socket TCP python file transfer - while True loop don't exit - python

I have made a socket TCP for file transfer using python. Everything is ok and I can receive the file from the server socket but the problem is that I can not exit the while True loop of client socket, even I put a break to exit this loop.
Someone can help me point out what is my mistake pls!
The loop run until to print "File Receiving..." and never exit, but I can receiver the file completely.
Thank you very much
Socket Client:
import socket
import os
import unicodedata
from tqdm import tqdm
SIZE = 1024*4
FILENAME = "xyz.bin"
HOST = "127.0.0.1"
PORT = 8001
client_tcp = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
tcp_server_address = (HOST, PORT)
client_tcp.connect(tcp_server_address)
try:
for i in range(1,11):
texte = "PING\n"
client_tcp.send(texte.encode())
data=client_tcp.recv(1024).decode('utf-8')
print("Received:", str(data))
texte = "ABC"
client_tcp.send(texte.encode())
data=client_tcp.recv(1024)
print('Server: ', data.decode("utf8"))
with open(f"recv_{FILENAME}", "wb") as f:
while True:
data = client_tcp.recv(SIZE)
if not data:
#print("not data")
break
f.write(data)
print("File Receiving...")
print("Received:", str(data))
client_tcp.send("Data received.".encode("utf-8"))
f.close()
finally:
client_tcp.close()
print("File Received")

The keyword with will automatically close the file so no need of f.close()

Related

Socket python doesn't send data if program is alive

I'm trying to run a client/server script, where the client sends a file to the server and waits for responses until the server sends a stop message.
The problem is: once the connection is established the client starts sending data but until I press CTRL-C the server cannot recreate the file. Only after CTRL-C print "file is fully created" and the file becomes visible, instead, before it's seems to be waiting for something. idk where the problem is. Also tried changing condition on send loop using len(), but doesn't work. Anyone know how to fix it ?
client.py :
import socket # Import socket module
# from threading import Thread
s = socket.socket() # Create a socket object
HOST = "101.xx.x.xxx" # public IP address
PORT = 4243 # Reserve a port for your service.
PDF_PATH = "exam.pdf"
s.connect((HOST, PORT))
def send():
f = open(PDF_PATH, "rb")
while data := f.read(4096):
s.send(data)
f.close()
return
def receive():
while 1:
exercise = s.recv(4096)
if exercise == "stop!":
s.close()
break
f = open(f"{exercise}.txt", "wb")
while data := f.read(4096):
f.write(data)
return
def main():
send()
receive()
if __name__ == "__main__":
main()
server.py :
import socket
from threading import Thread
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
HOST = socket.gethostname()
IP = socket.gethostbyname(HOST)
PORT = 4243
s.bind(('', PORT))
s.listen(5)
def receive_file(conn, i):
f = open(f"exam.pdf", "wb")
while received := conn.recv(4096):
f.write(received)
print("File is fully copied\n")
f.close()
def send_result(conn,i):
while 1:
nbr = str(input("which exercise? "))
if nbr == "stop!":
break
f = open(f"exercise{nbr}.txt", "rb")
conn.send(bytes(f"exercise{nbr}.txt", encoding="utf-8"))
while data := f.read(4096):
conn.send(data)
f.close()
def main():
try:
while 1:
i = 0
conn, addr = s.accept()
print("Got connection from", addr)
# c.send(b"Thank you for connecting")
t = Thread(target=receive_file, args=(conn, i))
t.start()
t.join()
t = Thread(target=send_result, args=(conn, i))
t.start()
t.join()
except KeyboardInterrupt:
print("interrupting \n")
conn.close()
s.close()
if _name_ == '_main_':
main()
conn.recv() in the server won't return '' (no more data) unless the client closes the connection or calls shutdown(SHUT_WR) to indicate sends are complete:
def send():
with open(PDF_PATH, "rb") as f:
while data := f.read(4096):
s.sendall(data)
s.shutdown(socket.SHUT_WR)
An alternative is to design a protocol that sends the length of data before the data so you know when you've received the complete transmission. This would be required if you need to send more than one thing without closing the socket or shutting down sends. You're going to need this to make the receive portion of the server work if you want to send more than one exercise file.
Refer to this answer for an example of sending multiple files over a socket.

Python socket connection error: OSError: [Errno 9] Bad file descriptor

I am trying to write a client/server program in python that will accept multiple connections and manage them using threading. The server and client both run, and the client will receive the "welcome" message from the servers "processClient" function, which means the connection is being made and the thread is being started. However, any subsequent receive or send on the connection object after the welcome message fails with an "OSError: [Errno 9] Bad file descriptor" error. I've done some searching on the error, and most problems seem to result from someone trying to use a socket or connection that's been previously closed-which should not be the case here. Does anyone know what could be causing the error? Running python version 3.5.2
Server code:
#!/usr/bin/env python3
import socket
import sys
import os
import datetime
import threading
import random
PORT = 65432 # Port to listen on (non-privileged ports are > 1023)
def processClient(conn, id):
welcome = "Hello, you are client number " + str(id)
welcome = bytes(welcome, 'utf-8')
conn.sendall(welcome)
while True:
data = conn.recv(1024)
print(rpr(data))
time = str(datetime.datetime.now())
arr = bytes(time, 'utf-8')
if data == b'time':
conn.sendall(arr)
elif data == b'':
conn.close()
return
else:
temp = data.decode("utf-8")
temp = temp.upper()
temp = bytes(temp, 'utf-8')
conn.sendall(temp)
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
except:
print("unable to create socket connection, shutting down.")
quit()
s.bind(('0.0.0.0', PORT))
s.listen()
sys.stdout.write("Server is running \n")
runningThreads = []
threadID = 0
while True:
conn, addr = s.accept()
with conn:
#conn.setblocking(False)
print('Connected by', addr)
threadID += 1
threadTemp = threading.Thread(target = processClient, args=(conn, threadID))
threadTemp.start()
runningThreads.append(threadTemp)
for t in runningThreads:
if not t.isAlive():
# get results from thtead
t.handled = True
threadID -= 1
else:
t.handled = False
runningThreads = [t for t in runningThreads if not t.handled]
Client code:
#!/usr/bin/env python3
import socket
import sys
import os
import datetime
HOST = 0
while HOST == 0 or HOST == "":
HOST = input("Please enter host IP: ")
PORT = 65432 # The port used by the server
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.connect((HOST, PORT))
data = s.recv(1024)
print(repr(data))
while True:
inputString = input("Please input a string: ")
temp = bytes(inputString, 'utf-8')
s.sendall(temp)
if inputString == "":
quit()
data = s.recv(1024)
if data:
print(rpr(data))
for anyone else who stumbles across this: I did finally work out the problem. The server was not waiting on input from the client before it attempts to read data from the connection, which was triggering the error (the error message was particularly unhelpful in diagnosing this issue). I rewrote this to use python selectors rather than threads-selectors includes very handy polling functionality that can be used to "pause" until there is data to be read. I could have built this into the program myself, but why do so when there's already a language feature that does it for you?

Python 3: Sending files through socket. (Client-Server Program)

I am having the above issue. The client is suppose to ask for a filename and send the file name to the server after which the server will open the file and display it. Problem is that the server isn't opening the file and displaying it.
Below is the client.
#!/usr/bin/env python3
import socket, os.path, datetime, sys
def Main():
host = '127.0.0.1'
port = 50001
s = socket.socket()
s.connect((host, port))
Filename = input("Type in ur file ")
s.send(Filename.encode('utf-8'))
data = s.recv(1024).decode('utf-8')
s.close()
if __name__ == '__main__':
Main()
Below is the server
#!/usr/bin/env python3
import socket
import os
import sys
def Main():
host = '127.0.0.1'
port = 50001
s = socket.socket()
s.bind((host,port))
print("server Started")
s.listen(1)
c, addr = s.accept()
print("Connection from: " + str(addr))
while True:
data = c.recv(1024).decode('utf-8')
myfile = open(data, "r")
if not data:
break
print("from connected user: " + myfile)
c.close()
if __name__ == '__main__':
Main()
I've made few minimal adjustments to your code with which it runs as so that server.py continuously listens on a given port and sends back data which each invocation of client.py asks for.
server.py
#!/usr/bin/env python3
import socket
import os
import sys
def Main():
host = '127.0.0.1'
port = 50001
s = socket.socket()
s.bind((host,port))
print("server Started")
s.listen(1)
while True:
c, addr = s.accept()
print("Connection from: " + str(addr))
filename = ''
while True:
data = c.recv(1024).decode('utf-8')
if not data:
break
filename += data
print("from connected user: " + filename)
myfile = open(filename, "rb")
c.send(myfile.read())
c.close()
if __name__ == '__main__':
Main()
client.py
#!/usr/bin/env python3
import socket, os.path, datetime, sys
def Main():
host = '127.0.0.1'
port = 50001
s = socket.socket()
s.connect((host, port))
Filename = input("Type in ur file ")
s.send(Filename.encode('utf-8'))
s.shutdown(socket.SHUT_WR)
data = s.recv(1024).decode('utf-8')
print(data)
s.close()
if __name__ == '__main__':
Main()
And now a bit of explanation.
On the server side. The outer loop accepts a connection, then reads from the connection until done (more on this later). Prints your debugging info, but note you were trying to print the file object and not the filename (which would fail trying to concatenate). I also open the file in binary mode (that way I can skip the str -> bytes translation.
On the client side. I've added closing the writing end of the socket when the file has been sent. Note you might want to use sendall instead of send for this use case: check those docs links for details. And I've added a print for the incoming data.
Now that bit with shutting down the writing end in the client and the inner loop reading (and also related to the sendall hint. Which BTW also holds true for the server side, otherwise you should loop, as you might see your content truncated; other option is to also have a sending loop.). Stream sockets will guarantee you get your bytes in in order you've send them. On itself it has no idea whether your message is complete and it also does not guarantee in how many and how large chunks will the data be sent and received (resp.).
The inner loop of server keep reading until we see an EOF (we've receive zero length string in python socket). This would happen (be returned by recv when the remote socket (or at least its writing end) has been shut down. Since we still want to reuse the connection, we only do that on the sending end in the client. Hope this helps you to move ahead.

Python Server send data not working

I am currently working on a server in Python, the problem I am facing is the client could not retrieve the sent data from server.
The code of the server is:
import sys
import socket
from threading import Thread
allClients=[]
class Client(Thread):
def __init__(self,clientSocket):
Thread.__init__(self)
self.sockfd = clientSocket #socket client
self.name = ""
self.nickName = ""
def newClientConnect(self):
allClients.append(self.sockfd)
while True:
while True:
try:
rm= self.sockfd.recv(1024)
print rm
try:
self.sockfd.sendall("\n Test text to check send.")
print "Data send successfull"
break
except socket.error, e:
print "Could not send data"
break
except ValueError:
self.sockfd.send("\n Could not connect properly")
def run(self):
self.newClientConnect()
self.sockfd.close()
while True:
buff = self.sockfd.recv(1024)
if buff.strip() == 'quit':
self.sockfd.close()
break # Exit when break
else:
self.sendAll(buff)
#Main
if __name__ == "__main__":
#Server Connection to socket:
IP = '127.0.0.1'
PORT = 80
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
serversocket.setsockopt( socket.SOL_SOCKET, socket.SO_REUSEADDR,1)
print ("Server Started")
try:
serversocket.bind(('',5000))
except ValueError,e:
print e
serversocket.listen(5)
while True:
(clientSocket, address) = serversocket.accept()
print 'New connection from ', address
ct = Client(clientSocket)
ct.start()
__all__ = ['allClients','Client']
#--
And the client connecting is:
import socket
HOST = '192.168.1.4' # The remote host
PORT = 5000 # The same port as used by the server
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST, PORT))
data = s.recv(1024)
s.close()
print 'Received', data#repr(data)
In need of a quick solution....
Thanks,
I tested out your code, and when I commented out
rm= self.sockfd.recv(1024)
print rm
it worked fine. Basically the server stopped there to wait for a message that never came. If it still does not work for you, there might be two problems. Either you have a firewall that blocks the connection somehow, or you have old servers running in the background from previous tries that actually wasn't killed. Check your processes if pythonw.exe or equivalent is running when it shouldn't be, and kill it.
To wait for response:
with s.makefile('rb') as f:
data = f.read() # block until the whole response is read
s.close()
There are multiple issues in your code:
nested while True without break
finally: ..close() is executed before except ValueError: ..send
multiple self.sockfd.close()
etc
Also you should probably use .sendall() instead of .send().
your server code is excepting client send something first,
rm= self.sockfd.recv(1024)
but I don't see any in your code
please try send something in your client code
s.connect((HOST, PORT))
s.send("hello")
Short solution
Add a short sleep after connect.
import time
time.sleep(3)

Python : How to handle multiple clients and a server

I am implementing a program with a server and multiple clients. All clients send data to the server and a server check out the step of each client. If all client's steps are the same, a server sends new data to all clients to do next step. And it continues this procedure again and again.
However, when I run my program, it cannot communicate each other. Here are my code. Would you give me some hints?
client & server
#client
from socket import *
from sys import *
import time
import stat, os
import glob
# set the socket parameters
host = "localhost"
port = 21567
buf = 1024
data = ''
addr = (host, port)
UDPSock = socket(AF_INET, SOCK_DGRAM)
UDPSock.settimeout(100)
def_msg = "=== TEST ==="
#FILE = open("test.jpg", "w+")
FILE = open("data.txt","w+")
while (1):
#data, addr = UDPSock.recvfrom(buf)
print "Sending"
UDPSock.sendto(def_msg, addr)
#time.sleep(3)
data, addr = UDPSock.recvfrom(buf)
if data == 'done':
FILE.close()
break
FILE.write(data)
print "Receiving"
#time.sleep(3)
UDPSock.close()
# server program for nvt
from socket import *
import os, sys, time, glob
#import pygame
import stat
host = 'localhost'
port = 21567
buf = 1024
addr = (host, port)
print 'test server'
UDPSock = socket(AF_INET, SOCK_DGRAM)
UDPSock.bind(addr)
msg = "send txt file to all clients"
#FILE = open("cam.jpg", "r+")
FILE = open("dna.dat","r+")
sending_data = FILE.read()
FILE.close()
tmp_data = sending_data
while (1):
#UDPSock.listen(1)
#UDPSock.sendto(msg, addr)
#FILE = open("gen1000.dat","r+")
#sending_data = FILE.read()
#FILE.close()
#print 'client is at', addr
data, addr = UDPSock.recvfrom(buf)
#time.sleep(3)
print data
#msg = 'hello'
#
tmp, sending_data = sending_data[:buf-6], sending_data[buf-6:]
if len(tmp) < 1:
msg = 'done'
UDPSock.sendto(msg, addr)
print "finished"
sending_data = tmp_data
UDPSock.sendto(tmp, addr)
print "sending"
#time.sleep(3)
UDPSock.close()
A server must perform the sequence socket(), bind(), listen(), accept() (possibly repeating the accept() to service more than one client), while a client only needs the sequence socket(), connect().
Your missing listen() i saw first. Listen for connections made to the socket.
More on this here: link text
Look at this: http://heather.cs.ucdavis.edu/~matloff/Python/PyNet.pdf
It's a very good Python networking tutorial including working examples of a client and server. Now, I'm not an expert on this, but it looks to me like your code is overcomplicated. And what's the deal with all the commented-out lines?
Quote from question:
#UDPSock.listen(1)
#UDPSock.sendto(msg, addr)
#FILE = open("gen1000.dat","r+")
#sending_data = FILE.read()
#FILE.close()
End quote
Those look like some pretty important lines to me.
Also, make sure the computers are connected. From a prompt run:
ping [IP]
where [IP] is the IP address of the other machine(Note: if you're not connected to the same LAN, this becomes much harder as you might then need port forwarding and possibly static IPs).

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