Develop Reference

How to load json url and get data using python

I want to load this api url and fetch data. I am using this code to get this but i am getting 400 bad request.
Actual website link is (https://www.lffs.eu/les-clubs/)
'''
import urllib, json
enter code hereurl = "https://gestion.lffs.eu/lms_league_ws/public/api/v1/club/byMyLeague?filter=&club_status_id=1&page=2&pagination=21"
response = urllib.urlopen(url)
data = json.loads(response.read())
print(data)
'''

There is a problem with the way you used the API. If you run it on Google you will see the error. The API expects some kind of token from you. Make sure you provide it first.

Accessing Elasticsearch with Python 3

I want to use the Python 3 module urllib to access an Elasticsearch database at localhost:9200. My script gets a valid request (generated by Kibana) piped to STDIN in JSON format.
Here is what I did:
import json
import sys
import urllib.parse
import urllib.request
er = json.load(sys.stdin)
data = urllib.parse.urlencode(er)
data = data.encode('ascii')
uri = urllib.request.Request('http://localhost:9200/_search', data)
with urllib.request.urlopen(uri) as repsonse:
response.read()
(I understand that my repsonse.read() doesn't make much sense by itself but I just wanted to keep it simple.)
When I execute the script, I get an
HTTP Error 400: Bad request
I am very sure that the JSON data I'm piping to the script is correct, since I had it printed and fed it via curl to Elasticsearch, and got back the documents I expected to get back.
Any ideas where I went wrong? Am I using urllib correctly? Do I maybe mess up the JSON data in the urlencode line? Am I querying Elasticsearch correctly?
Thanks for your help.

With requests you can do one of two things
1) Either you create the string representation of the json object yourself and send it off like so:
payload = {'param': 'value'}
response = requests.post(url, data=json.dumps(payload))
2) Or you have requests do it for you like so:
payload = {'param': 'value'}
response = requests.post(url, json = payload)
So depending on what actually comes out of the sys.stdin call (probably - as Kibana would be sending that if the target was ElasticSearch - a string representation of a json object == equivalent of doing json.dumps on a dictionary), but you might have to adjust a bit depending on the output of sys.stdin.
My guess is that your code could work by just doing so:
import sys
import requests
payload = sys.stdin
response = requests.post('http://localhost:9200/_search', data=payload)
And if you then want to do some work with it in Python, requests has a built in support for this too. You just call this:
json_response = response.json()
Hope this helps you on the right track. For further reading om json.dumps/loads - this answer has some good stuff on it.

For anyone who doesn't want to use requests (for example if you're using IronPython where its not supported):
import urllib2
import json
req = urllib2.Request(url, json.dumps(data), headers={'Content-Type': 'application/json'})
response = urllib2.urlopen(req)
Where 'url' can be something like this (example below is search in index):
http://<elasticsearch-ip>:9200/<index-name>/_search/

Get request python as a string

I wanted to send a get request in python and return it as a string. I wanna eventually use that string as something later on. Also by default does python return it in json format?
req = requests.get(server, auth=('user',"pass"))
thanks

Use python requests. Check the link, there are examples how you get json from response.
req = requests.get(server, auth=('user',"pass"))
req.json()
If you want it as string, use
req.text

HTTP Delete with python requests module

I would like to do a HTTP DELETE with python requests module that follows the API below;
https://thingspeak.com/docs/channels#create
DELETE https://api.thingspeak.com/channels/4/feeds
api_key=XXXXXXXXXXXXXXXX
I am using python v2.7 and requests module. My python code looks like this;
def clear(channel_id):
data = {}
data['api_key'] = 'DUCYS8xufsV613VX'
URL_delete = "http://api.thingspeak.com/channels/" + str(channel_id) + "/feeds"
r = requests.delete(URL_delete, data)
The code does not work because requests.delete() can only accept one parameter. How should the correct code look like?

You want
import json
mydata = {}
mydata['api_key'] = "Jsa9i23jka"
r = requests.delete(URL_delete, data=json.dumps(mydata))
You have to use the named input, 'data', and I'm guessing that you actually want JSON dumped, so you have to convert your dictionary, 'mydata' to a json string. You can use json.dumps() for that.
I don't know the API you are using, but by the sound of it you actually want to pass URL parameter, not data, for that you need:
r = requests.delete(URL_delete, params=mydata)
No need to convert mydata dict to a json string.

You can send the data params as #Eugene suggested, but conventionally delete requests only contains url and nothing else. The reason is that a RESTful url should uniquely identify the resource, thereby eliminating the need to provide additional parameters for deletion. On the other hand, if your 'APIKEY' has something to do with authentication, then it should be part of headers instead of request data, something like this.
headers = {'APIKEY': 'xxx'}
response = requests.delete(url, data=json.dumps(payload), headers=headers)

How to send a POST request using django?

I dont want to use html file, but only with django I have to make POST request.
Just like urllib2 sends a get request.

Here's how you'd write the accepted answer's example using python-requests:
post_data = {'name': 'Gladys'}
response = requests.post('http://example.com', data=post_data)
content = response.content
Much more intuitive. See the Quickstart for more simple examples.

In Python 2, a combination of methods from urllib2 and urllib will do the trick. Here is how I post data using the two:
post_data = [('name','Gladys'),] # a sequence of two element tuples
result = urllib2.urlopen('http://example.com', urllib.urlencode(post_data))
content = result.read()
urlopen() is a method you use for opening urls.
urlencode() converts the arguments to percent-encoded string.

The only thing you should look at now:
https://requests.readthedocs.io/en/master/

You can use urllib2 in django. After all, it's still python. To send a POST with urllib2, you can send the data parameter (taken from here):
urllib2.urlopen(url[, data][, timeout])
[..] the HTTP request will be a POST instead of a GET when the data parameter is provided

Pay attention, that when you're using 🐍 requests , and make POST request passing your dictionary in data parameter like this:
payload = {'param1':1, 'param2':2}
r = request.post('https://domain.tld', data=payload)
you are passing parameters form-encoded.
If you want to send POST request with only JSON (most popular type in server-server integration) you need to provide a str() in data parameter. In case with JSON, you need to import json lib and make like this:
payload = {'param1':1, 'param2':2}
r = request.post('https://domain.tld', data=json.dumps(payload))`
documentation is here
OR:
just use json parameter with provided data in the dict
payload = {'param1':1, 'param2':2}
r = request.post('https://domain.tld', json=payload)`