python newbie here, I'm currently learning about nested functions in python. I'm having a particularly hard time understanding code from the example below. Particularly, at the bottom of the script, when you print echo(2)("hello") - how does the inner_function know to take that string "hello" as its argument input? in my head, I'd think you would have to pass the string as some sort of input to the outer function (echo)? Simply placing the string in brackets adjacent to the call of the outer function just somehow works? I can't seem to wrap my head around this..
-aspiring pythonista
# Define echo
def echo(n):
"""Return the inner_echo function."""
# Define inner_echo
def inner_echo(word1):
"""Concatenate n copies of word1."""
echo_word = word1 * n
return echo_word
# Return inner_echo
return inner_echo
# Call twice() and thrice() then print
print(echo(2)('hello'), echo(3)('hello'))
The important thing here is that in Python, functions themselves are objects, too. Functions can return any type of object, so functions can in principle also return functions. And this is what echo does.
So, the output of your function call echo(2) is again a function and echo(2)("hello") evaluates that function - with "hello" as an input argument.
Maybe it is easier to understand that concept if you would split that call into two lines:
my_function_object = echo(2) # creates a new function
my_function_object("hello") # call that new function
EDIT
Perhaps this makes it clearer: If you spell out a function name without the brackets you are dealing with the function as an object. For example,
x = numpy.sqrt(4) # x is a number
y = numpy.sqrt # y is a function object
z = y(4) # z is a number
Next, if you look at the statement return echo_word in the echo function, you will notice that what is returned is the inner function (without any brackets). So it is a function object that is returned by echo. You can check that also with print(echo(2))
Related
In Python, is there a way to call a function without parentheses?
like
account.add 3000
I want to code a quick app and use it on a Python shell window, and I think it should save time to input values without those parentheses.
You can make use of the eval function in python to convert a string to a function call:
def fun(function, value):
eval(function + f'({value})')
def add(value):
x = value
print(x)
x,y = input().split()
fun(x,y)
Here we take x and y as inputs from the user.
x denotes the function to be called and y acts as the parameter.
Then we simply call eval and passing it a string to evaluate consisting of the function call as it was with parenthesis.
You can simply put this code in an infinite loop to be able to continuously evaluate functions in this way.
I'm trying to store a function in a list, retrieve the function from the list later, and then call on that function. This is basically what I want to do, without any specifics. It doesn't show my purpose, but it's the same issue.
elements: list = [] # List meant to contain a tuple with the name of the item and the function of the item.
def quit_code():
exit()
element.append(("quit", quit_code))
Now, somewhere else in the code, I want to be able to use an if statement to check the name of the item and, if it's the right one at that time, run the function.
user_input = "quit" # For brevity, I'm just writing this. Let's just imagine the user actually typed this.
if elements[0][0] == user_input:
#This is the part I don't understand so I'm just going to make up some syntax.
run_method(elements[0][1])
The method run_method that I arbitrarily made is the issue. I need a way to run the method returned by elements[0][1], which is the quit_code method. I don't need an alternative solution to this example because I just made it up to display what I want to do. If I have a function or object that contains a function, how can I run that function.
(In the most simplified way I can word it) If I have object_a (for me it's a tuple) that contains str_1 and fun_b, how can I run fun_b from the object.
To expand on this a little more, the reason I can't just directly call the function is because in my program, the function gets put into the tuple via user input and is created locally and then stored in the tuple.
__list_of_stuff: list = []
def add_to_list(name, function):
__list_of_stuff.append((name, function))
And then somewhere else
def example_init_method():
def stop_code():
exit()
add_to_list("QUIT", stop_code())
Now notice that I can't access the stop_code method anywhere else in the code unless I use it through the __list_of_stuff object.
Finally, It would be nice to not have to make a function for the input. By this, I mean directly inserting code into the parameter without creating a local function like stop_code. I don't know how to do this though.
Python treats functions as first-class citizens. As such, you can do things like:
def some_function():
# do something
pass
x = some_function
x()
Since you are storing functions and binding each function with a word (key), the best approach would be a dictionary. Your example could be like this:
def quit_code():
exit()
operations = dict(quit=quit_code)
operations['quit']()
A dictionary relates a value with a key. The only rule is the key must be immutable. That means numbers, strings, tuples and other immutable objects.
To create a dictionary, you can use { and }. And to get a value by its key, use [ and ]:
my_dictionary = { 'a' : 1, 'b' : 10 }
print(my_dictionary['a']) # It will print 1
You can also create a dictionary with dict, like so:
my_dictionary = dict(a=1, b=10)
However this only works for string keys.
But considering you are using quit_code to encapsulate the exit call, why not using exit directly?
operations = dict(quit=exit)
operations['quit']()
If dictionaries aren't an option, you could still use lists and tuples:
operations = [('quit',exit)]
for key, fun in operations:
if key == 'quit':
fun()
I'm relatively new to Python and I have a (I guess) pretty basic question on functions in Python.
I'm rewatching basics tutorials in order to really understand more of the structures and not just use them. I used some basic code from a tutorial and tried different simple variations and I don't fully understand the outcomes and when a function is being referred to, i.e. when its return value is being called for, and when it's being executed.
x=6
def example():
globx = x
print(globx)
globx+=5
print(globx)
example()
This defines the function and afterwards calls for it to be executed and as it's being executed it prints 6 and then prints 11, as expected.
Now:
x=6
def example():
globx = x
print(globx)
globx+=5
print(globx)
print(example())
I would have expected this to print "None" since print is looking for a return value of the function to print it but example() doesn't return a value. Instead 6, 11 and None are being printed. So I assume print(example()) calls for example()'s return value to print it but before also executes the function. (Please correct me if I got that wrong.).
Even when I'm just assigning the return value to a variable x = example() after the definition of the function, it will also execute the function and print 6 and then 11.
x=6
def example():
globx = x
print(globx)
globx+=5
print(globx)
x = example()
Is a function always being executed when it's written out? (Ecxcept in the def)
Is there a way to make use of a functions return value without it being fully executed?
For example if I had a more complex code and at some point I want to make use of a functions return value but don't want it to be run.
Thanks in advance!
What you say seems overall correct, even if it seems off what you expected.
Generally, you can see it as, when the function has parentheses at the end, i.e. example(), the function is executed.
Your last question is a bit vague, but you can stop executing the function at some point by using the return keyword inside the function. This makes sense in e.g. a function that performs some resource-intensive calculations, but occasionally there's a chance to take a shortcut.
As an example
def calculate_thing(shortcut = False):
if shortcut:
return 3
# Resource-intensive, time-consuming calculations go here
return result_of_calculations
Calling this function with calculate_thing(shortcut=True) will quickly return 3, because the function stops executing when we hit return 3. On the other hand, calling it by calculate_thing(shortcut=False) or calculate_thing() (False is the default value for shortcut) will make the function run for a while, doing some calculations, and then it returns whatever value was assigned to the variable result_of_calculations.
You are getting confused by what a function returns and what a function does.
In your case you have a function which has two print() statements. Those statements have nothing to do with the value that the function will return and will print their corresponding values on every invocation of the function example().
The return value of the function is defined using the return keyword and if it is not defined then it is None. Obviously the function needs to be executed in order to get it to return a value.
A function does something, it literally performs a function. If you want that function to show you results as it's doing its job, you can print() things. If you just want it to do its job and save the results for later, you return them to a variable that calls the function. You can do both!
def just_print(input):
print('Here is a function printing!', input)
just_print('cool!')
>> 'Here is a function printing!', 'cool!'
def return_value(input):
return 'Hello ' + input
# We can store the return for future use
save_return_val = return_value('Ari')
print(save_return_val)
>> 'Hello Ari'
# Just print it
print(return_value('Ari'))
>> 'Hello Ari'
I've heard that python functions are objects, similar to lists or dictionaries, etc. However, what would be a similar way of performing this type of action with a function?
# Assigning empty list to 'a'
a = list()
# Assigning empty function to 'a'
a = lambda: pass
# ???
How would you do this? Further, is it necessary or proper?
Here is the sense in which I would like to use it for better context:
I have a QListWidget for selecting items which are associated with keys in a dictionary. The values in this dictionary are also dictionaries, which hold certain properties of the items, which I can add. These certain properties are stored as keys, and the values in them are initialized or updated by calling different functions. So, I'm storing a variable in the window which gets updated when a button is pressed to tell this script which property to update.
As you can see, I would like to store the function to map to the data using the correct function based on the situation.
# Get selection from the list
name = selected_item
# Initialize an empty function
f = lambda: pass
# Use property that is being added now, which was updated by the specific button that was pushed
property_list = items[name][self.property_currently_being_added]
if self.property_currently_being_added == "prop1":
f = make_property1()
elif self.property_currently_being_added == "prop2":
f = make_property2()
elif self.property_currently_being_added == "prop3":
f = make_property3()
elif self.property_currently_being_added == "prop4":
f = make_property4()
# map the certain function to the data which was retrieved earlier
added_property = map(f, data)
property_list.append(added_property)
First, the reason this doesn't work:
a = lamdba: pass
… is that lambda only allows an expression, and defines a function that returns the value of the expression. Since pass is a statement, not an expression, this is illegal.
However, this works just fine:
a = lambda: None
In Python, a function that falls off the end without a return statement always returns None. So, these are equivalent:
def a(): return None
def a(): pass
However, I don't see why you want to write this as a lambda and an assignment anyway; the def is shorter, and more readable, and gives you an introspectable function object with a nice name (a instead of <lambda>), and so on. The only reasons to ever use lambda are when you don't want to give the function a name, or when you need to define the function inside an expression. Obviously neither of those are true, because you use the lambda directly inside an assignment statement. So, just use def.
Meanwhile, this is in a sense an "empty function", or at least as empty as possible (as you can see by, e.g., calling dis.dis(a), it still takes two bytecodes to do nothing but fall off the end and return None), but it's not useful for your case. You don't want an "empty function". If you try passing your a to map, you're just going to get a TypeError, because you're trying to call a function of no arguments with one argument. (Because that's what map does.)
What you might want is an identity function, which just returns its argument as-is. Like this:
def a(x): return x
But I'm not sure that's what you want. Did you want to append data as-is in that case? Or did you want to do something different, like return early, or raise an exception, or not append anything, or …?
Finally, I don't see why you want a function at all. Why not just not call map if you have nothing to map? You have a perfectly good else clause that already catches that case (especially handy if what you want to do is return early or raise…). Or, if you prefer, you can start with f = None, and then use an if f: do decide whether to map or not. Or, if you really want:
added_property = [f(element) if f else element for element in data]
… or …
added_property = map(f, data) if f else data
As one last note, instead of a long if/elif chain that repeats the same thing over and over again, you might want a dict:
propfuncs = {'prop1': make_property1(),
'prop2': make_property2(),
'prop3': make_property3(),
'prop4': make_property4()}
Then, all that cruft turns into these two lines:
f = propfuncs.get(self.property_currently_being_added)
added_property = map(f, data) if f else data
Or course an even better design might be to replace all those make_propertyN functions with a single function that you call as make_property(1) or make_property('prop1')… but without seeing what they actually do, I can't be sure of that.
For completeness and since the title is "empty function object in python", more general case is an empty function object that takes any number of parameters, so you can use it in any callback. It's this one:
callback = lambda *_, **__: None
Explanation is here: http://echochamber.me/viewtopic.php?t=64825
I am surprised to learn that you can even do...
def a(): "This is a test"
a()
this feels so much like you're looking for a Nothing functor, I am guessing that if you had knowledge of Monads you wouldn't even need an empty function , as inspiration PyMonad has a nice Nothing implementation, I usually like to create my own, but it's a good starting point.
I have been working at learning Python over the last week and it has been going really well, however I have now been introduced to custom functions and I sort of hit a wall. While I understand the basics of it, such as:
def helloworld():
print("Hello World!")
helloworld()
I know this will print "Hello World!".
However, when it comes to getting information from one function to another, I find that confusing. ie: function1 and function2 have to work together to perform a task. Also, when to use the return command.
Lastly, when I have a list or a dictionary inside of a function. I'll make something up just as an example.
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
How would I access the key/value and be able to change them from outside of the function? ie: If I had a program that let you input/output player stats or a character attributes in a video game.
I understand bits and pieces of this, it just confuses me when they have different functions calling on each other.
Also, since this was my first encounter with the custom functions. Is this really ambitious to pursue and this could be the reason for all of my confusion? Since this is the most complex program I have seen yet.
Functions in python can be both, a regular procedure and a function with a return value. Actually, every Python's function will return a value, which might be None.
If a return statement is not present, then your function will be executed completely and leave normally following the code flow, yielding None as a return value.
def foo():
pass
foo() == None
>>> True
If you have a return statement inside your function. The return value will be the return value of the expression following it. For example you may have return None and you'll be explicitly returning None. You can also have return without anything else and there you'll be implicitly returning None, or, you can have return 3 and you'll be returning value 3. This may grow in complexity.
def foo():
print('hello')
return
print('world')
foo()
>>>'hello'
def add(a,b):
return a + b
add(3,4)
>>>7
If you want a dictionary (or any object) you created inside a function, just return it:
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
return my_dict
d = my_function()
d['Key1']
>>> Value1
Those are the basics of function calling. There's even more. There are functions that return functions (also treated as decorators. You can even return multiple values (not really, you'll be just returning a tuple) and a lot a fun stuff :)
def two_values():
return 3,4
a,b = two_values()
print(a)
>>>3
print(b)
>>>4
Hope this helps!
The primary way to pass information between functions is with arguments and return values. Functions can't see each other's variables. You might think that after
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
my_function()
my_dict would have a value that other functions would be able to see, but it turns out that's a really brittle way to design a language. Every time you call my_function, my_dict would lose its old value, even if you were still using it. Also, you'd have to know all the names used by every function in the system when picking the names to use when writing a new function, and the whole thing would rapidly become unmanageable. Python doesn't work that way; I can't think of any languages that do.
Instead, if a function needs to make information available to its caller, return the thing its caller needs to see:
def my_function():
return {"Key1":"Value1",
"Key2":"Value2",
"Key3":"Value3",
"Key4":"Value4",}
print(my_function()['Key1']) # Prints Value1
Note that a function ends when its execution hits a return statement (even if it's in the middle of a loop); you can't execute one return now, one return later, keep going, and return two things when you hit the end of the function. If you want to do that, keep a list of things you want to return and return the list when you're done.
You send information into and out of functions with arguments and return values, respectively. This function, for example:
def square(number):
"""Return the square of a number."""
return number * number
... recieves information through the number argument, and sends information back with the return ... statement. You can use it like this:
>>> x = square(7)
>>> print(x)
49
As you can see, we passed the value 7 to the function, and it returned the value 49 (which we stored in the variable x).
Now, lets say we have another function:
def halve(number):
"""Return half of a number."""
return number / 2.0
We can send information between two functions in a couple of different ways.
Use a temporary variable:
>>> tmp = square(6)
>>> halve(tmp)
18.0
use the first function directly as an argument to the second:
>>> halve(square(8))
32.0
Which of those you use will depend partly on personal taste, and partly on how complicated the thing you're trying to do is.
Even though they have the same name, the number variables inside square() and halve() are completely separate from each other, and they're invisible outside those functions:
>>> number
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'number' is not defined
So, it's actually impossible to "see" the variable my_dict in your example function. What you would normally do is something like this:
def my_function(my_dict):
# do something with my_dict
return my_dict
... and define my_dict outside the function.
(It's actually a little bit more complicated than that - dict objects are mutable (which just means they can change), so often you don't actually need to return them. However, for the time being it's probably best to get used to returning everything, just to be safe).