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convert string date to another string date

from datetime import datetime
y='Monday, December 9, 2019'
I want to convert the above string to DD/MM/YYYY I tried
c=datetime.strptime(y,'%A, %B %-d,%Y')
so I can then easily convert it but it is giving me ValueError: '-' is a bad directive in format '%A, %B %-d,%Y I checked this question
'-' is a bad directive in format '%Y-%-m-%-d' - python/django but still gives error, is there a way to do this without using re ?

The correct format is '%A, %B %d, %Y' (noticed the removed -), and to change it to DD/MM/YYYY, the format is %d-%m-%Y'
from datetime import datetime
y='Monday, December 9, 2019'
#Fixed format
c=datetime.strptime(y,'%A, %B %d, %Y')
#Changed to represent DD/MM/YYYY
print(c.strftime('%d-%m-%Y'))
The output will be
09-12-2019

Convert string to DateTime for mysql in python

I want to convert my date into DateTime object for MySQL.
My string format is: Mon Aug 27 04:47:45 +0000 2018
Expected Output: 'YYYY-M-D H:mm:ss'

from datetime import datetime
t = datetime.strptime('Mon Aug 27 04:47:45 +0000 2008', '%a %b %d %H:%M:%S % z %Y')
t.strftime('%Y-%m-%d %H:%M:%S')
Refer section 8.1.8
here

If you are using python 3, this solution would work -
from datetime import datetime
x = 'Mon Aug 27 04:47:45 +0000 2018'
x = datetime.strftime(datetime.strptime(x, '%a %b %d %I:%M:%S %z %Y'), '%Y-%m-%d %H:%M:%S')
# OP '2018-08-27 04:47:45'
But for python 2, you might get a ValueError: 'z' is a bad directive.... In that case, you'll either have to use something like pytz or dateutil. The table that you need to look for all these conversions can be found here
Edit: You can't have Expected Output: 'YYYY-M-D H:mm:ss' if you convert your datetime string to datetime object. Datetime object has it's own format. Above gives you a string of the format that you want

from datetime import datetime
date_as_dt_object = datetime.strptime(dt, '%a %b %d %H:%M:%S %z %Y')
You can use date_as_dt_object in a raw query or an ORM. If used in a raw query pass it as a string like:
query = "select * from table where date >" + str(date_as_dt_object)
Check out this list for Python's strftime directives.
http://strftime.org/

get hours from full date date to python3

I work with api in python3 in this api return date like this
'Jun 29, 2018 12:44:14 AM'
but i need just hours, minute ad second like this
12:44:14
are there a fonction that can format this

It looks like the output is a string. So, you can use string slicing:
x = 'Jun 29, 2018 12:44:18 AM'
time = x[-11:-3]
It's best to use negative indexing here because the day may be single-digit or double-digit, so a solution like time = x[13:21] won't work every time.
If you're inclined, you may wish to use strptime() and strftime() to take your string, convert it into a datetime object, and then convert that into a string in HH:MM:SS format. (You may wish to consult the datetime module documentation for this approach).

Use the datetime module. Use .strptime() to convert string to datetime object and then .strftime() to convert to your required string output. Your sample datetime string is represented as '%b %d, %Y %H:%M:%S %p'
Ex:
import datetime
s = 'Jun 29, 2018 12:44:14 AM'
print( datetime.datetime.strptime(s, '%b %d, %Y %H:%M:%S %p').strftime("%H:%M:%S") )
Output:
12:44:14

Format Unicode time value

I have next time value in unicode (<type 'unicode'>):
2017-08-09T15:02:58+0000.
How to convert it to friendly view (e.g. Day, Month of Year)?

This should do what you ask:
from datetime import datetime
a = '2017-08-09T15:02:58+0000'
datetime.strptime(a[:-5], '%Y-%m-%dT%H:%M:%S').strftime('%d, %b of %Y')
#09, Aug of 2017
strptime method throws error for timezone parameter that doesn't seem to interest you so I removed that part with a[:-5].
For the rest of the string you can just follow guidelines from datetime docs.
Using the same docs you can construct your datetime string using strftime() method like you wanted '%d, %b of %Y' or in plain words [day], [abbreviated month] of [Year]

try this
import datetime
today = datetime.date.today()
print today.strftime('We are the %d, %b %Y')
'We are the 22, Nov 2008'

how to converting sting into dateobject for date comparison?

I am facing trouble while converting string into dateobject in python.
I want to convert string '10 JAN 2016" to dateobject so that i can compare it to the present date and get the time difference.
I tired but i am getting formatting error.What is the solution to this problem?

Use the datetime module.
import datetime
date = datetime.datetime.strptime('10 jan 2016`,'%d %b %Y').date()
difference_in_dates = date - datetime.date.today() #this returns a timedelta object
Use datetime.timedelta objects for comparison.
You can look up the documentation about the formats (%d, %m, etc.) here

You need to use a valid format.
Try looking here: https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior
dt = '10 JAN 2016'
dtime = datetime.datetime.strptime(dt, "theformat")