How can I strip Python logging calls without commenting them out? - python

Today I was thinking about a Python project I wrote about a year back where I used logging pretty extensively. I remember having to comment out a lot of logging calls in inner-loop-like scenarios (the 90% code) because of the overhead (hotshot indicated it was one of my biggest bottlenecks).
I wonder now if there's some canonical way to programmatically strip out logging calls in Python applications without commenting and uncommenting all the time. I'd think you could use inspection/recompilation or bytecode manipulation to do something like this and target only the code objects that are causing bottlenecks. This way, you could add a manipulator as a post-compilation step and use a centralized configuration file, like so:
[Leave ERROR and above]
my_module.SomeClass.method_with_lots_of_warn_calls
[Leave WARN and above]
my_module.SomeOtherClass.method_with_lots_of_info_calls
[Leave INFO and above]
my_module.SomeWeirdClass.method_with_lots_of_debug_calls
Of course, you'd want to use it sparingly and probably with per-function granularity -- only for code objects that have shown logging to be a bottleneck. Anybody know of anything like this?
Note: There are a few things that make this more difficult to do in a performant manner because of dynamic typing and late binding. For example, any calls to a method named debug may have to be wrapped with an if not isinstance(log, Logger). In any case, I'm assuming all of the minor details can be overcome, either by a gentleman's agreement or some run-time checking. :-)

What about using logging.disable?
I've also found I had to use logging.isEnabledFor if the logging message is expensive to create.

Use pypreprocessor
Which can also be found on PYPI (Python Package Index) and be fetched using pip.
Here's a basic usage example:
from pypreprocessor import pypreprocessor
pypreprocessor.parse()
#define nologging
#ifdef nologging
...logging code you'd usually comment out manually...
#endif
Essentially, the preprocessor comments out code the way you were doing it manually before. It just does it on the fly conditionally depending on what you define.
You can also remove all of the preprocessor directives and commented out code from the postprocessed code by adding 'pypreprocessor.removeMeta = True' between the import and
parse() statements.
The bytecode output (.pyc) file will contain the optimized output.
SideNote: pypreprocessor is compatible with python2x and python3k.
Disclaimer: I'm the author of pypreprocessor.

I've also seen assert used in this fashion.
assert logging.warn('disable me with the -O option') is None
(I'm guessing that warn always returns none.. if not, you'll get an AssertionError
But really that's just a funny way of doing this:
if __debug__: logging.warn('disable me with the -O option')
When you run a script with that line in it with the -O option, the line will be removed from the optimized .pyo code. If, instead, you had your own variable, like in the following, you will have a conditional that is always executed (no matter what value the variable is), although a conditional should execute quicker than a function call:
my_debug = True
...
if my_debug: logging.warn('disable me by setting my_debug = False')
so if my understanding of debug is correct, it seems like a nice way to get rid of unnecessary logging calls. The flipside is that it also disables all of your asserts, so it is a problem if you need the asserts.

As an imperfect shortcut, how about mocking out logging in specific modules using something like MiniMock?
For example, if my_module.py was:
import logging
class C(object):
def __init__(self, *args, **kw):
logging.info("Instantiating")
You would replace your use of my_module with:
from minimock import Mock
import my_module
my_module.logging = Mock('logging')
c = my_module.C()
You'd only have to do this once, before the initial import of the module.
Getting the level specific behaviour would be simple enough by mocking specific methods, or having logging.getLogger return a mock object with some methods impotent and others delegating to the real logging module.
In practice, you'd probably want to replace MiniMock with something simpler and faster; at the very least something which doesn't print usage to stdout! Of course, this doesn't handle the problem of module A importing logging from module B (and hence A also importing the log granularity of B)...
This will never be as fast as not running the log statements at all, but should be much faster than going all the way into the depths of the logging module only to discover this record shouldn't be logged after all.

You could try something like this:
# Create something that accepts anything
class Fake(object):
def __getattr__(self, key):
return self
def __call__(self, *args, **kwargs):
return True
# Replace the logging module
import sys
sys.modules["logging"] = Fake()
It essentially replaces (or initially fills in) the space for the logging module with an instance of Fake which simply takes in anything. You must run the above code (just once!) before the logging module is attempted to be used anywhere. Here is a test:
import logging
logging.basicConfig(level=logging.DEBUG,
format='%(asctime)s %(levelname)-8s %(message)s',
datefmt='%a, %d %b %Y %H:%M:%S',
filename='/temp/myapp.log',
filemode='w')
logging.debug('A debug message')
logging.info('Some information')
logging.warning('A shot across the bows')
With the above, nothing at all was logged, as was to be expected.

I'd use some fancy logging decorator, or a bunch of them:
def doLogging(logTreshold):
def logFunction(aFunc):
def innerFunc(*args, **kwargs):
if LOGLEVEL >= logTreshold:
print ">>Called %s at %s"%(aFunc.__name__, time.strftime("%H:%M:%S"))
print ">>Parameters: ", args, kwargs if kwargs else ""
try:
return aFunc(*args, **kwargs)
finally:
print ">>%s took %s"%(aFunc.__name__, time.strftime("%H:%M:%S"))
return innerFunc
return logFunction
All you need is to declare LOGLEVEL constant in each module (or just globally and just import it in all modules) and then you can use it like this:
#doLogging(2.5)
def myPreciousFunction(one, two, three=4):
print "I'm doing some fancy computations :-)"
return
And if LOGLEVEL is no less than 2.5 you'll get output like this:
>>Called myPreciousFunction at 18:49:13
>>Parameters: (1, 2)
I'm doing some fancy computations :-)
>>myPreciousFunction took 18:49:13
As you can see, some work is needed for better handling of kwargs, so the default values will be printed if they are present, but that's another question.
You should probably use some logger module instead of raw print statements, but I wanted to focus on the decorator idea and avoid making code too long.
Anyway - with such decorator you get function-level logging, arbitrarily many log levels, ease of application to new function, and to disable logging you only need to set LOGLEVEL. And you can define different output streams/files for each function if you wish. You can write doLogging as:
def doLogging(logThreshold, outStream=sys.stdout):
.....
print >>outStream, ">>Called %s at %s" etc.
And utilize log files defined on a per-function basis.

This is an issue in my project as well--logging ends up on profiler reports pretty consistently.
I've used the _ast module before in a fork of PyFlakes (http://github.com/kevinw/pyflakes) ... and it is definitely possible to do what you suggest in your question--to inspect and inject guards before calls to logging methods (with your acknowledged caveat that you'd have to do some runtime type checking). See http://pyside.blogspot.com/2008/03/ast-compilation-from-python.html for a simple example.
Edit: I just noticed MetaPython on my planetpython.org feed--the example use case is removing log statements at import time.
Maybe the best solution would be for someone to reimplement logging as a C module, but I wouldn't be the first to jump at such an...opportunity :p

:-) We used to call that a preprocessor and although C's preprocessor had some of those capablities, the "king of the hill" was the preprocessor for IBM mainframe PL/I. It provided extensive language support in the preprocessor (full assignments, conditionals, looping, etc.) and it was possible to write "programs that wrote programs" using just the PL/I PP.
I wrote many applications with full-blown sophisticated program and data tracing (we didn't have a decent debugger for a back-end process at that time) for use in development and testing which then, when compiled with the appropriate "runtime flag" simply stripped all the tracing code out cleanly without any performance impact.
I think the decorator idea is a good one. You can write a decorator to wrap the functions that need logging. Then, for runtime distribution, the decorator is turned into a "no-op" which eliminates the debugging statements.
Jon R

I am doing a project currently that uses extensive logging for testing logic and execution times for a data analysis API using the Pandas library.
I found this string with a similar concern - e.g. what is the overhead on the logging.debug statements even if the logging.basicConfig level is set to level=logging.WARNING
I have resorted to writing the following script to comment out or uncomment the debug logging prior to deployment:
import os
import fileinput
comment = True
# exclude files or directories matching string
fil_dir_exclude = ["__","_archive",".pyc"]
if comment :
## Variables to comment
source_str = 'logging.debug'
replace_str = '#logging.debug'
else :
## Variables to uncomment
source_str = '#logging.debug'
replace_str = 'logging.debug'
# walk through directories
for root, dirs, files in os.walk('root/directory') :
# where files exist
if files:
# for each file
for file_single in files :
# build full file name
file_name = os.path.join(root,file_single)
# exclude files with matching string
if not any(exclude_str in file_name for exclude_str in fil_dir_exclude) :
# replace string in line
for line in fileinput.input(file_name, inplace=True):
print "%s" % (line.replace(source_str, replace_str)),
This is a file recursion that excludes files based on a list of criteria and performs an in place replace based on an answer found here: Search and replace a line in a file in Python

I like the 'if __debug_' solution except that putting it in front of every call is a bit distracting and ugly. I had this same problem and overcame it by writing a script which automatically parses your source files and replaces logging statements with pass statements (and commented out copies of the logging statements). It can also undo this conversion.
I use it when I deploy new code to a production environment when there are lots of logging statements which I don't need in a production setting and they are affecting performance.
You can find the script here: http://dound.com/2010/02/python-logging-performance/

Related

Python logger- Selenium

I'm doing an automation project which in in i want to record the results into a log file, I creacted a function that create the log file and write in it the messeges.
I dont get why this log file function does'nt work.
P.S, The test in the example runs perfectly.
def test10(self):
log=User(self.driver)
log.LogIn('By1zx','Cb12')
log.LogOut()
logFile("INFO",10,True)
#Logger creator
def logFile(level,test,passedornot):
lfile=r'C:\Users\97252\PycharmProjects\Automation\AutomationLogging\log.txt'
logging.basicConfig(level= logging.INFO, filename="lfile",filemode="a")
passtext="Failed"
if(passedornot):passtext="Passed"
if level == "INFO":logging.info(f'The test {test} {passtext}')
if level == "ERROR":logging.error(f'The test {test} {passtext}')
I noticed inefficiency in the code and a minor bug as well.
The bug is, filename=lfile. No double quotes required. You are referring variable not the string "lfile"
logging.basicConfig(level= logging.INFO, filename=lfile,filemode="a")
Every time you call logFile function, it will try to open file_pointer to append logs to log file. This would be overhead for the OS, if you use logFile function more frequently. The best approach for this is, RotatingFileHandler. Its worth looking into this library. Please comment if you have any questions on this library.

Disable pytest warnings capture in a single test

I generally like the pytest warnings capture hook, as I can use it to force my test suite to not have any warnings triggered. However, I have one test that requires the warnings to print to stderr correctly to work.
How can I disable the warnings capture for just the one test?
For instance, something like
def test_warning():
mystderr = StringIO()
sys.stderr = mystderr
warnings.warn('warning')
assert 'UserWarning: warning' in mystderr.getvalue()
(I know I can use capsys, I just want to show the basic idea)
Thanks to the narrowing down in this discussion, I think the question might better be titled "In pytest, how to capture warnings and their standard error output in a single test?". Given that suggested rewording, I think the answer is "it can't, you need a separate test".
If there were no standard error capture requirement, you should be able to use the #pytest.mark.filterwarnings annotation for this.
#pytest.mark.filterwarnings("ignore")
def test_one():
assert api_v1() == 1
From:
https://docs.pytest.org/en/latest/warnings.html#pytest-mark-filterwarnings
#wim points out in a comment this will not capture the warning, though, and the answer he lays out captures and asserts on the warnings in a standard way.
If there were stderr output but not Python warnings thrown, capsys would be the technique, as you say
https://docs.pytest.org/en/latest/capture.html
I don't think it's meaningful to do both in a pytest test, because of the nature of the pytest implementation.
As previously noted pytest redirects stderr etc to an internal recorder. Secondly, it defines its own warnings handler
https://github.com/pytest-dev/pytest/blob/master/src/_pytest/warnings.py#L59
It is similar in idea to the answer to this question:
https://stackoverflow.com/a/5645133/5729872
I had a little poke around with redefining warnings.showwarning(), which worked fine from vanilla python, but pytest deliberately reinitializes that as well.
won't work in pytest, only straight python -->
def func(x):
warnings.warn('wwarn')
print(warnings.showwarning.__doc__)
# print('ewarn', file=sys.stderr)
return x + 1
sworig = warnings.showwarning
def showwarning_wrapper(message, category, filename, lineno, file=None, line=None):
"""Local override for showwarning()"""
print('swwrapper({})'.format(file) )
sworig(message,category,filename,lineno,file,line)
warnings.showwarning = showwarning_wrapper
<-- won't work in pytest, only straight python
You could probably put a warnings handler in your test case that reoutput to stderr ... but that doesn't prove much about the code under test, at that point.
It is your system at the end of the day. If after consideration of the point made by #wim that testing stderr as such may not prove much, you decide you still need it, I suggest separating the testing of the Python warning object (python caller layer) and the contents of stderr (calling shell layer). The first test would look at Python warning objects only. The new second test case would call the library under test as a script, through popen() or similar, and assert on the resulting standard error and output.
I'll encourage you to think about this problem in a different way.
When you want to assert that some of your code triggers warnings, you should be using a pytest.warns context for that. Check the warning message by using the match keyword, and avoid the extra complications of trying to capture it from stderr.
import re
import warnings
import pytest
def test_warning():
expected_warning_message = "my warning"
match = re.escape(expected_warning_message)
with pytest.warns(UserWarning, match=match):
warnings.warn("my warning", UserWarning)
That should be the edge of your testing responsibility. It is not your responsibility to test that the warnings module itself prints some output to stderr, because that behavior is coming from standard library code and it should be tested by Python itself.

Apply function decorator on print function across all files without having to import and/or reapply?

Edit: My first attempt at asking this might be a bit unfocused/poorly worded here's a better explanation of what I'm trying to do:
I'm trying to modify the default behavior of the print function for the entire environment python is running in without having to modify each file that's being run.
I'm attempting to decorate the print function (I know there are many ways to do this such as overriding it but that's not really the question I'm asking) so I can have it print out some debugging information and force it to always flush. I did that like so:
def modify_print(func):
# I made this so that output always gets flushed as it won't by default
# within the environment I'm using, I also wanted it to print out some
# debugging information, doesn't really matter much in the context of this
# question
def modified_print(*args,**kwargs):
return func(f"some debug prefix: ",flush=True,*args,**kwargs)
return modified_print
print = modify_print(print)
print("Hello world") # Prints "some debug prefix Hello World"
However what I'm trying to do is modify this behavior throughout my entire application. I know I can manually decorate/override/import the print function in each file however I'm wondering if there is some way I can globally configure my python environment to decorate this function everywhere. The only way I can think to do this would be to edit the python source code and build the modified version.
EDIT:
Here's the behavior I wanted implemented, thank you Match for your help.
It prints out the line number and filename everywhere you call a print function within your python environment. This means you don't have to import or override anything manually in all of your files.
https://gist.github.com/MichaelScript/444cbe5b74dce2c01a151d60b714ac3a
import site
import os
import pathlib
# Big thanks to Match on StackOverflow for helping me with this
# see https://stackoverflow.com/a/48713998/5614280
# This is some cool hackery to overwrite the default functionality of
# the builtin print function within your entire python environment
# to display the file name and the line number as well as always flush
# the output. It works by creating a custom user script and placing it
# within the user's sitepackages file and then overwriting the builtin.
# You can disable this behavior by running python with the '-s' flag.
# We could probably swap this out by reading the text from a python file
# which would make it easier to maintain larger modifications to builtins
# or a set of files to make this more portable or to modify the behavior
# of more builtins for debugging purposes.
customize_script = """
from inspect import getframeinfo,stack
def debug_printer(func):
# I made this so that output always gets flushed as it won't by default
# within the environment I'm running it in. Also it will print the
# file name and line number of where the print occurs
def debug_print(*args,**kwargs):
frame = getframeinfo(stack()[1][0])
return func(f"{frame.filename} : {frame.lineno} ", flush=True,*args,**kwargs)
return debug_print
__builtins__['print'] = debug_printer(print)
"""
# Creating the user site dir if it doesn't already exist and writing our
# custom behavior modifications
pathlib.Path(site.USER_SITE).mkdir(parents=True, exist_ok=True)
custom_file = os.path.join(site.USER_SITE,"usercustomize.py")
with open(custom_file,'w+') as f:
f.write(customize_script)
You can use usercustomize script from the site module to achieve something like this.
First, find out where your user site-packages directory is:
python3 -c "import site; print(site.USER_SITE)"
/home/foo/.local/lib/python3.6/site-packages
Next, in that directory, create a script called usercustomize.py - this script will now be run first whenever python is run.
One* way to replace print is to override the __builtins__ dict and replace it with a new method - something like:
from functools import partial
old_print = __builtins__['print']
__builtins__['print'] = partial(old_print, "Debug prefix: ", flush=True)
Drop this into the usercustomize.py script and you should see all python scripts from then on being overridden. You can temporarily disable calling this script by calling python with the -s flag.
*(Not sure if this is the correct way of doing this - there may be a better way - but the main point is that you can use usercustomize to deliver whatever method you choose).
There's no real reason to define a decorator here, because you are only intending to apply it to a single, predetermined function. Just define your modified print function directly, wrapping it around __builtins__.print to avoid recursion.
def print(*args, **kwargs):
__builtins.__print(f"some debug prefix: ", flush=True, *args, **kwargs)
print("Hello world") # Prints "some debug prefix Hello World"
You can use functools.partial to simplify this.
import functools
print = functools.partial(__builtins.__print, f"some debug prefix: ", flush=True)

Deciphering large program flow in Python

I'm in the process of learning how a large (356-file), convoluted Python program is set up. Besides manually reading through and parsing the code, are there any good methods for following program flow?
There are two methods which I think would be useful:
Something similar to Bash's "set -x"
Something that displays which file outputs each line of output
Are there any methods to do the above, or any other ways that you have found useful?
I don't know if this is actually a good idea, but since I actually wrote a hook to display the file and line before each line of output to stdout, I might as well give it to you…
import inspect, sys
class WrapStdout(object):
_stdout = sys.stdout
def write(self, buf):
frame = sys._getframe(1)
try:
f = inspect.getsourcefile(frame)
except TypeError:
f = 'unknown'
l = frame.f_lineno
self._stdout.write('{}:{}:{}'.format(f, l, buf))
def flush(self):
self._stdout.flush()
sys.stdout = WrapStdout()
Just save that as a module, and after you import it, every chunk of stdout will be prefixed with file and line number.
Of course this will get pretty ugly if:
Anyone tries to print partial lines (using stdout.write directly, or print magic comma in 2.x, or end='' in 3.x).
You mix Unicode and non-Unicode in 2.x.
Any of the source files have long pathnames.
etc.
But all the tricky deep-Python-magic bits are there; you can build on top of it pretty easily.
Could be very tedious, but using a debugger to trace the flow of execution, instruction by instruction could probably help you to some extent.
import pdb
pdb.set_trace()
You could look for a cross reference program. There is an old program called pyxr that does this. The aim of cross reference is to let you know how classes refer to each other. Some of the IDE's also do this sort of thing.
I'd recommend running the program inside an IDE like pydev or pycharm. Being able to stop the program and inspect its state can be very helpful.

Python failure injection

Is there a neat way to inject failures in a Python script? I'd like to avoid sprinkling the source code with stuff like:
failure_ABC = True
failure_XYZ = True
def inject_failure_ABC():
raise Exception('ha! a fake error')
def inject_failure_XYZ():
# delete some critical file
pass
# some real code
if failure_ABC:
inject_failure_ABC()
# some more real code
if failure_XYZ:
inject_failure_XYZ()
# even more real code
Edit:
I have the following idea: insert "failure points" as specially-crafted comments. The write a simple parser that will be called before the Python interpreter, and will produce the actual instrumented Python script with the actual failure code. E.g:
#!/usr/bin/parser_script_producing_actual_code_and_calls python
# some real code
# FAIL_123
if foo():
# FAIL_ABC
execute_some_real_code()
else:
# FAIL_XYZ
execute_some_other_real_code()
Anything starting with FAIL_ is considered as a failure point by the script, and depending on a configuration file the failure is enabled/disabled. What do you think?
You could use mocking libraries, for example unittest.mock, there also exist many third party ones as well. You can then mock some object used by your code such that it throws your exception or behaves in whatever way you want it to.
When testing error handling, the best approach is to isolate the code that can throw errors in a new method which you can override in a test:
class ToTest:
def foo(...):
try:
self.bar() # We want to test the error handling in foo()
except:
....
def bar(self):
... production code ...
In your test case, you can extend ToTest and override bar() with code that throws the exceptions that you want to test.
EDIT You should really consider splitting large methods into smaller ones. It will make the code easier to test, to understand and to maintain. Have a look at Test Driven Development for some ideas how to change your development process.
Regarding your idea to use "Failure Comments". This looks like a good solution. There is one small problem: You will have to write your own Python parser because Python doesn't keep comments when it produces bytecode.
So you can either spend a couple of weeks to write this or a couple of weeks to make your code easier to test.
There is one difference, though: If you don't go all the way, the parser will be useless. Also, the time spent won't have improved one bit of your code. Most of the effort will go into the parser and tools. So after all that time, you will still have to improve the code, add failure comments and write the tests.
With refactoring the code, you can stop whenever you want but the time spent so far will be meaningful and not wasted. Your code will start to get better with the first change you make and it will keep improving.
Writing a complex tool takes time and it will have it's own bugs which need to fix or work around. None of this will improve your situation in the short term and you don't have a guarantee that it will improve the long term.
If you only want to stop your code at some point, and fall back to interactive interpreter, one can use:
assert 1==0
But this only works if you do not run python with -O
Edit
Actually, my first answer was to quick, without really understanding what you want to do, sorry.
Maybe your code becomes already more readable if you do parameterization through parameters, not through variable/function suffices. Something like
failure = {"ABC": False, "XYZ":False}
#Do something, maybe set failure
def inject_failure(failure):
if not any(failure.values()):
return
if failure["ABC"]:
raise Exception('ha! a fake error')
elif failure["XYZ"]:
# delete some critical file
pass
inject_failure(failure)

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