I have a class A and i want a class B with exactly the same capabilities.
I cannot or do not want to inherit from B, such as doing class B(A):pass
Still i want B to be identical to A, yet have a different i: id(A) != id(B)
Watch out, i am not talking about instances but classes to be cloned.
I'm pretty sure whatever you are trying to do can be solved in a better way, but here is something that gives you a clone of the class with a new id:
def c():
class Clone(object):
pass
return Clone
c1 = c()
c2 = c()
print id(c1)
print id(c2)
gives:
4303713312
4303831072
I guess this is not what you wanted but its what the question seems to be asking for...
class Foo(object):
def bar(self):
return "BAR!"
cls = type("Bar", (object,), dict(Foo.__dict__))
print cls
x = cls()
print x.bar()
maybe i misunderstood you question but what about wrapping A in B?
class A:
def foo(self):
print "A.foo"
class B:
def __init__(self):
self._i = A()
def __getattr__(self, n):
return getattr(self._i, n)
You can clone the class via inheritance. Otherwise you are just passing around a reference to the class itself (rather than a reference to an instance of the class). Why would you want to duplicate the class anyway? It's obvious why you would want to create multiple instances of the class, but I can't fathom why you would want a duplicate class. Also, you could simply copy and paste with a new class name...
Related
I have a case, where I have an instance of a class in python which holds instances of other classes. For my use case, I would like a way to use the methods of the "inner" classes from the outer class without referencing the attribute holding the inner class.
I have made a simplistic example here:
class A:
def __init__(self):
pass
def say_hi(self):
print("Hi")
def say_goodbye(self):
print("Goodbye")
class C:
def __init__(self, other_instance):
self.other_instance= other_instance
def say_good_night(self):
print("Good night")
my_a = A()
my_c = C(other_instance=my_a)
# How to make this possible:
my_c.say_hi()
# Instead of
my_c.other_instance.say_hi()
Class inheritance is not possible, as the object passed to C may be an instance of a range of classes. Is this possible in Python?
I think this is the simplest solution although it is possible with metaprogramming.
class A:
def __init__(self):
pass
def say_hi(self):
print("Hi")
def say_goodbye(self):
print("Goodbye")
class C:
def __init__(self, other_class):
self.other_class = other_class
C._add_methods(other_class)
def say_good_night(self):
print("Good night")
#classmethod
def _add_methods(cls, obj):
type_ = type(obj)
for k, v in type_.__dict__.items():
if not k.startswith('__'):
setattr(cls, k, v)
my_a = A()
my_c = C(other_class=my_a)
my_c.say_hi()
output :
Hi
First we get the type of passed instance, then we iterate through it's attribute (because methods are attributes of the class not the instance).
If self.other_class is only needed for this purpose, you can omit it as well.
So, because you have done:
my_a = A() and my_c = C(other_class=my_a).
my_c.other_class is the same as my_a asthey point to the same location in memory.
Therefore, as you can do my_a.say_hi() you could also do my_c.other_class.say_hi().
Also, just a note, as you are calling A() before you store it into other_classes, I would probably rename the variable other_classes to class_instances.
Personally, I think that would make more sense, as each of those classes would have already been instantiated.
I'd like to be able to extend a class without inheriting one of the class variables.
Given this scenario:
class A:
aliases=['a','ay']
class B(A):
pass
print(B.aliases)
I would rather get an error that B has not defined the aliases variable rather than have B accidentally called ay.
One could imagine a solution where aliases becomes a member of the instantiated object (self.aliases) and is set in __init__ but I really want to be able to access the aliases using the cls object rather than an instance of the class.
Any suggestions?
Python does not have REALY private attributes. But you can define it with a double underscore (__):
class A:
__aliases=['a','ay']
class B(A):
pass
print(B.__aliases) # yields AttributeError
But you still will be able to access it with:
print(B._A__aliases)
This is kindof a ganky work around but here you go:
class K:
def __init__(self):
self.mems = dir(self)
def defaultMembers():
k = K()
return(k.mems)
class A:
aliases=['a','ay']
class B(A):
def __init__(self):
for k in set(dir(self))-set(defaultMembers()):
print("removing "+k)
setattr(self, k, None)
a = A()
b = B()
print(b.aliases)
#None
print(a.aliases)
#['a','ay']
I guess all you really need is the setattr(self, "aliases", None) still this results in a None and not a non-variable. Unfortunately calsses don't support deletion because I tried to use del first.
Toward the end of a program I'm looking to load a specific variable from all the instances of a class into a dictionary.
For example:
class Foo():
def __init__(self):
self.x = {}
foo1 = Foo()
foo2 = Foo()
...
Let's say the number of instances will vary and I want the x dict from each instance of Foo() loaded into a new dict. How would I do that?
The examples I've seen in SO assume one already has the list of instances.
One way to keep track of instances is with a class variable:
class A(object):
instances = []
def __init__(self, foo):
self.foo = foo
A.instances.append(self)
At the end of the program, you can create your dict like this:
foo_vars = {id(instance): instance.foo for instance in A.instances}
There is only one list:
>>> a = A(1)
>>> b = A(2)
>>> A.instances
[<__main__.A object at 0x1004d44d0>, <__main__.A object at 0x1004d4510>]
>>> id(A.instances)
4299683456
>>> id(a.instances)
4299683456
>>> id(b.instances)
4299683456
#JoelCornett's answer covers the basics perfectly. This is a slightly more complicated version, which might help with a few subtle issues.
If you want to be able to access all the "live" instances of a given class, subclass the following (or include equivalent code in your own base class):
from weakref import WeakSet
class base(object):
def __new__(cls, *args, **kwargs):
instance = object.__new__(cls, *args, **kwargs)
if "instances" not in cls.__dict__:
cls.instances = WeakSet()
cls.instances.add(instance)
return instance
This addresses two possible issues with the simpler implementation that #JoelCornett presented:
Each subclass of base will keep track of its own instances separately. You won't get subclass instances in a parent class's instance list, and one subclass will never stumble over instances of a sibling subclass. This might be undesirable, depending on your use case, but it's probably easier to merge the sets back together than it is to split them apart.
The instances set uses weak references to the class's instances, so if you del or reassign all the other references to an instance elsewhere in your code, the bookkeeping code will not prevent it from being garbage collected. Again, this might not be desirable for some use cases, but it is easy enough to use regular sets (or lists) instead of a weakset if you really want every instance to last forever.
Some handy-dandy test output (with the instances sets always being passed to list only because they don't print out nicely):
>>> b = base()
>>> list(base.instances)
[<__main__.base object at 0x00000000026067F0>]
>>> class foo(base):
... pass
...
>>> f = foo()
>>> list(foo.instances)
[<__main__.foo object at 0x0000000002606898>]
>>> list(base.instances)
[<__main__.base object at 0x00000000026067F0>]
>>> del f
>>> list(foo.instances)
[]
You would probably want to use weak references to your instances. Otherwise the class could likely end up keeping track of instances that were meant to have been deleted. A weakref.WeakSet will automatically remove any dead instances from its set.
One way to keep track of instances is with a class variable:
import weakref
class A(object):
instances = weakref.WeakSet()
def __init__(self, foo):
self.foo = foo
A.instances.add(self)
#classmethod
def get_instances(cls):
return list(A.instances) #Returns list of all current instances
At the end of the program, you can create your dict like this:
foo_vars = {id(instance): instance.foo for instance in A.instances}
There is only one list:
>>> a = A(1)
>>> b = A(2)
>>> A.get_instances()
[<inst.A object at 0x100587290>, <inst.A object at 0x100587250>]
>>> id(A.instances)
4299861712
>>> id(a.instances)
4299861712
>>> id(b.instances)
4299861712
>>> a = A(3) #original a will be dereferenced and replaced with new instance
>>> A.get_instances()
[<inst.A object at 0x100587290>, <inst.A object at 0x1005872d0>]
You can also solve this problem using a metaclass:
When a class is created (__init__ method of metaclass), add a new instance registry
When a new instance of this class is created (__call__ method of metaclass), add it to the instance registry.
The advantage of this approach is that each class has a registry - even if no instance exists. In contrast, when overriding __new__ (as in Blckknght's answer), the registry is added when the first instance is created.
class MetaInstanceRegistry(type):
"""Metaclass providing an instance registry"""
def __init__(cls, name, bases, attrs):
# Create class
super(MetaInstanceRegistry, cls).__init__(name, bases, attrs)
# Initialize fresh instance storage
cls._instances = weakref.WeakSet()
def __call__(cls, *args, **kwargs):
# Create instance (calls __init__ and __new__ methods)
inst = super(MetaInstanceRegistry, cls).__call__(*args, **kwargs)
# Store weak reference to instance. WeakSet will automatically remove
# references to objects that have been garbage collected
cls._instances.add(inst)
return inst
def _get_instances(cls, recursive=False):
"""Get all instances of this class in the registry. If recursive=True
search subclasses recursively"""
instances = list(cls._instances)
if recursive:
for Child in cls.__subclasses__():
instances += Child._get_instances(recursive=recursive)
# Remove duplicates from multiple inheritance.
return list(set(instances))
Usage: Create a registry and subclass it.
class Registry(object):
__metaclass__ = MetaInstanceRegistry
class Base(Registry):
def __init__(self, x):
self.x = x
class A(Base):
pass
class B(Base):
pass
class C(B):
pass
a = A(x=1)
a2 = A(2)
b = B(x=3)
c = C(4)
for cls in [Base, A, B, C]:
print cls.__name__
print cls._get_instances()
print cls._get_instances(recursive=True)
print
del c
print C._get_instances()
If using abstract base classes from the abc module, just subclass abc.ABCMeta to avoid metaclass conflicts:
from abc import ABCMeta, abstractmethod
class ABCMetaInstanceRegistry(MetaInstanceRegistry, ABCMeta):
pass
class ABCRegistry(object):
__metaclass__ = ABCMetaInstanceRegistry
class ABCBase(ABCRegistry):
__metaclass__ = ABCMeta
#abstractmethod
def f(self):
pass
class E(ABCBase):
def __init__(self, x):
self.x = x
def f(self):
return self.x
e = E(x=5)
print E._get_instances()
Another option for quick low-level hacks and debugging is to filter the list of objects returned by gc.get_objects() and generate the dictionary on the fly that way. In CPython that function will return you a (generally huge) list of everything the garbage collector knows about, so it will definitely contain all of the instances of any particular user-defined class.
Note that this is digging a bit into the internals of the interpreter, so it may or may not work (or work well) with the likes of Jython, PyPy, IronPython, etc. I haven't checked. It's also likely to be really slow regardless. Use with caution/YMMV/etc.
However, I imagine that some people running into this question might eventually want to do this sort of thing as a one-off to figure out what's going on with the runtime state of some slice of code that's behaving strangely. This method has the benefit of not affecting the instances or their construction at all, which might be useful if the code in question is coming out of a third-party library or something.
Here's a similar approach to Blckknght's, which works with subclasses as well. Thought this might be of interest, if someone ends up here. One difference, if B is a subclass of A, and b is an instance of B, b will appear in both A.instances and B.instances. As stated by Blckknght, this depends on the use case.
from weakref import WeakSet
class RegisterInstancesMixin:
instances = WeakSet()
def __new__(cls, *args, **kargs):
o = object.__new__(cls, *args, **kargs)
cls._register_instance(o)
return o
#classmethod
def print_instances(cls):
for instance in cls.instances:
print(instance)
#classmethod
def _register_instance(cls, instance):
cls.instances.add(instance)
for b in cls.__bases__:
if issubclass(b, RegisterInstancesMixin):
b._register_instance(instance)
def __init_subclass__(cls):
cls.instances = WeakSet()
class Animal(RegisterInstancesMixin):
pass
class Mammal(Animal):
pass
class Human(Mammal):
pass
class Dog(Mammal):
pass
alice = Human()
bob = Human()
cannelle = Dog()
Animal.print_instances()
Mammal.print_instances()
Human.print_instances()
Animal.print_instances() will print three objects, whereas Human.print_instances() will print two.
Using the answer from #Joel Cornett I've come up with the following, which seems to work. i.e. i'm able to total up object variables.
import os
os.system("clear")
class Foo():
instances = []
def __init__(self):
Foo.instances.append(self)
self.x = 5
class Bar():
def __init__(self):
pass
def testy(self):
self.foo1 = Foo()
self.foo2 = Foo()
self.foo3 = Foo()
foo = Foo()
print Foo.instances
bar = Bar()
bar.testy()
print Foo.instances
x_tot = 0
for inst in Foo.instances:
x_tot += inst.x
print x_tot
output:
[<__main__.Foo instance at 0x108e334d0>]
[<__main__.Foo instance at 0x108e334d0>, <__main__.Foo instance at 0x108e33560>, <__main__.Foo instance at 0x108e335a8>, <__main__.Foo instance at 0x108e335f0>]
5
10
15
20
(For Python)
I have found a way to record the class instances via the "dataclass" decorator while defining a class. Define a class attribute 'instances' (or any other name) as a list of the instances you want to record. Append that list with the 'dict' form of created objects via the dunder method __dict__. Thus, the class attribute 'instances' will record instances in the dict form, which you want.
For example,
from dataclasses import dataclass
#dataclass
class player:
instances=[]
def __init__(self,name,rank):
self.name=name
self.rank=rank
self.instances.append(self.__dict__)
I'm sorry for my silly question, but... let's suppose I have these classes:
class A():
msg = 'hehehe'
class B(A):
msg = 'hohoho'
class C(B):
pass
and an instance of B or C. How do I get the variable 'msg' from the parent's class object through this instance?
I've tried this:
foo = B()
print super(foo.__class__).msg
but got the message: "TypeError: super() argument 1 must be type, not classobj".
You actually want to use
class A(object):
...
...
b = B()
bar = super(b.__class__, b)
print bar.msg
Base classes must be new-style classes (inherit from object)
If the class is single-inherited:
foo = B()
print foo.__class__.__bases__[0].msg
# 'hehehe'
If the class is multiple-inherited, the question makes no sense because there may be multiple classes defining the 'msg', and they could all be meaningful. You'd better provide the actual parent (i.e. A.msg). Alternatively you could iterate through all direct bases as described in #Felix's answer.
Not sure why you want to do this
>>> class A(object):
... msg = 'hehehe'
...
>>> class B(A):
... msg = 'hohoho'
...
>>> foo=B()
>>> foo.__class__.__mro__[1].msg
'hehehe'
>>>
As msg is a class variable, you can just do:
print C.msg # prints hohoho
If you overwrite the variable (as you do in class B), you have to find the right parent class. Remember that Python supports multiple inheritance.
But as you define the classes and you now that B inherits from A you can always do this:
class B(A):
msg = 'hohoho'
def get_parent_message(self):
return A.msg
UPDATE:
The most reliable thing would be:
def get_parent_attribute(instance, attribute):
for parent in instance.__class__.__bases__:
if attribute in parent.__dict__:
return parent.__dict__[attribute]
and then:
foo = B()
print get_parent_attribute(foo, 'msg')
Try with:
class A(object):
msg = 'hehehe'
EDIT:
For the 'msg' attribute you would need:
foo = B()
bar = super(foo.__class__, foo)
print bar.msg
#for B() you can use __bases__
print foo.__class__.__bases__[0].msg
But this is not gonna be easy when there are multiple base classes and/or the depth of hierarchy is not one.
Lets say I have a library function that I cannot change that produces an object of class A, and I have created a class B that inherits from A.
What is the most straightforward way of using the library function to produce an object of class B?
edit- I was asked in a comment for more detail, so here goes:
PyTables is a package that handles hierarchical datasets in python. The bit I use most is its ability to manage data that is partially on disk. It provides an 'Array' type which only comes with extended slicing, but I need to select arbitrary rows. Numpy offers this capability - you can select by providing a boolean array of the same length as the array you are selecting from. Therefore, I wanted to subclass Array to add this new functionality.
In a more abstract sense this is a problem I have considered before. The usual solution is as has already been suggested- Have a constructor for B that takes an A and additional arguments, and then pulls out the relevant bits of A to insert into B. As it seemed like a fairly basic problem, I asked to question to see if there were any standard solutions I wasn't aware of.
This can be done if the initializer of the subclass can handle it, or you write an explicit upgrader. Here is an example:
class A(object):
def __init__(self):
self.x = 1
class B(A):
def __init__(self):
super(B, self).__init__()
self._init_B()
def _init_B(self):
self.x += 1
a = A()
b = a
b.__class__ = B
b._init_B()
assert b.x == 2
Since the library function returns an A, you can't make it return a B without changing it.
One thing you can do is write a function to take the fields of the A instance and copy them over into a new B instance:
class A: # defined by the library
def __init__(self, field):
self.field = field
class B(A): # your fancy new class
def __init__(self, field, field2):
self.field = field
self.field2 = field2 # B has some fancy extra stuff
def b_from_a(a_instance, field2):
"""Given an instance of A, return a new instance of B."""
return B(a_instance.field, field2)
a = A("spam") # this could be your A instance from the library
b = b_from_a(a, "ham") # make a new B which has the data from a
print b.field, b.field2 # prints "spam ham"
Edit: depending on your situation, composition instead of inheritance could be a good bet; that is your B class could just contain an instance of A instead of inheriting:
class B2: # doesn't have to inherit from A
def __init__(self, a, field2):
self._a = a # using composition instead
self.field2 = field2
#property
def field(self): # pass accesses to a
return self._a.field
# could provide setter, deleter, etc
a = A("spam")
b = B2(a, "ham")
print b.field, b.field2 # prints "spam ham"
you can actually change the .__class__ attribute of the object if you know what you're doing:
In [1]: class A(object):
...: def foo(self):
...: return "foo"
...:
In [2]: class B(object):
...: def foo(self):
...: return "bar"
...:
In [3]: a = A()
In [4]: a.foo()
Out[4]: 'foo'
In [5]: a.__class__
Out[5]: __main__.A
In [6]: a.__class__ = B
In [7]: a.foo()
Out[7]: 'bar'
Monkeypatch the library?
For example,
import other_library
other_library.function_or_class_to_replace = new_function
Poof, it returns whatever you want it to return.
Monkeypatch A.new to return an instance of B?
After you call obj = A(), change the result so obj.class = B?
Depending on use case, you can now hack a dataclass to arguably make the composition solution a little cleaner:
from dataclasses import dataclass, fields
#dataclass
class B:
field: int # Only adds 1 line per field instead of a whole #property method
#classmethod
def from_A(cls, a):
return cls(**{
f.name: getattr(a, f.name)
for f in fields(A)
})