This question already has answers here:
Specify float_format differently for each column (scientific notation vs decimal precision)
(2 answers)
Closed 2 years ago.
The output of Jupyter notebook was not able to show the value. May I know how I can change the width to fix the display problem?
one thing you must try is, reduce the number of digits after the period(.)
in pandas, there is an option
initial output:
random
0 2.339650e-03
1 6.714034e-02
2 1.381005e-15
3 4.846619e-05
4 6.375477e-06
Changed the pattern by using the following code:
dd = df.apply(lambda x: '%.10f' % x, axis=1)
corrected output:
0 0.0023396498
1 0.0671403367
2 0.0000000000
3 0.0000484662
4 0.0000063755
instead of .10f you and use any less number. because there is no need to put that much digit after the period
Related
This question already has answers here:
Given n, take tsum of the digits of n. If that value has more than one digit, continue reducing a single-digit number is produced
(4 answers)
Closed 1 year ago.
I have problem and trying to get next:
new_string = "35" #and this result must be like new_int = 3+5.
How im available to do this? I know the type conversion, but not a clue how i should do this.
As you are new to the python, i suggest you doing it using
int(new_string[0]) # 3
int(new_string[1]) # 5
So now you have 2 integers, you can to whatever you want
This question already has answers here:
Print a float number in normal form, not exponential form / scientific notation [duplicate]
(2 answers)
How to suppress scientific notation when printing float values?
(16 answers)
Closed 2 years ago.
I want to print the whole number instead of 1e-06
number = 1
result = number/1000000
print(result)
Please help whats the best way to do it?
Try out the following by using format:
number = 1
result = number/1000000
print('{0:.6f}'.format(result))
Output:
0.000001
output = f"{num:.9f}"
you can replace 9 with the amount of numbers you have after the decimal point in your number.
and also you will need to define your variable to float to order it will work.
This question already has answers here:
Why does integer division yield a float instead of another integer?
(4 answers)
Closed 3 years ago.
Pretty new to python, facing a problem that requires basically the opposite of the remainder "%" function. For example, if I wanted to divide 81.5 by 20, my output would be 4. My best attempt is as follows:
amount = 81.504
round(amount, 2)
num20s = amount / 20
int(num20s)
I've tried several different combinations of the above code, but nothing has worked so far. This is the closest I've gotten to what I want, but it won't work in edge cases, and for some reason still represents the number with a ".0" at the end, so that last line must not be doing anything.
Integer division operator in python is "//".
>>> amount = 81.504
>>> amount // 20
Out[3]: 4.0
>>> int(amount // 20)
Out[4]: 4
This question already has answers here:
Replace first occurrence of string in Python
(2 answers)
Closed 4 years ago.
Currently, i have a bit string represented as
current = "011"
and what I'm trying to do is to create a new string based of the bit string above with the 1 at index 1 replaced with 011 which would give me:
new = "00111"
The problem I'm having is that when I use the replace function, it replaced all the 1 in the string including the one at index 2 which is not what I desired.
new = current.replace("1","011")
= 0011011 #not what I wanted
Would appreciate some help on this.
Limit the number of replace to 1 such as below:
new = current.replace("1","011", 1)
This question already has answers here:
How to retain leading zeros of int variables?
(4 answers)
Closed 5 years ago.
I understand that the comma (,) makes Python think that print(1,000,000) is a list of three items to be printed.
However, why is only 1 zero (0) of the 3 printed? Surely 1 000 000 should be printed instead of 1 0 0? Why have the other 2 zeroes disappeared?
Thank you all for your help!! Alas I must appeal to the masters^^.
Python truncates leading zeros as they do not add to the value of the number, which in this case is 0.