I have a python script that has to fetch unseen messages, process it, and mark as seen (or read)
I do this after login in:
typ, data = self.server.imap_server.search(None, '(UNSEEN)')
for num in data[0].split():
print "Mensage " + str(num) + " mark"
self.server.imap_server.store(num, '+FLAGS', '(SEEN)')
The first problem is that, the search returns ALL messages, and not only the UNSEEN.
The second problem is that messages are not marked as SEEN.
Can anybody give me a hand with this?
Thanks!
import imaplib
obj = imaplib.IMAP4_SSL('imap.gmail.com', '993')
obj.login('user', 'password')
obj.select('Inbox') <--- it will select inbox
typ ,data = obj.search(None,'UnSeen')
obj.store(data[0].replace(' ',','),'+FLAGS','\Seen')
I think the flag names need to start with a backslash, eg: \SEEN
I am not so familiar with the imaplib but I implement this well with the imapclient module
import imapclient,pyzmail,html2text
from backports import ssl
context=ssl.SSLContext(ssl.PROTOCOL_TLSv1_2)
iobj=imapclient.IMAPClient('outlook.office365.com', ssl=True, ssl_context=context)
iobj.login(uname,pwd)# provide your username and password
iobj.select_folder('INBOX',readonly=True)# Selecting Inbox.
unread=iobj.search('UNSEEN')# Selecting Unread messages, you can add more search criteria here to suit your purpose.'FROM', 'SINCE' etc.
print('There are: ',len(unread),' UNREAD emails')
for i in unread:
mail=iobj.fetch(i,['BODY[]'])#I'm fetching the body of the email here.
mcontent=pyzmail.PyzMessage.factory(mail[i][b'BODY[]'])#This returns the email content in HTML format
subject=mcontent.get_subject()# You might not need this
receiver_name,receiver_email=mcontent.get_address('from')
mail_body=html2text.html2text(mcontent.html_part.get_payload().decode(mcontent.html_part.charset))# This returns the email content as text that you can easily relate with.
Let's say I want to just go through the unread emails, reply the sender and mark the email as read. I'd call the smtp function from here to compose and send a reply.
import smtplib
smtpobj=smtplib.SMTP('smtp.office365.com',587)
smtpobj.starttls()
smtpobj.login(uname,pwd)# Your username and password goes here.
sub='Subject: '+str(subject)+'\n\n'# Subject of your reply
msg='Thanks for your email! You're qualified for the next round' #Some random reply :(
fullmsg=sub+new_result
smtpobj.sendmail(uname,test,fullmsg)# This sends the email.
iobj.set_flags(i,['\\Seen','\\Answered'])# This marks the email as read and adds the answered flag
iobj.append('Sent Items', fullmsg)# This puts a copy of your reply in your Sent Items.
iobj.logout()
smtpobj.logout()
I hope this helps
Related
I'm sending emails with pyramid_mailer and found this weird issue that when I use Office365 as my SMTP server it adds random = characters into my message. I don't get that issue with any other mail server (I tested this with gmail and also with my own postfix server)
I send emails like below:
from pyramid_mailer.mailer import Mailer
from pyramid_mailer.message import Attachment, Message
mailer = Mailer()
mailer.smtp_mailer.hostname = "test.mail.at.office365"
mailer.smtp_mailer.username = "my_user"
mailer.smtp_mailer.password = "secret"
mailer.smtp_mailer.port = 587
mailer.smtp_mailer.tls = True
message = Message(
subject="Test",
sender="my_user#my_domain.com",
recipients="test_user#test_domain.com",
body="very long text, at least 75 characters long so Office 365 will break it and insert annoying '=' into message",
html="very long text, at least 75 characters long so Office 365 will break it and insert annoying '=' into message",
)
mailer.send_immediately(message)
I searched on google and found this has something to do with line breaks and Transfer-Content-Encoding. And indeed, if I add \r\n every ~50 characters I won't see = added. But the problem is that I might want to send a hyperlink that will be longer than that...
Pyramid documentation (https://docs.pylonsproject.org/projects/pyramid_mailer/en/latest/) says I can use Attachment rather than plain string. And indeed as soon as I do that I can set this Transfer-Content-Encoding to something like base64 (as suggested here: https://jeremytunnell.com/2009/01/04/really-hairy-problem-with-seemingly-random-crlf-and-spaces-inserted-in-emails/) but my message then shows as attachment, not as regular message...
There seems to be no way to add this Transfer-Content-Encoding to Message object... I tried to use Message.extra_headers = {'Transfer-Content-Encoding': 'base64'} but this did not help.
I'm totally out of ideas, would appreciate any help...
-- Edit --
Thanks to answer below from #Mess:
from pyramid_mailer.message import Attachment
my_message = "very long text, at least 75 characters long so Office 365 will break it and insert annoying '=' into message"
body_html = Attachment(data=my_message, transfer_encoding="base64", disposition='inline')
body_text = Attachment(data=my_message, transfer_encoding="base64", disposition='inline')
Then pass body_html and body_text to Message constructor.
This is "Content-Disposition" header you need to set to control how the content is available to the recipient.
Set it to "attachment" to let download the file, use "inline" to be able to include the content, for example a logo, directly to your email, etc:
https://developer.mozilla.org/en-US/docs/Web/HTTP/Headers/Content-Disposition
I hope it will point you to the right direction.
EDIT:
Using pyramid_mailer package it would be something like:
from pyramid_mailer.message import Attachment
attachment = Attachment(data=some_data, transfer_encoding="base64", disposition='inline')
We're currently using a super basic Python script that I found online a while ago to send an error report via HTML from out departmental email address. However, as it currently stands, it sends the email from our email address to our email address. I'm hoping there might be some way to send the email from the address of the current user. Here's what we've got:
def sendMail(sender, recipient, subject, html, text):
import MimeWriter, mimetools, cStringIO
import smtplib
out = cStringIO.StringIO()
htmlin = cStringIO.StringIO(html)
txtin = cStringIO.StringIO(text)
writer = MimeWriter.MimeWriter(out)
writer.addheader("From", sender)
writer.addheader("To", recipient)
writer.addheader("Subject", subject)
writer.addheader("MIME-Version", "1.0")
writer.startmultipartbody("alternative")
writer.flushheaders()
subpart = writer.nextpart()
subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
pout = subpart.startbody("text/plain", [("charset", 'us-ascii')])
mimetools.encode(txtin, pout, 'quoted-printable')
txtin.close()
subpart = writer.nextpart()
subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
pout = subpart.startbody("text/html", [("charset", 'us-ascii')])
mimetools.encode(htmlin, pout, 'quoted-printable')
htmlin.close()
writer.lastpart()
msg = out.getvalue()
server = smtplib.SMTP('smtp.office365.com',587)
server.ehlo()
server.starttls()
server.ehlo()
server.login("sample#email.com","sample")
server.sendmail(sender, recipient, msg)
server.quit()
Then we're using a simple try/except execfile script to run everything from:
try:
execfile('\\\\path.py')
except:
print 'ATTENTION: An error has been detected in a script process.'
traceback.print_exc(file=sys.stdout)
import sys, cgitb
recipient =
['sample#email.com','sample2#email.com','sample3#email.com','sample4#email.com']
for rec in recipient:
Utils.sendMail('sample#email.com',
rec,
'ATTENTION: An error has been detected in a script process...',
cgitb.html(sys.exc_info()),
cgitb.text(sys.exc_info()))
sys.exit()
It's here where we define the address we're sending to:
for rec in recipient:
Utils.sendMail('sample#email.com',
rec,
'ATTENTION: An error has been detected in a script process...',
cgitb.html(sys.exc_info()),
cgitb.text(sys.exc_info()))
sys.exit()
Is there some kind of AD script we can implement here? We've got about 30 people using our processes so whenever an error pops up all we get is an email with the error and no reference to who it belongs to.
It is not easy to work with AD in Python, and it's even tougher to do without installing any 3rd party modules.
Would adding the username that ran the script in the email body or subject suffice instead?:
import getpass
user = getpass.getuser()
Then in the execfile script:
Utils.sendMail(
'sample#email.com',
rec,
'ATTENTION: %s has run a script which has errored...' % user,
cgitb.html(sys.exc_info()),
cgitb.text(sys.exc_info())
)
It is important to note that this should not be used for any legitimate authentication purposes, as it does not protect against user-spoofing and the likes..
Sounds like you need to group you recipients i.e. you could have a group for engineers, quality assurance, business development, management, etc..
where each group is represented by a list of email addresses.
This way when an error occurs, you may send a human readable email describing the issue to the quality assurance group.
As for the engineers, you may want to send a more technical email that not only contains the human readable error descriptions, but also an additional stack trace. When an engineer is attempting to troubleshoot an error message more, is better.
As for the business development and management group, they probably shouldn't be receiving emails on failures.
hope that helps.
I am trying to write a python script to send an email that uses html formatting and involves a lot of non-breaking spaces. However, when I run it, some of the   strings are interrupted by spaces that occur every 171 characters, as can be seen by this example:
#!/usr/bin/env python
import smtplib
import socket
from email.mime.text import MIMEText
emails = ["my#email.com"]
sender = "test#{0}".format(socket.gethostname())
message = "<html><head></head><body>"
for i in range(20):
message += " " * 50
message += "<br/>"
message += "</body>"
message = MIMEText(message, "html")
message["Subject"] = "Test"
message["From"] = sender
message["To"] = ", ".join(emails)
mailer = smtplib.SMTP("localhost")
mailer.sendmail(sender, emails, message.as_string())
mailer.quit()
The example should produce a blank email that consists of only spaces, but it ends up looking something like this:
  ;
&nb sp;
& nbsp;
&nbs p;
&n bsp;
Edit: In case it is important, I am running Ubuntu 15.04 with Postfix for the smtp client, and using python2.6.
I can replicate this in a way but my line breaks come every 999 characters. RFC 821 says maximum length of a line is 1000 characters including the line break so that's probably why.
This post gives a different way to send a html email in python, and i believe the mime type "multipart/alternative" is the correct way.
Sending HTML email using Python
I'm the developer of yagmail, a package that tries to make it easy to send emails.
You can use the following code:
import yagmail
yag = yagmail.SMTP('me#gmail.com', 'mypassword')
for i in range(20):
message += " " * 50
message += "<br/>"
yag.send(contents = message)
Note that by default it will send a HTML message, and that it also adds automatically the alternative part for non HTML browsers.
Also, note that omitting the subject will leave an empty subject, and without a to argument it will send it to self.
Furthermore, note that if you set yagmail up correctly, you can just login using yag.SMTP(), without having to have username & password in the script (while still being secure). Omitting the password will prompt a getpass.
Adding an attachment is as simple as pointing to a local file, e.g.:
yag.send(contents = [message, 'previously a lot of whitespace', '/local/path/file.zip']
Awesome isn't it? Thanks for the allowing me to show a nice use case for yagmail :)
If you have any feature requests, issues or ideas please let me know at github.
I'm using SendGrid to send emails from my python-based Heroku app.I'm okay with it taking 10 or so minutes to get to my inbox, but I'm receiving three copies of the message and I can't figure out why. Here is the relevant code:
import sendgrid
from sendgrid import SendGridError, SendGridClientError, SendGridServerError
sg = sendgrid.SendGridClient('xxx#heroku.com', 'xxx')
message = sendgrid.Mail()
message.add_to('John Doe <xxx#xxx.com>')
message.set_subject('Example')
message.set_html('Body')
message.set_text('Body')
message.set_from('Dark Knight <xxx#xxx.com>')
message.add_attachment('image.jpg', './image.jpg')
status, msg = sg.send(message)
#app.route('/test2')
def test2():
sg.send(message)
return "sent"
When I go to the relevant route I get 'sent' returned and the email is sent, but again, it send three copies. I'm not sure why. Any help would be great.
Emails one and two:
status, msg = sg.send(message) would send two emails and then set status and msg to the response object.
Email three: after you load the route sg.send(message) sends the next email.
I suggest you to use sendgrid sendmail api to send email. its efficient, fast way to send emails.
You are calling sg.send(message) three times in your code.
It is called twice here: status, msg = sg.send(message) - this will send one mail for status and log it's response to that variable. It will then send again for msg and log it's response to that variable as well.
Then when the user hits the /test2 the function is called again, making it three messages in total.
Here's how you might change it to log responses but just send the one message out:
import sendgrid
from sendgrid import SendGridError, SendGridClientError, SendGridServerError
sg = sendgrid.SendGridClient('xxx#heroku.com', 'xxx')
def sendMessage(options):
message = sendgrid.Mail()
message.add_to('John Doe <xxx#xxx.com>')
message.set_subject('Example')
message.set_html('Body')
message.set_text('Body')
message.set_from('Dark Knight <xxx#xxx.com>')
message.add_attachment('image.jpg', './image.jpg')
// send the message and log the results to status
msg = sg.send(message)
return msg
#app.route('/test2')
def test2():
// send the message, pass any options like email address (not required)
status = sendMessage(options)
return status
I've added a new function above to send out the message and given it an optional options var, so you could use that to pass things to the message, like a different email address, or subject.
I'm using the following code to export all the emails in a specific gmail folder.
Its working well, in that its pulling out all the emails I expect, but it (or me) seems to be mangle the encoding for CR / newlines.
Code:
import imaplib
import email
import codecs
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login('myUser#gmail.com', 'myPassword') #user / password
mail.list()
mail.select("myFolder") # connect to folder with matching label
result, data = mail.uid('search', None, "ALL") # search and return uids instead
i = len(data[0].split())
for x in range(i):
latest_email_uid = data[0].split()[x]
result, email_data = mail.uid('fetch', latest_email_uid, '(RFC822)')
raw_email = email_data[0][1]
email_message = email.message_from_string(raw_email)
save_string = str("C:\\\googlemail\\boxdump\\email_" + str(x) + ".eml") #set to save location
myfile = open(save_string, 'a')
myfile.write(email_message)
myfile.close()
My problem is that by the time I get to the object its littered with '=0A', which I am assuming are incorrectly interpreted newline or carriage return flag.
I can find it in hex, [d3 03 03 0a] but because this is not 'characters' I can't find a way for str.replace() to take the parts out. I don't actually want the newline flags.
I could convert the whole string to hex, and do a do a replace of sorts / regex thing, but that seems like over kill - when the problem is in the encoding / reading of the source data
What I see:
====
CAUTION: This email message and any attachments con= tain information that may be confidential and may be LEGALLY PRIVILEGED. If yo= u are not the intended recipient, any use, disclosure or copying of this messag= e or attachments is strictly prohibited. If you have received this email messa= ge in error please notify us immediately and erase all copies of the message an= d attachments. Thank you.
====
what I want:
====
CAUTION: This email message and any attachments contain information that may be confidential and may be LEGALLY PRIVILEGED. If you are not the intended recipient, any use, disclosure or copying of this message or attachments is strictly prohibited. If you have received this email message in error please notify us immediately and erase all copies of the message and attachments. Thank you.
====
What you are looking at is Quoted Printable encoding.
Try changing:
email_message = email.message_from_string(raw_email)
to:
email_message = str(email.message_from_string(raw_email)).decode("quoted-printable")
For more info see Standard Encodings in the Python codecs module.
Just 2 additional items having gone thought the pain of this for a day.
1 do it at the payload level so you can process your email_message to get email addresses etc from your mail.
2 You need to decode the charset set also, I had trouble with people copying and pasting html from webpages and content from word docs etc into emails that I was then trying to process.
if maintype == 'multipart':
for part in email_message.get_payload():
if part.get_content_type() == 'text/plain':
text += part.get_payload().decode("quoted-printable").decode(part.get_content_charset())
Hope this helps someone !
Dave