I'm trying to automate MS Teams and can't get past the login because after entering the password I am having issues clicking the Sign In button.
If I try:
button = driver.find_element_by_xpath('//*[#id="idSIButton9"]')
button.click()
I get:
ElementNotInteractableException: Message: element not interactable.
If I try to solve it with Action Chains method (which seems to have solved many similiar issues for lots of people):
button = driver.find_element_by_xpath('//*[#id="idSIButton9"]')
driver.implicitly_wait(10)
ActionChains(driver).move_to_element(button).click(button).perform()
I get:
StaleElementReferenceException: Message: stale element reference: element is not attached to the page document
It is worth mentioning that when logging in manually I can get past this stage with pressing return after entering my password but I couldn't be successful with send keys methods neither.
If you still filled the form use submit() function - It is there to make your life easier.
Import webdriver:
from selenium import webdriver
Create webdriver object:
driver = webdriver.Firefox()
Get the website:
driver.get("https://www.YOUR_WEBSITE.de/")
Get element - In your case input for password
element = driver.find_element_by_xpath('//*[#id="i0118"]')
Send keys - Enter password
element.send_keys("YOUR_PASSWORD")
Submit contents
element.submit()
The element which you are trying to locate using the XPath driver.find_element_by_xpath('//*[#id="idSIButton9"]') might be the part of the previous screen and new screen, hence the driver might be referring to the element which is part of the previous screen, hence you are getting the StaleElementReferenceException.
The simplest way to resolve this is you can add, driver.refresh() just before the above xpath, this will load the page and DOM with the new elements.
Else, you can use a different locator strategy which will uniquely identify that element.
Related
i'm trying to click the "download Results" button on this website .
i'm using below python code to click this button
from selenium import webdriver
chromedriver_path = 'E:/software/python/chromedriver'
url = 'https://www.cms.gov/apps/physician-fee-schedule/search/search-results.aspx?Y=0&T=4&HT=2&CT=3&H1=74750&H2=74800&M=5'
driver= webdriver.Chrome(executable_path=chromedriver_path )
driver.get(url)
driver.find_element_by_xpath('//*[#title="Download Results"]').click()
i'm getting below error
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//frame[#name="aspnetForm"]"}
(Session info: headless chrome=83.0.4103.116)
i'm thinking if the button is within a iframe but how do I find out the iframe?
This may help you out: Unable to locate element using selenium webdriver in python
Try and switch to the frame first, and then search for the element.
i realized that there's a agreement page that i need to click 'Agree' button first.
i didn't see this in browser because i already clicked 'Agree' weeks ago. but in webdriver, i need to click that each time.
Just after the URL opens, a page comes up asking you to agree the terms. You need to click on that Agree first. Since it is possible that once clicking on the Agree button, it won't come again if you accepted it on default browser. So just be sure with code, you can first check the presence of the agree button first.
This kind of function you may make to check presence:
def elementPresent(locatorType, locator):
#present = true
#not present = false
wait = WebDriverWait(driver, 20)
try:
wait.until(EC.presence_of_element_located((locatorType, locator)))
except Exception:
return False
return True
And then using if condition you may proceed further like:
if(elementPresent("xpath", "//a[#title='Accept']/span")):
driver.find_element_by_xpath("//a[#title='Accept']/span").click()
and then you may click on the element you want, there is no frame that is required to be switched to.
driver.find_element_by_xpath("//a[#title = 'Download Results']/span").click()
Just extract the element and click on it and your required file will be downloaded.
I am learning python and selenium right now by making a small script that posts birthday comments to my facebook friends. I am able to successfully login and navigate to the "friends' birthday" modal, but then I am unable to comment in the textbox.
Here is the error I am getting:
selenium.common.exceptions.NoSuchElementException:
Message: no such element: Unable to locate element:
{"method":"xpath","selector":"//*[#id="u_i_6"]"}
I haven't had any issues finding other page elements via XPath so I am not sure what is causing the issue. I also tried finding the textbox to comment via classname, but had the same result. Can anyone offer some thoughts?
EDIT: forgot to paste code
from selenium import webdriver
from pynput.keyboard import Key, Controller
import time
import config
# fetch facebook password from separate file in the same directory
pw = config.secret['pw']
keyboard = Controller()
driver = webdriver.Chrome()
options = webdriver.ChromeOptions()
options.add_argument('--disable-extensions')
options.add_argument('--disable-notifications')
# navigate to facebook url
driver.get('https://facebook.com')
# input email address
email_input = driver.find_element_by_xpath('//*[#id="email"]')
email_input.send_keys(<omitted>)
# input pw
password_input = driver.find_element_by_xpath('//*[#id="pass"]')
password_input.send_keys(pw)
# click login button element
login_button = driver.find_element_by_xpath('//*[#id="u_0_b"]')
login_button.click()
home_button = driver.find_element_by_xpath('//*[#id="u_0_c"]/a')
# wait 8 seconds for browser popup before pressing esc to get out
time.sleep(8)
keyboard.press(Key.esc)
# check if there are any birthdays today
birthday_section = driver.find_element_by_xpath('//*[#id="home_birthdays"]/div/div/div/div/a/div/div/span/span[1]')
birthday_section.click()
first_comment = driver.find_element_by_xpath('//*[#id="u_i_6"]')
first_comment.send_keys('happy birthday!')
# click post button to post comment
# close browser window after actions are complete
time.sleep(5)
driver.close()
It is hard to answer without the code, but here are a couple of ideas:
Make sure you are using some sort of Selenium wait, implicit or explicit, so your code does not search for an element before this element appears on the page. You can add this code after driver.get() for implicit wait:
driver.implicitly_wait(5)
Also, it looks like IDs are dynamic on that page, I get a different one on my FB page. Try using this xpath to find the textarea:
"//form[contains(#action, 'birthday')]//textarea"
Hope this is helpful, good luck!
I am currently working on a project which fills a form automatically. And the next button appears when the form is filled, that's why it gives me an error.
I have tried:
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH,"//input[#type='button' and #class='button']")))
Next = driver.find_element_by_xpath("//input[#type='button' and #class='button']")
Next.click()
HTML:
<span class="btn">
<input type="button" value="Next" class="button" payoneer="Button" data-controltovalidate="PersonalDetails" data-onfieldsvalidation="ToggleNextButton" data-onclick="UpdateServerWithCurrentSection();" id="PersonalDetailsButton">
</input>
<div class="clearfix"></div>
</span>
ERROR:
selenium.common.exceptions.ElementClickInterceptedException: Message:
element click intercepted: Element is not clickable at point (203, 530).
Other element would receive the click: ... (Session info: chrome=76.0.3809.132)
If the path of the xpath is right, maybe you can try this method to solve this problem. Replace the old code with the following code:
button = driver.find_element_by_xpath("xpath")
driver.execute_script("arguments[0].click();", button)
I solved this problem before, but to be honestly, I don't know the reason.
This error message...
selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element is not clickable at point (203, 530). Other element would receive the click: ... (Session info: chrome=76.0.3809.132)
...implies that the click() on the desired element was intercepted by some other element and the desired element wasn't clickable.
There are a couple of things which you need to consider as follows:
While using Selenium for automation using time.sleep(secs) without any specific condition to achieve defeats the purpose of automation and should be avoided at any cost. As per the documentation:
time.sleep(secs) suspends the execution of the current thread for the given number of seconds. The argument may be a floating point number to indicate a more precise sleep time. The actual suspension time may be less than that requested because any caught signal will terminate the sleep() following execution of that signal’s catching routine. Also, the suspension time may be longer than requested by an arbitrary amount because of the scheduling of other activity in the system.
You can find a detailed discussion in How to sleep webdriver in python for milliseconds
As WebDriverWait returns the WebElement you can invoke the click() method directly.
Solution
To click on the button with value as Next you can use either of the following Locator Strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input.button#PersonalDetailsButton[data-controltovalidate='PersonalDetails']"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#class='button' and #id='PersonalDetailsButton'][#data-controltovalidate='PersonalDetails']"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
i faced similar issues, the .click() always returns a Not clickable exception. the
driver.execute_script('arguments[0].click()', button)
does the magic. You can also use it to execute any other js script this way
script = 'your JavaScript goes here'
element = driver.find_element_by_*('your element identifier goes here')
driver.execute_script(script, element)
I looked at the exact element that was causing it and it was a banner about consent/cookies. So at first, I made sure it clicked "OK" on the consent banner and then I clicked the other button that I needed. Hope it helps someone.
It look's like there are some other elements which are having the same xpath try changing the xpath something like this
Next = driver.find_element_by_xpath("//input[#id='PersonalDetailsButton']");
Next.Click();
or
Next = driver.find_element_by_xpath(//input[#value='Next' and #id='PersonalDetailsButton']);
Next.Click();
Try first xpath if that doesn't work go with the second one . If that also doesn't work try using sikuli. I am pretty sure that first xpath will work
I faced a similar issue and I observed something that might help to understand the root cause of the issue. In my case, I was able to click at an element being in PC view mode of the website but failed to do so in mobile view (in which I needed my script to run). I found out that in mobile view, ordering of elements (li in my case) changed in view while they remained same in the html document. That's why I was not able to click on it without actually scrolling to it first. It might also explain why this works: -
driver.execute_script("arguments[0].click();", button)
I don't have enough rep to comment but the common reason for this error might be Selenium locates the element from DOM on screen and locate the x-y coordinates (300, 650) then clicks on them but if some changes takes place on screen in between the click duration, for example google ads or some pop-up then it's unable to click on it resulting in this exception
I'm just guessing if anyone has a proper explanation to pls share
I had the same problem too. But my problem was not with the element. The button was activated with href. I changed the code from
<a class="services-button" href="desired url">
To
<a class="services-button" onclick="location.href='{% url "desired url" %}'";">
This solution worked for me :
from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
driver = webdriver.Firefox(executable_path="")
driver.get("https://UrlToOpen")
action = ActionChains(driver)
firstLevelMenu = driver.find_element_by_id("menu")
firstLevelMenu.click()
source : http://allselenium.info/mouse-over-actions-using-python-selenium-webdriver/
"selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element is not clickable ... "
This exception occurs when element is not found on a web page (When the element we are looking for is at bottom part of the page which is not loaded yet)
So we you can scroll the page using javascript and load complete page and
from selenium.webdriver.common.by import By
from selenium import webdriver
url = "YOUR URL"
SCROLL_PAUSE_TIME = 0.5
driver = webdriver.Chrome()
driver.maximize_window()
driver.get(url)
def scroll_page():
i = 0
while i < 5:
# Scroll down to 500 pixel
driver.execute_script("window.scrollBy(0, 500)", "")
# Wait to load page
time.sleep(SCROLL_PAUSE_TIME)
# Will scroll only for 4 increments of 500px
i += 1
You could try:
driver.execute_script("arguments[0].click();", button)
This solution solved my problems when I faced similar issues.
I am trying to scrape some information off this website using python's selenium.
First, I log into the website and get to the page. Then, I would like to click on the tab "Quickscan" to scrape some info. However, that's where I get stuck. I can't find a way to click on the tab.
Note that this problem would be surmounted if I managed to navigate to the page, though when I log in, even if I put such page in my WebDriver, I still get redirected to this one.
To get to the desired page I have tried finding the element both through the xpath and through the link, but it does not find the element.
import requests
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
driver =webdriver.Chrome(executable_path ="mypath")
driver.get("https://vc4a.com/ventures/autocollect/#quickscan-tab")
#find username and password bar
username = driver.find_element_by_id("user_login")
password = driver.find_element_by_id("user_pass")
#Input password and username
username.send_keys("username")
password.send_keys("password")
#click on submit
driver.find_element_by_name("wp-submit").click()
driver.find_element_by_name("rememberme").click()
#try to find element using text in the link
driver.find_elements_by_link_text('#quickscan-tab')[0].click()
#try to find element using xpath from the inspected element
driver.find_element_by_xpath('//*[#id="subnav"]/li[3]/a').click()
I would like to be able to open the tab so that I can scrape the content.
When I use the first code it returns the following error:
IndexError: list index out of range
However, by inspecting the page I can see there is indeed 2 elements with the text "#quickscan-tab", so I don't understand why the index 0 would be out of range.
When I use the second code it returns the following error:
NoSuchElementException: no such element: Unable to locate element: {"method":"xpath","selector":"//*[#id="subnav"]/li[3]/a"}
(Session info: chrome=74.0.3729.169)
(Driver info: chromedriver=74.0.3729.6 (255758eccf3d244491b8a1317aa76e1ce10d57e9-refs/branch-heads/3729#{#29}),platform=Mac OS X 10.14.5 x86_64)
What I did was just copying the xpath.
I created an account on that page and tried this modified script and it works:
import requests
import time
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
driver = webdriver.Chrome()
driver.get("https://vc4a.com/ventures/autocollect/#quickscan-tab")
#find username and password bar
username = driver.find_element_by_id("user_login")
password = driver.find_element_by_id("user_pass")
#Input password and username
username.send_keys("username")
password.send_keys("password")
#click on submit
driver.find_element_by_name("rememberme").click()
driver.find_element_by_name("wp-submit").click()
time.sleep(10)
#try to find element using text in the link
driver.find_elements_by_link_text('Quickscan')[0].click()
#try to find element using xpath from the inspected element
driver.find_element_by_xpath('//a[text()="Quickscan"]').click()
link_text means the text that you actually see. [Quickscan]
Login takes time and the script tries to locate before the tab is created thus causing error.
Your xpath would have worked if not for the login delay.
Click rememberme before submitting the form. Or don't, since selenium starts a clean session for every run.
driver.find_elements_by_link_text('#quickscan-tab')[0].click() - it's wrong
Link text doesn't work like this you need to create a different locator. try below XPath
driver.find_element_by_xpath((//*[#id='quickscan-tab'])[0])
Try this:
scanelements = driver.find_elements_by_xpath('//*[#id='quickscan-tab']')
for elt in scanelements :
elt.click()
break
I am trying to automate reading my phone bill from the carrier website. www.fido.ca
However, the site is built with angularjs and I can't find the element using python and selenium webdriver. Please see below for the codes I've tried.
driver = webdriver.Firefox()
url = 'https://www.fido.ca/pages/#/login?m=login'
driver.get(url)
wait = WebDriverWait(driver, 10)
wait.until(EC.visibility_of_element_located((By.XPATH, "//a[#id='BC']")))
It returns selenium.common.exceptions.TimeoutException: Message:
Note: I can see the element from the front end, but no idea why webdriver can't see it.
When you navigate to a page, you would see the overlay "Welcome to Fido!" screen which makes your desired element invisible - hence the timeout error.
Handle the screen by selecting a region and clicking "Continue" or "X" (close).