I am scraping an html file, each page has a video on it, and in the html there is the video id. I want to print out the video id.
I know that if i want to print a headline from a div class i would do this
with open('yeehaw.html') as html_file:
soup = BeautifulSoup(html_file, 'lxml')
article = soup.find('div', class_='article')
headline = article.h2.a.text
print headline
However the id for the video is found inside a data-id='qe67234'
I dont know how to access this 'qe67234' and print it out.
please help thank you!
Assuming that the tag for data-id begins with div:
from bs4 import BeautifulSoup
import re
soup = BeautifulSoup('<div class="_article" data-id="qe67234"></div>')
results = soup.findAll("div", {"data-id" : re.compile(r".*")})
print('output: ', results[0]['data-id'])
# output: qe67234
Assuming that the data-id is in div
BeautifulSoup.find returns you the found html element as a dictionary. You can therefore navigate it using standard means to get access to the text (as you did in your question) as well as html tags (as shown in the code below)
soup = BeautifulSoup('<div class="_article" data-id="qe67234">')
soup.find("div", {"class":"_article"})['data-id']
Note that, oftentimes, video elements require JS for playback, and you might not be able to find the necessary element if it was scraped with a non-javascript client (i.e. python requests).
If this happens, you have to use tools like phantomjs + selenium browser to get the website combined with the javascript to perform your scraping.
EDIT
If the data-id tag itself is not constant, you should look into lxml library to replace BeautifulSoup and use xpath values to find the element that you need
Related
This is the link of the webpage I want to scrape:
https://www.tripadvisor.in/Restaurants-g494941-Indore_Indore_District_Madhya_Pradesh.html
I have also applied additional filters, by clicking on the encircled heading1
This is how the webpage looks like after clicking on the heading2
I want to get names of all the places displayed on the webpage but I seem to be having trouble with it as the url doesn't get changed on applying the filter.
I am using python urllib for this.
Here is my code:
url = "https://www.tripadvisor.in/Hotels-g494941-Indore_Indore_District_Madhya_Pradesh-Hotels.html"
page = urlopen(url)
html_bytes = page.read()
html = html_bytes.decode("utf-8")
print(html)
You can use bs4. Bs4 is a python module that allows you to get certain things off of webpages. This will get the text from the site:
from bs4 import BeautifulSoup as bs
soup = bs(html, features='html5lib')
text = soup.get_text()
print(text)
If you would like to get something that is not the text, maybe something with a certain tag you can also use bs4:
soup.findall('p') # Getting all p tags
soup.findall('p', class_='Title') #getting all p tags with a class of Title
Find what class and tag all of the place names have, and then use the above to get all the place names.
https://www.crummy.com/software/BeautifulSoup/bs4/doc/
I am trying to web-scrape using an h2 tag, but BeautifulSoup returns an empty list.
<h2 class="iCIMS_InfoMsg iCIMS_InfoField_Job">
html=urlopen("https://careersus-endologix.icims.com/jobs/2034/associate-supplier-quality-engineer/job")
bs0bj=BeautifulSoup(html,"lxml")
nameList=bs0bj.findAll("h2",{"class":"iCIMS_InfoMsg iCIMS_InfoField_Job"})
print(nameList)
The content is inside an iframe and updated via js (so not present in initial request). You can use the same link the page is using to obtain iframe content (the iframe src). Then extract the string from the script tag that has the info and load with json, extract the description (which is html) and pass back to bs to then select the h2 tags. You now have the rest of the info stored in the second soup object as well if required.
import requests
from bs4 import BeautifulSoup as bs
import json
r = requests.get('https://careersus-endologix.icims.com/jobs/2034/associate-supplier-quality-engineer/job?mobile=false&width=1140&height=500&bga=true&needsRedirect=false&jan1offset=0&jun1offset=60&in_iframe=1')
soup = bs(r.content, 'lxml')
script = soup.select_one('[type="application/ld+json"]').text
data = json.loads(script)
soup = bs(data['description'], 'lxml')
headers = [item.text for item in soup.select('h2')]
print(headers)
The answer lays hidden in two elements:
javascript rendered contents: after document.onload
in particular the content managed by js comes after this comment and it's, indeed, rendered by js. The line where the block starts is: "< ! - -BEGIN ICIMS - - >" (space added to avoid it goes blank)
As you can imagine the h2 class="ICISM class here" DOESN'T exist WHEN you call the bs4 methods.
The solution?
IMHO the best way to achieve what you want is to use selenium, to get a full rendered web page.
check this also
Web-scraping JavaScript page with Python
I wrote this test code which uses BeautifulSoup.
url = "http://www.dailymail.co.uk/news/article-3795511/Harry-Potter-sale-half-million-pound-house-Iconic-Privet-Drive-market-suburban-Berkshire-complete-cupboard-stairs-one-magical-boy.html"
html = urllib.request.urlopen(url).read()
soup = BeautifulSoup(html,"lxml")
for n in soup.find_all('p'):
print(n.get_text())
It works fine but it also retrieves text that is not part of the news article, such as the time it was posted, number of comments, copyrights ect.
I would wish for it to only retrieve text from the news article itself, how would one go about this?
You might have much better luck with newspaper library which is focused on scraping articles.
If we talk about BeautifulSoup only, one option to get closer to the desired result and have more relevant paragraphs is to find them in the context of div element with itemprop="articleBody" attribute:
article_body = soup.find(itemprop="articleBody")
for p in article_body.find_all("p"):
print(p.get_text())
You'll need to target more specifically than just the p tag. Try looking for a div class="article" or something similar, then only grab paragraphs from there
Be more specific, you need to catch the div with class articleBody, so :
import urllib.request
from bs4 import BeautifulSoup
url = "http://www.dailymail.co.uk/news/article-3795511/Harry-Potter-sale-half-million-pound-house-Iconic-Privet-Drive-market-suburban-Berkshire-complete-cupboard-stairs-one-magical-boy.html"
html = urllib.request.urlopen(url).read()
soup = BeautifulSoup(html,"lxml")
for n in soup.find_all('div', attrs={'itemprop':"articleBody"}):
print(n.get_text())
Responses on SO is not just for you, but also for people coming from google searches and such. So as you can see, attrs is a dict, it is then possible to pass more attributes/values if needed.
I am new to Python and working on a scraping project. I am using Firebug to copy the CSS path of required links. I am trying to collect the links under the tab of "UPCOMING EVENTS" from http://kiascenehai.pk/ but it is just for learning how I can get the specified links.
I am looking for the fix of this problem and also suggestions for how to retrieve specified links using CSS selectors.
from bs4 import BeautifulSoup
import requests
url = "http://kiascenehai.pk/"
r = requests.get(url)
data = r.text
soup = BeautifulSoup(data)
for link in soup.select("html body div.body-outer-wrapper div.body-wrapper.boxed-mode div.main- outer-wrapper.mt30 div.main-wrapper.container div.row.row-wrapper div.page-wrapper.twelve.columns.b0 div.row div.page-wrapper.twelve.columns div.row div.eight.columns.b0 div.content.clearfix section#main-content div.row div.six.columns div.small-post-wrapper div.small-post-content h2.small-post-title a"):
print link.get('href')
First of all, that page requires a city selection to be made (in a cookie). Use a Session object to handle this:
s = requests.Session()
s.post('http://kiascenehai.pk/select_city/submit_city', data={'city': 'Lahore'})
response = s.get('http://kiascenehai.pk/')
Now the response gets the actual page content, not redirected to the city selection page.
Next, keep your CSS selector no larger than needed. In this page there isn't much to go on as it uses a grid layout, so we first need to zoom in on the right rows:
upcoming_events_header = soup.find('div', class_='featured-event')
upcoming_events_row = upcoming_events_header.find_next(class_='row')
for link in upcoming_events_row.select('h2 a[href]'):
print link['href']
This is co-founder KiaSceneHai.pk; please don't scrape websites, alot of effort goes into collecting the data, we offer access through our API, you can use the contact form to request access, ty
I am new to Python and I am learning it for scraping purposes I am using BeautifulSoup to collect links (i.e href of 'a' tag). I am trying to collect the links under the "UPCOMING EVENTS" tab of site http://allevents.in/lahore/. I am using Firebug to inspect the element and to get the CSS path but this code returns me nothing. I am looking for the fix and also some suggestions for how I can choose proper CSS selectors to retrieve desired links from any site. I wrote this piece of code:
from bs4 import BeautifulSoup
import requests
url = "http://allevents.in/lahore/"
r = requests.get(url)
data = r.text
soup = BeautifulSoup(data)
for link in soup.select( 'html body div.non-overlay.gray-trans-back div.container div.row div.span8 div#eh-1748056798.events-horizontal div.eh-container.row ul.eh-slider li.h-item div.h-meta div.title a[href]'):
print link.get('href')
The page is not the most friendly in the use of classes and markup, but even so your CSS selector is too specific to be useful here.
If you want Upcoming Events, you want just the first <div class="events-horizontal">, then just grab the <div class="title"><a href="..."></div> tags, so the links on titles:
upcoming_events_div = soup.select_one('div.events-horizontal')
for link in upcoming_events_div.select('div.title a[href]'):
print(link['href'])
Note that you should not use r.text; use r.content and leave decoding to Unicode to BeautifulSoup. See Encoding issue of a character in utf-8
import bs4 , requests
res = requests.get("http://allevents.in/lahore/")
soup = bs4.BeautifulSoup(res.text)
for link in soup.select('a[property="schema:url"]'):
print link.get('href')
This code will work fine!!