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Using xpath method in selenium in python - no such element: Unable to locate element

kinda new in the selenium, I'm trying to reach a "submit" element in a very long xml page.
Here is my code:
import pip
import time
import autoit
#import selenium
from selenium import webdriver
from selenium.webdriver.support.select import Select
from selenium.webdriver.support.ui import Select
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains
driver = webdriver.Chrome(executable_path=r"C:\Users\Admin\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\Python 3.10\chromedriver.exe")
driver.get("https://example.com/")
time.sleep(30)
element = driver.find_element(by=By.XPATH, value="//*[#id='btnLastMonth']")
I reached this xpath by clicking on the element from inspect > copy xpath.
I keep getting this massage:
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[#id='btnLastMonth']"}

Using Selenium to accept a splash page

When I load the my site as shown below, a splash screen appears to confirm I am 21 years of age. I am trying to load the element to click yes, but I am unable to bypass the age verification screen.
My approach was to load the page. Add a sleep time, find the element and click Yes. However it wont work.
driver.get('https://seelbachs.com/products/sagamore-spirit-cask-strength-rye-whiskey')
time.sleep(5)
element= driver.find_element_by_xpath('//*[#id="enter"]')
element.click()
Error received.
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[#id="enter"]"}
So either my find.element is off or my time.sleep is not helping with the splash page.

It seems the problem is that the pop-up is in an iframe.
This code appears to do the trick
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver import ActionChains
import time
driver = webdriver.Chrome('/usr/local/bin/chromedriver')
driver.get('https://seelbachs.com/products/sagamore-spirit-cask-strength-rye-whiskey')
# xpath of iframe
frame_xpath = '/html/body/div[5]/div/div/div/div/iframe'
wait = WebDriverWait(driver, 10)
# wait until iframe appears and select iframe
wait.until(EC.frame_to_be_available_and_switch_to_it((By.XPATH, frame_xpath)))
# select button
xpath = '//*[#id="enter"]'
time.sleep(2)
element= driver.find_element_by_xpath(xpath)
ActionChains(driver).move_to_element(element).click(element).perform()
referencing This answer on Stack Overflow

You need to switch to the frame, check the below code
driver.get('https://seelbachs.com/products/sagamore-spirit-cask-strength-rye-whiskey')
sleep(5)
driver.switch_to.frame(driver.find_element_by_xpath("//iframe[contains(#id,'fancyboxAge-frame')]"))
OR
#Using the explicitWait
WebDriverWait(driver,10).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH,"//iframe[contains(#id,'fancyboxAge-frame')]")))
element= driver.find_element_by_xpath('//*[#id="enter"]')
element.click()
import
from time import sleep
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.wait import WebDriverWait

How to select an iframe with Selenium in Python?

With selenium-python I want to select an iframe which has the following information:
<iframe title="Key to fetch simulation results" class="ltiLaunchFrame" name="ltiFrame-1548f8973dbf4d76840c56763e996767" src="/courses/course-v1:EPFL+SimNeuro2+2019_2/xblock/block-v1:EPFL+SimNeuro2+2019_2+type#lti_consumer+block#1548f8973dbf4d76840c56763e996767/handler/lti_launch_handler" allowfullscreen="true" webkitallowfullscreen="true" mozallowfullscreen="true" allow="microphone *; camera *; midi *; geolocation *; encrypted-media *"></iframe>
I tried to do
webdriver.switch_to.frame("ltiFrame-1548f8973dbf4d76840c56763e996767")'
but it says
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: [name="ltiFrame-1548f8973dbf4d76840c56763e996767"]
But I have used the correct name! What am I doing wrong?

In case title attribute value Key to fetch simulation results is unique this should work:
WebDriverWait(driver, 10).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH,"//iframe[#title='Key to fetch simulation results']")))
In order to use this you have to import
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
and initialize wait object
wait = WebDriverWait(driver, 20)

//iframe[contains(#name, 'ltiFrame-') and #class='ltiLaunchFrame']
you can use the above mentioned xpath to locate the iframe.
Code :
wait = WebDriverWait(driver, 10)
wait.until(EC.frame_to_be_available_and_switch_to_it((By.XPATH, "//iframe[contains(#name, 'ltiFrame-') and #class='ltiLaunchFrame']")))
Imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
also in case you wanna come out of the frame, use the below code :
driver.switch_to.default_content()

Message: no such element: Unable to locate element: {"method":"xpath","selector":"/html/body/div[2]/div[2]/div/div[3]/div[2]/div/div/div[2]/a[1]"}

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
import time
print('\n')
print("PROGRAM STARTING")
print('~~~~~~')
print('\n')
# initiate driver
driver = webdriver.Chrome()
driver.get('http://arcselfservice.sbcounty.gov/web/user/disclaimer')
#begin
driver.find_element_by_xpath('//*[#id="submitDisclaimerAccept"]').click()
driver.find_element_by_xpath('/html/body/div[2]/div[2]/div/div[3]/div[2]/div/div/div[2]/a[1]').click()
I have been stuck on this error for a long time, for some reason it can't find the element even though I am specifying the xpath. There doesn't seem to be any iframes, and implicit or explicit wait doesn't work either. Please help.

So the issue was waiting for the element to come up and then clicking it.
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "/html/body/div[2]/div[2]/div/div[3]/div[2]/div/div/div[2]/a[1]"))).click()
Another way if you want to change to the other tags later.
path = "//a/div/h1[text()='{}']/../..".format("Fictitious Business Names Application")
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH ,path))).click()
Import
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

The error is coming because the element is taking time to be available for use. Kindly use the explicit wait for the element extraction.
A small snippet can be:
WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.XPATH ,'/html/body/div[2]/div[2]/div/div[3]/div[2]/div/div/div[2]/a[1]'))).click()
Just dont forget to import
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

How to click on onclick link with image? Python Selenium

I'm just learning how to webscrape dynamically using Selenium in Python. I'm currently trying to click on a link within the webpage to page forward over search results.
So far this is the code that I'm using:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Chrome('C:\\Users\\km13\\chromedriver.exe')
driver.get("http://www.congreso.gob.pe/pley-2016-2021")
elem = driver.find_element_by_css_selector("img[src='/Sicr/TraDocEstProc/CLProLey2016.nsf/8eac1ef603908b5105256cdf006c41b1/$Body/0.AB2?OpenElement&FieldElemFormat=gif']")
elem.click()
This is the HTML that corresponds with the element I'd like to click on:
`<img src="/Sicr/TraDocEstProc/CLProLey2016.nsf/8eac1ef603908b5105256cdf006c41b1/$Body/0.AB2?OpenElement&FieldElemFormat=gif" width="81" height="16" border="0">`
From my somewhat limited knowledge of HTML this seems like the link is actually embedded in the gif which is why I tried to use the CSS selector that goes along with that image. But this did not work.
Any guidance would be greatly appreciated!
Update:
I changed my code by adding the following import
from selenium.webdriver.common.by import By
And I changed the following:
elem = driver.find_element(By.CSS_SELECTOR, "img[src='/Sicr/TraDocEstProc/CLProLey2016.nsf/8eac1ef603908b5105256cdf006c41b1/$Body/0.AB2?OpenElement&FieldElemFormat=gif']")
elem.click()
Now I get an error for "no such element."

There is an iframe.You need to switch to iframe first to access the element.Try below code.use WebDriverWait to handle dynamic element.
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome('C:\\Users\\km13\\chromedriver.exe')
driver.get("http://www.congreso.gob.pe/pley-2016-2021")
WebDriverWait(driver, 20).until(EC.frame_to_be_available_and_switch_to_it((By.NAME, 'ventana02')))
elem = WebDriverWait(driver, 10).until(EC.element_to_be_clickable(
(By.XPATH, "//a[contains(#onclick,'A50')]/img[contains(#src,'Sicr/TraDocEstProc/CLProLey')]")))
elem.click()
EDITED
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome('C:\\Users\\km13\\chromedriver.exe')
driver.get("http://www.congreso.gob.pe/pley-2016-2021")
driver.switch_to.frame(0)
elem=WebDriverWait(driver,10).until(EC.element_to_be_clickable((By.XPATH,"//a[contains(#onclick,'A50')]/img[contains(#src,'Sicr/TraDocEstProc/CLProLey')]")))
elem.click()