I've written the following PyQt4 snippet:
#!/usr/bin/env python3
import sys
from typing import Callable, Optional
from PyQt4 import QtCore, QtGui
class MainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self._createMenuBar()
def _createMenuBar(self):
mainMenu = self.menuBar()
fileMenu = mainMenu.addMenu("File")
fileMenu.addAction(self._createFileNewAction())
def _createFileNewAction(self) -> QtGui.QAction:
return self._createAction(
self.style().standardIcon(QtGui.QStyle.SP_DialogSaveButton),
"New",
QtGui.QKeySequence.New,
"Load new image to be annotated",
self._fileNew
)
def _createAction(
self,
icon: Optional[QtGui.QIcon],
name: str,
shortcut: Optional[QtGui.QKeySequence],
tooltip: Optional[str],
callback: Callable[[], None]
) -> QtGui.QAction:
if icon is not None:
action = QtGui.QAction(icon, name, self)
else:
action = QtGui.QAction(name, self)
if shortcut is not None:
action.setShortcut(shortcut)
action.setToolTip(tooltip)
action.setToolTip(tooltip)
self.connect(action, QtCore.SIGNAL('triggered()'), callback)
return action
def _fileNew(self):
pass
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
mainWin = MainWindow()
mainWin.show()
app.exec_()
When I execute this program, I would expect the SP_DialogSaveButton icon to be displayed next to the "New" field in the "File" drop-down menu but it is not. PyQt is definitely able to find the icon itself, I have tried obtaining it the same way as above and displaying it in a separate QLabel which works fine.
Can someone tell what is going on here?
The problem is not standardIcon, if you use any icon you will observe the same behavior.
In Qt4 the icons of the QActions are hidden in menus, to make them visible there are 2 possibilities:
Disable the Qt::AA_DontShowIconsInMenus attribute:
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
app.setAttribute(QtCore.Qt.AA_DontShowIconsInMenus, False)
mainWin = MainWindow()
mainWin.show()
sys.exit(app.exec_())
Use the setIconVisibleInMenu() method of QAction:
action = QtGui.QAction(icon, name, self)
action.setIconVisibleInMenu(True)
Related
I am new to PyQt and Qt at all and I have a problem with window rendering or updating or how to call it. Problem is that when I call QWidget.show(), none of added components after are displayed. Here is a simple code, where in init(), there is called self.show(). First QLabel item is displayed and the second one is not. What am I doing wrong?
Code:
from PyQt6.QtWidgets import QApplication, QWidget, QLabel
import sys
class MyGui(QWidget):
box = {}
def __init__(self) -> None:
super().__init__()
self.setFixedSize(200, 400)
self.setStyleSheet("background-color:#000000")
self.box["top"] = QLabel(self)
self.box["top"].setFixedSize(200, 200)
self.box["top"].setStyleSheet("background-color:red")
self.box["top"].move(0,0)
self.show()
self.box["botom"] = QLabel(self)
self.box["botom"].setFixedSize(200, 200)
self.box["botom"].setStyleSheet("background-color:green")
self.box["botom"].move(0,200)
if __name__ == "__main__":
app = QApplication(sys.argv)
my_app = MyGui()
my_app.show()
try:
sys.exit(app.exec())
except SystemExit:
print("Closing window..")
Screenshots of GUI window:
With self.show()
Without self.show()
I am trying to translate my small application written in pyside2/pyqt5 to several languages, for example, Chinese. After googling, I managed to change the main window to Chinese after select from the menu -> language -> Chinese. However, the pop up dialog from menu -> option still remains English version. It seems the translation info is not transferred to the dialog. How do I solve this?
Basically, I build two ui files in designer and convert to two python files:One mainui.py and one dialogui.py. I then convert the two python file into one *.ts file using
pylupdate5 -verbose mainui.py dialogui.py -ts zh_CN.ts
after that, in linguist input the translation words. I can see the items in the dialog, which means this information is not missing. Then I release the file as zh_CN.qm file. All this supporting file I attached below using google drive.
Supporting files for the question
The main file is as
import os
import sys
from PySide2 import QtCore, QtGui, QtWidgets
from mainui import Ui_MainWindow
from dialogui import Ui_Dialog
class OptionsDialog(QtWidgets.QDialog,Ui_Dialog):
def __init__(self,parent):
super().__init__(parent)
self.setupUi(self)
self.retranslateUi(self)
class MainWindow(QtWidgets.QMainWindow,Ui_MainWindow):
def __init__(self):
super().__init__()
self.setupUi(self)
self.actionConfigure.triggered.connect(self.showdialog)
self.actionChinese.triggered.connect(self.change_lang)
def showdialog(self):
dlg = OptionsDialog(self)
dlg.exec_()
def change_lang(self):
trans = QtCore.QTranslator()
trans.load('zh_CN')
QtCore.QCoreApplication.instance().installTranslator(trans)
self.retranslateUi(self)
if __name__=='__main__':
app = QtWidgets.QApplication(sys.argv)
mainWin = MainWindow()
mainWin.show()
ret = app.exec_()
sys.exit(ret)
I think it should be a typical task because almost no application will only have a mainwindow.
You have to overwrite the changeEvent() method and call retranslateUi() when the event is of type QEvent::LanguageChange, on the other hand the QTranslator object must be a member of the class but it will be deleted and it will not exist when the changeEvent() method is called.
Finally assuming that the Language menu is used to establish only translations, a possible option is to establish the name of the .qm as data of the QActions and to use the triggered method of the QMenu as I show below:
from PySide2 import QtCore, QtGui, QtWidgets
from mainui import Ui_MainWindow
from dialogui import Ui_Dialog
class OptionsDialog(QtWidgets.QDialog,Ui_Dialog):
def __init__(self,parent):
super().__init__(parent)
self.setupUi(self)
def changeEvent(self, event):
if event.type() == QtCore.QEvent.LanguageChange:
self.retranslateUi(self)
super(OptionsDialog, self).changeEvent(event)
class MainWindow(QtWidgets.QMainWindow,Ui_MainWindow):
def __init__(self):
super().__init__()
self.setupUi(self)
self.m_translator = QtCore.QTranslator(self)
self.actionConfigure.triggered.connect(self.showdialog)
self.menuLanguage.triggered.connect(self.change_lang)
# set translation for each submenu
self.actionChinese.setData('zh_CN')
#QtCore.Slot()
def showdialog(self):
dlg = OptionsDialog(self)
dlg.exec_()
#QtCore.Slot(QtWidgets.QAction)
def change_lang(self, action):
QtCore.QCoreApplication.instance().removeTranslator(self.m_translator)
if self.m_translator.load(action.data()):
QtCore.QCoreApplication.instance().installTranslator(self.m_translator)
def changeEvent(self, event):
if event.type() == QtCore.QEvent.LanguageChange:
self.retranslateUi(self)
super(MainWindow, self).changeEvent(event)
if __name__=='__main__':
import sys
app = QtWidgets.QApplication(sys.argv)
mainWin = MainWindow()
mainWin.show()
ret = app.exec_()
sys.exit(ret)
I want to add startup window that when I click button, it will open another window and close current window. For each window, it has seperated UI which created from Qt Designer in .ui form.
I load both .ui file via uic.loadUiType(). The first window(first UI) can normally show its UI but when I click button to go to another window, another UI (second UI) doesn't work. It likes open blank window.
Another problem is if I load first UI and then change to second UI (delete that Class and change to another Class, also delete uic.loadUiType()), the second UI still doesn't work (show blank window)
Please help... I research before create this question but can't find the answer.
Here's my code. How can I fix it?
import sys
from PyQt5.QtWidgets import QApplication, QWidget
from PyQt5.QtGui import QIcon
from PyQt5 import uic
#load both ui file
uifile_1 = 'UI/openPage.ui'
form_1, base_1 = uic.loadUiType(uifile_1)
uifile_2 = 'UI/mainPage.ui'
form_2, base_2 = uic.loadUiType(uifile_2)
class Example(base_1, form_1):
def __init__(self):
super(base_1,self).__init__()
self.setupUi(self)
self.startButton.clicked.connect(self.change)
def change(self):
self.main = MainPage()
self.main.show()
class MainPage(base_2, form_2):
def __int__(self):
super(base_2, self).__init__()
self.setupUi(self)
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example()
ex.show()
sys.exit(app.exec_())
First you have an error, you must change __int__ to __init__. To close the window call the close() method.
import sys
from PyQt5.QtWidgets import QApplication, QWidget
from PyQt5.QtGui import QIcon
from PyQt5 import uic
#load both ui file
uifile_1 = 'UI/openPage.ui'
form_1, base_1 = uic.loadUiType(uifile_1)
uifile_2 = 'UI/mainPage.ui'
form_2, base_2 = uic.loadUiType(uifile_2)
class Example(base_1, form_1):
def __init__(self):
super(base_1,self).__init__()
self.setupUi(self)
self.startButton.clicked.connect(self.change)
def change(self):
self.main = MainPage()
self.main.show()
self.close()
class MainPage(base_2, form_2):
def __init__(self):
super(base_2, self).__init__()
self.setupUi(self)
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example()
ex.show()
sys.exit(app.exec_())
I have an application in development using PyQt4.
This app will popup a window on particular events in the application.
I want to know if the popup window which was popped up exists on the next event i wan to display the message on the same window rather tan creating another window.
For example you can consider a messaging application. where when we get a message the window will popup. and if we receive the message again from same user the message will be appended to that window itself.
My scenario is also the same.
Anyone have any idea on this...?
All you have to do is keep a reference to the popup window and then reset the text as necessary.
Here's a simple demo:
from PyQt4 import QtGui, QtCore
class Window(QtGui.QWidget):
def __init__(self):
QtGui.QWidget.__init__(self)
self.button = QtGui.QPushButton('ShowTime!', self)
self.button.clicked.connect(self.handleButton)
layout = QtGui.QVBoxLayout(self)
layout.addWidget(self.button)
self._dialog = None
def handleButton(self):
if self._dialog is None:
self._dialog = QtGui.QMessageBox(self)
self._dialog.setWindowTitle('Messages')
self._dialog.setModal(False)
pos = self.pos()
pos.setX(pos.x() + self.width() + 10)
self._dialog.move(pos)
self._dialog.setText(
'The time is: %s' % QtCore.QTime.currentTime().toString())
self._dialog.show()
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = Window()
window.show()
sys.exit(app.exec_())
I would like to use a QMenu as a permanent widget in the gui. (I like its appearance and layout, and the fact that as soon as I hover over it, the requisite menu pops up, no clicking needed. It would be a pain in the neck to try and emulate it with a custom widget.) I have tried adding it to a parent widget's layout, but after the first time it is used, it disappears. How would I go about keeping it there?
I can't find any option in QMenu that would disable auto-hide, so simplest way would be a subclass that overrides hideEvent. hideEvent is fired just before hide() completes. That means you can't intercept/ignore hide() but you can re-show it:
class PermanentMenu(QtGui.QMenu):
def hideEvent(self, event):
self.show()
Just make your top-level menu from PermanentMenu and it should be fine.
A simple example using it:
import sys
from PyQt4 import QtGui
class PermanentMenu(QtGui.QMenu):
def hideEvent(self, event):
self.show()
class Window(QtGui.QWidget):
def __init__(self, parent=None):
super(Window, self).__init__(parent)
self.menu = PermanentMenu()
self.menu.addAction('one')
self.menu.addAction('two')
self.submenu = self.menu.addMenu('submenu')
self.submenu.addAction('sub one')
self.submenu.addAction('sub two')
self.submenu2 = self.menu.addMenu('submenu 2')
self.submenu2.addAction('sub 2 one')
self.submenu2.addAction('sub 2 two')
layout = QtGui.QHBoxLayout()
layout.addWidget(self.menu)
self.setLayout(layout)
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
w = Window()
w.show()
sys.exit(app.exec_())