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How to add string in specific positions in geojson object

i have the below posted geojson mentioned in geojson_1 section below. i want to add to it "geometry":{ and }, so that to appear as follows
{"geometry":{"type":"Polygon","coordinates":[[[1216374.67364018,6563498.44078949],[1216387.86261675,6563523.87797899],[1216397.66970116,6563548.2905649],[1216424.17569103,6563588.32082324],[1216458.19258303,6563622.16452455],[1216498.32084288,6563648.42909789],[1216542.90943577,6563666.03380959],[1216590.12376481,6563674.25425166],[1216638.02117068,6563672.7521636],[1216684.63088244,6563661.58935797],[1216728.03512655,6563641.225175],[1216752.29181681,6563626.67066235],[1216787.17700448,6563601.12371718],[1216816.83970763,6563569.63465531],[1216831.39332728,6563551.03748989],[1216838.2508451,6563541.8226918],[1216897.47283376,6563458.0765492],[1216918.74007329,6563421.44644481],[1216933.156564,6563381.60258193],[1216940.26085904,6563339.82061228],[1216939.82562707,6563297.43819918],[1216931.86491641,6563255.81218836],[1216907.60647856,6563170.91644364],[1216887.20280767,6563121.46139137],[1216856.24799209,6563077.86160203],[1216821.48046704,6563039.0529759],[1216799.23490474,6563017.28929875],[1216753.95673639,6562978.48086898],[1216737.29066155,6562965.4435638],[1216673.22488836,6562919.79826372],[1216644.73178636,6562899.22061724],[1216601.13622245,6562874.31962206],[1216562.32695185,6562857.3410734],[1216556.56069412,6562854.90900462],[1216549.97837146,6562852.23502385],[1216545.77480552,6562849.58841453],[1216504.75306873,6562829.03095075],[1216487.0229317,6562822.21187019],[1216482.65368148,6562820.3796627],[1216478.79578194,6562814.49158384],[1216462.95127963,6562793.04723497],[1216450.44559886,6562777.97698661],[1216448.65520854,6562774.19751598],[1216429.39331353,6562740.84427663],[1216404.99213055,6562711.06486155],[1216382.3528849,6562687.61801865],[1216357.97638417,6562665.64947943],[1216339.38004804,6562651.09634054],[1216299.24217837,6562625.743469],[1216254.86196793,6562608.94292463],[1216208.02902037,6562601.37212065],[1216160.63182011,6562603.33631786],[1216114.58159971,6562614.75632195],[1216071.73529105,6562635.17167463],[1216033.82066317,6562663.75921023],[1216002.36666225,6562699.36623124],[1215978.64176027,6562740.55696848],[1215963.60279766,6562785.67045603],[1215957.85638339,6562832.88749107],[1215961.63441126,6562880.30398198],[1215963.25125904,6562889.19806131],[1215964.03213898,6562893.28933659],[1215968.1319511,6562913.79137984],[1215972.03222389,6562937.19708669],[1215977.28745991,6563016.79645952],[1215971.45390521,6563048.0427099],[1215969.39172682,6563061.09023781],[1215963.73069651,6563104.75131293],[1215962.06592533,6563123.22251112],[1215960.00953034,6563163.6421848],[1215954.35640427,6563213.80082903],[1215954.63230125,6563269.34572034],[1215960.29082704,6563315.43307246],[1215970.70253119,6563361.57391952],[1215982.82982632,6563397.95907391],[1216001.20120538,6563439.38870108],[1216027.10825421,6563476.54992802],[1216059.60193364,6563508.08124916],[1216097.4918555,6563532.82739871],[1216139.38989254,6563549.8816932],[1216183.76104002,6563558.61926572],[1216228.97966418,6563558.71997125],[1216273.38907516,6563550.18012236],[1216287.1346647,6563546.13717455],[1216332.92682121,6563527.24586381],[1216373.78586258,6563499.1986745],[1216374.67364018,6563498.44078949]]]}}
to simpify it even more, i want to add "geometry":{ right after the the first curly bracket, and the } at the very end
i attmepted the following:
asString = asString[:2] + "geometry:" + asString[2:]
asString = asString[:len(asString)] + "}" + asString[len(asString):]
but i am not getting the expected results
geojson_1:
{"type":"Polygon","coordinates":[[[1216374.67364018,6563498.44078949],[1216387.86261675,6563523.87797899],[1216397.66970116,6563548.2905649],[1216424.17569103,6563588.32082324],[1216458.19258303,6563622.16452455],[1216498.32084288,6563648.42909789],[1216542.90943577,6563666.03380959],[1216590.12376481,6563674.25425166],[1216638.02117068,6563672.7521636],[1216684.63088244,6563661.58935797],[1216728.03512655,6563641.225175],[1216752.29181681,6563626.67066235],[1216787.17700448,6563601.12371718],[1216816.83970763,6563569.63465531],[1216831.39332728,6563551.03748989],[1216838.2508451,6563541.8226918],[1216897.47283376,6563458.0765492],[1216918.74007329,6563421.44644481],[1216933.156564,6563381.60258193],[1216940.26085904,6563339.82061228],[1216939.82562707,6563297.43819918],[1216931.86491641,6563255.81218836],[1216907.60647856,6563170.91644364],[1216887.20280767,6563121.46139137],[1216856.24799209,6563077.86160203],[1216821.48046704,6563039.0529759],[1216799.23490474,6563017.28929875],[1216753.95673639,6562978.48086898],[1216737.29066155,6562965.4435638],[1216673.22488836,6562919.79826372],[1216644.73178636,6562899.22061724],[1216601.13622245,6562874.31962206],[1216562.32695185,6562857.3410734],[1216556.56069412,6562854.90900462],[1216549.97837146,6562852.23502385],[1216545.77480552,6562849.58841453],[1216504.75306873,6562829.03095075],[1216487.0229317,6562822.21187019],[1216482.65368148,6562820.3796627],[1216478.79578194,6562814.49158384],[1216462.95127963,6562793.04723497],[1216450.44559886,6562777.97698661],[1216448.65520854,6562774.19751598],[1216429.39331353,6562740.84427663],[1216404.99213055,6562711.06486155],[1216382.3528849,6562687.61801865],[1216357.97638417,6562665.64947943],[1216339.38004804,6562651.09634054],[1216299.24217837,6562625.743469],[1216254.86196793,6562608.94292463],[1216208.02902037,6562601.37212065],[1216160.63182011,6562603.33631786],[1216114.58159971,6562614.75632195],[1216071.73529105,6562635.17167463],[1216033.82066317,6562663.75921023],[1216002.36666225,6562699.36623124],[1215978.64176027,6562740.55696848],[1215963.60279766,6562785.67045603],[1215957.85638339,6562832.88749107],[1215961.63441126,6562880.30398198],[1215963.25125904,6562889.19806131],[1215964.03213898,6562893.28933659],[1215968.1319511,6562913.79137984],[1215972.03222389,6562937.19708669],[1215977.28745991,6563016.79645952],[1215971.45390521,6563048.0427099],[1215969.39172682,6563061.09023781],[1215963.73069651,6563104.75131293],[1215962.06592533,6563123.22251112],[1215960.00953034,6563163.6421848],[1215954.35640427,6563213.80082903],[1215954.63230125,6563269.34572034],[1215960.29082704,6563315.43307246],[1215970.70253119,6563361.57391952],[1215982.82982632,6563397.95907391],[1216001.20120538,6563439.38870108],[1216027.10825421,6563476.54992802],[1216059.60193364,6563508.08124916],[1216097.4918555,6563532.82739871],[1216139.38989254,6563549.8816932],[1216183.76104002,6563558.61926572],[1216228.97966418,6563558.71997125],[1216273.38907516,6563550.18012236],[1216287.1346647,6563546.13717455],[1216332.92682121,6563527.24586381],[1216373.78586258,6563499.1986745],[1216374.67364018,6563498.44078949]]]}

I'm going to assume that geojson_1 is available as a string in which case:
import json
output = {'geometry': json.loads(geojson_1)}
...will give you a dictionary with the structure you need.

It looks like plain json data, or a string representation of a dict (they wouldn't be any different in this case), did you consider wrapping the returned data in a new dict rather than manipulating it as a string?
import json
# Assume this returns the geojson as text
geojson = json.loads(get_geojson())
geojson = {"geometry": geojson}
print(json.dumps(geojson))

I get the expected result using the following:
'{"geometry":' + d + "}"
It adds the string {"geometry": to the string d and at the end }.
The variable dis:
d = '{"type":"Polygon","co (rest of json) ,6563498.44078949]]]}'
Or you can use the json library for this:
import json
data = json.loads(d) # note d is the same string as above, this can also be from a file or read file using json.load(FILE)
# Create your new object:
result = {'geometry': data}
# print you new json:
print( json.dumps(result, indent=2))
edit:
'"geometry":{' + d + "}"
Note that you get a string starting with geometry and a { and directly another { from you input json. This is not a correct dictionary nor a proper json format.
Result:
'"geometry":{{"type":"Polygon", ... ,6563498.44078949]]]}}'
(the dots are just the rest of your original json.

how to print after the keyword from python?

i have following string in python
b'{"personId":"65a83de6-b512-4410-81d2-ada57f18112a","persistedFaceIds":["792b31df-403f-4378-911b-8c06c06be8fa"],"name":"waqas"}'
I want to print the all alphabet next to keyword "name" such that my output should be
waqas
Note the waqas can be changed to any number so i want print any name next to keyword name using string operation or regex?

First you need to decode the string since it is binary b. Then use literal eval to make the dictionary, then you can access by key
>>> s = b'{"personId":"65a83de6-b512-4410-81d2-ada57f18112a","persistedFaceIds":["792b31df-403f-4378-911b-8c06c06be8fa"],"name":"waqas"}'
>>> import ast
>>> ast.literal_eval(s.decode())['name']
'waqas'

It is likely you should be reading your data into your program in a different manner than you are doing now.
If I assume your data is inside a JSON file, try something like the following, using the built-in json module:
import json
with open(filename) as fp:
data = json.load(fp)
print(data['name'])

if you want a more algorithmic way to extract the value of name:
s = b'{"personId":"65a83de6-b512-4410-81d2-ada57f18112a",\
"persistedFaceIds":["792b31df-403f-4378-911b-8c06c06be8fa"],\
"name":"waqas"}'
s = s.decode("utf-8")
key = '"name":"'
start = s.find(key) + len(key)
stop = s.find('"', start + 1)
extracted_string = s[start : stop]
print(extracted_string)
output
waqas

You can convert the string into a dictionary with json.loads()
import json
mystring = b'{"personId":"65a83de6-b512-4410-81d2-ada57f18112a","persistedFaceIds":["792b31df-403f-4378-911b-8c06c06be8fa"],"name":"waqas"}'
mydict = json.loads(mystring)
print(mydict["name"])
# output 'waqas'

First you need to convert the string into a proper JSON Format by removing b from the string using substring in python suppose you have a variable x :
import json
x = x[1:];
dict = json.loads(x) //convert JSON string into dictionary
print(dict["name"])

How to remove a particular character from a txt file?

Have a txt with contents :
{
hello : 1,two:three,four:five,six:seven,
}
how to remove the last , in the above string ?
while using them as dictionaries for further. it cant be parsed because of the last delimiter.
code :
import json
d2=json.load(open(test.txt))
i cant change the source code. coz i am extracting data from a json file(json.dump) and creating a new json. is there any way of doing that other than dump/changing the source code

This removes the last , in your string without the need of any further import's.
with open('test.txt', 'r') as f:
s = f.read()
s = s[::-1].replace(',', '', 1)[::-1]
the output of s is then:
{
hello : 1,two:three,four:five,six:seven
}

Simple replace should work fine.
broken_json = '''{
hello : 1,two:three,four:five,six:seven,
bye : 42,ick:poo,zoo:bar,}'''
j = broken_json.replace(',}', '}').replace(',\n}','\n}')
The result at this point is still not valid JSON, because the dictionary keys need to be quoted; but this is outside the scope of your question so I will not try to tackle that part.

string ='{hello : 1,two:three,four:five,six:seven,}'
length = len(string)
for i in range(length):
if(string[i] == ','):
string2 = string[0:i] + string[i + 1:length]
print (string2)
The output type would be a string. So, convert it to a dict later.

import re
string ='{hello : 1,two:three,four:five,six:seven,}'
match = re.search(r'(.*),[^,]*$', string)
print (match.group(1)+"}")
Try this #selcuk for an efficient one

How to fetch single item out of long string?

I have a very string as output of function as follows:
tmp = <"last seen":1568,"reviews [{"id":15869,"author":"abnbvg","changes":........>
How will I fetch the "id":15869 out of it?

The string content looks like JSON, so either use the json module or use a regular expression to extract the specific string you need.

The data looks like a JSON string. Use:
try:
import json
except ImportError:
import simplejson as json
tmp = '"last seen":1568,"reviews":[{"id":15869,"author":"abnbvg"}]'
data = json.loads('{{{}}}'.format(tmp))
>>> print data
{u'reviews': [{u'id': 15869, u'author': u'abnbvg'}], u'last seen': 1568}
>>> print data['reviews'][0]['id']
15869
Note that I wrapped the string in { and } to make a dictionary. You might not have to do that if the actual JSON string is already encapsulated with braces.

If id is the only thing you need from the string and it will always be something like {"id":15869,"author":"abnbvg"..., then you can go with sinple string split instead of json conversion.
tmp = '"last seen":1568,"reviews" : [{"id":15869,"author":"abnbvg","changes":........'
tmp1 = tmp.split('"id":', 1)[1]
id = tmp1.split(",", 1)[0]
Please note that tmp1 line may raise IndexError in case there is no "id" key found in the string. You can use -1 instead of 1 to side step. But in this way, you can report that "id" is not found.
try:
tmp1 = tmp.split('"id":', 1)[1]
id = tmp1.split(",", 1)[0]
except IndexError:
print "id key is not present in the json"
id = None
If you do really need more variables from the json string, please go with mhawke's solution of converting the json to dictionary and getting the value. You can use ast.literal_eval
from ast import literal_eval
tmp = '"last seen":1568,"reviews" : [{"id":15869,"author":"abnbvg","changes":........'
tmp_dict = literal_eval("""{%s}"""%(tmp))
print tmp_dict["reviews"][0]["id"]
In the second case, if you need to collect all the "id" keys in the list, this will help:
id_list =[]
for id_dict in tmp_dict["reviews"]:
id_list.append(id_dict["id"])
print id_list

Python: remove double quotes from JSON dumps

I have a database which returns the rows as lists in following format:
data = ['(1000,"test value",0,0.00,0,0)', '(1001,"Another test value",0,0.00,0,0)']
After that, I use json_str = json.dumps(data) to get a JSON string. After applying json.dumps(), I get the following output:
json_str = ["(1000,\"test value\",0,0.00,0,0)", "(1001,\"Another test value\",0,0.00,0,0)"]
However, I need the JSON string in the following format:
json_str = [(1000,\"test value\",0,0.00,0,0), (1001,\"Another test value\",0,0.00,0,0)]
So basically, I want to remove the surrounding double quotes. I tried to accomplish this with json_str = json_str.strip('"') but this doesn't work. Then, I tried json_str = json_str.replace('"', '') but this also removes the escaped quotes.
Does anybody know a way to accomplish this or is there a function in Python similiar to json.dumps() which produces the same result, but without the surrounding double quotes?

You are dumping list of strings so json.dumps does exactly what you are asking for. Rather ugly solution for your problem could be something like below.
def split_and_convert(s):
bits = s[1:-1].split(',')
return (
int(bits[0]), bits[1], float(bits[2]),
float(bits[3]), float(bits[4]), float(bits[5])
)
data_to_dump = [split_and_convert(s) for s in data]
json.dumps(data_to_dump)