How Can I Fill These Squares in Turtle - Python - python

I am trying to fill the color in these squares:
Right now the turtle only fills the corners of theses squares, not the entire square.
Here is my code:
import turtle
import time
import random
print ("This program draws shapes based on the number you enter in a uniform pattern.")
num_str = input("Enter the side number of the shape you want to draw: ")
if num_str.isdigit():
squares = int(num_str)
angle = 180 - 180*(squares-2)/squares
turtle.up
x = 0
y = 0
turtle.setpos(x,y)
numshapes = 8
for x in range(numshapes):
turtle.color(random.random(),random.random(), random.random())
x += 5
y += 5
turtle.forward(x)
turtle.left(y)
for i in range(squares):
turtle.begin_fill()
turtle.down()
turtle.forward(40)
turtle.left(angle)
turtle.forward(40)
print (turtle.pos())
turtle.up()
turtle.end_fill()
time.sleep(11)
turtle.bye()
I've tried moving around turtle.begin_fill() and end_fill() in numerous locations with no luckā€¦ Using Python 3.2.3, thanks.

I haven't really used turtle, but it looks like this may be what you want to do. Correct me if I've assumed the wrong functionality for these calls:
turtle.begin_fill() # Begin the fill process.
turtle.down() # "Pen" down?
for i in range(squares): # For each edge of the shape
turtle.forward(40) # Move forward 40 units
turtle.left(angle) # Turn ready for the next edge
turtle.up() # Pen up
turtle.end_fill() # End fill.

You're drawing a series of triangles, using begin_fill() and end_fill() for each one. What you can probably do is move your calls to begin_fill() and end_fill() outside the inner loop, so you draw a full square and then ask for it to be filled.

Use fill
t.begin_fill()
t.color("red")
for x in range(4):
t.fd(100)
t.rt(90)
t.end_fill()

Along with moving begin_fill() and end_fill() outside the loop, as several folks have mentioned, you've other issues with your code. For example, this is a no-op:
turtle.up
I.e. it doesn't do anything. (Missing parentheses.) This test:
if num_str.isdigit():
Doesn't do much for you as there is no else clause to handle the error. (I.e. when it isn't a number, the next statement simply uses the string as a number and fails.) This calculation seems a bit too complicated:
angle = 180 - 180*(squares-2)/squares
And finally there should be a cleaner way to exit the program. Let's address all these issues:
from turtle import Screen, Turtle
from random import random
NUMBER_SHAPES = 8
print("This program draws shapes based on the number you enter in a uniform pattern.")
num_str = ""
while not num_str.isdigit():
num_str = input("Enter the side number of the shape you want to draw: ")
sides = int(num_str)
angle = 360 / sides
delta_distance = 0
delta_angle = 0
screen = Screen()
turtle = Turtle()
for x in range(NUMBER_SHAPES):
turtle.color(random(), random(), random())
turtle.penup()
delta_distance += 5
turtle.forward(delta_distance)
delta_angle += 5
turtle.left(delta_angle)
turtle.pendown()
turtle.begin_fill()
for _ in range(sides):
turtle.forward(40)
turtle.left(angle)
turtle.forward(40)
turtle.end_fill()
screen.exitonclick()

Related

Flowchart nested for-loop

I have this code and I tried to do a flowchart but I have no clue how to make one.
All of my Flowchart I made, don't make any sense.
Could anyone of you guys please help me out???
import turtle
STARTING_X, STARTING_Y = 350, 200
turtle.penup()
turtle.width(2)
turtle.setheading(180)
turtle.sety(STARTING_Y)
for a in range(1, 8):
turtle.penup()
turtle.setx(STARTING_X)
for b in range(a):
turtle.pendown()
turtle.circle(25)
turtle.penup()
turtle.forward(60)
turtle.sety(turtle.ycor() - 60)
turtle.done()
The code:
# part 1
import turtle
STARTING_X, STARTING_Y = 350, 200
turtle.penup()
turtle.width(2)
turtle.setheading(180)
turtle.sety(STARTING_Y)
# part 2
for a in range(1, 8):
turtle.penup()
turtle.setx(STARTING_X)
for b in range(a): # part 3
turtle.pendown()
turtle.circle(25)
turtle.penup()
turtle.forward(60)
turtle.sety(turtle.ycor() - 60)
turtle.done()
Part 1:
Importing turtle
Making global variables for starting positions
turtle stuff (read docs)
Part 2:
for loop that runs 8 times
turtle pen up (not drawing)
start at predefined x position
for loop (see Part 3)
lower the y position with 60
Part 3:
runs a times
turtle pendown (drawing)
drawing a circle
turtle penup (not drawing)
go forward with 60 (in this case, lower the x position with 60 because of the direction in part 1)
**Summary**
This program draws 8 lines of circles, and each nth line contains n circles aligned to the right like this:
*
**
***
****
*****
******
*******
********
But circles instead of stars
First of all thank you very much for your help :)
But my question now is how to put that information into a flowchart like this.
I mean what's the Condition 1 / 2, what are the statements etc.

Turning simple polygons about a point in Python Turtle

I need help turning polygon shapes (triangle and square) in Python turtle to match a picture.
Below I am trying to copy the image.
I specifically need help on what to add to my code given the triangle and square to have them repeat outwards like the picture. Because as of now the triangles and squares look like this (pentagon code is correct and works) All help is appreciated. Thank you.
import turtle
def polygon(turtle, side, length):
turtle.color("Blue")
for i in range(4):
turtle.backward(length)
turtle.left(side)
def polygon1(turtle, side1, length):
turtle.color("Green")
for i in range(3):
turtle.left(side1)
turtle.forward(length)
def polygon2(turtle, side2, length):
turtle.color("Red")
for i in range(5):
turtle.forward(length)
turtle.left(side2)
def main():
my_turtle = turtle.Turtle()
wn = turtle.Screen()
Bill = turtle.Turtle()
length = 100
side = 90
side1 = 120
side2 = 72
Bill.pensize(5)
Bill.speed(0)
#Pentagons
Bill.pu()
Bill.right(180)
y = -45
for i in range(5):
Bill.pu()
Bill.goto(60, y)
Bill.pd()
polygon2(Bill, side2, length)
y -= 20
#Triangle
Bill.pu()
Bill.left(240)
x = 45
for j in range(5):
Bill.pu()
Bill.goto(10, x)
Bill.pd()
polygon1(Bill, side1, length)
x += 20
#Square
Bill.pu()
Bill.left(240)
b = 6
for b in range(5):
Bill.pu()
Bill.goto(148, b)
Bill.pd()
polygon(Bill, side, length)
b -= 20
wn.exitonclick()
if __name__ == '__main__':
main()
pentagon code is correct and works
I don't believe the pentagon code is correct nor that you're approaching this in the correct way. The inner three shapes should form an equilateral triangle -- yours don't as you're eyeballing instead of calculating. Instead of trying to get the turtle to be in the right spot, why not have the turtle move forward in the direction of the sides of this central triangle, drawing polygons as it goes.
That is, embrace the drawing as a whole rather than trying to divide and conquer.
We'd need to make sure the polygon drawing code restores the turtle's state when it's done, so it can simply move forward to the next polygon. We'll need to make explicit which numbers are arbitrary, and which are calculable. Although the original diagram appears to use at least three turtles to achieve it's result, we'll do it with one as you attempted:
from turtle import Turtle, Screen
SHAPES = [(5, "Red"), (3, "Green"), (4, "Blue")]
LENGTH = 100
DELTA = 20
REPLICATIONS = 5
THICKNESS = 5
HEIGHT = (3 ** 0.5 / 2) * LENGTH # assumes 3 shapes, should fix!
DIVISIONS = 360 / len(SHAPES)
def polygon(turtle, sides, color):
turtle.color(color)
turtle.left(90)
turtle.forward(LENGTH / 2)
for _ in range(sides):
turtle.right(360 / sides)
turtle.forward(LENGTH)
turtle.backward(LENGTH / 2) # restore turtle to original state
turtle.right(90)
wn = Screen()
bill = Turtle()
bill.speed('fastest')
bill.pensize(THICKNESS)
bill.penup()
for offset, (sides, color) in enumerate(SHAPES):
bill.setheading(-DIVISIONS * offset - 90)
bill.forward(HEIGHT / 3) # assumes 3 shapes, should fix!
for _ in range(REPLICATIONS):
bill.pendown()
polygon(bill, sides, color)
bill.penup()
bill.forward(DELTA)
bill.home()
wn.exitonclick()

Turtle Graphics: Repeating Squares

I am trying to create a loop that takes an input by a user and draws however many squares but it increases the size of the squares with each loop, however 2 sides are stay connected. I'll include the graphic to better explain.
import turtle
squares = 1
while squares >= 1:
squares = int(input('How many squares would you like drawn?:'))
if squares == 0:
print("You must have at-least 1 square.")
squares = int(input('How many squares would you like drawn?:'))
else:
for count in range(squares):
turtle.forward(30)
turtle.left(90)
turtle.forward(30)
turtle.left(90)
turtle.forward(30)
turtle.left(90)
turtle.forward(30)
turtle.left(90)
turtle.done()
The input request and the drawing logic ought to be separated.
Here is one approach that returns the turtle at the start at each turn, after increasing the side length.
import turtle
num_squares = 3
t = turtle.Turtle()
t.pendown()
side = side_unit = 30
while True:
try:
num_squares = int(input('input the number of squares'))
except ValueError:
print("please enter an integer")
if num_squares > 3:
break
for sq in range(1, num_squares + 1):
t.left(90)
t.forward(side)
t.left(90)
t.forward(side)
t.left(90)
t.forward(side)
t.left(90)
side = side_unit + 3 * sq # increase the size of the side
t.goto(0,0) # return to base
turtle.done()
While waiting for #ReblochonMasque's solution to finish drawing 100 squares, there's plenty of time to implement an alternate, faster solution based on stamping.
The first thing to note is in the provided instructions it says to draw 100 squares to create the design in the figure, but that figure consists of just under 50 squares. It's also been scaled in some non integral fashion which makes it appear to have different line thicknesses.
Let's focus on the spirt of the problem rather than the example. The OP had a 1 square minimum so I've preserved that. This solution also naturally tends to center the square on the window:
from turtle import Turtle, Screen
DELTA = 3
MINIMUM = DELTA * 2
CURSOR_SIZE = 20
num_squares = -1
while num_squares < 1:
try:
num_squares = int(input('Input the number of squares: '))
except ValueError:
print("please enter an integer.")
if num_squares < 1:
print("You must have at least 1 square.")
screen = Screen()
turtle = Turtle("square", visible=False)
turtle.fillcolor("white")
for size in range(((num_squares - 1) * DELTA) + MINIMUM, MINIMUM - 1, -DELTA):
turtle.goto(turtle.xcor() + DELTA/2, turtle.ycor() - DELTA/2)
turtle.shapesize(size / CURSOR_SIZE)
turtle.stamp()
screen.exitonclick()
This is clearly not the kind of solution the OP was looking for, but maybe next time a problem like this comes up, it might be one the OP will at least consider.

New to Python: Turtle 25 squares checkerboard using loops

def main():
square(0,0,50,'red')
def square(x,y,width,color):
turtle.penup()
turtle.goto(0,0)
turtle.fillcolor(color)
turtle.pendown()
turtle.begin_fill()
for number in range(5):
for count in range(4):
turtle.forward(width)
turtle.left(90)
turtle.end_fill()
x = x+50
turtle.goto(x,y)
turtle.showturtle()
Call the main function
main()
This gives me one row of 5 squares. How do i code an outer loop to draw 4 more
of rows of such 5 squares - a 5 by 5 checkerboard?
I simplified your "square" function to only draw a single square. Then I added a separate function which included a nested loop that calls the square function.
Trying to keep it simple and have only one responsibility for each function:
import turtle
def main():
board(5, 5, 50)
input("Hit enter to close")
def square(x,y,width,color):
turtle.penup()
turtle.fillcolor(color)
turtle.goto(x, y)
turtle.pendown()
turtle.begin_fill()
for side in range(4):
turtle.forward(width)
turtle.left(90)
turtle.end_fill()
def board(rows, columns, square_width):
turtle.showturtle()
for row in range(rows):
for column in range(columns):
color = "red" if (row + column)%2 == 1 else "white"
square(row*square_width, column*square_width, square_width, color)
turtle.hideturtle()
You already have code to draw a row of squares, that's the loop you have right now.
You want that code to be run 5 times, so just wrap it in another loop, making sure to modify variables as necessary. Something along the lines of this:
for i in range(5):
for number in range(5):
for count in range(4):
turtle.forward(width)
turtle.left(90)
turtle.end_fill()
x += width
turtle.goto(x,y)
x -= 5*width
y += width
Also a note on style, square() is ignoring most of its parameters. You hardcode your turtle to go to (0,0), regardless of the values of x and y. Because your later gotos use these values, your code will break if you set them to anything other than 0. Your line x = x+50 also ignores the value of width, even though the line the turtle draws uses it. Again, if you set it to anything other than 50, this will break.

How to initialize multiple turtles in Python with classes

I am a beginner at Python and I'm new to Stack Exchange. I'm trying to write a program that has 5 turtles moving within a square. I've got code that does what I want, but it's tedious and I'd like to initialize all my turtles using classes instead of doing it one by one. I just want them to start out at random coordinates and with a random heading.
The problems with my code:
Only one turtle is shown on screen. Two are defined in the code below.
The turtle's heading and coordinates aren't being initialized.
Here's the code that I've tried:
import numpy as np
from turtle import *
# setting up screen
reset()
screensize(550)
Screen().bgcolor('black')
tracer(0)
# drawing box
t0 = Turtle()
t0.penup()
t0.goto(-256,-256)
t0.color('cyan')
t0.pendown()
for i in range(4):
t0.forward(512)
t0.left(90)
t0.ht()
# parameters
velocity = 5
iterations = 200
boxsize = 512
ranheader = np.random.random()*360
ranx = np.random.random()*boxsize
rany = np.random.random()*boxsize
class turtle_agents(Turtle):
def _init_(self):
self.up()
self.seth(ranheader)
self.setpos(ranx,rany)
self.velocity = velocity
self.down()
# turtle
t1 = turtle_agents()
t1.color('green')
t2 = turtle_agents()
t2.color('blue')
# turtle movement
for turtle in turtles():
for i in range(iterations):
turtle.forward(velocity)
if turtle.xcor() >= 256:
turtle.goto(-256,t0.ycor())
elif turtle.xcor() <= -256:
turtle.goto(256,t0.ycor())
elif turtle.ycor() >= 256:
turtle.goto(t0.xcor(),-256)
elif turtle.ycor() <= -256:
turtle.goto(t0.xcor(),256)
update()
exitonclick()
only one turtle shown on screen. Two are defined in the code below.
the turtle's heading and coordinates aren't being initialized.
I believe the problem is that you defined the random position and heading once, outside the turtle creation loop so they all start in the same place, move in the same direction at the same speed. I.e. they're right on top of each other.
We don't need #BlivetWidget's explicit List to fix the problem since, as you discovered, turtles are already maintained in a list which we can get via the screen's turtles() method. Below is my rework of your code to fix various issues:
from turtle import Screen, Turtle
from random import randrange, randint
# parameters
COLORS = ['green', 'blue', 'red', 'orange', 'white']
ITERATIONS = 500
VELOCITY = 5
BOX_SIZE = 512
# setting up screen
screen = Screen()
screen.setup(BOX_SIZE + 50, BOX_SIZE + 50)
screen.bgcolor('black')
screen.tracer(False)
# drawing box
turtle = Turtle()
turtle.hideturtle()
turtle.color('cyan')
turtle.penup()
turtle.goto(-BOX_SIZE/2, -BOX_SIZE/2)
turtle.pendown()
for _ in range(4):
turtle.forward(BOX_SIZE)
turtle.left(90)
# turtle
for color in COLORS:
angle = randrange(360)
x = randint(-BOX_SIZE/2, BOX_SIZE/2)
y = randint(-BOX_SIZE/2, BOX_SIZE/2)
turtle = Turtle()
turtle.color(color)
turtle.setheading(angle)
turtle.penup()
turtle.setposition(x, y)
turtle.pendown()
# turtle movement
for _ in range(ITERATIONS):
for turtle in screen.turtles():
turtle.forward(VELOCITY)
x, y = turtle.position()
if x >= BOX_SIZE/2:
turtle.penup()
turtle.setx(-BOX_SIZE/2)
turtle.pendown()
elif x <= -BOX_SIZE/2:
turtle.penup()
turtle.setx(BOX_SIZE/2)
turtle.pendown()
elif y >= BOX_SIZE/2:
turtle.penup()
turtle.sety(-BOX_SIZE/2)
turtle.pendown()
elif y <= -BOX_SIZE/2:
turtle.penup()
turtle.sety(BOX_SIZE/2)
turtle.pendown()
screen.update()
screen.exitonclick()
I agree with #BlivetWidget that "you don't need to create a class just to move them to your starting positions". I use a simple loop above.
You should consider storing your turtles in a list, as the turtles are already objects and you don't need to create a class just to move them to your starting positions. Lists in Python are incredibly powerful because they can store arbitrary data types. Here, I will create 5 turtles and move them so you can tell them apart:
import turtle
num_turtles = 5
my_turtles = [turtle.Turtle() for i in range(num_turtles)]
for i, turt in enumerate(my_turtles):
turt.forward(50 * i)
You want to do the same thing, just replace my turt.forward() line with whatever you want the turtles to do. In your case, go to a random position within your square.

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