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getting the total of 3rd items on a list [closed]

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I'm trying to write a program that adds only the third item in a list with dictionaries. Please help me. Here is my code so far.
# SalesManager Code
# pseudo sales list
sales = {"Meat Loaf": [50, 69, 19],
"Mineral Water": [5, 15, 10]
}
for key, value in sales.items():
total = total + value[2]
print(total)

Define total outside the loop:
total = 0
for key, value in sales.items():
total = total + value[2]
print(total)
print(total) # 29

you can use below one liner code to achieve this:
print(sum(v[2] for v in sales.values()))

You first need to declare your variable total:
sales = {"Meat Loaf": [50, 69, 19],
"Mineral Water": [5, 15, 10]
}
total = 0
for key, value in sales.items():
total = total + value[2]
print(total)

dunno what i do, splitting number like lul [closed]

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the desired output
splitnumber(-9)----->-5,-4
my code
def spliiiiit(angka):
hasil1 = angka/2
hasil1 = int(hasil1)
batas = angka%2
hasil2 = 0
if batas == 0:
hasil2 = hasil1
elif angka < 0:
hasil1 = hasil1 - 1
hasil2 = hasil1 + 1
else:
hasil2 = (angka/2)+0.5
hasilakhir = []
hasilakhir.insert(0,hasil1)
hasilakhir.insert(1, int(hasil2))
print(hasilakhir)
can some one tell me how the right way to solve that
the function output is like this
splitnumber(-9) ----> [-5,-4] or splitnumber(9) ----> [4,5]

def spliiiiit(angka):
x = angka//2
return(x, angka-x)

In Python, how can I make it so the first 2 elements of a list are added together, then the first 4, then the first 6, and so on? [closed]

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I am making a game where two players take turns adding a number 1 to 10 to the running total. The player who adds to get 100 wins. I stored the inputs of the players in a list, and at the end of the game, I want to display the total after every turn. The list is in the format:
allTurns = [player1move1, player2move1, player1move2, player2move2, ...]
How can I add only the first 2 elements and display them, then add only the first 4 elements and display them, and then the first 6, and so on?

for i in range(0, len(list)):
if i % 2 == 0:
print(sum(list[:i+1]))
Or
sums = []
for i in range(0, len(list)):
if i % 2 == 0:
sums.append(sums[-1] + list[i-1] + list[i])

Try this:
allTurns = [1,2,3,6,12,23]
out = []
for n in range(len(allTurns)):
if n % 2 is 1:
out.append(allTurns[n] + allTurns[n-1])
if len(allTurns) % 2 is 1:
out.append(allTurns[-1])
print(out)
I've coded it so that it could work for any situation, and not just yours.

Try this:
allTurns = [1,2,3,6,12,23,4]
out = []
for n in allTurns:
if allTurns.index(n) % 2 is 0:
i = 0
for a in range(allTurns.index(n)+2):
try:
i=i+allTurns[a]
except IndexError:
pass
out.append(i)
print(out)
This is probably as simple as it can get.

How can I do this effectively? [closed]

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This problem:
Input: 123456
Result:
1+2+3+4+5+6 = 21
2+1 = 3
Return: 3
This is my code:
num = input()
print(sum(list(map(int, list(num)))))
I don't know how to do until it is 1 digit.

Try this (example in IPython):
In [1]: s = '123456'
Out[1]: '123456'
In [2]: digits = [int(j) for j in s]
Out[2]: [1, 2, 3, 4, 5, 6]
In [3]: s = str(sum(digits))
Out[3]: '21'
Repeat steps 2 and three until len(s) == 1.

One way:
while len(str(ans))>1:
ans = sum(map(int, str(ans)))
Full code:
num = 45637
ans = num
while len(str(ans))>1:
ans = sum(map(int, str(ans)))
print(ans)
Output for input 45637:
7

You can try this:
s = input()
while(len(s)>1):
s = str(sum(list(map(int,s))))

One way to do it using sum(), list comprehension and recursion,
def simulated_sum(input):
"""This is a recursive function
to find the simulated sum of an integer"""
if len(str(input)) == 1:
return input
else:
input_digits = [int(x) for x in str(input)]
latest_sum = sum(input_digits)
return simulated_sum(latest_sum)
input = int(input('Enter a number'))
print(simulated_sum(input))
DEMO: https://rextester.com/WCBXIL71483

Is this what you want? (instructions unclear):
def myfunction(number):
total = 0
answertotal = 0
for i in str(number):
total += int(i)
for i in str(total):
answertotal += int(i)
return answertotal
myfunction(123456)
This function returns 3

Python code for deleting a list is not working [closed]

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The following function should delete a element in an list if it has an overlap with a first list.
However it only works with the first example(a and b1). With others it does not even send an error message and I have no idea where there problem lies. Can someone point me in the right direction?
def funct(firstone, secondone):
counter = 0
while secondone != [] and counter < len(firstone):
if firstone[counter] in secondone:
del(secondone[secondone.index(firstone[counter])])
counter += 1
return secondone
a = [0, 1, 2]
b1 = [1, 2, 0]
b2 = [-1, 1, 1]
b3 = [0, 0, 2]
print(funct(a, b1))
print(funct(a, b2))
print(funct(b3, a))

i think last line in your code "return" must be in the same level with "while" loop like that
def funct(firstone, secondone ):
counter = 0
while secondone != [] and counter < len(firstone):
if firstone [counter] in secondone :
del(secondone[ secondone .index(firstone[counter ])])
counter += 1
return secondone

You need to continue the for loop when the condition is False otherwise you will always return on the first iteration
while secondone != [] and counter < len(firstone):
if firstone[counter] in secondone :
del(secondone[secondone.index(firstone[counter])])
counter += 1
else:
continue
return secondone