Centroidal Voronoi tessellation - python

I am trying to build a bounded Voronoi diagram using the scipy package and in each iteration I compute the centroids of the Voronoi cells and move a bit say some delta towards the centroid and recompute the Voronoi diagram by updating the generator points. When I try to plot the updated points I get a weird error as in the point I plot is not where it is expected to be.
Here's the code
import matplotlib.pyplot as pl
import numpy as np
import scipy as sp
import scipy.spatial
import sys
np.random.seed(1)
eps = sys.float_info.epsilon
n_robots = 10
robots = np.random.rand(n_robots, 2)
#print(robots)
bounding_box = np.array([0., 1., 0., 1.])
def in_box(robots, bounding_box):
return np.logical_and(np.logical_and(bounding_box[0] <= robots[:, 0],
robots[:, 0] <= bounding_box[1]),
np.logical_and(bounding_box[2] <= robots[:, 1],
robots[:, 1] <= bounding_box[3]))
def voronoi(robots, bounding_box):
i = in_box(robots, bounding_box)
points_center = robots[i, :]
points_left = np.copy(points_center)
points_left[:, 0] = bounding_box[0] - (points_left[:, 0] - bounding_box[0])
points_right = np.copy(points_center)
points_right[:, 0] = bounding_box[1] + (bounding_box[1] - points_right[:, 0])
points_down = np.copy(points_center)
points_down[:, 1] = bounding_box[2] - (points_down[:, 1] - bounding_box[2])
points_up = np.copy(points_center)
points_up[:, 1] = bounding_box[3] + (bounding_box[3] - points_up[:, 1])
points = np.append(points_center,
np.append(np.append(points_left,
points_right,
axis=0),
np.append(points_down,
points_up,
axis=0),
axis=0),
axis=0)
# Compute Voronoi
vor = sp.spatial.Voronoi(points)
# Filter regions
regions = []
ind = np.arange(points.shape[0])
ind = np.expand_dims(ind,axis= 1)
for region in vor.regions:
flag = True
for index in region:
if index == -1:
flag = False
break
else:
x = vor.vertices[index, 0]
y = vor.vertices[index, 1]
if not(bounding_box[0] - eps <= x and x <= bounding_box[1] + eps and
bounding_box[2] - eps <= y and y <= bounding_box[3] + eps):
flag = False
break
if region != [] and flag:
regions.append(region)
vor.filtered_points = points_center
vor.filtered_regions = regions
return vor
def centroid_region(vertices):
A = 0
C_x = 0
C_y = 0
for i in range(0, len(vertices) - 1):
s = (vertices[i, 0] * vertices[i + 1, 1] - vertices[i + 1, 0] * vertices[i, 1])
A = A + s
C_x = C_x + (vertices[i, 0] + vertices[i + 1, 0]) * s
C_y = C_y + (vertices[i, 1] + vertices[i + 1, 1]) * s
A = 0.5 * A
C_x = (1.0 / (6.0 * A)) * C_x
C_y = (1.0 / (6.0 * A)) * C_y
return np.array([[C_x, C_y]])
def plot(r,index):
vor = voronoi(r, bounding_box)
fig = pl.figure()
ax = fig.gca()
# Plot initial points
ax.plot(vor.filtered_points[:, 0], vor.filtered_points[:, 1], 'b.')
print("initial",vor.filtered_points)
# Plot ridges points
for region in vor.filtered_regions:
vertices = vor.vertices[region, :]
ax.plot(vertices[:, 0], vertices[:, 1], 'go')
# Plot ridges
for region in vor.filtered_regions:
vertices = vor.vertices[region + [region[0]], :]
ax.plot(vertices[:, 0], vertices[:, 1], 'k-')
# Compute and plot centroids
centroids = []
for region in vor.filtered_regions:
vertices = vor.vertices[region + [region[0]], :]
centroid = centroid_region(vertices)
centroids.append(list(centroid[0, :]))
ax.plot(centroid[:, 0], centroid[:, 1], 'r.')
centroids = np.asarray(centroids)
rob = np.copy(vor.filtered_points)
# the below code is for the plotting purpose the update happens in the update function
interim_x = np.asarray(centroids[:,0] - rob[:,0])
interim_y = np.asarray(centroids[:,1] - rob[:,1])
magn = [np.linalg.norm(centroids[i,:] - rob[i,:]) for i in range(rob.shape[0])]
x = np.copy(interim_x)
x = np.asarray([interim_x[i]/magn[i] for i in range(interim_x.shape[0])])
y = np.copy(interim_y)
y = np.asarray([interim_y[i]/magn[i] for i in range(interim_y.shape[0])])
nor = np.copy(rob)
for i in range(x.shape[0]):
nor[i,0] = x[i]
nor[i,1] = y[i]
temp = np.copy(rob)
temp[:,0] = [rob[i,0] + 0.5*interim_x[i] for i in range(rob.shape[0])]
temp[:,1] = [rob[i,1] + 0.5*interim_y[i] for i in range(rob.shape[0])]
ax.plot(temp[:,0] ,temp[:,1], 'y.' )
ax.set_xlim([-0.1, 1.1])
ax.set_ylim([-0.1, 1.1])
pl.savefig("voronoi" + str(index) + ".png")
return centroids
def update(rob,centroids):
interim_x = np.asarray(centroids[:,0] - rob[:,0])
interim_y = np.asarray(centroids[:,1] - rob[:,1])
magn = [np.linalg.norm(centroids[i,:] - rob[i,:]) for i in range(rob.shape[0])]
x = np.copy(interim_x)
x = np.asarray([interim_x[i]/magn[i] for i in range(interim_x.shape[0])])
y = np.copy(interim_y)
y = np.asarray([interim_y[i]/magn[i] for i in range(interim_y.shape[0])])
nor = [np.linalg.norm([x[i],y[i]]) for i in range(x.shape[0])]
temp = np.copy(rob)
temp[:,0] = [rob[i,0] + 0.5*interim_x[i] for i in range(rob.shape[0])]
temp[:,1] = [rob[i,1] + 0.5*interim_y[i] for i in range(rob.shape[0])]
return np.asarray(temp)
if __name__ == '__main__':
for i in range(1):
centroids = plot(robots,i)
robots = update(robots,centroids)
Also here is an image of what the code does. The blue points are the generator points, red are the centroids and yellow are supposed to be the midway points between the blue and red points. But as you can see the yellow points are not in between the blue and red points.

The problem is that your points when fed to Voronoi get inflated during the construction of the tessellation, and when you later filter them out the points are in the wrong order. Consequently when you set vor.filtered_points = points_center in voronoi(), the points are shuffled compared to the order of regions. So while you're computing the midpoints correctly, you're using the wrong pairs of points.
I circled two correct pairings in green and an incorrect one in red here:
As you can see from the red circle, the basis point in an edge cell is paired with the centroid of an adjacent cell.
The solution is simple: when you're filtering the regions and find a region to keep, you need to gather the point which falls inside the corresponding region. You can do this by matching vor.points to vor.point_region and finding the corresponding region, for which you'll need to enumerate your regions:
# Compute Voronoi
vor = sp.spatial.Voronoi(points)
# Filter regions and select corresponding points
regions = []
points_to_filter = [] # we'll need to gather points too
ind = np.arange(points.shape[0])
ind = np.expand_dims(ind,axis= 1)
for i,region in enumerate(vor.regions): # enumerate the regions
if not region: # nicer to skip the empty region altogether
continue
flag = True
for index in region:
if index == -1:
flag = False
break
else:
x = vor.vertices[index, 0]
y = vor.vertices[index, 1]
if not(bounding_box[0] - eps <= x and x <= bounding_box[1] + eps and
bounding_box[2] - eps <= y and y <= bounding_box[3] + eps):
flag = False
break
if flag:
regions.append(region)
# find the point which lies inside
points_to_filter.append(vor.points[vor.point_region == i][0,:])
vor.filtered_points = np.array(points_to_filter)
vor.filtered_regions = regions
With these modifications the averaging works fine:

Related

Deriving Cubic Bezier Curve control points & handles from series of points in Python

I am trying to find the control points and handles of a Cubic Bezier curve from a series of points. My current code is below (credit to Zero Zero on the Python Discord). The Cubic Spline is creating the desired fit, but the handles (in orange) are incorrect. How may I find the handles of this curve?
Thank you!
import numpy as np
import scipy as sp
def fit_curve(points):
# Fit a cubic bezier curve to the points
curve = sp.interpolate.CubicSpline(points[:, 0], points[:, 1], bc_type=((1, 0.0), (1, 0.0)))
# Get 4 control points for the curve
p = np.zeros((4, 2))
p[0, :] = points[0, :]
p[3, :] = points[-1, :]
p[1, :] = points[0, :] + 0.3 * (points[-1, :] - points[0, :])
p[2, :] = points[-1, :] - 0.3 * (points[-1, :] - points[0, :])
return p, curve
ypoints = [0.0, 0.03771681353260319, 0.20421680080883106, 0.49896111463402026, 0.7183501026981503, 0.8481517096346528, 0.9256128196832564, 0.9705404287079152, 0.9933297674379904, 1.0]
xpoints = [x for x in range(len(ypoints))]
points = np.array([xpoints, ypoints]).T
from scipy.interpolate import splprep, splev
tck, u = splprep([xpoints, ypoints], s=0)
#print(tck, u)
xnew, ynew = splev(np.linspace(0, 1, 100), tck)
# Plot the original points and the Bézier curve
import matplotlib.pyplot as plt
#plt.plot(xpoints, ypoints, 'x', xnew, ynew, xpoints, ypoints, 'b')
plt.axis([0, 10, -0.05, 1.05])
plt.legend(['Points', 'Bézier curve', 'True curve'])
plt.title('Bézier curve fitting')
# Get the curve
p, curve = fit_curve(points)
# Plot the points and the curve
plt.plot(points[:, 0], points[:, 1], 'o')
plt.plot(p[:, 0], p[:, 1], 'o')
plt.plot(np.linspace(0, 9, 100), curve(np.linspace(0, 9, 100)))
plt.show()
The answer for my case was a Bezier best fit function that accepts an input of point values, fits the points to a Cubic Spline, and outputs the Bézier handles of the curve by finding their coefficients.
Here is one such script, fitCurves, which can be used like so:
import numpy as np
from fitCurve import fitCurve
import matplotlib.pyplot as plt
y = [0.0,
0.03771681353260319,
0.20421680080883106,
0.49896111463402026,
0.7183501026981503,
0.8481517096346528,
0.9256128196832564,
0.9705404287079152,
0.9933297674379904,
1.0]
x = np.linspace(0, 1, len(y))
pts = np.array([x,y]).T
bezier_handles = fitCurve(points=pts , maxError=20)
x_bez = []
y_bez = []
for bez in bezier_handles:
for pt in bez:
x_bez.append(pt[0])
y_bez.append(pt[1])
plt.plot(pts[:,0], pts[:,1], 'bo-', label='Points')
plt.plot(x_bez[:2], y_bez[:2], 'ro--', label='Handle') # handle 1
plt.plot(x_bez[2:4], y_bez[2:4], 'ro--') # handle 2
plt.legend()
plt.show()
fitCurve.py
from numpy import *
""" Python implementation of
Algorithm for Automatically Fitting Digitized Curves
by Philip J. Schneider
"Graphics Gems", Academic Press, 1990
"""
# evaluates cubic bezier at t, return point
def q(ctrlPoly, t):
return (1.0-t)**3 * ctrlPoly[0] + 3*(1.0-t)**2 * t * ctrlPoly[1] + 3*(1.0-t)* t**2 * ctrlPoly[2] + t**3 * ctrlPoly[3]
# evaluates cubic bezier first derivative at t, return point
def qprime(ctrlPoly, t):
return 3*(1.0-t)**2 * (ctrlPoly[1]-ctrlPoly[0]) + 6*(1.0-t) * t * (ctrlPoly[2]-ctrlPoly[1]) + 3*t**2 * (ctrlPoly[3]-ctrlPoly[2])
# evaluates cubic bezier second derivative at t, return point
def qprimeprime(ctrlPoly, t):
return 6*(1.0-t) * (ctrlPoly[2]-2*ctrlPoly[1]+ctrlPoly[0]) + 6*(t) * (ctrlPoly[3]-2*ctrlPoly[2]+ctrlPoly[1])
# Fit one (ore more) Bezier curves to a set of points
def fitCurve(points, maxError):
leftTangent = normalize(points[1] - points[0])
rightTangent = normalize(points[-2] - points[-1])
return fitCubic(points, leftTangent, rightTangent, maxError)
def fitCubic(points, leftTangent, rightTangent, error):
# Use heuristic if region only has two points in it
if (len(points) == 2):
dist = linalg.norm(points[0] - points[1]) / 3.0
bezCurve = [points[0], points[0] + leftTangent * dist, points[1] + rightTangent * dist, points[1]]
return [bezCurve]
# Parameterize points, and attempt to fit curve
u = chordLengthParameterize(points)
bezCurve = generateBezier(points, u, leftTangent, rightTangent)
# Find max deviation of points to fitted curve
maxError, splitPoint = computeMaxError(points, bezCurve, u)
if maxError < error:
return [bezCurve]
# If error not too large, try some reparameterization and iteration
if maxError < error**2:
for i in range(20):
uPrime = reparameterize(bezCurve, points, u)
bezCurve = generateBezier(points, uPrime, leftTangent, rightTangent)
maxError, splitPoint = computeMaxError(points, bezCurve, uPrime)
if maxError < error:
return [bezCurve]
u = uPrime
# Fitting failed -- split at max error point and fit recursively
beziers = []
centerTangent = normalize(points[splitPoint-1] - points[splitPoint+1])
beziers += fitCubic(points[:splitPoint+1], leftTangent, centerTangent, error)
beziers += fitCubic(points[splitPoint:], -centerTangent, rightTangent, error)
return beziers
def generateBezier(points, parameters, leftTangent, rightTangent):
bezCurve = [points[0], None, None, points[-1]]
# compute the A's
A = zeros((len(parameters), 2, 2))
for i, u in enumerate(parameters):
A[i][0] = leftTangent * 3*(1-u)**2 * u
A[i][1] = rightTangent * 3*(1-u) * u**2
# Create the C and X matrices
C = zeros((2, 2))
X = zeros(2)
for i, (point, u) in enumerate(zip(points, parameters)):
C[0][0] += dot(A[i][0], A[i][0])
C[0][1] += dot(A[i][0], A[i][1])
C[1][0] += dot(A[i][0], A[i][1])
C[1][1] += dot(A[i][1], A[i][1])
tmp = point - q([points[0], points[0], points[-1], points[-1]], u)
X[0] += dot(A[i][0], tmp)
X[1] += dot(A[i][1], tmp)
# Compute the determinants of C and X
det_C0_C1 = C[0][0] * C[1][1] - C[1][0] * C[0][1]
det_C0_X = C[0][0] * X[1] - C[1][0] * X[0]
det_X_C1 = X[0] * C[1][1] - X[1] * C[0][1]
# Finally, derive alpha values
alpha_l = 0.0 if det_C0_C1 == 0 else det_X_C1 / det_C0_C1
alpha_r = 0.0 if det_C0_C1 == 0 else det_C0_X / det_C0_C1
# If alpha negative, use the Wu/Barsky heuristic (see text) */
# (if alpha is 0, you get coincident control points that lead to
# divide by zero in any subsequent NewtonRaphsonRootFind() call. */
segLength = linalg.norm(points[0] - points[-1])
epsilon = 1.0e-6 * segLength
if alpha_l < epsilon or alpha_r < epsilon:
# fall back on standard (probably inaccurate) formula, and subdivide further if needed.
bezCurve[1] = bezCurve[0] + leftTangent * (segLength / 3.0)
bezCurve[2] = bezCurve[3] + rightTangent * (segLength / 3.0)
else:
# First and last control points of the Bezier curve are
# positioned exactly at the first and last data points
# Control points 1 and 2 are positioned an alpha distance out
# on the tangent vectors, left and right, respectively
bezCurve[1] = bezCurve[0] + leftTangent * alpha_l
bezCurve[2] = bezCurve[3] + rightTangent * alpha_r
return bezCurve
def reparameterize(bezier, points, parameters):
return [newtonRaphsonRootFind(bezier, point, u) for point, u in zip(points, parameters)]
def newtonRaphsonRootFind(bez, point, u):
"""
Newton's root finding algorithm calculates f(x)=0 by reiterating
x_n+1 = x_n - f(x_n)/f'(x_n)
We are trying to find curve parameter u for some point p that minimizes
the distance from that point to the curve. Distance point to curve is d=q(u)-p.
At minimum distance the point is perpendicular to the curve.
We are solving
f = q(u)-p * q'(u) = 0
with
f' = q'(u) * q'(u) + q(u)-p * q''(u)
gives
u_n+1 = u_n - |q(u_n)-p * q'(u_n)| / |q'(u_n)**2 + q(u_n)-p * q''(u_n)|
"""
d = q(bez, u)-point
numerator = (d * qprime(bez, u)).sum()
denominator = (qprime(bez, u)**2 + d * qprimeprime(bez, u)).sum()
if denominator == 0.0:
return u
else:
return u - numerator/denominator
def chordLengthParameterize(points):
u = [0.0]
for i in range(1, len(points)):
u.append(u[i-1] + linalg.norm(points[i] - points[i-1]))
for i, _ in enumerate(u):
u[i] = u[i] / u[-1]
return u
def computeMaxError(points, bez, parameters):
maxDist = 0.0
splitPoint = len(points)/2
for i, (point, u) in enumerate(zip(points, parameters)):
dist = linalg.norm(q(bez, u)-point)**2
if dist > maxDist:
maxDist = dist
splitPoint = i
return maxDist, splitPoint
def normalize(v):
return v / linalg.norm(v)

How to simulate a heat diffusion on a rectangular ring with FiPy?

I am new to solving a PDE and experimenting with a heat diffusion on a copper body of a rectangular ring shape using FiPy.
And this is a plot of simulation result at some times.
I am using the Grid2D() for a mesh and the CellVariable.constrain() to specify boundary conditions. The green dots are centers of exterior faces where T = 273.15 + 25 (K), and blue dots are centers of interior faces where T = 273.15 + 30 (K).
Obviously, I am doing something wrong, because the temperature goes down to 0K. How should I specify boundary conditions correctly?
These are the code.
import numpy as np
import matplotlib.pyplot as plt
import fipy
def get_mask_of_rect(mesh, x, y, w, h):
def left_id(i, j): return mesh.numberOfHorizontalFaces + i*mesh.numberOfVerticalColumns + j
def right_id(i, j): return mesh.numberOfHorizontalFaces + i*mesh.numberOfVerticalColumns + j + 1
def bottom_id(i, j): return i*mesh.nx + j
def top_id(i, j): return (i+1)*mesh.nx + j
j0, i0 = np.floor(np.array([x, y]) / [mesh.dx, mesh.dy]).astype(int)
n, m = np.round(np.array([w, h]) / [mesh.dx, mesh.dy]).astype(int)
mask = np.zeros_like(mesh.exteriorFaces, dtype=bool)
for i in range(i0, i0 + n):
mask[left_id(i, j0)] = mask[right_id(i, j0 + m-1)] = True
for j in range(j0, j0 + m):
mask[bottom_id(i0, j)] = mask[top_id(i0 + n-1, j)] = True
return mask
mesh = fipy.Grid2D(Lx = 1, Ly = 1, nx = 20, ny = 20) # Grid of size 1m x 1m
k_over_c_rho = 3.98E2 / (3.85E2 * 8.96E3) # The thermal conductivity, specific heat capacity, and density of Copper in MKS
dt = 0.1 * (mesh.dx**2 + mesh.dy**2) / (4*k_over_c_rho)
T0 = 273.15 # 0 degree Celsius in Kelvin
T = fipy.CellVariable(mesh, name='T', value=T0+25)
mask_e = mesh.exteriorFaces
T.constrain(T0+25., mask_e)
mask_i = get_mask_of_rect(mesh, 0.25, 0.25, 0.5, 0.5)
T.constrain(T0+30, mask_i)
eq = fipy.TransientTerm() == fipy.DiffusionTerm(coeff=k_over_c_rho)
viewer = fipy.MatplotlibViewer(vars=[T], datamin=0, datamax=400)
plt.ioff()
viewer._plot()
plt.plot(*mesh.faceCenters[:, mask_e], '.g')
plt.plot(*mesh.faceCenters[:, mask_i], '.b')
def update():
for _ in range(10):
eq.solve(var=T, dt=dt)
viewer._plot()
plt.draw()
timer = plt.gcf().canvas.new_timer(interval=50)
timer.add_callback(update)
timer.start()
plt.show()
.constrain() does not work for internal faces (see the warning at the end of Applying internal “boundary” conditions).
You can achieve an internal fixed value condition using sources, however. As a first cut, try
mask_i = get_mask_of_rect(mesh, 0.25, 0.25, 0.5, 0.5)
mask_i_cell = fipy.CellVariable(mesh, value=False)
mask_i_cell[mesh.faceCellIDs[..., mask_i]] = True
largeValue = 1e6
eq = (fipy.TransientTerm() == fipy.DiffusionTerm(coeff=k_over_c_rho)
- fipy.ImplicitSourceTerm(mask_i_cell * largeValue)
+ mask_i_cell * largeValue * (T0 + 30))
This constrains the cells on either side of the faces identified by mask_i to be at T0+30.
I am posting my own answer for future readers.
For boundary conditions for internal faces, you should use the implicit and explicit source terms on the equation, as in the jeguyer's answer.
By using source terms, you don't need to calculate a mask for faces, like this.(The get_mask_of_rect() in my question isn't required.)
T = fipy.CellVariable(mesh, name = 'T', value = T0 + 25)
mask_e = mesh.exteriorFaces
T.constrain(T0 + 25., mask_e)
mask_i_cell = (
(0.25 < mesh.x) & (mesh.x < 0.25 + 0.5) &
(0.25 < mesh.y) & (mesh.y < 0.25 + 0.5)
)
large_value = 1E6
eq = fipy.TransientTerm() == (
fipy.DiffusionTerm(coeff = k_over_c_rho) -
fipy.ImplicitSourceTerm(mask_i_cell * large_value) +
mask_i_cell * (large_value * (T0 + 30) # explicit source
))
viewer = fipy.MatplotlibViewer(vars = [T], datamin = T0, datamax = T0+50)

Image Cropping with transformation matrix?

I am training a neural network to do Human Single Pose Estimation on the MPII dataset. Within it, many images contain more than one person and I need to crop the image in order to extract each single person.
Of each I have the position (or center) and the scale w.r.t. 200 px height.
This code does just what I need:
def get_transform(center, scale, res, rot=0):
# Generate transformation matrix
h = 200 * scale
t = np.zeros((3, 3))
t[0, 0] = float(res[1]) / h
t[1, 1] = float(res[0]) / h
t[0, 2] = res[1] * (-float(center[0]) / h + .5)
t[1, 2] = res[0] * (-float(center[1]) / h + .5)
t[2, 2] = 1
if not rot == 0:
rot = -rot # To match direction of rotation from cropping
rot_mat = np.zeros((3,3))
rot_rad = rot * np.pi / 180
sn,cs = np.sin(rot_rad), np.cos(rot_rad)
rot_mat[0,:2] = [cs, -sn]
rot_mat[1,:2] = [sn, cs]
rot_mat[2,2] = 1
# Need to rotate around center
t_mat = np.eye(3)
t_mat[0,2] = -res[1]/2
t_mat[1,2] = -res[0]/2
t_inv = t_mat.copy()
t_inv[:2,2] *= -1
t = np.dot(t_inv,np.dot(rot_mat,np.dot(t_mat,t)))
return t
def transform(pt, center, scale, res, invert=0, rot=0):
# Transform pixel location to different reference
t = get_transform(center, scale, res, rot=rot)
if invert:
t = np.linalg.inv(t)
new_pt = np.array([pt[0], pt[1], 1.]).T
new_pt = np.dot(t, new_pt)
return new_pt[:2].astype(int)
def crop(img, center, scale, res, rot=0):
# Upper left point
ul = np.array(transform([0, 0], center, scale, res, invert=1))
# Bottom right point
br = np.array(transform(res, center, scale, res, invert=1))
new_shape = [br[1] - ul[1], br[0] - ul[0]]
if len(img.shape) > 2:
new_shape += [img.shape[2]]
new_img = np.zeros(new_shape)
# Range to fill new array
new_x = max(0, -ul[0]), min(br[0], len(img[0])) - ul[0]
new_y = max(0, -ul[1]), min(br[1], len(img)) - ul[1]
# Range to sample from original image
old_x = max(0, ul[0]), min(len(img[0]), br[0])
old_y = max(0, ul[1]), min(len(img), br[1])
new_img[new_y[0]:new_y[1], new_x[0]:new_x[1]] = img[old_y[0]:old_y[1], old_x[0]:old_x[1]]
return cv2.resize(new_img, res)
However, I haven't figured out what kind of transformation matrix it is (the one that was created to derive ul or br).
Could someone explain to me what happens in these functions?
Thank you

Closing a shape using bezier curves

In my assignment I tried to creat a shape using bezier curves. i used the method of bezier interpolation but because of that im missing the last curve because when i solve the linear equations i assum the second derivative in the edges are 0.
I want to know if there is a way to draw a closed shape and connecting the first and last points. Here is my code so far.
result = np.array(result, dtype=np.float32)
P = [2 * (2 * result[i] + result[i + 1]) for i in range(len(result)-1)]
P[0] = result[0] + 2 * result[1]
P[13] = 8 * result[13] + result[14]
A = np.linalg.solve(self.C, P)
B = [0] * 14
for i in range(13):
B[i] = 2 * result[i + 1] - A[i + 1]
B[13] = (A[13] + result[14]) / 2
for i in range(6):
Ci = np.stack([result[i],
A[i],
B[i],
result[i+1],
])
multi = np.matmul(self.T3, self.M3)
pts = np.matmul(multi, Ci)
plt.plot(pts[:, 0], pts[:, 1])
last_A = 2*result[-1] - B[-1]
last_B = A[-1] - 2* B[-1] + 2*last_A
Ci = np.stack([result[-1],
last_A,
last_B,
result[0],
])
multi = np.matmul(self.T3, self.M3)
pts = np.matmul(multi, Ci)
plt.plot(pts[:, 0], pts[:, 1],'b')
plt.show()

In Python: How to make a bifurcation diagram of the Lorenz system under a varying parameter value?

So, I've seen the coded solution to my question in Mathematica, but with very little understanding of mathematica, I havn't been able to reproduce it yet.
This is what I'm trying to do with Python: https://mathematica.stackexchange.com/questions/159211/how-to-make-a-bifurcation-diagram-of-the-lorenz-system-under-a-varying-parameter
I'm thinking my errors are in understanding how to calculate what I'm looking for and how to adjust my visualization to make it look just like that in the link, but any ideas are welcome.
The code I have so far looks like this:
def lorenz_system(x,y,z,r,s=10,b=6):
x_dot = s*(y-x)
y_dot = r*x-y-x*z
z_dot = x*z-b*z
return x_dot, y_dot, z_dot
dr = 0.1 # parameter step size
r=np.arange(40,200,dr) # parameter range
dt = 0.001 # time step
t = np.arange(0,10,dt) # time range
#initialize solution arrays
xs = np.empty(len(t) + 1)
ys = np.empty(len(t) + 1)
zs = np.empty(len(t) + 1)
#initial values x0,y0,z0 for the system
xs[0], ys[0], zs[0] = (1, 1, 1)
for R in r:
for i in range(len(t)):
#approximate numerical solutions to system
x_dot, y_dot, z_dot = lorenz_system(xs[i], ys[i], zs[i],R)
xs[i + 1] = xs[i] + (x_dot * dt)
ys[i + 1] = ys[i] + (y_dot * dt)
zs[i + 1] = zs[i] + (z_dot * dt)
#calculate and plot the peak values of the z solution
for i in range(0,len(zs)-1):
#using only the positive values in the z solution
if zs[i]>0:
#find the local maxima
if (zs[i-1] < zs[i] and zs[i] > zs[i+1]):
if (zs[i]<=1000):
#plot the local maxima point of the z solution that used the parameter R in r
plt.scatter(R,zs[i], color='black')
plt.xlim(0,200)
plt.ylim(0,400)
There is a bug in the lorenz_system function, it should be z_dot = x * y - b * z.
The linked answer also "Uses final values from one run as initial conditions for the next as an easy way to stay near the attractor.", and plots both local minima and local maxima.
Here is a way to get a similar plot using your code
import numpy as np
import matplotlib.pyplot as plt
def lorenz_system(x, y, z, r, b=10, s=6):
x_dot = b * (y - x)
y_dot = r * x - y - x * z
z_dot = x * y - s * z
return x_dot, y_dot, z_dot
dr = 0.1 # parameter step size
r = np.arange(40, 200, dr) # parameter range
dt = 0.001 # time step
t = np.arange(0, 10, dt) # time range
# initialize solution arrays
xs = np.empty(len(t) + 1)
ys = np.empty(len(t) + 1)
zs = np.empty(len(t) + 1)
# initial values x0,y0,z0 for the system
xs[0], ys[0], zs[0] = (1, 1, 1)
# Save the plot points coordinates and plot the with a single call to plt.plot
# instead of plotting them one at a time, as it's much more efficient
r_maxes = []
z_maxes = []
r_mins = []
z_mins = []
for R in r:
# Print something to show everything is running
print(f"{R=:.2f}")
for i in range(len(t)):
# approximate numerical solutions to system
x_dot, y_dot, z_dot = lorenz_system(xs[i], ys[i], zs[i], R)
xs[i + 1] = xs[i] + (x_dot * dt)
ys[i + 1] = ys[i] + (y_dot * dt)
zs[i + 1] = zs[i] + (z_dot * dt)
# calculate and save the peak values of the z solution
for i in range(1, len(zs) - 1):
# save the local maxima
if zs[i - 1] < zs[i] and zs[i] > zs[i + 1]:
r_maxes.append(R)
z_maxes.append(zs[i])
# save the local minima
elif zs[i - 1] > zs[i] and zs[i] < zs[i + 1]:
r_mins.append(R)
z_mins.append(zs[i])
# "use final values from one run as initial conditions for the next to stay near the attractor"
xs[0], ys[0], zs[0] = xs[i], ys[i], zs[i]
plt.scatter(r_maxes, z_maxes, color="black", s=0.5, alpha=0.2)
plt.scatter(r_mins, z_mins, color="red", s=0.5, alpha=0.2)
plt.xlim(0, 200)
plt.ylim(0, 400)
plt.show()
Result:

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