I'm very new to working with Django and I've been relying on some tutorials to link this one to React, but the problem is that initially (when I open 127.0.0.1:8000) React loads the routes perfectly, then when I reload the page Django tries to interpret the path from urls.py and obviously can't find it.
The error is:
Page not found (404) Using the URLconf defined in memberstack.urls, Django tried these URL patterns, in this order:
admin/
api/token-auth/
core/
I hope you can help me, thanks in advance
my_project/urls.py
from django.contrib import admin
from django.urls import path, include
from rest_framework_jwt.views import obtain_jwt_token
from frontend.views import index
urlpatterns = [
path('', include('frontend.urls')),
path('admin/', admin.site.urls),
path('api/token-auth/', obtain_jwt_token),
path('core/', include('core.urls')),
]
frontend/urls.py
from django.urls import path
from . import views
urlpatterns = [
path('', views.index),
]
frontend/views.py
from django.shortcuts import render
def index(request):
return render(request, 'frontend/index.html')
For this, you'll have to use a catch-all in order for React to handle all the routing instead of django there.
from django.urls import path, re_path
from . import views
urlpatterns = [
path('', include('frontend.urls')),
path('admin/', admin.site.urls),
path('api/token-auth/', obtain_jwt_token),
path('core/', include('core.urls')),
re_path(r'^(?:.*)/?$', include('frontend.urls')),
]
Or
urlpatterns = [
path('', views.index),
re_path(r'^(?:.*)/?$', views.index)
]
I think the better practice would be to implement Django-Rest-Framework and build them separately.
Related
I am following the django tutorial (found here):
views.py code:
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, world. You're at the poll index.")
urls.py code (this is inside polls app urls.py file):
from django.urls import path, include
from django.conf import settings
from . import views
urlpatterns = [path(r'^$', views.index, name='index'), ]
urls.py code ( this is root urls.py file code):
from django.contrib import admin
from django.urls import include, path
urlpatterns = [path('polls/', include('polls.urls')),path('admin/',admin.site.urls), ]
Here is my run command : python manage.py runserver 8080
I tried to run it today, but I am getting the following error:
Page not found (404)
Request Method: GET
Request URL: http://35527a91f40c4e228d6c464d8a8c8487.vfs.cloud9.eu-west-1.amazonaws.com/
Using the URLconf defined in PollApp.urls, Django tried these URL patterns, in this order:
poll/
admin/
The empty path didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
You are using regex-syntax with path, you should use the empty string instead:
from . import views
urlpatterns = [
path('', views.index, name='index'),
]
Furthermore, you use a poll/ prefix here, so that means you either need to visit localhost:8000/poll/, or change this to an empty prefix:
urlpatterns = [
path('', include('polls.urls')),
path('admin/', admin.site.urls),
]
Djano errors are self-explanatory, follow its instructions, and are good to go.Also is there the Indentation in your first return ?
from . import views
urlpatterns = [
path('', views.index, name='index'),
]
I was taking a youtube tutorial on making a basic website using django and I got this error when coding:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/
Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order:
app/
admin/
The empty path didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
This is my code:
For urls.py/mysite:
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('app/', include('myapp.urls')),
path('admin/', admin.site.urls),
]
For views.py:
from django.shortcuts import render
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, world!")
For urls.py/myapp:
from django.urls import path
from . import views
urlpatterns = [
path('', views.index, name='index'),
]
You need to add root level path to access the path you specified http://127.0.0.1:8000/:
urls.py/mysite
urlpatterns = [
path('', views.index, name='home'),
path('app/', include('myapp.urls')),
path('admin/', admin.site.urls),
]
views.py/mysite
def index(request):
return HttpResponse('This is home page')
Since you specified:
path('app/', include('myapp.urls')),
It means all the paths in myapp.urls are prefixed with app/. So you can access the index view with: http://127.0.0.1:8000/app/. Or if you want to access the index view with http://127.0.0.1:8000/ you rewrite the path to:
path('', include('myapp.urls')),
from django.contrib import admin
from django.urls import path, include
from pages import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.index, name='index'),
path('dashboard/', include(pages.urls)),
]
I'm trying to use include method under my urls.py file to direct the dashboad/ request to my app urls.py file, which is not working.
change this line :
path('dashboard/', include(pages.urls)),
to this :
path('dashboard/', include('pages.urls')),
see this link
Hi and welcome to StackOverflow!
The problem you are facing is that Django expects the include(...) method to be given a list of url patterns or the string of the module url's you want to be included at the path.
I would refactor your code like so:
from django.contrib import admin
from django.urls import path, include
from pages import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.index, name='index'),
path('dashboard/', include('pages.urls')),
]
I'm trying to reach the Django admin page but when I type in http://localhost:8000/admin/ it pops up with my web application instead.
For more context I have two url.py's in separate folders.
from django.contrib import admin
from django.urls import path
from . import views
urlpatterns = [
path('', views.project_list, name='list'),
path('<slug:project_slug>/', views.project_detail, name='detail')
]
and...
from django.urls import path, include
urlpatterns = [
path('', include('budget.urls')),
path('admin/', admin.site.urls),
I'm not sure why http://localhost:8000/admin/ doesn't go to Django's admin page but if anyone has any suggestions that would be very much appreciated.
In your project level urls.py place admin url in top.
Like this
urlpatterns = [
path('admin/',admin.site.urls),
path('',include('budget.urls'))
]
Change urlpatterns order here:
from django.urls import path, include
urlpatterns = [
path('', include('budget.urls')),
path('admin/', admin.site.urls),
like this:
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('budget.urls')),
In your code pattern path('<slug:project_slug>/', views.project_detail, name='detail') resolve before path('admin',admin.site.urls),.
See Django documentation
I have a problem with Django. Actually I want to create a login panel in my new site but when I try to write address the debugger respond me a error:
Page not found (404)
Request Method: GET
Request URL: http://localhost:8000/account/login
Using the URLconf defined in firmowa.urls, Django tried these URL patterns, in this order:
admin/
^account/
The current path, account/login, didn't match any of these.
My firmowa.urls is
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path(r'^account/', include('account.urls')),
]
And the project urls.py is:
from django.urls import path
from . import views
urlpatterns = [
path(r'^login/$', views.user_login, name='login'),
]
I'm looking a solution from few hours but still nothing.
path is a new feature in Django 2.0 and works different than the old url. Don't use regex in path. If you need regex, use re_path instead, but in your case there's no need for that.
Change your code to:
urlpatterns = [
path('login/', views.user_login, name='login'),
]
etc. and it should work.
More on the topic here and here.
from django.urls import path
from . import views
from django.conf.urls import url
urlpatterns = [
url( r'^$', views.index , name='index') ,
]