This is the link of the webpage I want to scrape:
https://www.tripadvisor.in/Restaurants-g494941-Indore_Indore_District_Madhya_Pradesh.html
I have also applied additional filters, by clicking on the encircled heading1
This is how the webpage looks like after clicking on the heading2
I want to get names of all the places displayed on the webpage but I seem to be having trouble with it as the url doesn't get changed on applying the filter.
I am using python urllib for this.
Here is my code:
url = "https://www.tripadvisor.in/Hotels-g494941-Indore_Indore_District_Madhya_Pradesh-Hotels.html"
page = urlopen(url)
html_bytes = page.read()
html = html_bytes.decode("utf-8")
print(html)
You can use bs4. Bs4 is a python module that allows you to get certain things off of webpages. This will get the text from the site:
from bs4 import BeautifulSoup as bs
soup = bs(html, features='html5lib')
text = soup.get_text()
print(text)
If you would like to get something that is not the text, maybe something with a certain tag you can also use bs4:
soup.findall('p') # Getting all p tags
soup.findall('p', class_='Title') #getting all p tags with a class of Title
Find what class and tag all of the place names have, and then use the above to get all the place names.
https://www.crummy.com/software/BeautifulSoup/bs4/doc/
Related
from bs4 import BeautifulSoup
import requests
req = requests.get("https://www.airtel.in/myplan-infinity/")
soup = BeautifulSoup(req.content, 'html.parser')
#finding the div with the id
div_bs4 = soup.find('div')
print(div_bs4)
What should I do to scrape the recharge plans of the page?
you should use content when you need to get media data (like pictures, videos, etc)
if you need to get non-media data you've to use text instead of content
make the soup like this: `soup = BeautifulSoup(req.text, 'lxml')
make sure that this like div_bs4 = soup.find('div') finds the exact div you need (cuz it will just get the first div in html)
this line print(div_bs4) won't give you needed data
you'd better use this print(div_bs4.text)
I am trying to Scrape NBA.com play by play table so I want to get the text for each box that is in the example picture.
for example(https://www.nba.com/game/bkn-vs-cha-0022000032/play-by-play).
checking the html code I figured that each line is in an article tag that contains div tag that contains two p tags with the information I want, however I wrote the following code and I get back that there are 0 articles and only 9 P tags (should be much more) but even the tags I get their text is not the box but something else. I get 9 tags so I am doing something terrible wrong and I am not sure what it is.
this is the code to get the tags:
from urllib.request import urlopen
from bs4 import BeautifulSoup
def contains_word(t):
return t and 'keyword' in t
url = "https://www.nba.com/game/bkn-vs-cha-0022000032/play-by-play"
page = urlopen(url)
html = page.read().decode("utf-8")
soup = BeautifulSoup(html, "html.parser")
div_tags = soup.find_all('div', text=contains_word("playByPlayContainer"))
articles=soup.find_all('article')
p_tag = soup.find_all('p', text=contains_word("md:bg"))
thank you!
Use Selenium since it's using Javascript and pass it to Beautifulsoup. Also pip install selenium and get the chromedriver.exe
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://www.nba.com/game/bkn-vs-cha-0022000032/play-by-play")
soup = BeautifulSoup(driver.page_source, "html.parser")
I have used Beautifulsoup to scrape a website. My current code helps me to get the website content in HTML format. I used soup to find the word if it is present or not but I am not able to get the paragraph it belongs to.
import requests
from bs4 import BeautifulSoup
# Make a request
page = requests.get(
"https://manychat.com/")
soup = BeautifulSoup(page.content, 'html.parser')
# Extract title of page
page_title = soup.title.text
# Extract body of page
page_body = soup.body
# Extract head of page
page_head = soup.head
# print the result
print(page_body, page_head)
thirdParty = soup.find(text = 'Facebook')
Usually, the areas you're interested in searching are of a common kind, like <div> with a common class. So, you have Soup return all of the <div>s with that class, and you search the div text for your word.
I 've been trying to scrape two values from a website using beautiful soup in Python, and it's been giving me trouble. Here is the URL of the page I'm scraping:
https://www.stjosephpartners.com/Home/Index
Here are the values I'm trying to scrape:
HTML of Website to be Scraped
I tried:
from bs4 import BeautifulSoup
import requests
source = requests.get('https://www.stjosephpartners.com/Home/Index').text
soup = BeautifulSoup(source, 'lxml')
gold_spot_shell = soup.find('div', class_ = 'col-lg-10').children
print(gold_spot_shell)
the output I got was: <list_iterator object at 0x039FD0A0>
When I tried using: gold_spot_shell = soup.find('div', class_ = 'col-lg-10').children
The output was: ['\n']
when I tried using: gold_spot_shell = soup.find('div', class_ = 'col-lg-10').span
The output was: none
The HTML definitely has at least one span child. I'm not sure how to scrape the values I'm after. Thanks.
Beautifulsoup + Request is not a good method to scrape dynamic website like this. That span is generated by javascript so when you get the html using request, it just does not exist.
You can try to use selenium instead.
You can check if the website is using javascript to render element or not by disabling javascript on the page and find that element again, or just "view page source"
I have the following html pattern I want to scrap using BeautifulSoup. The html pattern is:
TITLE
I want to grab TITLE and the information that is displayed in the link. That is, if you clicked the link there is a a description of the TITLE. I want that description.
I started with just trying to grab the title with the following code:
import urllib
from bs4 import BeautifulSoup
import re
webpage = urrlib.urlopen("http://urlofinterest")
title = re.compile('<a>(.*)</a>')
findTitle = re.findall(title,webpage)
print findTile
My output is:
% python beta2.py
[]
So this is obviously not even finding the title. I even tried <a href>(.*)</a> and that didn't work. Based on my reading of the documentation and I thought BeautifulSoup will grab whatever text is between the symbols I give it. In this case, , so what am I doing wrong?
How come you're importing beautifulsoup and then not using it at all?
webpage = urrlib.urlopen("http://urlofinterest")
You'll want to read the data from this, so that:
webpage = urrlib.urlopen("http://urlofinterest").read()
Something like (should get you to a point to go further):
>>> blah = 'TITLE'
>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup(blah) # change to webpage later
>>> for tag in soup('a', href=True):
print tag['href'], tag.string
link TITLE