This question already has answers here:
How to convert string representation of list to a list
(19 answers)
Closed 3 years ago.
I have a string that consists of a list which made of different product code.
"['B00GHX7H0A', 'B00FRERO7G', 'B00R68QXCS', 'B000Z65AZE', 'B07GFHJRMX', 'B074KGBGL7', 'B00R68QXJG', 'B00025WYZC', 'B07H3W9BM5', 'B00KOBT82G', 'B072N2M1P6', 'B071G8FG2N', 'B00FASVFI8', 'B00GHXE4N8', 'B00EPG2QJI', 'B01MQ4MEFE', 'B01M8ML0SY', 'B074KHCPLH', 'B004XQWY4W', 'B00FASV6UU', 'B01M31HJBJ', 'B00KC8TU7O', 'B00B9TU5T2', 'B00K75EZ04', 'B000Q2Y0FI', 'B00FEGOCCM', 'B00EPFXFBW', 'B00H6SQY3Q', 'B00HZAOWUC', 'B07GFJF1DN', 'B001WBS68E', 'B074KJZCPH']"
How can I extract each product code out of this string?
There is nother option than to replace the unnecessary characters and then splitting it by the commas:
myList = "['123','231','312','123']"
myList = myList.replace("[","").replace("]","").replace("'", "").split(",")
print(myList)
# output: ["123","231","312","123"]
But with this you would get problems if the items inside the list could potentially contain commas.
Related
This question already has answers here:
Returning original string with symbols between each character
(2 answers)
Closed 9 months ago.
I have a string that i want to modify.
The string is something like 0rty4653 and i want to convert it into this format :-
0--r--t--y--4--6--5--3-- or in other words make it look into the following format --[CHAR]--.
The string could be dynamic.
I converted my string into a list thus far :-
my_str = 0rty4653
my_list = my_str.split()
but how do i convert it into the above format?
final = ""
for i in my_list:
final += i+"--"
iterating over the list should allow you to concat each element and -- to create that product
This question already has answers here:
How to extract numbers from a string in Python?
(19 answers)
Closed 3 years ago.
So, I have a string "AB256+74POL". I want to extract the numbers only into a list say num = [256,74]. How to do this in python?
I have tried string.split('+') and followed by iterating over the two parts and adding the characters which satisfy isdigit(). But is there an easier way to that?
import re
a = 'AB256+74POL'
array = re.findall(r'[0-9]+', a)
"".join([c if c.isdigit() else " " for c in mystring]).split()
Explanation
Strings are iterable in python. So we iterate on each character in the string, and replace non digits with spaces, then split the result to get all sequences of digits in a list.
This question already has answers here:
Convert a list with strings all to lowercase or uppercase
(13 answers)
Closed 4 years ago.
I have a list that has 12 elements. I am getting an input and matching that input with the value of another variable. Now that means that case-sensitivity will be a problem. I know how to go through the list with a loop but how can I convert every character in each element to a lowercase character?
for i in sa:
# something here to convert element in sa to lowercase
A simple one liner:
lowercase_list = [ i.lower() for i in input_list ]
This question already has answers here:
Check if multiple strings exist in another string
(17 answers)
Closed 4 years ago.
I want to when I input a string, if words in string is contain in a list of words, delete words in the strings
Or, you could do the following:
raw_string = input("Enter String:")
useless_list = ["Birds", "Cat"]
print(' '.join([i for i in raw_string.split() if i not in useless_list]))
This question already has answers here:
Split string every nth character?
(19 answers)
Closed 4 years ago.
how to split a string into words of 2 letters. Like given string is "HelloThere" now i want to make it ["He","ll","oT","he","re"]. Please help to code that in python.
yourList = []
yourString = "HelloThere"
while yourString:
yourList.append(yourString[:2])
yourString = yourString[2:]
If you print yourList, you will get the result.