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I have a list of full names (titled "FullNames") and I am trying to pull out the last names. The problem is that some of the full names include middle names (e.g., some of the items in the list are "Craig Nelson" while others are "Craig T. Nelson") which stops me from using a simple list comprehension statement such as:
LastNames = ([x.split()[1] for x in FullNames])
Instead, I am trying to loop through the list with this code:
LastNames = []
for item in FullNames:
if '.' in FullNames:
LastNames.appened(item[2])
else:
LastNames.append(item[1])
print(LastNames)
However, I am just getting a bunch of letters back:
['u', 'a', 'e', 'i', 'o', 'a', 't', 'h', 'r', 'e', 'e', 'r', 'e', 'h', 'a', 'i', 't', 'a', 'r', 'a', 'i', 'e', 'o', 'e', 'e', 'a', 'r', 'o', 'a', 'y', 'i', 'e', 'e', 'o', 'o', 'e', 'e', 'a', 'i', 'i', 'e', 'm', 'a', 'a', 'a', 'n', 'e', 'a', 'r']
Is there a simple way around this?
def get_last(name):
return name.split(' ')[-1].split('.')[-1]
full_names = ["Craig T. Nelson", "Craig Nelson"]
output = list(map(get_last, full_names))
print(output)
#['Nelson', 'Nelson']
I am trying to make code that breaks a password that I create, at first I got it to just make random answers to the password I created and eventually I would get the right one.
But I realized that if I could change the first letter of my answer and then when I had done all of the letters, change the second letter.
Ex: AA AB AC ... AY AZ BA BB BC.
I understand that I could make a loop to print every single letter, but how would I be able to change the first letter after I have gone through every letter.
I also need this to be able to break a password of any length so the loop would have to be able to change how many letters I need. I also need to get rid of the brackets and quotes in the output.
lower_upper_alphabet = ['a','b','c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
while done == 0:
for i in range (int(passwordlen)):
for i in range(52):
for i in range(len(lower_upper_alphabet)):
characters2 = []
characters2.append(str(lower_upper_alphabet[next1]))
next1 += 1
print(characters2)
Output:
["A"]
["B"]
["C"]
["D"]
["E"]
["F"]
["G"]
["H"]
["I"]
["J"]
["K"]
["L"]
["M"]
["N"]
["O"]
["P"]
["Q"]
["R"]
["S"]
["T"]
["U"]
["V"]
["W"]
["X"]
["Y"]
["Z"]
I want to write a really short script that will help me generate a random/nonsense word with the following qualities:
-Has 8 letters
-First letter is "A"
-Second and Fourth letters are random letters
-Fifth letter is a vowel
-Sixth and Seventh letters are random letters and are the same
-Eighth letter is a vowel that's not "a"
This is what I have tried so far (using all the info I could find and understand online)
firsts = 'A'
seconds = ['a','b','c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
thirds = ['a', 'e', 'i', 'o', 'u', 'y']
fourths = ['a','b','c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
fifths = ['a', 'e', 'i', 'o', 'u', 'y']
sixths = sevenths = ['a','b','c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
eighths = ['e', 'i', 'o', 'u', 'y']
print [''.join(first, second, third, fourth, fifth)
for first in firsts
for second in seconds
for third in thirds
for fourth in fourths
for fifth in fifths
for sixth in sixths
for seventh in sevenths
for eighth in eighths]
However it keeps showing a SyntaxError: invalid syntax after the for and now I have absolutely no idea how to make this work. If possible please look into this for me, thank you so much!
So the magic function you need to know about to pick a random letter is random.choice. You can pass a list into this function and it will give you a random element from that list. It also works with strings because strings are basically a list of chars. Also to make your life easier, use string module. string.ascii_lowercase returns all the letters from a to z in a string so you don't have to type it out. Lastly, you don't use loops to join strings together. Keep it simple. You can just add them together.
import string
from random import choice
first = 'A'
second = choice(string.ascii_lowercase)
third = choice(string.ascii_lowercase)
fourth = choice(string.ascii_lowercase)
fifth = choice("aeiou")
sixthSeventh = choice(string.ascii_lowercase)
eighth = choice("eiou")
word = first + second + third + fourth + fifth + sixthSeventh + sixthSeventh + eighth
print(word)
Try this:
import random
sixth=random.choice(sixths)
s='A'+random.choice(seconds)+random.choice(thirds)+random.choice(fourths)+random.choice(fifths)+sixth+sixth+random.choice(eighths)
print(s)
Output:
Awixonno
Ahiwojjy
etc
There are several things to consider. First, the str.join() method takes in an iterable (e.g. a list), not a bunch of individual elements. Doing
''.join([first, second, third, fourth, fifth])
fixes the program in this respect. If you are using Python 3, print() is a function, and so you should add parentheses around the entire list comprehension.
With the syntax out of the way, let's get to a more interesting problem: Your program constructs every (82255680 !) possible word. This takes a long time and memory. What you want is probably to just pick one. You can of course do this by first constructing all, then picking one at random. It's far cheaper though to pick one letter from each of firsts, seconds, etc. at random and then collecting these. All together then:
import random
firsts = ['A']
seconds = ['a','b','c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
thirds = ['a', 'e', 'i', 'o', 'u', 'y']
fourths = ['a','b','c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
fifths = ['a', 'e', 'i', 'o', 'u', 'y']
sixths = sevenths = ['a','b','c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
eighths = ['e', 'i', 'o', 'u', 'y']
result = ''.join([
random.choice(firsts),
random.choice(seconds),
random.choice(thirds),
random.choice(fourths),
random.choice(fifths),
random.choice(sixths),
random.choice(sevenths),
random.choice(eighths),
])
print(result)
To improve the code from here, try to:
Find a way to generate the "data" in a neater way than writing it out explicitly. As an example:
import string
seconds = list(string.ascii_lowercase) # you don't even need list()!
Instead of having a separate variable firsts, seconds, etc., collect these into a single variable, e.g. a single list containing each original list as a single str with all characters included.
This will implement what you describe. You can make the code neater by putting the choices into an overall list rather than have several different variables, but you will have to explicitly deal with the fact that the sixth and seventh letters are the same; they will not be guaranteed to be the same simply because there are the same choices available for each of them.
The list choices_list could contain sub-lists per your original code, but as you are choosing single characters it will work equally with strings when using random.choice and this also makes the code a bit neater.
import random
choices_list = [
'A',
'abcdefghijklmnopqrstuvwxyz',
'aeiouy',
'abcdefghijklmnopqrstuvwxyz',
'aeiouy',
'abcdefghijklmnopqrstuvwxyz',
'eiouy'
]
letters = [random.choice(choices) for choices in choices_list]
word = ''.join(letters[:6] + letters[5:]) # here the 6th letter gets repeated
print(word)
Some example outputs:
Alaeovve
Aievellu
Ategiwwo
Aeuzykko
Here's the syntax fix:
print(["".join([first, second, third])
for first in firsts
for second in seconds
for third in thirds])
This method might take up a lot of memory.
If I make list for e.g.
lst=['a','b','c','d','e','f','g','h','i','j','k','l','n','o','p','q','s','t','u','v','w','x','y','z']
I want a user to select input only from this given list
def select():
select=''
while guess not in ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'n', 'o', 'p', 'q', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']:
guess=input("select a letter? ")
return (select)
We can use this method but is there any other method so instead of putting the whole list we can put variable assign to that list
You need a while loop to ask the user get input till the input is valid like below:
In [1]: valid_input_lst=['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i',
...: 'j', 'k', 'l', 'n', 'o', 'p', 'q', 's', 't',
...: 'u', 'v', 'w', 'x', 'y', 'z']
In [2]:
In [2]: input_char = None
In [4]: while True:
...: print("Input:")
...: input_char = input()
...: if input_char in valid_input_lst:
...: break
...: print("The input is not valid..\n. It should be one of :{}".format(valid_input_lst))
...:
Input:
sy
The input is not valid..
. It should be one of :['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'n', 'o', 'p', 'q', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
Input:
x
You probably want something like this:
char = input('Enter a character')
if char not in list:
print("not a valid character")
You can't deny the user from entering anything, you should write software that knows how to handle the possible input.
get inquirer using pip:
pip install inquirer
here is an example
import inquirer
options = [
inquirer.List("option",
message="Select an option ",
choices=["A","B","C","D"],
),
]
select = inquirer.prompt(options)
#you can print option using 'select' variable
I have to print letters from an array backwards. I got all the letters to be backwards but I realized I used the sort method and I'm not allowed to use it. I can't figure out any other way. Any suggestions?
The output should be:
w
v
u
t
.
.
.
g
f
This is the code I have so far:
letter = ['f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w']
letter.sort(reverse=True)
for i in range(len(letter)):
print(letter[i])
letter = ['f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w']
letter[::-1]
OR
reverseletter=letter[::-1]
letters = 'fghijklmnopqrstuvw'
for letter in reversed(letters):
print(letter)
Strings work like lists. A string is a list of characters.
reversed() can be used to reverse the order of a list.
There is no need to use range()
you can use use the built-in function reversed :
print(*reversed(letter), sep='\n')
output:
w
v
u
t
s
r
q
p
o
n
m
l
k
j
i
h
g
f
*reversed(letter) will give as non-keyword arguments all the
letters in reverse order for the print built-in function
the keyword argument sep='\n' will ensure that all the letters will be printed on a separate line
To reverse a list you can use.
Slicing [::-1]
for i in letters[::-1]:
print(i)
You can use reversed.
for i in reversed(letter):
print(i)
Note: reversed spits an iterator.
you can use revered() method to print it in reverse order such as below
letter = ['f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w']
for i in reversed(letter):
print(i)
letterrev=letter[::-1]
for i in letterrev:
print(i)
use this one
You can directly use list indexing or slicing such as:
letter = ['f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w']
print(letter[::-1])