List element case conversion [duplicate] - python

This question already has answers here:
Convert a list with strings all to lowercase or uppercase
(13 answers)
Closed 4 years ago.
I have a list that has 12 elements. I am getting an input and matching that input with the value of another variable. Now that means that case-sensitivity will be a problem. I know how to go through the list with a loop but how can I convert every character in each element to a lowercase character?
for i in sa:
# something here to convert element in sa to lowercase


A simple one liner:
lowercase_list = [ i.lower() for i in input_list ]

Related

Python add dashes to your characters in a string? [duplicate]

This question already has answers here:
Returning original string with symbols between each character
(2 answers)
Closed 9 months ago.
I have a string that i want to modify.
The string is something like 0rty4653 and i want to convert it into this format :-
0--r--t--y--4--6--5--3-- or in other words make it look into the following format --[CHAR]--.
The string could be dynamic.
I converted my string into a list thus far :-
my_str = 0rty4653
my_list = my_str.split()
but how do i convert it into the above format?

final = ""
for i in my_list:
final += i+"--"
iterating over the list should allow you to concat each element and -- to create that product

Get each element in a list string [duplicate]

This question already has answers here:
How to convert string representation of list to a list
(19 answers)
Closed 3 years ago.
I have a string that consists of a list which made of different product code.
"['B00GHX7H0A', 'B00FRERO7G', 'B00R68QXCS', 'B000Z65AZE', 'B07GFHJRMX', 'B074KGBGL7', 'B00R68QXJG', 'B00025WYZC', 'B07H3W9BM5', 'B00KOBT82G', 'B072N2M1P6', 'B071G8FG2N', 'B00FASVFI8', 'B00GHXE4N8', 'B00EPG2QJI', 'B01MQ4MEFE', 'B01M8ML0SY', 'B074KHCPLH', 'B004XQWY4W', 'B00FASV6UU', 'B01M31HJBJ', 'B00KC8TU7O', 'B00B9TU5T2', 'B00K75EZ04', 'B000Q2Y0FI', 'B00FEGOCCM', 'B00EPFXFBW', 'B00H6SQY3Q', 'B00HZAOWUC', 'B07GFJF1DN', 'B001WBS68E', 'B074KJZCPH']"
How can I extract each product code out of this string?

There is nother option than to replace the unnecessary characters and then splitting it by the commas:
myList = "['123','231','312','123']"
myList = myList.replace("[","").replace("]","").replace("'", "").split(",")
print(myList)
# output: ["123","231","312","123"]
But with this you would get problems if the items inside the list could potentially contain commas.

How to get the numbers from a string (contains no spaces between letters and numbers)? [duplicate]

This question already has answers here:
How to extract numbers from a string in Python?
(19 answers)
Closed 3 years ago.
So, I have a string "AB256+74POL". I want to extract the numbers only into a list say num = [256,74]. How to do this in python?
I have tried string.split('+') and followed by iterating over the two parts and adding the characters which satisfy isdigit(). But is there an easier way to that?

import re
a = 'AB256+74POL'
array = re.findall(r'[0-9]+', a)

"".join([c if c.isdigit() else " " for c in mystring]).split()
Explanation
Strings are iterable in python. So we iterate on each character in the string, and replace non digits with spaces, then split the result to get all sequences of digits in a list.

NLTK RegexpTokenizer: Regex to retain just characters in Random text [duplicate]

This question already has answers here:
Using explicitly numbered repetition instead of question mark, star and plus
(4 answers)
Closed 5 years ago.
I used tokenizer = RegexpTokenizer(r'\w+') which retains alphanumeric characters
But how do I combine a regular expression to remove every other element retaining just characters greater than length 2
Below is one row in the dataframe which contains random text
0 [ANOTHER 2'' F/P SAMPLE 01:52 ...A13232 / AS OUTPUT MSG...

I think you need for find words with len>2:
RegexpTokenizer(r'\w{3,}')
Or if need only letters:
RegexpTokenizer(r'[a-zA-Z]{3,}')

Find last occurrence of character in string Python [duplicate]

This question already has answers here:
Find index of last occurrence of a substring in a string
(12 answers)
Closed 8 years ago.
How would I find the last occurrence of a character in a string?
string = "abcd}def}"
string = string.find('}',last) # Want something like this

You can use rfind:
>>> "abcd}def}".rfind('}')
8

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