I'm trying to set my django homepage, linked to the root of my website: i.e. http://127.0.0.1:8000/index/ but instead, I keep getting errors where Django is searching for myapp as the homepage: http://127.0.0.1:8000/myapp/. I would just like to land on a homepage with "index" in the url instead of "myapp/"
The error is as follows:
Using the URLconf defined in Main.urls, Django tried these URL patterns, in this order:
admin/
[name='index']
[name='myapp_index']
publications/ [name='publications']
^static\/(?P<path>.*)$
The current path, myapp/, didn't match any of these.
Views.py
def index(request):
return render(request, 'index.html')
Main/urls
from django.contrib import admin
from django.urls import path, include
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('myapp.urls')),
] + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
myapp/urls
from django.urls import path
from logbook import views
urlpatterns = [
path('', views.index, name='index'),
path('', views.myapp_index, name='myapp_index'),
path('publications/', views.publications, name='publications'),
]
Now, if I change the path in Main/urls.py to path('myapp/', include('myapp.urls')), I land on the appropriate homepage, except, I would prefer that there is "index/" listed in the URL instead of "myapp/".
I may be missing something very simple here. This is what I think is my MWE, happy to add more.
I was having the same problem and I was cracking my head finding a solution.
The solution was to erase browser's cache and history
I realized that because when I tried with incognito mode worked perfectly!
This should be in the main urls.py
path('', views.index, name='index')
instead of my_app/urls.py
path('myapp/', include('myapp.urls'))
path('index/', include('myapp.urls'))
That might get the desired result.
Did you try following:
Main/urls
...
path(r'^', include('myapp.urls')),
...
myapp/urls
...
path(r'^$', views.index, name='index'),
# path('', views.myapp_index, name='myapp_index'), ## REMOVE THIS ROW ##
...
first you must choose one of below lines in myapp.urls and delete other
you can not set two views for one url patterns
path('', views.index, name='index'),
path('', views.myapp_index, name='myapp_index'),
you have two solution for get index/ as main url
1.change Main.urls like below
path('', include('myapp.urls')),
to
path('index/', include('myapp.urls')),
2.change myapp.urls like below
path('', views.index, name='index'),
to
path('index/', views.index, name='index'),
you actually changed name of urls that using in python codes not path of urls
edit
Do you mean index/ like the following?
www.example.com/
so u must do that as above but delete "index/"
so u cant do it as below :
change Main.urls like below
path('', include('myapp.urls')),
to
path('^$', include('myapp.urls')),
or
change myapp.urls like below
path('', views.index, name='index'),
to
path('^$', views.index, name='index'),
This is what worked for me (Django2) - pointing to index action in 'static_pages' app's views.py as home page:
main urls.py:
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('static_pages.urls')), #included urls from static_pages app
]
static_pages/urls.py:
from django.contrib import admin
from django.urls import path
from . import views
urlpatterns = [
path('', views.index, name="index"),
]
static_pages/views.py
from django.shortcuts import render
from django.http import HttpResponse
def index(request):
return HttpResponse("First Django2 Message!")
Note that 'static_pages' app is added to INSTALLED_APPS in settings.py.
Now, calling http://127.0.0.1:8000/ I got: "First Django2 Message!".
Related
I'm very new to working with Django and I've been relying on some tutorials to link this one to React, but the problem is that initially (when I open 127.0.0.1:8000) React loads the routes perfectly, then when I reload the page Django tries to interpret the path from urls.py and obviously can't find it.
The error is:
Page not found (404) Using the URLconf defined in memberstack.urls, Django tried these URL patterns, in this order:
admin/
api/token-auth/
core/
I hope you can help me, thanks in advance
my_project/urls.py
from django.contrib import admin
from django.urls import path, include
from rest_framework_jwt.views import obtain_jwt_token
from frontend.views import index
urlpatterns = [
path('', include('frontend.urls')),
path('admin/', admin.site.urls),
path('api/token-auth/', obtain_jwt_token),
path('core/', include('core.urls')),
]
frontend/urls.py
from django.urls import path
from . import views
urlpatterns = [
path('', views.index),
]
frontend/views.py
from django.shortcuts import render
def index(request):
return render(request, 'frontend/index.html')
For this, you'll have to use a catch-all in order for React to handle all the routing instead of django there.
from django.urls import path, re_path
from . import views
urlpatterns = [
path('', include('frontend.urls')),
path('admin/', admin.site.urls),
path('api/token-auth/', obtain_jwt_token),
path('core/', include('core.urls')),
re_path(r'^(?:.*)/?$', include('frontend.urls')),
]
Or
urlpatterns = [
path('', views.index),
re_path(r'^(?:.*)/?$', views.index)
]
I think the better practice would be to implement Django-Rest-Framework and build them separately.
from django.contrib import admin
from django.urls import path, include
from pages import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.index, name='index'),
path('dashboard/', include(pages.urls)),
]
I'm trying to use include method under my urls.py file to direct the dashboad/ request to my app urls.py file, which is not working.
change this line :
path('dashboard/', include(pages.urls)),
to this :
path('dashboard/', include('pages.urls')),
see this link
Hi and welcome to StackOverflow!
The problem you are facing is that Django expects the include(...) method to be given a list of url patterns or the string of the module url's you want to be included at the path.
I would refactor your code like so:
from django.contrib import admin
from django.urls import path, include
from pages import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.index, name='index'),
path('dashboard/', include('pages.urls')),
]
I'm trying to reach the Django admin page but when I type in http://localhost:8000/admin/ it pops up with my web application instead.
For more context I have two url.py's in separate folders.
from django.contrib import admin
from django.urls import path
from . import views
urlpatterns = [
path('', views.project_list, name='list'),
path('<slug:project_slug>/', views.project_detail, name='detail')
]
and...
from django.urls import path, include
urlpatterns = [
path('', include('budget.urls')),
path('admin/', admin.site.urls),
I'm not sure why http://localhost:8000/admin/ doesn't go to Django's admin page but if anyone has any suggestions that would be very much appreciated.
In your project level urls.py place admin url in top.
Like this
urlpatterns = [
path('admin/',admin.site.urls),
path('',include('budget.urls'))
]
Change urlpatterns order here:
from django.urls import path, include
urlpatterns = [
path('', include('budget.urls')),
path('admin/', admin.site.urls),
like this:
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('budget.urls')),
In your code pattern path('<slug:project_slug>/', views.project_detail, name='detail') resolve before path('admin',admin.site.urls),.
See Django documentation
I want to define URLs in Django but get an error:
from django.contrib import admin
from django.urls import path
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.index, name="index"),
]
the error is:
nameError(name'view' is not defind)
please inform me.
thanks,
Saeed
You need to import views. If you have an app named myapp and it has views.py inside the app directory, then import it like this:
from django.contrib import admin
from django.urls import path
from myapp import views # <--- Here
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.index, name="index"),
]
I am very new to Django and I have created two apps in my project one is login & server_status. I have used the namespace method to access my login and server_status across both apps. It is working fine when I tried to access index but when I tried to access dashboard in server_status it is not working.
Reverse for 'server_status' not found. 'server_status' is not a valid view function or pattern name
# server_status URL
from django.urls import path
from . import views
urlpatterns = [
path('', include('server_status.urls', namespace='server_status')),
path('', include('login.urls', namespace='login')),
path('admin/', admin.site.urls),
]
# login app URL
app_name = 'login'
urlpatterns = [
path('login', views.index, name='index')
]
# project URL
from django.contrib import admin
from django.urls import include, path
app_name = 'server_status'
urlpatterns = [
path('', views.index, name='index'),
path('dashboard/', views.dashboard, name='dashboard'),
path('server_status/', views.server_status, name='server_status'),
path('request_access/', views.request_access, name='request_access'),
]
In server_status/templates/server_status/index.html
Login
I know this is very simple one, but it makes me very complicated.
In the posted code, you define urlpatterns twice, so the first set of urlpatterns is overridden by the second. Since server_status is defined in the first set, it is not present in memory, since you obliterate it in the second definition. index is the only pattern that survives. I think what you meant to do in the second stanza was to add to the urlpatterns with:
urlpatterns += [...]
To declare namespace you should do something like this:
# project URL
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('', include('server_status.urls', namespace='server_status')),
path('', include('login.urls', namespace='login')),
path('admin/', admin.site.urls),
]
then you can use
Login
or
Server status index