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TypeError: module() takes at most 2 arguments (3 given) code taken from pluralsight course [duplicate]

This question already has answers here:
TypeError: module.__init__() takes at most 2 arguments (3 given)
(5 answers)
Closed 3 years ago.
I am viewing the Pluralsight course on Python. At the end of the module we are to write a Python script. The author does not show how to create two of the scripts. I have them coded as the follows:
main.py
from hs_student import *
james = HighSchoolStudent("james")
print(james.get_name_capitalize)
student.py
students = []
class Student:
school_name = "Springfield Elementary"
def __init__(self, name, s_id=332):
self.name = name
self.s_id = s_id
students.append(self)
def get_name_capitalize(self):
return self.name.capitalize()
...
hs_student.py
import student as student
students = []
class HighSchoolStudent(student):
school_name = "Springfield High School"
def get_school_name(self):
return "This is a High School student"
def get_name_capitalize(self):
original_value = super().get_name_capitalize()
return original_value + "-HS"
...
When running the code, I get an error. From my understanding, I am passing too many arguments to the get_name_capitalize function. How can I fix this?
The error message is:
TypeError: module() takes at most 2 arguments (3 given)

This code:
class HighSchoolStudent(student):
is trying to inherit from the student module, not the student.Student class. Change it to:
class HighSchoolStudent(student.Student):
to inherit from the intended class.

Python. How to call a function from a dictionary? [duplicate]

This question already has an answer here:
What does <function at ...> mean [duplicate]
(1 answer)
Closed 4 years ago.
I want to have a dictionary where a certain key calls a value... that value is a function and I would want that function to execute.
Below is my attempt to do it but all I get is the value of where it is stored in memory.
class Testing:
def __init__(self):
self.method = {'Method1': self.another, 'Method2': self.there}
def launch(self, input):
print(self.method[input])
#staticmethod
def another():
print('This print statement should pop out.')
#staticmethod
def there():
print('This should not appear.')
new = Testing()
new.launch('Method1')
The result that I get from that is:
<function Testing.another at 0x01519540>
Is there a way to do this?

You are missing the actual function call: (notice the added () at the end)
def launch(self, input):
print(self.method[input]())

Using MyClass(object) gone wrong? [duplicate]

This question already has answers here:
I'm getting an IndentationError. How do I fix it?
(6 answers)
Closed 4 years ago.
class Myclass(object):
def __init__(self , msg , integer):
self.msg = msg
self.integer = integer
print (self.msg)
print (self.integer)
return
Error
File "<input>", line 3
self.msg = msg
^
IndentationError: expected an indented block

This question is a duplicate, and fyi Python2 allows mixed usage of tabs and spaces but Python3 does not. It recommends using spaces for uniformity.
Please check PEP8 for more info:
https://www.python.org/dev/peps/pep-0008/#tabs-or-spaces
EDIT:
And please indent after defining a function. It must be all indented up to the code block.

class Myclass(object):
def __init__(self , msg , integer):
self.msg = msg
self.integer = integer
print (self.msg)
print (self.integer)
return
Whitespace matters in python.
Edit: Ran without issues
>>> class MyClass(object):
... def __init__(self, msg, integer):
... self.msg=msg
... self.integer = integer
... print(self.msg)
...
>>> x = MyClass('foo', 5)
foo

Calling out a function, not defined error [duplicate]

This question already has answers here:
How can I call a function within a class?
(2 answers)
Closed 3 years ago.
I'm new to making classes and I'm trying to complete exercise 9-1 in my 'Python Crash Course' book where the last part of the question asks me to call back my method but I end up getting
'not defined error' for describe_restaurant().
Here is my code:
class Restaurant():
def __init__(self, r_name, c_type):
self.r_name = r_name
self.c_type = c_type
def describe_restaurant():
print(self.r_name.title())
print(self.c_type.title())
def open_restaurant():
print(self.r_name + " is now open!")
Restaurant = Restaurant('Joe\'s Sushi', 'sushi')
print(Restaurant.r_name)
print(Restaurant.c_type)
describe_restaurant()
open_restaurant()
I thought that describe_restaurant shouldn't need to be defined though because I'm calling it out as a function to use?

Try:
class Restaurant():
def __init__(self, r_name, c_type):
self.r_name = r_name
self.c_type = c_type
def describe_restaurant(self):
print(self.r_name)
print(self.c_type)
def open_restaurant(self):
return "{} is now open!".format(self.r_name)
restaurant = Restaurant('Joe\'s Sushi', 'sushi')
print(restaurant.r_name)
print(restaurant.c_type)
restaurant.describe_restaurant()
restaurant.open_restaurant()
You need to create a class instance and call it's functions. In addition, as mentioned in the comments, you need to pass self to the instance methods. A short explanation of this can be found here.

python: how list increase in a object [duplicate]

This question already has answers here:
How to avoid having class data shared among instances?
(7 answers)
Should I use instance or class attributes if there will only be one instance? [closed]
(4 answers)
Closed 7 years ago.
Could you help me to find the problems?
I just add the object to one list, but it seems that it appears in another list!
class people(object):
name = ""
__adjacent = []
position = 0
def __init__(self,nam):
self.name = nam
def print_name(self):
print self.name
def get_adjacent(self):
return self.__adjacent
def append_adjacent(self,people):
self.__adjacent.append(people)
sis = people('sister')
bro = people('brother')
sis.append_adjacent(bro)
print len(bro.get_adjacent())
for i in bro.get_adjacent():
i.print_name()
print len(sis.get_adjacent())
Question: why there is a object in bro's adjacent list???