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python selenium: element click intercepted:

I'm trying to click via find_element_by_xpath() as i did it always. In the case below, there is an error when try to click this element. I'm quite new with selenium and researched already. It seems that i have to click on specific coordination. Do you have any idea how to solve this problem? i'm struggling for quite a while.
section of HTML code:
<map ng-if="!enableSvgHighlighting" id="clickareasVillage" name="clickareasVillage"
ng-show="areas.village.length > 0" class="">
<area ng-repeat="a in areas.village" location-id="32" on-pointer-over="highlightStart(32)" on-
pointer-out="highlightStop(32)" clickable="openBuildingDialog(32)" tg-
coords="758,341,758,342,761,343,763,344,767,345,769"
coords="758,341,758,342,761,343,763,344,767,345,769"
shape="poly" building-positioner="32" class="clickable">
my Code:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//map[#id='clickareasVillage']/area[2]")))
ele1=driver.find_element_by_xpath("//map[#id='clickareasVillage']/area[2]")
ele1.click()
error message:
ElementClickInterceptedException: element click intercepted: Element
<area ng-repeat="a in areas.village" location-id="32"
on-pointer-over="highlightStart(32)" on-pointer-out="highlightStop(32)" clickable="openBuildingDialog(32)"
tg-coords="758,341,758,342,761,343,763,344,767,345,769" coords="758,341,758,342,761,343,763,344,767,345,769"
shape="poly" building-positioner="32"
class="clickable"> is not clickable at point (391, 477).
Other element would receive the click: <img ng-if="!enableSvgHighlighting"
ng-show="areas.village.length > 0" class="clickareas" src="layout/images/x.gif" usemap="#clickareasVillage" data-cmp-info="9">
on other treads at stackoverflow, people suggest to use the following line. If i try, there is a TimeoutExeption.
WebDriverWait(driver, 20).until(EC.invisibility_of_element((By.XPATH, "//map[#id='clickareasVillage']/area[2]")))

As said above, usually when you encounter this error it's because a pop-up or an invisible overlay is preventing the driver from clicking on your element.
You said that JS clicking wasn't working either so i'm going to give you 2 quick workarounds that you can try:
ActionChains to move and click on your element:
from selenium.webdriver.common.action_chains import ActionChains
ActionChains(driver).move_to_element(element).click().perform()
Send keys using ActionChains
from selenium.webdriver.common.action_chains import ActionChains
for i in range(#determine how much time):
ActionChains(driver).send_keys(Keys.TAB).perform() #tab until element is selected
ActionChains(driver).send_keys(Keys.ENTER).perform() #press enter to "click" on it
Let me know if that helped you.

Try using javascript
element = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//map[#id='clickareasVillage']/area[2]")))
driver.execute_script("arguments[0].click();", element)

There may be something which could be preventing click on the element, check if any pop-up occuring.

Selenium Python Can't click button: ElementNotInteractable or StaleElementReferenceException

I'm trying to automate MS Teams and can't get past the login because after entering the password I am having issues clicking the Sign In button.
If I try:
button = driver.find_element_by_xpath('//*[#id="idSIButton9"]')
button.click()
I get:
ElementNotInteractableException: Message: element not interactable.
If I try to solve it with Action Chains method (which seems to have solved many similiar issues for lots of people):
button = driver.find_element_by_xpath('//*[#id="idSIButton9"]')
driver.implicitly_wait(10)
ActionChains(driver).move_to_element(button).click(button).perform()
I get:
StaleElementReferenceException: Message: stale element reference: element is not attached to the page document
It is worth mentioning that when logging in manually I can get past this stage with pressing return after entering my password but I couldn't be successful with send keys methods neither.

If you still filled the form use submit() function - It is there to make your life easier.
Import webdriver:
from selenium import webdriver
Create webdriver object:
driver = webdriver.Firefox()
Get the website:
driver.get("https://www.YOUR_WEBSITE.de/")
Get element - In your case input for password
element = driver.find_element_by_xpath('//*[#id="i0118"]')
Send keys - Enter password
element.send_keys("YOUR_PASSWORD")
Submit contents
element.submit()

The element which you are trying to locate using the XPath driver.find_element_by_xpath('//*[#id="idSIButton9"]') might be the part of the previous screen and new screen, hence the driver might be referring to the element which is part of the previous screen, hence you are getting the StaleElementReferenceException.
The simplest way to resolve this is you can add, driver.refresh() just before the above xpath, this will load the page and DOM with the new elements.
Else, you can use a different locator strategy which will uniquely identify that element.

Unable to locate element in Python Selenium webdriver find_element_by_xpath

i'm trying to click the "download Results" button on this website .
i'm using below python code to click this button
from selenium import webdriver
chromedriver_path = 'E:/software/python/chromedriver'
url = 'https://www.cms.gov/apps/physician-fee-schedule/search/search-results.aspx?Y=0&T=4&HT=2&CT=3&H1=74750&H2=74800&M=5'
driver= webdriver.Chrome(executable_path=chromedriver_path )
driver.get(url)
driver.find_element_by_xpath('//*[#title="Download Results"]').click()
i'm getting below error
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//frame[#name="aspnetForm"]"}
(Session info: headless chrome=83.0.4103.116)
i'm thinking if the button is within a iframe but how do I find out the iframe?

This may help you out: Unable to locate element using selenium webdriver in python
Try and switch to the frame first, and then search for the element.

i realized that there's a agreement page that i need to click 'Agree' button first.
i didn't see this in browser because i already clicked 'Agree' weeks ago. but in webdriver, i need to click that each time.

Just after the URL opens, a page comes up asking you to agree the terms. You need to click on that Agree first. Since it is possible that once clicking on the Agree button, it won't come again if you accepted it on default browser. So just be sure with code, you can first check the presence of the agree button first.
This kind of function you may make to check presence:
def elementPresent(locatorType, locator):
#present = true
#not present = false
wait = WebDriverWait(driver, 20)
try:
wait.until(EC.presence_of_element_located((locatorType, locator)))
except Exception:
return False
return True
And then using if condition you may proceed further like:
if(elementPresent("xpath", "//a[#title='Accept']/span")):
driver.find_element_by_xpath("//a[#title='Accept']/span").click()
and then you may click on the element you want, there is no frame that is required to be switched to.
driver.find_element_by_xpath("//a[#title = 'Download Results']/span").click()
Just extract the element and click on it and your required file will be downloaded.

Button Click element issue in selenium using python

I am trying to click button(name command page) on web page but i am unable to do so. i am using selenium with python
code:
wait= WebDriverWait(driver,20)
command_page = wait.until(EC.element_to_be_clickable((By.ID,"Button_ID")))
command_page.click()
I have tried by class name also but i am unable to click the element.
Please help me on this.

As an alternative you can use JavascriptExecutor to perfrom click on certain element if Selenium click() method doesn't trigger the action without any Exception.
element = driver.find_element_by_id("etoolbar_toolbarSection_newcommandpagebtn_id")
driver.execute_script("arguments[0].click();", element)

Please try below solution :
WebDriverWait(driver, 20)
both_button=wait.until(EC.element_to_be_clickable((By.XPATH, "//*[contains(text(), 'Command Page')]")))
both_button.click()

I tried this, seems to be working
from selenium import webdriver
driver = webdriver.Firefox()
driver.get("file://c:/cygwin64/home/das2/abcd.html")
element = driver.find_element_by_id("etoolbar_toolbarSection_newcommandpagebtn_id")
element.click()

selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element is not clickable with Selenium and Python

I am currently working on a project which fills a form automatically. And the next button appears when the form is filled, that's why it gives me an error.
I have tried:
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH,"//input[#type='button' and #class='button']")))
Next = driver.find_element_by_xpath("//input[#type='button' and #class='button']")
Next.click()
HTML:
<span class="btn">
<input type="button" value="Next" class="button" payoneer="Button" data-controltovalidate="PersonalDetails" data-onfieldsvalidation="ToggleNextButton" data-onclick="UpdateServerWithCurrentSection();" id="PersonalDetailsButton">
</input>
<div class="clearfix"></div>
</span>
ERROR:
selenium.common.exceptions.ElementClickInterceptedException: Message:
element click intercepted: Element is not clickable at point (203, 530).
Other element would receive the click: ... (Session info: chrome=76.0.3809.132)

If the path of the xpath is right, maybe you can try this method to solve this problem. Replace the old code with the following code:
button = driver.find_element_by_xpath("xpath")
driver.execute_script("arguments[0].click();", button)
I solved this problem before, but to be honestly, I don't know the reason.

This error message...
selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element is not clickable at point (203, 530). Other element would receive the click: ... (Session info: chrome=76.0.3809.132)
...implies that the click() on the desired element was intercepted by some other element and the desired element wasn't clickable.
There are a couple of things which you need to consider as follows:
While using Selenium for automation using time.sleep(secs) without any specific condition to achieve defeats the purpose of automation and should be avoided at any cost. As per the documentation:
time.sleep(secs) suspends the execution of the current thread for the given number of seconds. The argument may be a floating point number to indicate a more precise sleep time. The actual suspension time may be less than that requested because any caught signal will terminate the sleep() following execution of that signal’s catching routine. Also, the suspension time may be longer than requested by an arbitrary amount because of the scheduling of other activity in the system.
You can find a detailed discussion in How to sleep webdriver in python for milliseconds
As WebDriverWait returns the WebElement you can invoke the click() method directly.
Solution
To click on the button with value as Next you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input.button#PersonalDetailsButton[data-controltovalidate='PersonalDetails']"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#class='button' and #id='PersonalDetailsButton'][#data-controltovalidate='PersonalDetails']"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

i faced similar issues, the .click() always returns a Not clickable exception. the
driver.execute_script('arguments[0].click()', button)
does the magic. You can also use it to execute any other js script this way
script = 'your JavaScript goes here'
element = driver.find_element_by_*('your element identifier goes here')
driver.execute_script(script, element)

I looked at the exact element that was causing it and it was a banner about consent/cookies. So at first, I made sure it clicked "OK" on the consent banner and then I clicked the other button that I needed. Hope it helps someone.

It look's like there are some other elements which are having the same xpath try changing the xpath something like this
Next = driver.find_element_by_xpath("//input[#id='PersonalDetailsButton']");
Next.Click();
or
Next = driver.find_element_by_xpath(//input[#value='Next' and #id='PersonalDetailsButton']);
Next.Click();
Try first xpath if that doesn't work go with the second one . If that also doesn't work try using sikuli. I am pretty sure that first xpath will work

I faced a similar issue and I observed something that might help to understand the root cause of the issue. In my case, I was able to click at an element being in PC view mode of the website but failed to do so in mobile view (in which I needed my script to run). I found out that in mobile view, ordering of elements (li in my case) changed in view while they remained same in the html document. That's why I was not able to click on it without actually scrolling to it first. It might also explain why this works: -
driver.execute_script("arguments[0].click();", button)

I don't have enough rep to comment but the common reason for this error might be Selenium locates the element from DOM on screen and locate the x-y coordinates (300, 650) then clicks on them but if some changes takes place on screen in between the click duration, for example google ads or some pop-up then it's unable to click on it resulting in this exception
I'm just guessing if anyone has a proper explanation to pls share

I had the same problem too. But my problem was not with the element. The button was activated with href. I changed the code from
<a class="services-button" href="desired url">
To
<a class="services-button" onclick="location.href='{% url "desired url" %}'";">

This solution worked for me :
from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
driver = webdriver.Firefox(executable_path="")
driver.get("https://UrlToOpen")
action = ActionChains(driver)
firstLevelMenu = driver.find_element_by_id("menu")
firstLevelMenu.click()
source : http://allselenium.info/mouse-over-actions-using-python-selenium-webdriver/

"selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element is not clickable ... "
This exception occurs when element is not found on a web page (When the element we are looking for is at bottom part of the page which is not loaded yet)
So we you can scroll the page using javascript and load complete page and
from selenium.webdriver.common.by import By
from selenium import webdriver
url = "YOUR URL"
SCROLL_PAUSE_TIME = 0.5
driver = webdriver.Chrome()
driver.maximize_window()
driver.get(url)
def scroll_page():
i = 0
while i < 5:
# Scroll down to 500 pixel
driver.execute_script("window.scrollBy(0, 500)", "")
# Wait to load page
time.sleep(SCROLL_PAUSE_TIME)
# Will scroll only for 4 increments of 500px
i += 1

You could try:
driver.execute_script("arguments[0].click();", button)
This solution solved my problems when I faced similar issues.