():
R = int(input("The radius of the fixed circle: "))
r = int(input("The radius of the moving circle: "))
p = int(input("The offset of the pen point, between <10 - 100>: "))
if p < 10 or p > 100:
input("Incorrect value for p!")
t_iterating(R, r, p)
input("Hit enter to close...")
main()'
I am trying to make that kind of shape. Here is the coding I have done so far.
Try changing your t_iterating function to this:
def t_iterating(R, r, p):
t = 2*pi # It seems odd to me to start from 2*pi rather than 0.
down()
while t < 20*pi: # This loops while t goes from 2*pi to 20*pi.
t = t+0.01
goto(formulaX(R, r, p, t), formulaY(R, r, p, t))
up()
No! You're missing the point of the turtle! You should try to do it all with relative movements of the turtle. Think about how you would draw the shape if you were the turtle, crawling on a large floor, dragging a paintbrush from your butt.
At each small fragment of time, the turtle will perform one small iteration of a differential equation which governs the whole behavior. It is not generally wise to precompute the x y coordinates and use the turtle's GOTO function.
The turtle itself should have only relative knowledge of its surroundings. It has a direction, and a position. And these two pieces of state are modified by turning and moving.
So, think about how you would draw the spiral. Particularly, think about drawing the very first circle. As the circle appears to close, something interesting happens: it misses. It misses by a tiny little amount, which turns out to be a fraction of a circle. It is this missing curvature that closes the large pattern of circles in a circle, as they add up to one complete turn.
When the whole figure is drawn, the turtle is back to its original position and orientation.
This is my code. The color may not be exact, but here it is:
from turtle import *
from random import randint
speed(10000)
for i in range(20):
col = randint(1, 5)
if col == 1:
pencolor("orange")
elif col == 2:
pencolor("blue")
elif col == 3:
pencolor("green")
elif col == 4:
pencolor("purple")
elif col == 5:
pencolor("dark blue")
circle(50)
left(20)
This is the output:
My code is here and the function was built for automatically choosing the random colour.
from turtle import Turtle, Screen
import random
timmy = Turtle()
screen = Screen()
screen.colormode(255)
timmy.shape("turtle")
timmy.speed("fastest")
angle = [0, 90, 180, 270]
def random_color():
red = random.randint(0, 255)
green = random.randint(0, 255)
blue = random.randint(0, 255)
colour = (red, green, blue)
return colour
def draw_circles(num_of_gap):
for _ in range(int(360 / num_of_gap)):
timmy.color(random_color())
timmy.circle(100)
timmy.right(num_of_gap)
draw_circles(20)
screen.exitonclick()
Spirograph using Python Turtle with random colours
Code:
import random
from turtle import Turtle, Screen
tim = Turtle()
tim.shape("classic")
def turtle_color():
R = random.random()
G = random.random()
B = random.random()
return tim.pencolor(R, G, B)
tim.speed("fastest")
for _ in range(72):
turtle_color()
tim.circle(100)
tim.left(5)
screen = Screen()
screen.exitonclick()
Output:
You basically get the turtle to loop through the 360 degrees and you can choose two pen colours.
from turtle import Turtle, Screen
tim = Turtle()
tim.shape("turtle")
tim.color("green")
### total degrees in circle = 360
### turn left must be a divisor of 360 (1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 30, 36, 40, 45, 60, 72, 90) NOTE: some divisors do not work as well
degrees = 360
turn_left = 12
total_circles = int(degrees / turn_left)
tim.pensize(3)
tim.speed(0)
def circle_colour1():
### choose your colour here:
tim.pencolor("pink")
tim.circle(-100)
tim.left(turn_left)
def circle_colour2():
### choose your colour here:
tim.pencolor("grey")
tim.circle(-100)
tim.left(turn_left)
for _ in range(0, int(total_circles / 2)):
circle_colour1()
circle_colour2()
screen = Screen()
screen.exitonclick()
Real basic (360°/10) is:
from turtle import Turtle as d
draw = d()
draw.speed(0)
draw.pensize(3)
for _ in range(0, 36):
draw.circle(-100)
draw.left(10)
I am trying to fill the color in these squares:
Right now the turtle only fills the corners of theses squares, not the entire square.
Here is my code:
import turtle
import time
import random
print ("This program draws shapes based on the number you enter in a uniform pattern.")
num_str = input("Enter the side number of the shape you want to draw: ")
if num_str.isdigit():
squares = int(num_str)
angle = 180 - 180*(squares-2)/squares
turtle.up
x = 0
y = 0
turtle.setpos(x,y)
numshapes = 8
for x in range(numshapes):
turtle.color(random.random(),random.random(), random.random())
x += 5
y += 5
turtle.forward(x)
turtle.left(y)
for i in range(squares):
turtle.begin_fill()
turtle.down()
turtle.forward(40)
turtle.left(angle)
turtle.forward(40)
print (turtle.pos())
turtle.up()
turtle.end_fill()
time.sleep(11)
turtle.bye()
I've tried moving around turtle.begin_fill() and end_fill() in numerous locations with no luck… Using Python 3.2.3, thanks.
I haven't really used turtle, but it looks like this may be what you want to do. Correct me if I've assumed the wrong functionality for these calls:
turtle.begin_fill() # Begin the fill process.
turtle.down() # "Pen" down?
for i in range(squares): # For each edge of the shape
turtle.forward(40) # Move forward 40 units
turtle.left(angle) # Turn ready for the next edge
turtle.up() # Pen up
turtle.end_fill() # End fill.
You're drawing a series of triangles, using begin_fill() and end_fill() for each one. What you can probably do is move your calls to begin_fill() and end_fill() outside the inner loop, so you draw a full square and then ask for it to be filled.
Use fill
t.begin_fill()
t.color("red")
for x in range(4):
t.fd(100)
t.rt(90)
t.end_fill()
Along with moving begin_fill() and end_fill() outside the loop, as several folks have mentioned, you've other issues with your code. For example, this is a no-op:
turtle.up
I.e. it doesn't do anything. (Missing parentheses.) This test:
if num_str.isdigit():
Doesn't do much for you as there is no else clause to handle the error. (I.e. when it isn't a number, the next statement simply uses the string as a number and fails.) This calculation seems a bit too complicated:
angle = 180 - 180*(squares-2)/squares
And finally there should be a cleaner way to exit the program. Let's address all these issues:
from turtle import Screen, Turtle
from random import random
NUMBER_SHAPES = 8
print("This program draws shapes based on the number you enter in a uniform pattern.")
num_str = ""
while not num_str.isdigit():
num_str = input("Enter the side number of the shape you want to draw: ")
sides = int(num_str)
angle = 360 / sides
delta_distance = 0
delta_angle = 0
screen = Screen()
turtle = Turtle()
for x in range(NUMBER_SHAPES):
turtle.color(random(), random(), random())
turtle.penup()
delta_distance += 5
turtle.forward(delta_distance)
delta_angle += 5
turtle.left(delta_angle)
turtle.pendown()
turtle.begin_fill()
for _ in range(sides):
turtle.forward(40)
turtle.left(angle)
turtle.forward(40)
turtle.end_fill()
screen.exitonclick()