I can't figure out why this isn't working. I'm trying to send an email from my school email address with this code I got online. The same code works for sending from my GMail address. Does anyone know what this error means? The error occurs after waiting for about one and a half minutes.
import smtplib
FROMADDR = "FROM_EMAIL"
LOGIN = "USERNAME"
PASSWORD = "PASSWORD"
TOADDRS = ["TO_EMAIL"]
SUBJECT = "Test"
msg = ("From: %s\r\nTo: %s\r\nSubject: %s\r\n\r\n"
% (FROMADDR, ", ".join(TOADDRS), SUBJECT) )
msg += "some text\r\n"
server = smtplib.SMTP('OUTGOING_SMTP', 465)
server.set_debuglevel(1)
server.ehlo()
server.starttls()
server.login(LOGIN, PASSWORD)
server.sendmail(FROMADDR, TOADDRS, msg)
server.quit()
And here's the error I get:
Traceback (most recent call last):
File "emailer.py", line 13, in
server = smtplib.SMTP('OUTGOING_SMTP', 465)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 239, in init
(code, msg) = self.connect(host, port)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 295, in connect
self.sock = self._get_socket(host, port, self.timeout)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 273, in _get_socket
return socket.create_connection((port, host), timeout)
File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 514, in create_connection
raise error, msg
socket.error: [Errno 60] Operation timed out
It's likely that your school's SMTP server does not permit outside access to port 587. Gmail does, and requires authentication to ensure that you are who you say you are (and so that spammers can't send email appearing to be from you unless they know your password). Your school may have chosen to set up their mail server so that only connections from within the school can send mail in this way.
Related
When trying to send the email with the host:cpanel.freehosting.com
P it is raising an error like
This is my code:
import smtplib
s = smtplib.SMTP('cpanel.freehosting.com', 465)
s.starttls()
s.login("myusername", "mypassword")
message = "Message_you_need_to_send"
s.sendmail("myemailid", "receiver_email_id", message)
s.quit()
This is the error i got:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python3.5/smtplib.py", line 251, in __init__
(code, msg) = self.connect(host, port)
File "/usr/lib/python3.5/smtplib.py", line 337, in connect
(code, msg) = self.getreply()
File "/usr/lib/python3.5/smtplib.py", line 393, in getreply
raise SMTPServerDisconnected("Connection unexpectedly closed")
smtplib.SMTPServerDisconnected: Connection unexpectedly closed
Considering the port number you are using I'd try with SMTP_SSL instead of SMTP and starttls().
https://docs.python.org/3/library/smtplib.html:
An SMTP_SSL instance behaves exactly the same as instances of SMTP.
SMTP_SSL should be used for situations where SSL is required from the
beginning of the connection and using starttls() is not appropriate.
If host is not specified, the local host is used. If port is zero, the
standard SMTP-over-SSL port (465) is used.
STARTTLS is a form of opportunistic TLS, it is supposed to be used with old protocols, that originally did't support TLS, to upgrade the connection.
The port 465 was used before the introduction of STARTTLS for SMTPS, which is now deprecated.
import smtplib
s = smtplib.SMTP_SSL('cpanel.freehosting.com', 465)
s.login("myusername", "mypassword")
message = "Message_you_need_to_send"
s.sendmail("myemailid", "receiver_email_id", message)
s.quit()
Alternatively you should be able to use port 25 with your original code.
import smtplib
s = smtplib.SMTP('cpanel.freehosting.com', 25)
s.starttls()
s.login("myusername", "mypassword")
message = "Message_you_need_to_send"
s.sendmail("myemailid", "receiver_email_id", message)
s.quit()
In both examples you can completely omit the port number as you are using the default ports.
Hi I am trying to send an email through python. I use this code to send:
server = smtplib.SMTP(host='send.one.com',port=465)
server.starttls()
server.login(USER, PASS)
text = msg.as_string()
server.sendmail(mailFrom, mailTo, text)
server.quit()
but I get an error on the first line:
File "/home/emil/Name_Generator/VoteMail.py", line 69, in sendVoteMail
server = smtplib.SMTP(host='send.one.com',port=465)
File "/usr/lib/python3.4/smtplib.py", line 242, in __init__
(code, msg) = self.connect(host, port)
File "/usr/lib/python3.4/smtplib.py", line 323, in connect
(code, msg) = self.getreply()
File "/usr/lib/python3.4/smtplib.py", line 376, in getreply
raise SMTPServerDisconnected("Connection unexpectedly closed")
smtplib.SMTPServerDisconnected: Connection unexpectedly closed
Has anyone else tried to connect to one.com smtp server with Python?
For everyone else that use one.com for your email and you want to connect to theire SMTP server thene I found out that they use SSL, and that was why my code did't work the proper way to do it is as follow:
server = smtplib.SMTP_SSL(host='send.one.com',port=465)
server.login(USER, PASS)
text = msg.as_string()
server.sendmail(mailFrom, mailTo, text)
server.quit()
I am trying to send an email form my server with python, I asked my server provider what port to use for this and they said "choose SMTP Ports 465 (Secure SSL/TLS outgoing server) , 25 ( Non-SSL outgoing server)." Not sure what this exactly means but currently I am using 25, here is my code
#! /usr/bin/python
import smtplib
import smtplib
server = smtplib.SMTP('smtp.gmail.com', 25)
#Next, log in to the server
server.login("youremailusername", "password")
#Send the mail
msg = "\nHello!" # The /n separates the message from the headers
server.sendmail("you#gmail.com", "target#example.com", msg)
I filled in my username (which is my email address right) and password,a dn the target but it is not working, when I try to navigate to the url where my py script is, it just doesn't load. I have an internet connection cause I am loving other things, and go to other pages on my server. I have also tried running with cron jobs but that also doesn't work.
The permissions on the script are 0755, is there a problem with the script?
When i ran with cron jobs here is the traceback
Traceback (most recent call last):
File "/home/spencerf/public_html/cgi-bin/send_email.py", line 6, in <module>
server = smtplib.SMTP('smtp.gmail.com', 25)
File "/usr/lib64/python2.6/smtplib.py", line 239, in __init__
(code, msg) = self.connect(host, port)
File "/usr/lib64/python2.6/smtplib.py", line 295, in connect
self.sock = self._get_socket(host, port, self.timeout)
File "/usr/lib64/python2.6/smtplib.py", line 273, in _get_socket
return socket.create_connection((port, host), timeout)
File "/usr/lib64/python2.6/socket.py", line 567, in create_connection
raise error, msg
socket.error: [Errno 101] Network is unreachable
Thanks for the help in advance.
EDIT
here is updated error log with the port at 587
Traceback (most recent call last):
File "/home/spencerf/public_html/cgi-bin/send_email.py", line 7, in <module>
server = smtplib.SMTP('smtp.gmail.com', 587)
File "/usr/lib64/python2.6/smtplib.py", line 239, in __init__
(code, msg) = self.connect(host, port)
File "/usr/lib64/python2.6/smtplib.py", line 295, in connect
self.sock = self._get_socket(host, port, self.timeout)
File "/usr/lib64/python2.6/smtplib.py", line 273, in _get_socket
return socket.create_connection((port, host), timeout)
File "/usr/lib64/python2.6/socket.py", line 567, in create_connection
raise error, msg
socket.error: [Errno 101] Network is unreachable
EDIT 2
When I had server = smtplib.SMTP('telnet smtp.gmail.com', 587)
I got this error
Traceback (most recent call last):
File "/home/spencerf/public_html/cgi-bin/send_email.py", line 8, in <module>
server = smtplib.SMTP('telnet smtp.gmail.com', 587)
File "/usr/lib64/python2.6/smtplib.py", line 239, in __init__
(code, msg) = self.connect(host, port)
File "/usr/lib64/python2.6/smtplib.py", line 295, in connect
self.sock = self._get_socket(host, port, self.timeout)
File "/usr/lib64/python2.6/smtplib.py", line 273, in _get_socket
return socket.create_connection((port, host), timeout)
File "/usr/lib64/python2.6/socket.py", line 553, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
socket.gaierror: [Errno -2] Name or service not known
BUG:
First of all you are using gmail server not your company server to send mail .For gmail server the output port is 587
The code:
Due to security issues gmail blocks accessing mail via code or program
But still you can use gmail to send mail via code if you do the following things
What i have done in code :
1.Added a error object to get the error message
import smtplib
try:
server = smtplib.SMTP('smtp.gmail.com', 587)
#Next, log in to the server
server.login("youremailusername", "password")
#Send the mail
msg = "\nHello!" # The /n separates the message from the headers
server.sendmail("you#gmail.com", "target#example.com", msg)
print "Successfully sent email"
except smtplib.SMTPException,error:
print str(error)
print "Error: unable to send email"
If u ran this code u would see a error message like this stating that google is not allowing u to login via code
Things to change in gmail:
1.Login to gmail
2.Go to this link https://www.google.com/settings/security/lesssecureapps
3.Click enable then retry the code
Hopes it help :)
But there are security threats if u enable it
Updated
import smtplib
try:
content = 'test'
mail = smtplib.SMTP('smtp.gmail.com',587)
mail.ehlo()
mail.starttls()
mail.login("ABC#gmail.com", "password")
mail.sendmail("ABC#gmail.com", "recivermailaddress", content)
mail.quit
print "Successfully sent email"
except smtplib.SMTPException,error:
print str(error)
In python, please download yagmail (disclaimer: I'm the developer):
pip install yagmail
It is then simply a matter of:
import yagmail
yag = yagmail.SMTP("you#gmail.com", "password")
yag.send("target#example.com", 'This is the subject', 'Hello!')
I guess it mostly just has to do with the fact that you gave a wrong port (smtp.gmail.com is not at 25).
On the github you can also see a common list of errors.
I tried this with Verizon and Gmail. Both servers denied authentication. Gmail emailed me that it denied a login attempt because the connection was not using "modern security".
I would like to know how I can use modern security with this logging handler.
logging.handlers.SMTPHandler(mailhost=('', 25),
fromaddr='',
toaddrs='',
subject='',
credentials=('username','password'),
secure=())
For anyone coming back to this, here is how I got the SMTPHandler working with Gmail:
eh = SMTPHandler(mailhost=('smtp.gmail.com', 587),
fromaddr=from_addr,
toaddrs=to_addrs,
subject=subject,
credentials=(username, password),
secure=())
The to_addrs variable is a string in my example. I am not sure if it can be an array or is supposed to be a space or comma-delimited string. The username variable includes the domain, like this: foo#gmail.com.
Most guides said to use port 465, here is the difference if you are curious. However, when I tried to use port 465, I got a SMTP timeout error:
Traceback (most recent call last):
File "/usr/local/lib/python3.5/smtplib.py", line 386, in getreply
line = self.file.readline(_MAXLINE + 1)
File "/usr/local/lib/python3.5/socket.py", line 571, in readinto
return self._sock.recv_into(b)
socket.timeout: timed out
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/usr/local/lib/python3.5/logging/handlers.py", line 972, in emit
smtp = smtplib.SMTP(self.mailhost, port, timeout=self.timeout)
File "/usr/local/lib/python3.5/smtplib.py", line 251, in __init__
(code, msg) = self.connect(host, port)
File "/usr/local/lib/python3.5/smtplib.py", line 337, in connect
(code, msg) = self.getreply()
File "/usr/local/lib/python3.5/smtplib.py", line 390, in getreply
+ str(e))
smtplib.SMTPServerDisconnected: Connection unexpectedly closed: timed out
I switched to port 587 and Google successfully authenticated. The messages were sent.
Gmail problem:
Not addressed here. See other answers about Gmail's app authentication.
Verizon problem:
Some mail submission servers may only accept SMTPS on port 465. See What is the difference between ports 465 and 587? for elaboration. The Verizon mail submission server smtp.verizon.net, is one such example.
SMTPHandler does not support SMTPS by default. You can monkeypatch the functionality.
Solution:
This forces any server to use SMTPS.
A more thorough fix would be to edit the class with a flag to enable SMTPS.
Paste the edited emit function from below, into the relevant file.
Then set it
logging.handlers.SMTPHandler.emit = emit
The default /logging/handlers.py logging.handlers.SMTPHandler.emit function
# Class SMTPHandler...
def emit(self, record):
"""
Emit a record.
Format the record and send it to the specified addressees.
"""
try:
import smtplib
from email.utils import formatdate
port = self.mailport
if not port:
port = smtplib.SMTP_PORT
smtp = smtplib.SMTP(self.mailhost, port, timeout=self._timeout)
msg = self.format(record)
msg = "From: %s\r\nTo: %s\r\nSubject: %s\r\nDate: %s\r\n\r\n%s" % (
self.fromaddr,
",".join(self.toaddrs),
self.getSubject(record),
formatdate(), msg)
if self.username:
if self.secure is not None:
smtp.ehlo()
smtp.starttls(*self.secure)
smtp.ehlo()
smtp.login(self.username, self.password)
smtp.sendmail(self.fromaddr, self.toaddrs, msg)
smtp.quit()
except (KeyboardInterrupt, SystemExit):
raise
except:
self.handleError(record)
The edited emit function
def emit(self, record):
"""
Overwrite the logging.handlers.SMTPHandler.emit function with SMTP_SSL.
Emit a record.
Format the record and send it to the specified addressees.
"""
try:
import smtplib
from email.utils import formatdate
port = self.mailport
if not port:
port = smtplib.SMTP_PORT
smtp = smtplib.SMTP_SSL(self.mailhost, port, timeout=self._timeout)
msg = self.format(record)
msg = "From: %s\r\nTo: %s\r\nSubject: %s\r\nDate: %s\r\n\r\n%s" % (self.fromaddr, ", ".join(self.toaddrs), self.getSubject(record), formatdate(), msg)
if self.username:
smtp.ehlo()
smtp.login(self.username, self.password)
smtp.sendmail(self.fromaddr, self.toaddrs, msg)
smtp.quit()
except (KeyboardInterrupt, SystemExit):
raise
except:
self.handleError(record)
I try to send mail via python. I got a function:
def mail():
fromaddr = 'mymail#gmail.com'
toaddrs = 'targetmail#o2.pl'
msg = 'There was a terrible error that occured and I wanted you to know!'
# Credentials (if needed)
username = 'mymail#gmail.com'
password = 'password'
# The actual mail send
server = smtplib.SMTP('smtp.gmail.com:587')
server.ehlo()
server.starttls()
server.ehlo()
server.login(username,password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()
When I try to execute this function it whows me WinError 10060. Error text below:
Traceback (most recent call last):
File "C:\python-factory\ServiceChecker\main\mainBlock.py", line 75, in <module> mail()
File "C:\python-factory\ServiceChecker\main\mainBlock.py", line 65, in mail server = smtplib.SMTP('smtp.gmail.com:587')
File "C:\Python34\Lib\smtplib.py", line 242, in __init__ (code, msg) = self.connect(host, port)
File "C:\Python34\Lib\smtplib.py", line 321, in connect self.sock = self._get_socket(host, port, self.timeout)
File "C:\Python34\Lib\smtplib.py", line 292, in _get_socket self.source_address)
File "C:\Python34\Lib\socket.py", line 509, in create_connection raise err
File "C:\Python34\Lib\socket.py", line 500, in create_connection sock.connect(sa)
TimeoutError: [WinError 10060]
I don't know where is problem... i tried many mail servers (gmail,o2,wp,) all of them returned the same error. I tried also other available solutions in the internet to send mail via pyython.... the same problem...
Please help
According to your posted backtrace, you are failing at the line
server = smtplib.SMTP('smtp.gmail.com:587')
I've run that line and it works for me. The clue is in the TimeoutError. I believe you are having networking problems and the code itself is fine.
You do have an extra call to ehlo but as it stands you are not getting that far.
Additionally, it would probably be better to pass the port number as a separate argument, rather than using a colon to split it. E.g.
server = smtplib.SMTP(host='smtp.gmail.com', port=587)
The documentation for smptlib is here: https://docs.python.org/2/library/smtplib.html
Try removing the second server.ehlo() . The one just before login. That worked for me.
toaddrs should be a list
toaddrs = ['targetmail#o2.pl']