Develop Reference

CLion: force the attach process to attach process to certain debugger

I am trying to debug some c++ codes called from a python program (through python-c++ binding). My original approach was to start ipython, open lldb and attach the ipython process in lldb. Then go to ipython to run my python program. This works fine.
Now I want to take advantages of CLion IDE by attaching the ipython process inside CLion. However, When I did the attach process from CLion, it seems to attach to the process to the pydev debugger like below instead of attach the process to lldb:
Attaching to a process with PID=18016
/Library/Frameworks/Python.framework/Versions/3.6/Resources/Python.app/Contents/MacOS/Python /Applications/CLion.app/Contents/plugins/python/helpers/pydev/pydevd_attach_to_process/attach_pydevd.py --port 51406 --pid 18016
Connected to pydev debugger (build 183.5429.37)
However, I want the process to be attached to lldb, not pydev_debugger.
How do I force the attach_process in CLion to attach the process to lldb instead of pydev_debugger? Thanks!

There must be two entries in the attach dialog corresponding to the target process in question: attach using the pydev debugger and the native debugger. You may try filtering the list by the process PID in order to check that.
Please find a similar report in the CLion issue tracker here:
Inside the "Attach to Local Process..." dialog there're two kinds of processes you're able to attach to: one comes from CLion (attach with LLDB or GDB), another is provided by the Python plugin (attach with Python Debugger). Since the process you intend to attach to is a Python interpreter, the latter (the Python debugger) is suggested by default, while you should rather use the former (the CLion debugger) for debugging C/C++ code.

Debugger is not detaching from Winpdb

I am using PythonQT to execute python script (because I need to call c++ methods from python script)
My winpdb version is 1.4.6 and machine is CetOS 6.5
Now I want to enable debugging in python script
I have added rpdb2.start_embedded_debugger('test') inside the script and called PythonQt.EvalFile() function, now script is waiting for debugger.
I have opened winpdb UI from terminal and attached to the debugger. I am able to do the “Next”, “Step into” etc. and all local variables are visible correctly
But when I am trying to detach the debugger it is not detaching. Status showing “DETACHING” and nothing happening and I cannot even close winpdb. The only way to exit is kill winpdb.
If I run the same script file from terminal it is working properly (python ) and detaching as expected.
By looking the logs I have found that ,If I run from terminal then the debug channel is encrypted but when from PythonQt debug channel is NOT encrypted, not sure this have any relation with detaching
By further looking into rpdb2.py code I have found that Winpdb is hang on the line self.getSession().getProxy().request_go(fdetach) of request_go(self, fdetach = False): in rpdb2.py
The port 51000 is still in established mode
Please advise me on this.

Finally i have fixed the issue by using the latest version of python QT

launch external shell python instance in shell from python

I'd like to call a separate non-child python program from a python script and have it run externally in a new shell instance. The original python script doesn't need to be aware of the instance it launches, it shouldn't block when the launched process is running and shouldn't care if it dies. This is what I have tried which returns no error but seems to do nothing...
import subprocess
python_path = '/usr/bin/python'
args = [python_path, '&']
p = subprocess.Popen(args, shell=True)
What should I be doing differently
EDIT
The reason for doing this is I have an application with a built in version of python, I have written some python tools that should be run separately alongside this application but there is no assurance that the user will have python installed on their system outside the application with the builtin version I'm using. Because of this I can get the python binary path from the built in version programatically and I'd like to launch an external version of the built in python. This eliminates the need for the user to install python themselves. So in essence I need a simple way to call an external python script using my current running version of python programatically.
I don't need to catch any output into the original program, in fact once launched I'd like it to have nothing to do with the original program
EDIT 2
So it seems that my original question was very unclear so here are more details, I think I was trying to over simplify the question:
I'm running OSX but the code should also work on windows machines.
The main application that has a built in version of CPython is a compiled c++ application that ships with a python framework that it uses at runtime. You can launch the embedded version of this version of python by doing this in a Terminal window on OSX
/my_main_app/Contents/Frameworks/Python.framework/Versions/2.7/bin/python
From my main application I'd like to be able to run a command in the version of python embedded in the main app that launches an external copy of a python script using the above python version just like I would if I did the following command in a Terminal window. The new launched orphan process should have its own Terminal window so the user can interact with it.
/my_main_app/Contents/Frameworks/Python.framework/Versions/2.7/bin/python my_python_script
I would like the child python instance not to block the main application and I'd like it to have its own terminal window so the user can interact with it. The main application doesn't need to be aware of the child once its launched in any way. The only reason I would do this is to automate launching an external application using a Terminal for the user

If you're trying to launch a new terminal window to run a new Python in (which isn't what your question asks for, but from a comment it sounds like it's what you actually want):
You can't. At least not in a general-purpose, cross-platform way.
Python is just a command-line program that runs with whatever stdin/stdout/stderr it's given. If those happen to be from a terminal, then it's running in a terminal. It doesn't know anything about the terminal beyond that.
If you need to do this for some specific platform and some specific terminal program—e.g., Terminal.app on OS X, iTerm on OS X, the "DOS prompt" on Windows, gnome-terminal on any X11 system, etc.—that's generally doable, but the way to do it is by launching or scripting the terminal program and telling it to open a new window and run Python in that window. And, needless to say, they all have completely different ways of doing that.
And even then, it's not going to be possible in all cases. For example, if you ssh in to a remote machine and run Python on that machine, there is no way it can reach back to your machine and open a new terminal window.
On most platforms that have multiple possible terminals, you can write some heuristic code that figures out which terminal you're currently running under by just walking os.getppid() until you find something that looks like a terminal you know how to deal with (and if you get to init/launchd/etc. without finding one, then you weren't running in a terminal).

The problem is that you're running Python with the argument &. Python has no idea what to do with that. It's like typing this at the shell:
/usr/bin/python '&'
In fact, if you pay attention, you're almost certainly getting something like this through your stderr:
python: can't open file '&': [Errno 2] No such file or directory
… which is exactly what you'd get from doing the equivalent at the shell.
What you presumably wanted was the equivalent of this shell command:
/usr/bin/python &
But the & there isn't an argument at all, it's part of sh syntax. The subprocess module doesn't know anything about sh syntax, and you're telling it not to use a shell, so there's nobody to interpret that &.
You could tell subprocess to use a shell, so it can do this for you:
cmdline = '{} &'.format(python_path)
p = subprocess.Popen(cmdline, shell=True)
But really, there's no good reason to. Just opening a subprocess and not calling communicate or wait on it already effectively "puts it in the background", just like & does on the shell. So:
args = [python_path]
p = subprocess.Popen(args)
This will start a new Python interpreter that sits there running in the background, trying to use the same stdin/stdout/stderr as your parent. I'm not sure why you want that, but it's the same thing that using & in the shell would have done.

Actually I think there might be a solution to your problem, I found a useful solution at another question here.
This way subprocess.popen starts a new python shell instance and runs the second script from there. It worked perfectly for me on Windows 10.

You can try using screen command
with this command a new shell instance created and the current instance runs in the background.
# screen; python script1.py
After running above command, a new shell prompt will be seen where we can run another script and script1.py will be running in the background.
Hope it helps.

How to properly use PyDev with two different Python versions with scripts that are recalling other python scripts?

The story began with a very strange error while I was running my script from PyDev. Running the same script from outside will not encounter the same problem.
Fatal Python error: Py_Initialize: can't initialize sys standard streams
File "C:\Python26\lib\encodings\__init__.py", line 123
raise CodecRegistryError,\
^
SyntaxError: invalid syntax
This application has requested the Runtime to terminate it in an unusual way.
Please contact the application's support team for more information.
I was able to find why this is happening: In PyDev I use two different Python versions: 3.1 that is the default installation and 2.6 as the alternative one.
My Windows Environment does not contains PYTHONHOME, CLASSPATH, PYTHONPATH but PyDev does add them.
Now the problem is at one stage my python script does execute another python script using os.system(python second.py) and the second script will fail with the above error.
Now I'm looking to find a way to prevent this issue, issue that is happening because it will run the execute the default python using the settings for the non-default one (added by PyDev).
I do not want to change the standard call (python file.py) but I want to be able to run my script from pydev without problem and being able to use default or alternative python environment.
Any ideas?

I found a solution that seams acceptable specially because it will not interfere with running the scripts on other systems, just to run python -E second.py - this will force Python to ignore PYTHON* environment variables.

I may not be understanding this quite right, but I think you're invoking a script from pydev that works okay, but this script executes another script which requires a different version.
While this would unfortunately be installation-specific, you could use os.system("c:\absolute\path\to\proper\version\of\python.exe second.py").
If PyDev is setting up conflicting environmental variables, you may want to look into subprocess over os.system.
http://docs.python.org/library/subprocess.html#using-the-subprocess-module
This will allow you to invoke a process with a handle, so you can optionally wait for it to terminate. It will also allow you to pass environment variables upon execution.

I believe your call should be:
import sys
os.system(sys.executable+ ' second.py')
So that you guarantee you're using the same interpreter you're currently running and not launching the other one (or did you really mean to use the other interpreter?)

Run pdb without stdin/stdout using FIFO

I am developing FUSE filesystem with python. The problem is that after mounting a filesystem I have no access to stdin/stdout/stderr from my fuse script. I don't see anything, even tracebacks. I am trying to launch pdb like this:
import pdb
pdb.Pdb(None, open('pdb.in', 'r'), open('pdb.out', 'w')).set_trace()
All works fine but very inconvenient. I want to make pdb.in and pdb.out as fifo files but don't know how to connect it correctly. Ideally I want to type commands and see output in one terminal, but will be happy even with two terminals (in one put commands and see output in another). Questions:
1) Is it better/other way to run pdb without stdin/stdout?
2) How can I redirect stdin to pdb.in fifo (All what I type must go to pdb.in)? How can I redirect pdb.out to stdout (I had strange errors with "cat pdb.out" but maybe I don't understand something)

Ok. Exactly what I want, has been done in http://pypi.python.org/pypi/rpdb/0.1.1 .

Before starting the python app
mkfifo pdb.in
mkfifo pdb.out
Then when pdb is called you can interact with it using these two cat commands, one running in the background
cat pdb.out & cat > pdb.in
Note the readline support does not work (i.e. up arrow)

I just ran into a similar issue in a much simpler use-case:
debug a simple Python program running from the command line that had a file piped into sys.stdin, meaning, no way to use the console for pdb.
I ended up solving it by using wdb.
Quick rundown for my use-case. In the shell, install both the wdb server and the wdb client:
pip install wdb.server wdb
Now launch the wdb server with:
wdb.server.py
Now you can navigate to localhost:1984 with your browser and see an interface listing all Python programs running. The wdb project page above has instructions on what you can do if you want to debug any of these running programs.
As for a program under your control, you can you can debug it from the start with:
wdb myscript.py --script=args < and/stdin/redirection
Or, in your code, you can do:
import wdb; wdb.set_trace()
This will pop up an interface in your browser (if local) showing the traced program.
Or you can navigate to the wdb.server.py port to see all ongoing debugging sessions on top of the list of running Python programs, which you can then use to access the specific debugging session you want.
Notice that the commands for navigating the code during the trace are different from the standard pdb ones, for example, to step into a function you use .s instead of s and to step over use .n instead of n. See the wdb README in the link above for details.