how to print after the keyword from python? - python

i have following string in python
b'{"personId":"65a83de6-b512-4410-81d2-ada57f18112a","persistedFaceIds":["792b31df-403f-4378-911b-8c06c06be8fa"],"name":"waqas"}'
I want to print the all alphabet next to keyword "name" such that my output should be
waqas
Note the waqas can be changed to any number so i want print any name next to keyword name using string operation or regex?

First you need to decode the string since it is binary b. Then use literal eval to make the dictionary, then you can access by key
>>> s = b'{"personId":"65a83de6-b512-4410-81d2-ada57f18112a","persistedFaceIds":["792b31df-403f-4378-911b-8c06c06be8fa"],"name":"waqas"}'
>>> import ast
>>> ast.literal_eval(s.decode())['name']
'waqas'

It is likely you should be reading your data into your program in a different manner than you are doing now.
If I assume your data is inside a JSON file, try something like the following, using the built-in json module:
import json
with open(filename) as fp:
data = json.load(fp)
print(data['name'])

if you want a more algorithmic way to extract the value of name:
s = b'{"personId":"65a83de6-b512-4410-81d2-ada57f18112a",\
"persistedFaceIds":["792b31df-403f-4378-911b-8c06c06be8fa"],\
"name":"waqas"}'
s = s.decode("utf-8")
key = '"name":"'
start = s.find(key) + len(key)
stop = s.find('"', start + 1)
extracted_string = s[start : stop]
print(extracted_string)
output
waqas

You can convert the string into a dictionary with json.loads()
import json
mystring = b'{"personId":"65a83de6-b512-4410-81d2-ada57f18112a","persistedFaceIds":["792b31df-403f-4378-911b-8c06c06be8fa"],"name":"waqas"}'
mydict = json.loads(mystring)
print(mydict["name"])
# output 'waqas'

First you need to convert the string into a proper JSON Format by removing b from the string using substring in python suppose you have a variable x :
import json
x = x[1:];
dict = json.loads(x) //convert JSON string into dictionary
print(dict["name"])

Related

How to convert string to a list of json in python?

I have a string in the form of
[[sourceId:111, clientId:12345, clientName:testclient, module:test,source:Request, userName:Michelle Jackson],[sourceId:112, clientId:1233, clientName:testclient2, module:test, source:Request, userName:Michelle Jackson]]
How do I convert it into a valid python list of json ?
Although I never recommend doing this, here's the code
import re
arr = []
for x in s.split('],['):
kv = re.sub('\[|\]', '', x)
arr.append(dict(kvi.split(':') for kvi in kv.split(',')))
NOTE: If the string is system generated, it's better to get it in JSON format in the first place.

Get list from string with exec in python

I have:
"[15765,22832,15289,15016,15017]"
I want:
[15765,22832,15289,15016,15017]
What should I do to convert this string to list?
P.S. Post was edited without my permission and it lost important part. The type of line that looks like list is 'bytes'. This is not string.
P.S. №2. My initial code was:
import urllib.request, re
f = urllib.request.urlopen("http://www.finam.ru/cache/icharts/icharts.js")
lines = f.readlines()
for line in lines:
m = re.match('var\s+(\w+)\s*=\s*\[\\s*(.+)\s*\]\;', line.decode('windows-1251'))
if m is not None:
varname = m.group(1)
if varname == "aEmitentIds":
aEmitentIds = line #its type is 'bytes', not 'string'
I need to get list from line
line from web page looks like
[15765, 22832, 15289, 15016, 15017]
Assuming s is your string, you can just use split and then cast each number to integer:
s = [int(number) for number in s[1:-1].split(',')]
For detailed information about split function:
Python3 split documentation
What you have is a stringified list. You could use a json parser to parse that information into the corresponding list
import json
test_str = "[15765,22832,15289,15016,15017]"
l = json.loads(test_str) # List that you need.
Or another way to do this would be to use ast
import ast
test_str = "[15765,22832,15289,15016,15017]"
data = ast.literal_eval(test_str)
The result is
[15765, 22832, 15289, 15016, 15017]
To understand why using eval() is bad practice you could refer to this answer
You can also use regex to pull out numeric values from the string as follows:
import re
lst = "[15765,22832,15289,15016,15017]"
lst = [int(number) for number in re.findall('\d+',lst)]
Output of the above code is,
[15765, 22832, 15289, 15016, 15017]

How to fetch single item out of long string?

I have a very string as output of function as follows:
tmp = <"last seen":1568,"reviews [{"id":15869,"author":"abnbvg","changes":........>
How will I fetch the "id":15869 out of it?
The string content looks like JSON, so either use the json module or use a regular expression to extract the specific string you need.
The data looks like a JSON string. Use:
try:
import json
except ImportError:
import simplejson as json
tmp = '"last seen":1568,"reviews":[{"id":15869,"author":"abnbvg"}]'
data = json.loads('{{{}}}'.format(tmp))
>>> print data
{u'reviews': [{u'id': 15869, u'author': u'abnbvg'}], u'last seen': 1568}
>>> print data['reviews'][0]['id']
15869
Note that I wrapped the string in { and } to make a dictionary. You might not have to do that if the actual JSON string is already encapsulated with braces.
If id is the only thing you need from the string and it will always be something like {"id":15869,"author":"abnbvg"..., then you can go with sinple string split instead of json conversion.
tmp = '"last seen":1568,"reviews" : [{"id":15869,"author":"abnbvg","changes":........'
tmp1 = tmp.split('"id":', 1)[1]
id = tmp1.split(",", 1)[0]
Please note that tmp1 line may raise IndexError in case there is no "id" key found in the string. You can use -1 instead of 1 to side step. But in this way, you can report that "id" is not found.
try:
tmp1 = tmp.split('"id":', 1)[1]
id = tmp1.split(",", 1)[0]
except IndexError:
print "id key is not present in the json"
id = None
If you do really need more variables from the json string, please go with mhawke's solution of converting the json to dictionary and getting the value. You can use ast.literal_eval
from ast import literal_eval
tmp = '"last seen":1568,"reviews" : [{"id":15869,"author":"abnbvg","changes":........'
tmp_dict = literal_eval("""{%s}"""%(tmp))
print tmp_dict["reviews"][0]["id"]
In the second case, if you need to collect all the "id" keys in the list, this will help:
id_list =[]
for id_dict in tmp_dict["reviews"]:
id_list.append(id_dict["id"])
print id_list

convert string value to dictionary from pickled

val = "{t:30, f:50}"
is a string value and i need to convert it into dictionary other than the conventional method of using val.split(',') and then remove brackets and take out key and bind value to it and convert it in dictionary. Can anyone suggest any better approach towards it. PLz do care that even there is no quotes in strings in keys(t and s). Got some values from db.Already tried json loads or dumps.
import re
x="{t:30, f:50}"
y=re.findall(r"([^ {,]*):([^ {,]*)[,}]",x)
print dict(y)
Try this.Simple and done in one or two steps.
import re
val = "{t:30, f:50}"
t = re.search("[^{].*[^}]",val).group()
print (t)
z = t.split(",")
print (z)
mydict = {}
mydict[z[0][0]]=z[0][2]+z[0][3]
print (mydict)
>>>
t:30, f:50
['t:30', ' f:50']
{'t': '30'}
>>>
Use search() method ofre module

Python program treating dictionary like a string

I set up a dictionary, and filled it from a file, like so:
filedusers = {} # cheap way to keep track of users, not for production
FILE = open(r"G:\School\CS442\users.txt", "r")
filedusers = ast.literal_eval("\"{" + FILE.readline().strip() + "}\"")
FILE.close()
then later I did a test on it, like this:
if not filedusers.get(words[0]):
where words[0] is a string for a username, but I get the following error:
'str' object has no attribute 'get'
but I verified already that after the FILE.close() I had a dictionary, and it had the correct values in it.
Any idea what's going on?
literal_eval takes a string, and converts it into a python object. So, the following is true...
ast.literal_eval('{"a" : 1}')
>> {'a' : 1}
However, you are adding in some quotations that aren't needed. If your file simply contained an empty dictionary ({}), then the string you create would look like this...
ast.literal_eval('"{}"') # The quotes that are here make it return the string "{}"
>> '{}'
So, the solution would be to change the line to...
ast.literal_eval("{" + FILE.readline().strip() + "}")
...or...
ast.literal_eval(FILE.readline().strip())
..depending on your file layout. Otherwise, literal_eval sees your string as an ACTUAL string because of the quotes.
>>> import ast
>>> username = "asd: '123'"
>>> filedusers = ast.literal_eval("\"{" + username + "}\"")
>>> print filedusers, type(filedusers)
{asd} <type 'str'>
You don't have a dictionary, it just looks like one. You have a string.
Python is dynamically typed: it does not require you to define variables as a specific type. And it lets you define variables implicitly. What you are doing is defining filedusers as a dictionary, and then redefining it as a string by assigning the result of ast.literal_eval to it.
EDIT: You need to remove those quotes. ast.literal_eval('"{}"') evaluates to a string. ast.literal_eval('{}') evaluates to a dictionary.

Categories

Resources