I've heard that python functions are objects, similar to lists or dictionaries, etc. However, what would be a similar way of performing this type of action with a function?
# Assigning empty list to 'a'
a = list()
# Assigning empty function to 'a'
a = lambda: pass
# ???
How would you do this? Further, is it necessary or proper?
Here is the sense in which I would like to use it for better context:
I have a QListWidget for selecting items which are associated with keys in a dictionary. The values in this dictionary are also dictionaries, which hold certain properties of the items, which I can add. These certain properties are stored as keys, and the values in them are initialized or updated by calling different functions. So, I'm storing a variable in the window which gets updated when a button is pressed to tell this script which property to update.
As you can see, I would like to store the function to map to the data using the correct function based on the situation.
# Get selection from the list
name = selected_item
# Initialize an empty function
f = lambda: pass
# Use property that is being added now, which was updated by the specific button that was pushed
property_list = items[name][self.property_currently_being_added]
if self.property_currently_being_added == "prop1":
f = make_property1()
elif self.property_currently_being_added == "prop2":
f = make_property2()
elif self.property_currently_being_added == "prop3":
f = make_property3()
elif self.property_currently_being_added == "prop4":
f = make_property4()
# map the certain function to the data which was retrieved earlier
added_property = map(f, data)
property_list.append(added_property)
First, the reason this doesn't work:
a = lamdba: pass
… is that lambda only allows an expression, and defines a function that returns the value of the expression. Since pass is a statement, not an expression, this is illegal.
However, this works just fine:
a = lambda: None
In Python, a function that falls off the end without a return statement always returns None. So, these are equivalent:
def a(): return None
def a(): pass
However, I don't see why you want to write this as a lambda and an assignment anyway; the def is shorter, and more readable, and gives you an introspectable function object with a nice name (a instead of <lambda>), and so on. The only reasons to ever use lambda are when you don't want to give the function a name, or when you need to define the function inside an expression. Obviously neither of those are true, because you use the lambda directly inside an assignment statement. So, just use def.
Meanwhile, this is in a sense an "empty function", or at least as empty as possible (as you can see by, e.g., calling dis.dis(a), it still takes two bytecodes to do nothing but fall off the end and return None), but it's not useful for your case. You don't want an "empty function". If you try passing your a to map, you're just going to get a TypeError, because you're trying to call a function of no arguments with one argument. (Because that's what map does.)
What you might want is an identity function, which just returns its argument as-is. Like this:
def a(x): return x
But I'm not sure that's what you want. Did you want to append data as-is in that case? Or did you want to do something different, like return early, or raise an exception, or not append anything, or …?
Finally, I don't see why you want a function at all. Why not just not call map if you have nothing to map? You have a perfectly good else clause that already catches that case (especially handy if what you want to do is return early or raise…). Or, if you prefer, you can start with f = None, and then use an if f: do decide whether to map or not. Or, if you really want:
added_property = [f(element) if f else element for element in data]
… or …
added_property = map(f, data) if f else data
As one last note, instead of a long if/elif chain that repeats the same thing over and over again, you might want a dict:
propfuncs = {'prop1': make_property1(),
'prop2': make_property2(),
'prop3': make_property3(),
'prop4': make_property4()}
Then, all that cruft turns into these two lines:
f = propfuncs.get(self.property_currently_being_added)
added_property = map(f, data) if f else data
Or course an even better design might be to replace all those make_propertyN functions with a single function that you call as make_property(1) or make_property('prop1')… but without seeing what they actually do, I can't be sure of that.
For completeness and since the title is "empty function object in python", more general case is an empty function object that takes any number of parameters, so you can use it in any callback. It's this one:
callback = lambda *_, **__: None
Explanation is here: http://echochamber.me/viewtopic.php?t=64825
I am surprised to learn that you can even do...
def a(): "This is a test"
a()
this feels so much like you're looking for a Nothing functor, I am guessing that if you had knowledge of Monads you wouldn't even need an empty function , as inspiration PyMonad has a nice Nothing implementation, I usually like to create my own, but it's a good starting point.
Related
I'm trying to store a function in a list, retrieve the function from the list later, and then call on that function. This is basically what I want to do, without any specifics. It doesn't show my purpose, but it's the same issue.
elements: list = [] # List meant to contain a tuple with the name of the item and the function of the item.
def quit_code():
exit()
element.append(("quit", quit_code))
Now, somewhere else in the code, I want to be able to use an if statement to check the name of the item and, if it's the right one at that time, run the function.
user_input = "quit" # For brevity, I'm just writing this. Let's just imagine the user actually typed this.
if elements[0][0] == user_input:
#This is the part I don't understand so I'm just going to make up some syntax.
run_method(elements[0][1])
The method run_method that I arbitrarily made is the issue. I need a way to run the method returned by elements[0][1], which is the quit_code method. I don't need an alternative solution to this example because I just made it up to display what I want to do. If I have a function or object that contains a function, how can I run that function.
(In the most simplified way I can word it) If I have object_a (for me it's a tuple) that contains str_1 and fun_b, how can I run fun_b from the object.
To expand on this a little more, the reason I can't just directly call the function is because in my program, the function gets put into the tuple via user input and is created locally and then stored in the tuple.
__list_of_stuff: list = []
def add_to_list(name, function):
__list_of_stuff.append((name, function))
And then somewhere else
def example_init_method():
def stop_code():
exit()
add_to_list("QUIT", stop_code())
Now notice that I can't access the stop_code method anywhere else in the code unless I use it through the __list_of_stuff object.
Finally, It would be nice to not have to make a function for the input. By this, I mean directly inserting code into the parameter without creating a local function like stop_code. I don't know how to do this though.
Python treats functions as first-class citizens. As such, you can do things like:
def some_function():
# do something
pass
x = some_function
x()
Since you are storing functions and binding each function with a word (key), the best approach would be a dictionary. Your example could be like this:
def quit_code():
exit()
operations = dict(quit=quit_code)
operations['quit']()
A dictionary relates a value with a key. The only rule is the key must be immutable. That means numbers, strings, tuples and other immutable objects.
To create a dictionary, you can use { and }. And to get a value by its key, use [ and ]:
my_dictionary = { 'a' : 1, 'b' : 10 }
print(my_dictionary['a']) # It will print 1
You can also create a dictionary with dict, like so:
my_dictionary = dict(a=1, b=10)
However this only works for string keys.
But considering you are using quit_code to encapsulate the exit call, why not using exit directly?
operations = dict(quit=exit)
operations['quit']()
If dictionaries aren't an option, you could still use lists and tuples:
operations = [('quit',exit)]
for key, fun in operations:
if key == 'quit':
fun()
I have function like this one:
def get_list_of_movies(table):
#some code here
print(a_list)
return a_list
Reason why I want to use print and return is that I'm using this function in many places. So after calling this function from menu I want to get printed list of content.
This same function I'm using in another function - just to get list. Problem is - when I call this function it prints list as well.
Question: How to prevent function from executing print line when its used in another function just to get list?
This is part of exercise so I can't define more functions / split this or soo - I'm kind of limited to this one function.
Edit: Thank you for all answers! I'm just beginner but you showed me ways in python(programming in general) that I never thought of! Using second parameter (boolin) is very cleaver. I do learn here a lot!
Add a separate argument with a default value of None to control the printing. Pass
def get_list_of_movies(table, printIt=False):
...
if printIt:
print(a_list)
return a_list
...
movies = get_list_of_movies(table, printIt=True)
Another approach is to pass print itself as the argument, where the default value is a no-op:
def get_list_of_movies(table, printer=lambda *args: None):
...
printer(a_list)
return a_list
...
movies = get_list_of_movies(table, printer=print)
This opens the door to being able to customize exactly how the result is print; you are effectively adding an arbitrary callback to be performed on the return value, which admittedly can be handled with a custom pass-through function as well:
def print_it_first(x):
print(x)
return x
movies = print_it_first(get_list_of_movies(table))
This doesn't require any special treatment of get_list_of_movies itself, so is probably preferable from a design standpoint.
A completely different approach is to always print the list, but control where it gets printed to:
def get_list_of_movies(table, print_to=os.devnull):
...
print(a_list, file=location)
return a_list
movies = get_list_of_movies(table, print_to=sys.stdout)
The print_to argument can be any file-like object, with the default ensuring no output is written anywhere.
Currently i'm using a list of strings with names of functions to fix the flow of my software:
flow = [
"func1",
"func2",
"func3",
"func4",
"func5"
]
Then i iterate over the flow and call each one passing the options:
options = {}
[getattr(__import__(phase), phase)(options) for phase in flow]
I would like to know if is it possible to do the same, but avoiding side effects, using reduce. Currently, this approach it's making the functions receive the option, but isn't necessary return the options for the next function, so i'm changing the options that is declared in other scope.
Thanks.
You can use functools.reduce (which is sometimes called fold in other functional programming languages like Haskell) to indeed call the function.
In that case however you will need to define a function taking two parameters: the old accumulator value and the element itself. You simply ignore the old value and call the function on the element.
So for a generic function f(x), you can do this with:
functools.reduce(lambda _,x:f(x),list,initializer=0)
So in your case that would be:
options = {}
functools.reduce(lambda _,phase:getattr(__import__(phase),phase)(options),flow,initializer=0)
EDIT:
after rereading your question, it appears to me that each of the functions takes as input options, and generates the "new" options that should be passed to the next function. Well the return of the first function, is the first parameter of the lambda of the next function. So you can fold it together like:
first_options = {}
functools.reduce(lambda options,phase:getattr(__import__(phase),phase)(options),flow,initializer=first_options)
This will result in something equivalent to:
options_0 = first_options
options_1 = getattr(__import__(phase),flow[0])(options_0)
options_2 = getattr(__import__(phase),flow[1])(options_1)
# ...
return options_n
but of course this happens inside the reduce.
so reduce takes one a function, say reduce_func, that takes on 2 arguments. When it goes through a list it takes the first two items as the params of reduce_func for the first call, then on each subsequent call, uses the return value as the first param, and the next value on the list as the second param. This means, for you, reduce_func needs to be the following
def reduce_func(param, f):
return f(param)
and your list needs to be the following:
[options, func1, func2, func3, func4]
Now, I used a list of functions and didn't use import. In stead of f, you could pass in [module].[function] as a string (call the param something like func_str), and do some splitting and inside of reduce_func as some set up.
I have some topic to discuss. I have a fragment of code with 24 ifs/elifs. Operation is my own class that represents functionality similar to Enum. Here is a fragment of code:
if operation == Operation.START:
strategy = strategy_objects.StartObject()
elif operation == Operation.STOP:
strategy = strategy_objects.StopObject()
elif operation == Operation.STATUS:
strategy = strategy_objects.StatusObject()
(...)
I have concerns from readability point of view. Is is better to change it into 24 classes and use polymorphism? I am not convinced that it will make my code maintainable... From one hand those ifs are pretty clear and it shouldn't be hard to follow, on the other hand there are too many ifs.
My question is rather general, however I'm writing code in Python so I cannot use constructions like switch.
What do you think?
UPDATE:
One important thing is that StartObject(), StopObject() and StatusObject() are constructors and I wanted to assign an object to strategy reference.
You could possibly use a dictionary. Dictionaries store references, which means functions are perfectly viable to use, like so:
operationFuncs = {
Operation.START: strategy_objects.StartObject
Operation.STOP: strategy_objects.StopObject
Operation.STATUS: strategy_objects.StatusObject
(...)
}
It's good to have a default operation just in case, so when you run it use a try except and handle the exception (ie. the equivalent of your else clause)
try:
strategy = operationFuncs[operation]()
except KeyError:
strategy = strategy_objects.DefaultObject()
Alternatively use a dictionary's get method, which allows you to specify a default if the key you provide isn't found.
strategy = operationFuncs.get(operation(), DefaultObject())
Note that you don't include the parentheses when storing them in the dictionary, you just use them when calling your dictionary. Also this requires that Operation.START be hashable, but that should be the case since you described it as a class similar to an ENUM.
Python's equivalent to a switch statement is to use a dictionary. Essentially you can store the keys like you would the cases and the values are what would be called for that particular case. Because functions are objects in Python you can store those as the dictionary values:
operation_dispatcher = {
Operation.START: strategy_objects.StartObject,
Operation.STOP: strategy_objects.StopObject,
}
Which can then be used as follows:
try:
strategy = operation_dispatcher[operation] #fetch the strategy
except KeyError:
strategy = default #this deals with the else-case (if you have one)
strategy() #call if needed
Or more concisely:
strategy = operation_dispatcher.get(operation, default)
strategy() #call if needed
This can potentially scale a lot better than having a mess of if-else statements. Note that if you don't have an else case to deal with you can just use the dictionary directly with operation_dispatcher[operation].
You could try something like this.
For instance:
def chooseStrategy(op):
return {
Operation.START: strategy_objects.StartObject
Operation.STOP: strategy_objects.StopObject
}.get(op, strategy_objects.DefaultValue)
Call it like this
strategy = chooseStrategy(operation)()
This method has the benefit of providing a default value (like a final else statement). Of course, if you only need to use this decision logic in one place in your code, you can always use strategy = dictionary.get(op, default) without the function.
Starting from python 3.10
match i:
case 1:
print("First case")
case 2:
print("Second case")
case _:
print("Didn't match a case")
https://pakstech.com/blog/python-switch-case/
You can use some introspection with getattr:
strategy = getattr(strategy_objects, "%sObject" % operation.capitalize())()
Let's say the operation is "STATUS", it will be capitalized as "Status", then prepended to "Object", giving "StatusObject". The StatusObject method will then be called on the strategy_objects, failing catastrophically if this attribute doesn't exist, or if it's not callable. :) (I.e. add error handling.)
The dictionary solution is probably more flexible though.
If the Operation.START, etc are hashable, you can use dictionary with keys as the condition and the values as the functions to call, example -
d = {Operation.START: strategy_objects.StartObject ,
Operation.STOP: strategy_objects.StopObject,
Operation.STATUS: strategy_objects.StatusObject}
And then you can do this dictionary lookup and call the function , Example -
d[operation]()
Here is a bastardized switch/case done using dictionaries:
For example:
# define the function blocks
def start():
strategy = strategy_objects.StartObject()
def stop():
strategy = strategy_objects.StopObject()
def status():
strategy = strategy_objects.StatusObject()
# map the inputs to the function blocks
options = {"start" : start,
"stop" : stop,
"status" : status,
}
Then the equivalent switch block is invoked:
options["string"]()
I have been working at learning Python over the last week and it has been going really well, however I have now been introduced to custom functions and I sort of hit a wall. While I understand the basics of it, such as:
def helloworld():
print("Hello World!")
helloworld()
I know this will print "Hello World!".
However, when it comes to getting information from one function to another, I find that confusing. ie: function1 and function2 have to work together to perform a task. Also, when to use the return command.
Lastly, when I have a list or a dictionary inside of a function. I'll make something up just as an example.
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
How would I access the key/value and be able to change them from outside of the function? ie: If I had a program that let you input/output player stats or a character attributes in a video game.
I understand bits and pieces of this, it just confuses me when they have different functions calling on each other.
Also, since this was my first encounter with the custom functions. Is this really ambitious to pursue and this could be the reason for all of my confusion? Since this is the most complex program I have seen yet.
Functions in python can be both, a regular procedure and a function with a return value. Actually, every Python's function will return a value, which might be None.
If a return statement is not present, then your function will be executed completely and leave normally following the code flow, yielding None as a return value.
def foo():
pass
foo() == None
>>> True
If you have a return statement inside your function. The return value will be the return value of the expression following it. For example you may have return None and you'll be explicitly returning None. You can also have return without anything else and there you'll be implicitly returning None, or, you can have return 3 and you'll be returning value 3. This may grow in complexity.
def foo():
print('hello')
return
print('world')
foo()
>>>'hello'
def add(a,b):
return a + b
add(3,4)
>>>7
If you want a dictionary (or any object) you created inside a function, just return it:
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
return my_dict
d = my_function()
d['Key1']
>>> Value1
Those are the basics of function calling. There's even more. There are functions that return functions (also treated as decorators. You can even return multiple values (not really, you'll be just returning a tuple) and a lot a fun stuff :)
def two_values():
return 3,4
a,b = two_values()
print(a)
>>>3
print(b)
>>>4
Hope this helps!
The primary way to pass information between functions is with arguments and return values. Functions can't see each other's variables. You might think that after
def my_function():
my_dict = {"Key1":Value1,
"Key2":Value2,
"Key3":Value3,
"Key4":Value4,}
my_function()
my_dict would have a value that other functions would be able to see, but it turns out that's a really brittle way to design a language. Every time you call my_function, my_dict would lose its old value, even if you were still using it. Also, you'd have to know all the names used by every function in the system when picking the names to use when writing a new function, and the whole thing would rapidly become unmanageable. Python doesn't work that way; I can't think of any languages that do.
Instead, if a function needs to make information available to its caller, return the thing its caller needs to see:
def my_function():
return {"Key1":"Value1",
"Key2":"Value2",
"Key3":"Value3",
"Key4":"Value4",}
print(my_function()['Key1']) # Prints Value1
Note that a function ends when its execution hits a return statement (even if it's in the middle of a loop); you can't execute one return now, one return later, keep going, and return two things when you hit the end of the function. If you want to do that, keep a list of things you want to return and return the list when you're done.
You send information into and out of functions with arguments and return values, respectively. This function, for example:
def square(number):
"""Return the square of a number."""
return number * number
... recieves information through the number argument, and sends information back with the return ... statement. You can use it like this:
>>> x = square(7)
>>> print(x)
49
As you can see, we passed the value 7 to the function, and it returned the value 49 (which we stored in the variable x).
Now, lets say we have another function:
def halve(number):
"""Return half of a number."""
return number / 2.0
We can send information between two functions in a couple of different ways.
Use a temporary variable:
>>> tmp = square(6)
>>> halve(tmp)
18.0
use the first function directly as an argument to the second:
>>> halve(square(8))
32.0
Which of those you use will depend partly on personal taste, and partly on how complicated the thing you're trying to do is.
Even though they have the same name, the number variables inside square() and halve() are completely separate from each other, and they're invisible outside those functions:
>>> number
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'number' is not defined
So, it's actually impossible to "see" the variable my_dict in your example function. What you would normally do is something like this:
def my_function(my_dict):
# do something with my_dict
return my_dict
... and define my_dict outside the function.
(It's actually a little bit more complicated than that - dict objects are mutable (which just means they can change), so often you don't actually need to return them. However, for the time being it's probably best to get used to returning everything, just to be safe).