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This problem:
Input: 123456
Result:
1+2+3+4+5+6 = 21
2+1 = 3
Return: 3
This is my code:
num = input()
print(sum(list(map(int, list(num)))))
I don't know how to do until it is 1 digit.
Try this (example in IPython):
In [1]: s = '123456'
Out[1]: '123456'
In [2]: digits = [int(j) for j in s]
Out[2]: [1, 2, 3, 4, 5, 6]
In [3]: s = str(sum(digits))
Out[3]: '21'
Repeat steps 2 and three until len(s) == 1.
One way:
while len(str(ans))>1:
ans = sum(map(int, str(ans)))
Full code:
num = 45637
ans = num
while len(str(ans))>1:
ans = sum(map(int, str(ans)))
print(ans)
Output for input 45637:
7
You can try this:
s = input()
while(len(s)>1):
s = str(sum(list(map(int,s))))
One way to do it using sum(), list comprehension and recursion,
def simulated_sum(input):
"""This is a recursive function
to find the simulated sum of an integer"""
if len(str(input)) == 1:
return input
else:
input_digits = [int(x) for x in str(input)]
latest_sum = sum(input_digits)
return simulated_sum(latest_sum)
input = int(input('Enter a number'))
print(simulated_sum(input))
DEMO: https://rextester.com/WCBXIL71483
Is this what you want? (instructions unclear):
def myfunction(number):
total = 0
answertotal = 0
for i in str(number):
total += int(i)
for i in str(total):
answertotal += int(i)
return answertotal
myfunction(123456)
This function returns 3
Related
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if __name__ == '__main__':
n = int(input())
for i in range (0,n):
result = i**2
print(result)
#input : 5
#output : 0 1 4 9 16
range 0,n = 0,1,2,3,4 and
we gave i**2 but how we got 0,1,4,9,16 as output?
range(start, stop, step)
** = square of Number
start Optional. An integer number specifying at which position to
start. Default is 0
stop Required. An integer number specifying at which position to
stop (not included).
step Optional. An integer number specifying the incrementation. Default is 1
you are passing required parameter as 5 which will not be included in the loop. so as per your calculation it will start from 0
result = 0**2 = 0
result = 1**2 = 1
result = 2**2 = 4
result = 3**2 = 9
result = 4**2 = 16
'i' will not reach 5 because of non-inclusive nature of range() operator.
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I am making a game where two players take turns adding a number 1 to 10 to the running total. The player who adds to get 100 wins. I stored the inputs of the players in a list, and at the end of the game, I want to display the total after every turn. The list is in the format:
allTurns = [player1move1, player2move1, player1move2, player2move2, ...]
How can I add only the first 2 elements and display them, then add only the first 4 elements and display them, and then the first 6, and so on?
for i in range(0, len(list)):
if i % 2 == 0:
print(sum(list[:i+1]))
Or
sums = []
for i in range(0, len(list)):
if i % 2 == 0:
sums.append(sums[-1] + list[i-1] + list[i])
Try this:
allTurns = [1,2,3,6,12,23]
out = []
for n in range(len(allTurns)):
if n % 2 is 1:
out.append(allTurns[n] + allTurns[n-1])
if len(allTurns) % 2 is 1:
out.append(allTurns[-1])
print(out)
I've coded it so that it could work for any situation, and not just yours.
Try this:
allTurns = [1,2,3,6,12,23,4]
out = []
for n in allTurns:
if allTurns.index(n) % 2 is 0:
i = 0
for a in range(allTurns.index(n)+2):
try:
i=i+allTurns[a]
except IndexError:
pass
out.append(i)
print(out)
This is probably as simple as it can get.
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Let's consider this string :
st = 'text1text6253text'
How could I please extract the two first consecutive figures ?
Expected output :
62
You can either use regex with \d{2}and return that, or go over the string:
st = 'text1text6253text'
for i in range(len(st)-1):
if st[i].isdigit() and st[i+1].isdigit():
print(st[i]+st[i+1])
break
import re
def find_con(n, s):
result = re.search('\d{%s}'%n, s)
return result.group(0) if result else result
st = 'text1text6253text'
print(find_con(2, st))
st = 'text1text6253text'
lst = list(st)
lst2 = []
for i,v in enumerate(lst):
if lst[i].isdigit() and lst[i+1].isdigit():
lst2.append(lst[i])
lst2.append(lst[i+1])
ans = int(lst2[0] + lst2[1])
print(ans)
Thanks to your answers, I built a general function that I propose you below :
def extract_n_consecutive_numbers(st,nb):
for i in range(len(st)-nb+1):
is_numeric = True
for j in range(nb):
is_numeric = is_numeric & st[i+j].isdigit()
if is_numeric :
output = ""
for j in range(nb):
output += st[i+j]
return output
return ""
Example :
extract_n_consecutive_numbers('text1text6253text',2)
Out[1]: 62
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I am given a user entered string 'aaabbbccaa'.
I want to find the duplicates and print the string back as 'a3b3c2a2'
Maybe with this way:
from itertools import groupby
s = "aaabbbccaa"
# group by characters
groups = groupby(s)
# process result
result = "".join([label + str(len(list(group))) for label, group in groups])
print(result)
Output:
a3b3c2a2
def process_string(source):
new = ''
while source:
counter = 0
first_char = source[0]
while source and source[0] == first_char:
counter += 1
source = source[1:]
new += f'{first_char}{counter}'
return new
print(process_string('aaabbbccaa'))
'a3b3c2a2'
this kind of solution could mabye solve it, it does what you specify, however if you are able to put it into your context, no idea :)
hope it helps!
c = 0
foo = "aaabbbccaa"
bar = ""
prev = None
for counter, index in enumerate(foo):
print(c)
if prev == None:
print("first")
elif prev == index:
print("second")
elif prev != index:
c = 0
c += 1
prev = index
try:
if index in foo[counter+1]:
print("third")
else:
print("fourth")
bar += index + str(c)
except:
print("fifth")
bar += index + str(c)
print("foo is {}".format(foo)) # will output aaabbbccaa
print("bar is {}".format(bar)) # will output a3b3c2a2
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Today, i have trying to resolve a small star pyramid :
Input:
5 1
Output:
*
**
***
****
Code:
x = 1
y = 0
m, e = map(int, raw_input().split())
while x < m:
print "\n" * y, "*" * e
m -= 1
e += 1
I did that but there is a better solution?? Thanks =)
I think this can be solved more easily:
stop, first = map(int, raw_input().split())
for i in range(stop - 1):
print '*' * (i + first)
just for fun >:)
class c:
def __init__(s,m,e):
s.e , s.m = sorted([e, m])
s.r = 42
def __iter__(s):
return s
def next(s):
if s.m < s.e:
t = "".join(chr(s.r) for _ in range(s.m))
s.m += 1
return t
else:
raise StopIteration
print "\n".join(c(*map(int,raw_input().split())))
n = int(raw_input())
for i in range(n): print "*"*i
This appears to do what your program intends to do, however I can't quite tell because of the issues I raised in my comment above.