I am facing trouble while converting string into dateobject in python.
I want to convert string '10 JAN 2016" to dateobject so that i can compare it to the present date and get the time difference.
I tired but i am getting formatting error.What is the solution to this problem?
Use the datetime module.
import datetime
date = datetime.datetime.strptime('10 jan 2016`,'%d %b %Y').date()
difference_in_dates = date - datetime.date.today() #this returns a timedelta object
Use datetime.timedelta objects for comparison.
You can look up the documentation about the formats (%d, %m, etc.) here
You need to use a valid format.
Try looking here: https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior
dt = '10 JAN 2016'
dtime = datetime.datetime.strptime(dt, "theformat")
Related
Does anyone know how I can extract the end 6 characters in a absoloute URL e.g
/es/ideas-de-trading-y-noticias/el-ibex-35-insiste-en-buscar-los-7900-puntos-a-la-espera-de-las--221104
This is not a typical URL sometimetimes it ends -221104
Also, is there a way to turn 221104 into the date 04 11 2022 easily?
Thanks in advance
Mark
You should use the datetime module for parsing strings into datetimes, like so.
from datetime import datetime
url = 'https://www.ig.com/es/ideas-de-trading-y-noticias/el-ibex-35-insiste-en-buscar-los-7900-puntos-a-la-espera-de-las--221104'
datetime_string = url.split('--')[1]
date = datetime.strptime(datetime_string, '%y%m%d')
print(f"{date.day} {date.month} {date.year}")
the %y%m%d text tells the strptime method that the string of '221104' is formatted in the way that the first two letters are the year, the next two are the month, and the final two are the day.
Here is a link to the documentation on using this method:
https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior
If the url always has this structure (that is it has the date at the end after a -- and only has -- once), you can get the date with:
str_date = str(url).split("--")[1]
Relaxing the assumption to have only one --, we can have the code working by just taking the last element of the splitted list (again assuming the date is always at the end):
str_date = str(url).split("--")[-1]
(Thanks to #The Myth for pointing that out)
To convert the obtained date into a datetime.date object and get it in the format you want:
from datetime import datetime
datetime_date = datetime.strptime(str_date, "%y%m%d")
formatted_date = datetime_date.strftime("%d %m %Y")
print(formatted_date) # 04 11 2022
Docs:
strftime
strptime
behaviour of the above two functions and format codes
Taking into consideration the date is constant in the format yy-mm-dd. You can split the URL by:
url = "https://www.ig.com/es/ideas-de-trading-y-noticias/el-ibex-35-insiste-en-buscar-los-7900-puntos-a-la-espera-de-las--221104"
time = url[-6:] # Gets last 6 values
To convert yy-mm-dd into dd mm yy we will use the DateTime module:
import datetime as dt
new_time = dt.datetime.strptime(time, '%y%m%d') # Converts your date into datetime using the format
format_time = dt.datetime.strftime(new_time, '%d-%m-%Y') # Format
print(format_time)
The whole code looks like this:
url = "https://www.ig.com/es/ideas-de-trading-y-noticias/el-ibex-35-insiste-en-buscar-los-7900-puntos-a-la-espera-de-las--221104"
time = url[-6:] # Gets last 6 values
import datetime as dt
new_time = dt.datetime.strptime(time, '%y%m%d') # Converts your date into datetime using the format
format_time = dt.datetime.strftime(new_time, '%d %m %Y') # Format
print(format_time)
Learn more about datetime
You can use python built-in split function.
date = url.split("--")[1]
It gives us 221104
then you can modify the string by rearranging it
date_string = f"{date[4:6]} {date[2:4]} {date[0:2]}"
this gives us 04 11 22
Assuming that -- will only be there as it is in the url you posted, you can do something as follows:
You can split the URL at -- & extract the element
a = 'https://www.ig.com/es/ideas-de-trading-y-noticias/el-ibex-35-insiste-en-buscar-los-7900-puntos-a-la-espera-de-las--221104'
desired_value = a.split('--')[1]
& to convert:
from datetime import datetime
converted_date = datetime.strptime(desired_value , "%y%m%d")
formatted_date = datetime.strftime(converted_date, "%d %m %Y")
I have a dataset which contains some columns with datetime. My problem is, I found this type datetime format:
Apr'11
Apr-11
Apr 11
How can I automatically change this format to be datetime format?
for you can use datetime module
from datetime import datetime
this is the link if you want any confusion
date_string = "Apr'11"
date = datetime.strptime(date_string, "%b'%d")
%b = Locale’s abbreviated month name. (like Apr, Mar, Jan, etc)
%d = Day of the month as a decimal number [01,31]
date_string_2 = "Apr-11"
date = datetime.strptime(date_string, "%b-%d")
date_string_3 = "Apr 11"
date = datetime.strptime(date_string, "%b %d")
You should write this "%b %d" same as like date_string otherwise it will give you, even if you give an extra space.
go to this link to learn more about this:
https://docs.python.org/3/library/time.html
This is the data that is being returned from my API:
"Jun 02, 2021, 2 PMEST"
If I'm within 7 days of the current date which I'm getting by doing this:
from datetime import date
today = date.today()
print("Today's date:", today)
Just need to convert Jun to a number and 02 and compare to see if it's within 7 days in the future of the current date, then return True
APPROACH 0:
Given the format of your example data, you should be able to convert it to a datetime using this code:
datetime.strptime("Jun 02, 2021, 2 PMEST", "%b %d, %Y, %I %p%Z")
The details about this format string are here: https://docs.python.org/3/library/datetime.html#strftime-strptime-behavior
However, when I tested this locally, it worked for this input:
"Jun 02, 2021, 2 PMUTC"
but not for your input (which has different timezone):
"Jun 02, 2021, 2 PMEST"
I have investigated this some more and "read the docs" (https://docs.python.org/3/library/time.html).
To get EST parsing to work, you would have to change your OS timezone and reset the time module's timezones like this:
from datetime import datetime
import os
import time
os.environ["TZ"] = "US/Eastern". # change timezone
time.tzset(). # reset time.tzname tuple
datetime.strptime("Jun 02, 2021, 2 PMEST", "%b %d, %Y, %I %p%Z")
When you're done, be safe and delete the "hacked" environment variable:
del os.environ["TZ"]
Note - Since your system timezone is presumably still UTC, it can still parse UTC timezone too.
See this thread for detailed discussion: https://bugs.python.org/issue22377
Also note that the timestamp is not actually captured. The result you get with EST and UTC is a naive datetime object.
APPROACH 1
So, it seems like there is a better way to approach this.
First, you need to pip install dateutils if you don't already have it.
THen do something like this:
from dateutil import parser
from dateutil.tz import gettz
tzinfos = {"EST": gettz("US/Eastern")}
my_datetime = parser.parse("Jun 02, 2021, 2 PM EST", tzinfos=tzinfos)
What's happening here is we use gettz to get timezone information from the timezones listed in usr/share/zoneinfo. Then the parse function can (fuzzy) parse your string (no format needs to be specified!) and returns my_datetime which has timezone information on it. Here are the parser docs: https://dateutil.readthedocs.io/en/stable/parser.html
I don't know how many different timezones you need to deal with so the rest is up to you. Good luck.
Convert the date to a datetime structure and take the direct difference. Note that today must be a datetime, too.
import datetime
date_string = "Jun 02, 2021, 2 PMEST"
today = datetime.datetime.today()
date = datetime.datetime.strptime(date_string,
"%b %d, %Y, %I %p%Z") # Corrected
(date - today).days
#340
I have next time value in unicode (<type 'unicode'>):
2017-08-09T15:02:58+0000.
How to convert it to friendly view (e.g. Day, Month of Year)?
This should do what you ask:
from datetime import datetime
a = '2017-08-09T15:02:58+0000'
datetime.strptime(a[:-5], '%Y-%m-%dT%H:%M:%S').strftime('%d, %b of %Y')
#09, Aug of 2017
strptime method throws error for timezone parameter that doesn't seem to interest you so I removed that part with a[:-5].
For the rest of the string you can just follow guidelines from datetime docs.
Using the same docs you can construct your datetime string using strftime() method like you wanted '%d, %b of %Y' or in plain words [day], [abbreviated month] of [Year]
try this
import datetime
today = datetime.date.today()
print today.strftime('We are the %d, %b %Y')
'We are the 22, Nov 2008'
I have a timestamp like:
2014-01-01T05:00:00.000Z
How do I convert this so that I can easily get the month like "January"? And in general convert it to a nice format like:
January 1st, 2014
You can use datetime module. datetime.datetime expects a time string and its formatting and returns a datetime.datetime object, on which you can call strftime() to format it according to your needs.
>>> import datetime
>>> my_date = datetime.datetime.strptime("2014-01-01T05:00:00.000Z", "%Y-%m-%dT%H:%M:%S.%fZ")
>>> my_date.strftime('%d.%m.%Y')
01.01.2014
>>> date.strftime('%H:%M:%S %d.%m.%Y')
'05:00:00 01.01.2014'
There is also a python-dateutils module, which can do the same.
The strftime() method in datetime modulecan achieve this. It expects a string pattern explaining how you want to format your date.
import datetime
today = datetime.date.today()
print today.strftime('It is %d %b %Y')
The above code prints something like "It is 12 Nov 2015"
You can find more format codes at https://docs.python.org/2/library/datetime.html#strftime-and-strptime-behavior