I'm not familiar with multiprocessing module. I am tring to verify that variables in different processes are irrelevant. After the test, I find different processes probably "share" variables. That happens when process has the same pid. I am not sure if there is some relationship?
Environment : Windows 10 ; python 3.7
# -*- coding: utf-8 -*-
import os
from multiprocessing import Pool
p=0
def Child_process(id_number):
global p
print('Task start: %s(%s)' % (id_number, os.getpid()))
print('p = %d' % p)
p=p+1
print('Task {} end'.format(id_number))
if __name__ == '__main__':
p = Pool(4)
p.map(Child_process,range(5))
p.close()
p.join()
The result is:
Task start: 0(7668)
p = 0
Task start: 1(10384)
Task 0 end
p = 0
Task start: 2(7668)
p = 1
Task 1 end
Task 2 end
Task start: 3(7668)
Task start: 4(10384)
p = 1
Task 4 end
p = 2
Task 3 end
I think the p should always be 0, but it increases when different processes have the same pid?
By definition, a thread/process pool will re-use the same thread/process. This lets you setup resources in the when the thread/process starts so that each thread/process won't have to initialize them each time. This includes global variables, open files, sockets, etc. You can do the one time initialization by passing an initializer function to the thread/process. So if you set or increment the variable p it will remain set throughout the various runs of the process. If you want the variable to always start at 0 for each run, you'll need to set it to 0 at the start of each run.
This note is in the multiprocessing.pool.Pool class:
Note: Worker processes within a Pool typically live for the complete duration of the Pool’s work queue. A frequent pattern found in other systems (such as Apache, mod_wsgi, etc) to free resources held by workers is to allow a worker within a pool to complete only a set amount of work before being exiting, being cleaned up and a new process spawned to replace the old one. The maxtasksperchild argument to the Pool exposes this ability to the end user.
Related
So I'm using multiprocessing pool with 3 threads, to run a function that does a certain job, and I have a variable defined outside this function which equals 0, and every time the function do it job it should add 1 to that variable and print it, but every thread uses a separated variable
here is the code:
from multiprocessing import Pool
number_of_doe_jobs = 0
def thefunction():
global number_of_doe_jobs
# JOB CODE GOES HERE
number_of_doe_jobs+=1
if __name__ =="__main__":
p = Pool(3)
p.map(checker, datalist)
the desired output is that it adds 1 to number_of_doe_jobs ,
but every thread add 1 to it own number_of_doe_jobs , so there are 3 number_of_doe_jobs variables now.
You are not spawning 3 threads. You are spawning 3 processes. Each process has its own memory space, with its own copy of the interpreter and its own independent object space. Global variables are not shared across processes. There are ways to create shared variables (which communicate over sockets), but you might be better served by using a multiprocessing.Queue. Create it in the mainline code, and pass it as a parameter to the subprocesses. Have the jobs push a "complete" flag on the queue, and have the mainline code read the results.
FOLLOWUP
The NUMBER of jobs will always be equal to len(datalist), so it's not clear why you would track that. Here, I create a multiprocessing queue and pass that to the function. Python implements that by creating a socket. The checker function sends a signal when it finishes, and the mainline code fetches each one and prints it. q.get will block until something is in the queue.
import multiprocessing
def checker(q):
# JOB CODE GOES HERE
q.put( "done" )
if __name__ =="__main__":
q = multiprocessing.Queue()
p = Pool(3)
p.map(lambda: checker(q), datalist)
for _ in datalist:
print( q.get() )
I have created a (rather large) program that takes quite a long time to finish, and I started looking into ways to speed up the program.
I found that if I open task manager while the program is running only one core is being used.
After some research, I found this website:
Why does multiprocessing use only a single core after I import numpy? which gives a solution of os.system("taskset -p 0xff %d" % os.getpid()),
however this doesn't work for me, and my program continues to run on a single core.
I then found this:
is python capable of running on multiple cores?,
which pointed towards using multiprocessing.
So after looking into multiprocessing, I came across this documentary on how to use it https://docs.python.org/3/library/multiprocessing.html#examples
I tried the code:
from multiprocessing import Process
def f(name):
print('hello', name)
if __name__ == '__main__':
p = Process(target=f, args=('bob',))
p.start()
p.join()
a = input("Finished")
After running the code (not in IDLE) It said this:
Finished
hello bob
Finished
Note: after it said Finished the first time I pressed enter
So after this I am now even more confused and I have two questions
First: It still doesn't run with multiple cores (I have an 8 core Intel i7)
Second: Why does it input "Finished" before its even run the if statement code (and it's not even finished yet!)
To answer your second question first, "Finished" is printed to the terminal because a = input("Finished") is outside of your if __name__ == '__main__': code block. It is thus a module level constant which gets assigned when the module is first loaded and will execute before any code in the module runs.
To answer the first question, you only created one process which you run and then wait to complete before continuing. This gives you zero benefits of multiprocessing and incurs overhead of creating the new process.
Because you want to create several processes, you need to create a pool via a collection of some sort (e.g. a python list) and then start all of the processes.
In practice, you need to be concerned with more than the number of processors (such as the amount of available memory, the ability to restart workers that crash, etc.). However, here is a simple example that completes your task above.
import datetime as dt
from multiprocessing import Process, current_process
import sys
def f(name):
print('{}: hello {} from {}'.format(
dt.datetime.now(), name, current_process().name))
sys.stdout.flush()
if __name__ == '__main__':
worker_count = 8
worker_pool = []
for _ in range(worker_count):
p = Process(target=f, args=('bob',))
p.start()
worker_pool.append(p)
for p in worker_pool:
p.join() # Wait for all of the workers to finish.
# Allow time to view results before program terminates.
a = input("Finished") # raw_input(...) in Python 2.
Also note that if you join workers immediately after starting them, you are waiting for each worker to complete its task before starting the next worker. This is generally undesirable unless the ordering of the tasks must be sequential.
Typically Wrong
worker_1.start()
worker_1.join()
worker_2.start() # Must wait for worker_1 to complete before starting worker_2.
worker_2.join()
Usually Desired
worker_1.start()
worker_2.start() # Start all workers.
worker_1.join()
worker_2.join() # Wait for all workers to finish.
For more information, please refer to the following links:
https://docs.python.org/3/library/multiprocessing.html
Dead simple example of using Multiprocessing Queue, Pool and Locking
https://pymotw.com/2/multiprocessing/basics.html
https://pymotw.com/2/multiprocessing/communication.html
https://pymotw.com/2/multiprocessing/mapreduce.html
I have searched and cannot find an answer to this question elsewhere. Hopefully I haven't missed something.
I am trying to use Python multiprocessing to essentially batch run some proprietary models in parallel. I have, say, 200 simulations, and I want to batch run them ~10-20 at a time. My problem is that the proprietary software crashes if two models happen to start at the same / similar time. I need to introduce a delay between processes spawned by multiprocessing so that each new model run waits a little bit before starting.
So far, my solution has been to introduced a random time delay at the start of the child process before it fires off the model run. However, this only reduces the probability of any two runs starting at the same time, and therefore I still run into problems when trying to process a large number of models. I therefore think that the time delay needs to be built into the multiprocessing part of the code but I haven't been able to find any documentation or examples of this.
Edit: I am using Python 2.7
This is my code so far:
from time import sleep
import numpy as np
import subprocess
import multiprocessing
def runmodels(arg):
sleep(np.random.rand(1,1)*120) # this is my interim solution to reduce the probability that any two runs start at the same time, but it isn't a guaranteed solution
subprocess.call(arg) # this line actually fires off the model run
if __name__ == '__main__':
arguments = [big list of runs in here
]
count = 12
pool = multiprocessing.Pool(processes = count)
r = pool.imap_unordered(runmodels, arguments)
pool.close()
pool.join()
multiprocessing.Pool() already limits number of processes running concurrently.
You could use a lock, to separate the starting time of the processes (not tested):
import threading
import multiprocessing
def init(lock):
global starting
starting = lock
def run_model(arg):
starting.acquire() # no other process can get it until it is released
threading.Timer(1, starting.release).start() # release in a second
# ... start your simulation here
if __name__=="__main__":
arguments = ...
pool = Pool(processes=12,
initializer=init, initargs=[multiprocessing.Lock()])
for _ in pool.imap_unordered(run_model, arguments):
pass
One way to do this with thread and semaphore :
from time import sleep
import subprocess
import threading
def runmodels(arg):
subprocess.call(arg)
sGlobal.release() # release for next launch
if __name__ == '__main__':
threads = []
global sGlobal
sGlobal = threading.Semaphore(12) #Semaphore for max 12 Thread
arguments = [big list of runs in here
]
for arg in arguments :
sGlobal.acquire() # Block if more than 12 thread
t = threading.Thread(target=runmodels, args=(arg,))
threads.append(t)
t.start()
sleep(1)
for t in threads :
t.join()
The answer suggested by jfs caused problems for me as a result of starting a new thread with threading.Timer. If the worker just so happens to finish before the timer does, the timer is killed and the lock is never released.
I propose an alternative route, in which each successive worker will wait until enough time has passed since the start of the previous one. This seems to have the same desired effect, but without having to rely on another child process.
import multiprocessing as mp
import time
def init(shared_val):
global start_time
start_time = shared_val
def run_model(arg):
with start_time.get_lock():
wait_time = max(0, start_time.value - time.time())
time.sleep(wait_time)
start_time.value = time.time() + 1.0 # Specify interval here
# ... start your simulation here
if __name__=="__main__":
arguments = ...
pool = mp.Pool(processes=12,
initializer=init, initargs=[mp.Value('d')])
for _ in pool.imap_unordered(run_model, arguments):
pass
I would like to control the number of Processes spawned while using the multiprocessing package.
Say I only want three processes active at the same time. The only way I know how to do this is:
import multiprocessing
import Queue
def worker(arg):
## Do stuff
return returnvalue
argument = list(1,2,3,4,5,6)
aliveprocesses = 0
jobs = Queue.Queue()
for arg in argument:
while jobs.qsize() > 2:
jobs.get().join()
p = multiprocessing.Process(target=worker,args=(arg,))
jobs.put(p)
p.start()
Basically I only know how to monitor one process at a time using the Process.join() function. I monitor the oldest process until it is done and then create a new process. For my program the oldest process should finish before the others, on average. But who knows? Maybe another process finishes first and I would have no way of knowing.
The only alternative I can think of is something like this:
import multiprocessing
import time
def worker(arg):
## Do stuff
return returnvalue
argument = list(1,2,3,4,5,6)
aliveprocesses = 0
jobs = set()
for arg in argument:
while aliveprocesses > 2:
for j in jobs:
if not j.is_alive():
aliveprocesses -= 1
break
time.sleep(1)
p = multiprocessing.Process(target=worker,args=(arg,))
jobs.put(p)
p.start()
aliveprocesses += 1
In the above function you are checking all of processes if they are still alive. If they are all still alive you sleep for a bit and then check again until there is a dead process after which you spawn a new process. The problem here is that from what I understand the time.sleep() function is not a particularly efficient way to wait for a process to end.
Ideally I would like a function "superjoin()" like Process.join() only it uses a set of Process objects and when one Process within the set returns then superjoin() returns. And superjoin() does not itself use the time.sleep() function ie it's not being "passed the buck"
Since you seem to have a single (parallel) task, instead of managing processes individually, you should use the higher-level multiprocessing.Pool, which makes managing the number of processes easier.
You can't join a pool, but you have blocking calls (such as Pool.map) that perform this kind of task.
If you need finer-grained control, you may want to adapt Pool's source code
I would like to run a number of jobs using a pool of processes and apply a given timeout after which a job should be killed and replaced by another working on the next task.
I have tried to use the multiprocessing module which offers a method to run of pool of workers asynchronously (e.g. using map_async), but there I can only set a "global" timeout after which all processes would be killed.
Is it possible to have an individual timeout after which only a single process that takes too long is killed and a new worker is added to the pool again instead (processing the next task and skipping the one that timed out)?
Here's a simple example to illustrate my problem:
def Check(n):
import time
if n % 2 == 0: # select some (arbitrary) subset of processes
print "%d timeout" % n
while 1:
# loop forever to simulate some process getting stuck
pass
print "%d done" % n
return 0
from multiprocessing import Pool
pool = Pool(processes=4)
result = pool.map_async(Check, range(10))
print result.get(timeout=1)
After the timeout all workers are killed and the program exits. I would like instead that it continues with the next subtask. Do I have to implement this behavior myself or are there existing solutions?
Update
It is possible to kill the hanging workers and they are automatically replaced. So I came up with this code:
jobs = pool.map_async(Check, range(10))
while 1:
try:
print "Waiting for result"
result = jobs.get(timeout=1)
break # all clear
except multiprocessing.TimeoutError:
# kill all processes
for c in multiprocessing.active_children():
c.terminate()
print result
The problem now is that the loop never exits; even after all tasks have been processed, calling get yields a timeout exception.
The pebble Pool module has been built for solving these types of issue. It supports timeout on given tasks allowing to detect them and easily recover.
from pebble import ProcessPool
from concurrent.futures import TimeoutError
with ProcessPool() as pool:
future = pool.schedule(function, args=[1,2], timeout=5)
try:
result = future.result()
except TimeoutError:
print "Function took longer than %d seconds" % error.args[1]
For your specific example:
from pebble import ProcessPool
from concurrent.futures import TimeoutError
results = []
with ProcessPool(max_workers=4) as pool:
future = pool.map(Check, range(10), timeout=5)
iterator = future.result()
# iterate over all results, if a computation timed out
# print it and continue to the next result
while True:
try:
result = next(iterator)
results.append(result)
except StopIteration:
break
except TimeoutError as error:
print "function took longer than %d seconds" % error.args[1]
print results
Currently the Python does not provide native means to the control execution time of each distinct task in the pool outside the worker itself.
So the easy way is to use wait_procs in the psutil module and implement the tasks as subprocesses.
If nonstandard libraries are not desirable, then you have to implement own Pool on base of subprocess module having the working cycle in the main process, poll() - ing the execution of each worker and performing required actions.
As for the updated problem, the pool becomes corrupted if you directly terminate one of the workers (it is the bug in the interpreter implementation, because such behavior should not be allowed): the worker is recreated, but the task is lost and the pool becomes nonjoinable.
You have to terminate all the pool and then recreate it again for another tasks:
from multiprocessing import Pool
while True:
pool = Pool(processes=4)
jobs = pool.map_async(Check, range(10))
print "Waiting for result"
try:
result = jobs.get(timeout=1)
break # all clear
except multiprocessing.TimeoutError:
# kill all processes
pool.terminate()
pool.join()
print result
UPDATE
Pebble is an excellent and handy library, which solves the issue. Pebble is designed for the asynchronous execution of Python functions, where is PyExPool is designed for the asynchronous execution of modules and external executables, though both can be used interchangeably.
One more aspect is when 3dparty dependencies are not desirable, then PyExPool can be a good choice, which is a single-file lightweight implementation of Multi-process Execution Pool with per-Job and global timeouts, opportunity to group Jobs into Tasks and other features.
PyExPool can be embedded into your sources and customized, having permissive Apache 2.0 license and production quality, being used in the core of one high-loaded scientific benchmarking framework.
Try the construction where each process is being joined with a timeout on a separate thread. So the main program never gets stuck and as well the processes which if gets stuck, would be killed due to timeout. This technique is a combination of threading and multiprocessing modules.
Here is my way to maintain the minimum x number of threads in the memory. Its an combination of threading and multiprocessing modules. It may be unusual to other techniques like respected fellow members have explained above BUT may be worth considerable. For the sake of explanation, I am taking a scenario of crawling a minimum of 5 websites at a time.
so here it is:-
#importing dependencies.
from multiprocessing import Process
from threading import Thread
import threading
# Crawler function
def crawler(domain):
# define crawler technique here.
output.write(scrapeddata + "\n")
pass
Next is threadController function. This function will control the flow of threads to the main memory. It will keep activating the threads to maintain the threadNum "minimum" limit ie. 5. Also it won't exit until, all Active threads(acitveCount) are finished up.
It will maintain a minimum of threadNum(5) startProcess function threads (these threads will eventually start the Processes from the processList while joining them with a time out of 60 seconds). After staring threadController, there would be 2 threads which are not included in the above limit of 5 ie. the Main thread and the threadController thread itself. thats why threading.activeCount() != 2 has been used.
def threadController():
print "Thread count before child thread starts is:-", threading.activeCount(), len(processList)
# staring first thread. This will make the activeCount=3
Thread(target = startProcess).start()
# loop while thread List is not empty OR active threads have not finished up.
while len(processList) != 0 or threading.activeCount() != 2:
if (threading.activeCount() < (threadNum + 2) and # if count of active threads are less than the Minimum AND
len(processList) != 0): # processList is not empty
Thread(target = startProcess).start() # This line would start startThreads function as a seperate thread **
startProcess function, as a separate thread, would start Processes from the processlist. The purpose of this function (**started as a different thread) is that It would become a parent thread for Processes. So when It will join them with a timeout of 60 seconds, this would stop the startProcess thread to move ahead but this won't stop threadController to perform. So this way, threadController will work as required.
def startProcess():
pr = processList.pop(0)
pr.start()
pr.join(60.00) # joining the thread with time out of 60 seconds as a float.
if __name__ == '__main__':
# a file holding a list of domains
domains = open("Domains.txt", "r").read().split("\n")
output = open("test.txt", "a")
processList = [] # thread list
threadNum = 5 # number of thread initiated processes to be run at one time
# making process List
for r in range(0, len(domains), 1):
domain = domains[r].strip()
p = Process(target = crawler, args = (domain,))
processList.append(p) # making a list of performer threads.
# starting the threadController as a seperate thread.
mt = Thread(target = threadController)
mt.start()
mt.join() # won't let go next until threadController thread finishes.
output.close()
print "Done"
Besides maintaining a minimum number of threads in the memory, my aim was to also have something which could avoid stuck threads or processes in the memory. I did this using the time out function. My apologies for any typing mistake.
I hope this construction would help anyone in this world.
Regards,
Vikas Gautam