I was taking a youtube tutorial on making a basic website using django and I got this error when coding:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/
Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order:
app/
admin/
The empty path didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
This is my code:
For urls.py/mysite:
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('app/', include('myapp.urls')),
path('admin/', admin.site.urls),
]
For views.py:
from django.shortcuts import render
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, world!")
For urls.py/myapp:
from django.urls import path
from . import views
urlpatterns = [
path('', views.index, name='index'),
]
You need to add root level path to access the path you specified http://127.0.0.1:8000/:
urls.py/mysite
urlpatterns = [
path('', views.index, name='home'),
path('app/', include('myapp.urls')),
path('admin/', admin.site.urls),
]
views.py/mysite
def index(request):
return HttpResponse('This is home page')
Since you specified:
path('app/', include('myapp.urls')),
It means all the paths in myapp.urls are prefixed with app/. So you can access the index view with: http://127.0.0.1:8000/app/. Or if you want to access the index view with http://127.0.0.1:8000/ you rewrite the path to:
path('', include('myapp.urls')),
Related
I am following the django tutorial (found here):
views.py code:
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello, world. You're at the poll index.")
urls.py code (this is inside polls app urls.py file):
from django.urls import path, include
from django.conf import settings
from . import views
urlpatterns = [path(r'^$', views.index, name='index'), ]
urls.py code ( this is root urls.py file code):
from django.contrib import admin
from django.urls import include, path
urlpatterns = [path('polls/', include('polls.urls')),path('admin/',admin.site.urls), ]
Here is my run command : python manage.py runserver 8080
I tried to run it today, but I am getting the following error:
Page not found (404)
Request Method: GET
Request URL: http://35527a91f40c4e228d6c464d8a8c8487.vfs.cloud9.eu-west-1.amazonaws.com/
Using the URLconf defined in PollApp.urls, Django tried these URL patterns, in this order:
poll/
admin/
The empty path didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
You are using regex-syntax with path, you should use the empty string instead:
from . import views
urlpatterns = [
path('', views.index, name='index'),
]
Furthermore, you use a poll/ prefix here, so that means you either need to visit localhost:8000/poll/, or change this to an empty prefix:
urlpatterns = [
path('', include('polls.urls')),
path('admin/', admin.site.urls),
]
Djano errors are self-explanatory, follow its instructions, and are good to go.Also is there the Indentation in your first return ?
from . import views
urlpatterns = [
path('', views.index, name='index'),
]
I'm very new to working with Django and I've been relying on some tutorials to link this one to React, but the problem is that initially (when I open 127.0.0.1:8000) React loads the routes perfectly, then when I reload the page Django tries to interpret the path from urls.py and obviously can't find it.
The error is:
Page not found (404) Using the URLconf defined in memberstack.urls, Django tried these URL patterns, in this order:
admin/
api/token-auth/
core/
I hope you can help me, thanks in advance
my_project/urls.py
from django.contrib import admin
from django.urls import path, include
from rest_framework_jwt.views import obtain_jwt_token
from frontend.views import index
urlpatterns = [
path('', include('frontend.urls')),
path('admin/', admin.site.urls),
path('api/token-auth/', obtain_jwt_token),
path('core/', include('core.urls')),
]
frontend/urls.py
from django.urls import path
from . import views
urlpatterns = [
path('', views.index),
]
frontend/views.py
from django.shortcuts import render
def index(request):
return render(request, 'frontend/index.html')
For this, you'll have to use a catch-all in order for React to handle all the routing instead of django there.
from django.urls import path, re_path
from . import views
urlpatterns = [
path('', include('frontend.urls')),
path('admin/', admin.site.urls),
path('api/token-auth/', obtain_jwt_token),
path('core/', include('core.urls')),
re_path(r'^(?:.*)/?$', include('frontend.urls')),
]
Or
urlpatterns = [
path('', views.index),
re_path(r'^(?:.*)/?$', views.index)
]
I think the better practice would be to implement Django-Rest-Framework and build them separately.
I got the follwoing error whenever I run the project and automatically catalog/ is added to the url:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/catalog/
Using the URLconf defined in first_project.urls, Django tried these URL patterns, in this order:
[name='index']
admin/
first_app/
The current path, catalog/, didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
Here is my project urls.py
from django.contrib import admin
from django.urls import path, include
from first_app import views
urlpatterns = [
path('', views.index, name='index'),
path('admin/', admin.site.urls),
path('first_app/', include('first_app.urls')),
]
Here is first_app urls.py code:
from django.urls import path
from first_app import views
urlpatterns = [
path('', views.index, name='index'),
]
How to get the index page as a default and get rid of the catalog.
Here is views.py file:
from django.shortcuts import render
from django.http import HttpResponse
from first_app.models import Topic, AccessRecord, Webpage
# Create your views here.
def index(request):
webpages_list = AccessRecord.objects.order_by('date')
date_dict = {'access_records': webpages_list}
return render(request, 'first_app/index.html', context=date_dict)
Hey Mak in your code u didnt mention any url related to /catalog/ so you are getting that 404 error message. Error 404 means that the page couldnt found by the server add /catalog/ in your url patterns so that the server could know which page is to be shown if /catalog/ is requested . And as far as ur proble"and automatically catalog/ is added to the url:" may be its your browser autocompleting the address field so once plesase check it. if the request is only /catalog then ur myproject urls.py file should be something like this
from django.contrib import admin
from django.urls import path, include
from first_app import views
urlpatterns = [
path('', views.index, name='index'),
path('admin/', admin.site.urls),
path('first_app/', include('first_app.urls')),
path('catalog',views.your_function_name)
]
if the request is first_app/catalog then ur first_app urls.py file should be something like this in url patterns
urlpatterns = [
path('/catalog', views.catalog, name='catalog'),
]
from django.contrib import admin
from django.urls import path, include
from first_app import views
urlpatterns = [
path('admin/', admin.site.urls),
path('first_app/', include('first_app.urls')),]
and
from django.urls import path
from first_app import views
urlpatterns = [
path('', views.index, name='index'),
]
>>>>> if your templates files :
templates/index.html
def index(request):
webpages_list = AccessRecord.objects.order_by('date')
date_dict = {'access_records': webpages_list}
return render(request, 'index.html', context=date_dict)
I keep getting this error:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/home
Using the URLconf defined in personal_portfolio.urls, Django tried these URL patterns, in this order:
admin/
home/
The current path, home, didn't match any of these.
This is my urls.py for the overall project
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('home/', include('hello_world.urls')),
]
this is my code for hello_world urls.py
from django.urls import path
from hello_world import views
urlpatterns = [
path('home/', views.hello_world, name='hello_world'),
]
this is my code for hello_world views.py
from django.shortcuts import render
def hello_world(request):
return render(request, 'hello_world.html')
you need to change this url from
urlpatterns = [
path('home/', views.hello_world, name='hello_world'),
]
to
urlpatterns = [
path('', views.hello_world, name='hello_world'),
]
to get to http://127.0.0.1:8000/home/
else you need to goto http://127.0.0.1:8000/home/home/ for the current url
Am using django I got this error Page not Found (404) Request Method: GET Request URL: http://127.0.0.1:8000/ Using the URLconf defined in VibezT.urls, Django tried these URL patterns, in this order
music/
admin/
The empty path didn't match any of these.
VibezT\urls.py
from django.contrib import admin
from django.urls import include, path
urlpatterns =[
path('music/', include('music.urls')),
path('admin/', admin.site.urls),
]
For music URLs I have this code
music\urls.py
from django.urls import path
from . import views
urlpattern = [
path(r'^$',/ views.index, name='index')
]
For views i have this code
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello World")
You have not defined a URL for / in your code. Your code is defined for music/
You need to go to http://127.0.0.1:8000/music/ to find your view.
Also, I do not know why you are structuring your URL like this if you are using path. path(r'^$',/ views.index, name='index')
Just replace that with this:
path('', views.index, name='index'),
in your music\urls.py