How can I discover classes in a specific package in python? - python

I have a package of plug-in style modules. It looks like this:
/Plugins
/Plugins/__init__.py
/Plugins/Plugin1.py
/Plugins/Plugin2.py
etc...
Each .py file contains a class that derives from PluginBaseClass. So I need to list every module in the Plugins package and then search for any classes that implement PluginBaseClass. Ideally I want to be able to do something like this:
for klass in iter_plugins(project.Plugins):
action = klass()
action.run()
I have seen some other answers out there, but my situation is different. I have an actual import to the base package (ie: import project.Plugins) and I need to find the classes after discovering the modules.

Edit: here's a revised solution. I realised I was making a mistake while testing my previous one, and it doesn't really work the way you would expect. So here is a more complete solution:
import os
from imp import find_module
from types import ModuleType, ClassType
def iter_plugins(package):
"""Receives package (as a string) and, for all of its contained modules,
generates all classes that are subclasses of PluginBaseClass."""
# Despite the function name, "find_module" will find the package
# (the "filename" part of the return value will be None, in this case)
filename, path, description = find_module(package)
# dir(some_package) will not list the modules within the package,
# so we explicitly look for files. If you need to recursively descend
# a directory tree, you can adapt this to use os.walk instead of os.listdir
modules = sorted(set(i.partition('.')[0]
for i in os.listdir(path)
if i.endswith(('.py', '.pyc', '.pyo'))
and not i.startswith('__init__.py')))
pkg = __import__(package, fromlist=modules)
for m in modules:
module = getattr(pkg, m)
if type(module) == ModuleType:
for c in dir(module):
klass = getattr(module, c)
if (type(klass) == ClassType and
klass is not PluginBaseClass and
issubclass(klass, PluginBaseClass)):
yield klass
My previous solution was:
You could try something like:
from types import ModuleType
import Plugins
classes = []
for item in dir(Plugins):
module = getattr(Plugins, item)
# Get all (and only) modules in Plugins
if type(module) == ModuleType:
for c in dir(module):
klass = getattr(module, c)
if isinstance(klass, PluginBaseClass):
classes.append(klass)
Actually, even better, if you want some modularity:
from types import ModuleType
def iter_plugins(package):
# This assumes "package" is a package name.
# If it's the package itself, you can remove this __import__
pkg = __import__(package)
for item in dir(pkg):
module = getattr(pkg, item)
if type(module) == ModuleType:
for c in dir(module):
klass = getattr(module, c)
if issubclass(klass, PluginBaseClass):
yield klass

You may (and probably should) define __all__ in __init__.py as a list of the submodules in your package; this is so that you support people doing from Plugins import *. If you have done so, you can iterate over the modules with
import Plugins
import sys
modules = { }
for module in Plugins.__all__:
__import__( module )
modules[ module ] = sys.modules[ module ]
# iterate over dir( module ) as above
The reason another answer posted here fails is that __import__ imports the lowest-level module, but returns the top-level one (see the docs). I don't know why.

Scanning modules isn't good idea. If you need class registry you should look at metaclasses or use existing solutions like zope.interface.
Simple solution through metaclasses may look like that:
from functools import reduce
class DerivationRegistry(type):
def __init__(cls,name,bases,cls_dict):
type.__init__(cls,name,bases,cls_dict)
cls._subclasses = set()
for base in bases:
if isinstance(base,DerivationRegistry):
base._subclasses.add(cls)
def getSubclasses(cls):
return reduce( set.union,
( succ.getSubclasses() for succ in cls._subclasses if isinstance(succ,DerivationRegistry)),
cls._subclasses)
class Base(object):
__metaclass__ = DerivationRegistry
class Cls1(object):
pass
class Cls2(Base):
pass
class Cls3(Cls2,Cls1):
pass
class Cls4(Cls3):
pass
print(Base.getSubclasses())

If you don't know what's going to be in Plugins ahead of time, you can get a list of python files in the package's directory, and import them like so:
# compute a list of modules in the Plugins package
import os
import Plugins
plugin_modules = [f[:-3] for f in os.listdir(os.path.dirname(Plugins.__file__))
if f.endswith('.py') and f != '__init__.py']
Sorry, that comprehension might be a mouthful for someone relatively new to python. Here's a more verbose version (might be easier to follow):
plugin_modules = []
package_path = Plugins.__file__
file_list = os.listdir(os.path.dirname(package_path))
for file_name in file_list:
if file_name.endswith('.py') and file_name != '__init__.py':
plugin_modules.append(file_name)
Then you can use __import__ to get the module:
# get the first one
plugin = __import__('Plugins.' + plugin_modules[0])

Related

Set a module's class method as an attribute of that module from outside that module

The objective:
I have a package with submodules that I would like to be accessible in the most straightforward way possible. The submodules contain classes to take advantage of the class structure, but don't need to be initialized (as they contain static and class methods). So, ideally, I would like to access them as follows:
from myPackage.subModule import someMethod
print (someMethod)
from myPackage import subModule
print (subModule.someMethod)
import myPackage
print(myPackage.subModule.someMethod)
Here is the package structure:
myPackage ─┐
__init__.py
subModule
subModule2
etc.
Example of a typical submodule:
# submodule.py
class SomeClass():
someAttr = list(range(10))
#classmethod
def someMethod(cls):
pass
#staticmethod
def someMethod2():
pass
Here is the code I have in my '__init __.py': In order to achieve the above; it attempts to set attributes for each class at the package level, and the same for it's methods at the sub-module level.
# __init__.py
def import_submodules(package, filetypes=('py', 'pyc', 'pyd'), ignoreStartingWith='_'):
'''Import submodules to the given package, expose any classes at the package level
and their respective class methods at submodule level.
:Parameters:
package (str)(obj) = A python package.
filetypes (str)(tuple) = Filetype extension(s) to include.
ignoreStartingWith (str)(tuple) = Ignore submodules starting with given chars.
'''
if isinstance(package, str):
package = sys.modules[package]
if not package:
return
pkg_dir = os.path.dirname(os.path.abspath(package.__file__))
sys.path.append(pkg_dir) #append this dir to the system path.
for mod_name in os.listdir(pkg_dir):
if mod_name.startswith(ignoreStartingWith):
continue
elif os.path.isfile(os.path.join(pkg_dir, mod_name)):
mod_name, *mod_ext = mod_name.rsplit('.', 1)
if filetypes:
if not mod_ext or mod_ext[0] not in filetypes:
continue
mod = importlib.import_module(mod_name)
vars(package)[mod_name] = mod
classes = inspect.getmembers(mod, inspect.isclass)
for cls_name, clss in classes:
vars(package)[cls_name] = clss
methods = inspect.getmembers(clss, inspect.isfunction)
for method_name, method in methods:
vars(mod)[method_name] = method
del mod_name
import_submodules(__name__)
At issue is this line:
vars(mod)[method_name] = method
Which ultimately results in: (indicating that the attribute was not set)
from myPackage.subModule import someMethod
ImportError: cannot import name 'someMethod' from 'myPackage.subModule'
I am able to set the methods as attributes to the module within that module, but setting them from outside (ie. in the package __init __), isn't working as written. I understand this isn't ideal to begin with, but my current logic is; that the ease of use, outweighs any perceived issues with namespace pollution. I am, of course, always open to counter-arguments.
I just checked it on my machine.
Created a package myPackage with a module subModule that has a function someMethod.
I run a python shell with working directory in the same directory that the myPackage is in, and to get these 3 import statements to work:
from myPackage.subModule import someMethod
from myPackage import subModule
import myPackage
All I had to do was to create an __init__.py with this line in it:
from . import subModule
Found a nice "hacky" solution -
subModule.py:
class myClass:
#staticmethod
def someMethod():
print("I have a bad feeling about this")
myInstance = myClass()
someMethod = myInstance.someMethod
init.py is empty
Still scratching my head of why I am unable to do this from the package __init __, but this solution works with the caveat it has to be called at the end of each submodule. Perhaps someone, in the future, someone can chime in as to why this wasn't working when completely contained in the __init __.
def addMembers(module, ignoreStartingWith='_'):
'''Expose class members at module level.
:Parameters:
module (str)(obj) = A python module.
ignoreStartingWith (str)(tuple) = Ignore class members starting with given chars.
ex. call: addMembers(__name__)
'''
if isinstance(module, str):
module = sys.modules[module]
if not module:
return
classes = inspect.getmembers(module, inspect.isclass)
for cls_name, clss in classes:
cls_members = [(o, getattr(clss, o)) for o in dir(clss) if not o.startswith(ignoreStartingWith)]
for name, mem in cls_members:
vars(module)[name] = mem
This is the solution I ended up going with. It needs to be put at the end of each submodule of your package. But, it is simple and in addition to all the standard ways of importing, allows you to import a method directly:
def __getattr__(attr):
'''Attempt to get a class attribute.
:Parameters:
attr (str): A name of a class attribute.
:Return:
(obj) The attribute.
'''
try:
return getattr(Someclass, attr)
except AttributeError as error:
raise AttributeError(f'{__file__} in __getattr__\n\t{error} ({type(attr).__name__})')
from somePackage.someModule import someMethod

Python: Force import to prefer .py over .so

I have a situation where the same Python module is present in the same directory in two different versions; mymodule.py and mymodule.so (I obtain the latter from the first via Cython, but that's irrelevant to my question). When from Python I do
import mymodule
it always chooses mymodule.so. Sometimes I really want to import mymodule.py instead. I could temporarily move mymodule.so to another location, but that does not play well if I simultaneously have another Python instance running which needs to import mymodule.so.
The question is how to make import prefer .py files over .so, rather than vice versa?
Here's my thoughts on a solution:
I imagine performing some magic using importlib and possibly edit sys.meta_path. Specifically I see that sys.meta_path[2] holds _frozen_importlib_external.PathFinder which is used to import external modules, i.e. this is used for both mymodule.py and mymodule.so. If I could just replace this with a similar PathFinder which used the reverse ordering for file types, I would have a solution.
I'm using Python 3.7, if that affects the solution.
Edit
Note that simply reading in the source lines of mymodule.py and exec'ing them won't do, as mymodule.py may itself import other modules which again exist in both a .py and .so version (I want to import the .py version of these as well).
Here is another solution, that works just by tweaking the finders that the runtime generates by default. This uses hidden implementation details (FileFinder._loaders), but I've tested on CPythons 3.7, 3.8, and 3.9.
from contextlib import contextmanager
from dataclasses import dataclass
from importlib.machinery import FileFinder
from importlib.abc import Finder
import sys
from typing import Callable
#dataclass
class PreferPureLoaderHook:
orig_hook: Callable[[str], Finder]
def __call__(self, path: str) -> Finder:
finder = self.orig_hook(path)
if isinstance(finder, FileFinder):
# Move pure python file loaders to the front
finder._loaders.sort(key=lambda pair: 0 if pair[0] in (".py", ".pyc") else 1) # type: ignore
return finder
#contextmanager
def prefer_pure_python_imports():
sys.path_hooks = [PreferPureLoaderHook(h) for h in sys.path_hooks]
sys.path_importer_cache.clear()
yield
assert all(isinstance(h, PreferPureLoaderHook) for h in sys.path_hooks)
sys.path_hooks = [h.orig_hook for h in sys.path_hooks]
sys.path_importer_cache.clear()
with prefer_pure_python_imports():
...
Using these notes I came up with this. It's not too pretty, but it seems to work.
import glob, importlib, sys
def hook(name):
if name != '.':
raise ImportError()
modnames = set(f.rstrip('.py') for f in glob.glob('*.py'))
return Finder(modnames)
sys.path_hooks.insert(1, hook)
sys.path.insert(0, '.')
class Finder(object):
def __init__(self, modnames):
self.modnames = modnames
def find_spec(self, modname, target=None):
if modname in self.modnames:
origin = './' + modname + '.py'
loader = Loader()
return importlib.util.spec_from_loader(modname, loader, origin=origin)
else:
return None
class Loader(object):
def create_module(self, target):
return None
def exec_module(self, module):
with open(module.__spec__.origin, 'r', encoding='utf-8') as f:
code = f.read()
compile(code, module.__spec__.origin, 'exec')
exec(code, module.__dict__)

How do I change the name of an imported library?

I am using jython with a third party application. The third party application has some builtin libraries foo. To do some (unit) testing we want to run some code outside of the application. Since foo is bound to the application we decided to write our own mock implementation.
However there is one issue, we implemented our mock class in python while their class is in java. Thus to use their code one would do import foo and foo is the mock class afterwards. However if we import the python module like this we get the module attached to the name, thus one has to write foo.foo to get to the class.
For convenience reason we would love to be able to write from ourlib.thirdparty import foo to bind foo to the foo-class. However we would like to avoid to import all the classes in ourlib.thirdparty directly, since the loading time for each file takes quite a while.
Is there any way to this in python? ( I did not get far with Import hooks I tried simply returning the class from load_module or overwriting what I write to sys.modules (I think both approaches are ugly, particularly the later))
edit:
ok: here is what the files in ourlib.thirdparty look like simplified(without magic):
foo.py:
try:
import foo
except ImportError:
class foo
....
Actually they look like this:
foo.py:
class foo
....
__init__.py in ourlib.thirdparty
import sys
import os.path
import imp
#TODO: 3.0 importlib.util abstract base classes could greatly simplify this code or make it prettier.
class Importer(object):
def __init__(self, path_entry):
if not path_entry.startswith(os.path.join(os.path.dirname(__file__), 'thirdparty')):
raise ImportError('Custom importer only for thirdparty objects')
self._importTuples = {}
def find_module(self, fullname):
module = fullname.rpartition('.')[2]
try:
if fullname not in self._importTuples:
fileObj, self._importTuples[fullname] = imp.find_module(module)
if isinstance(fileObj, file):
fileObj.close()
except:
print 'backup'
path = os.path.join(os.path.join(os.path.dirname(__file__), 'thirdparty'), module+'.py')
if not os.path.isfile(path):
return None
raise ImportError("Could not find dummy class for %s (%s)\n(searched:%s)" % (module, fullname, path))
self._importTuples[fullname] = path, ('.py', 'r', imp.PY_SOURCE)
return self
def load_module(self, fullname):
fp = None
python = False
print fullname
if self._importTuples[fullname][1][2] in (imp.PY_SOURCE, imp.PY_COMPILED, imp.PY_FROZEN):
fp = open( self._importTuples[fullname][0], self._importTuples[fullname][1][1])
python = True
try:
imp.load_module(fullname, fp, *self._importTuples[fullname])
finally:
if python:
module = fullname.rpartition('.')[2]
#setattr(sys.modules[fullname], module, getattr(sys.modules[fullname], module))
#sys.modules[fullname] = getattr(sys.modules[fullname], module)
if isinstance(fp, file):
fp.close()
return getattr(sys.modules[fullname], module)
sys.path_hooks.append(Importer)
As others have remarked, it is such a plain thing in Python that the import statement iself has a syntax for that:
from foo import foo as original_foo, for example -
or even import foo as module_foo
Interesting to note is that the import statemente binds a name to the imported module or object ont he local context - however, the dictionary sys.modules (on the moduels sys of course), is a live reference to all imported modules, using their names as a key. This mechanism plays a key role in avoding that Python re-reads and re-executes and already imported module , when running (that is, if various of yoru modules or sub-modules import the samefoo` module, it is just read once -- the subsequent imports use the reference stored in sys.modules).
And -- besides the "import...as" syntax, modules in Python are just another object: you can assign any other name to them in run time.
So, the following code would also work perfectly for you:
import foo
original_foo = foo
class foo(Mock):
...

Dynamically import a method in a file, from a string

I have a string, say: abc.def.ghi.jkl.myfile.mymethod. How do I dynamically import mymethod?
Here is how I went about it:
def get_method_from_file(full_path):
if len(full_path) == 1:
return map(__import__,[full_path[0]])[0]
return getattr(get_method_from_file(full_path[:-1]),full_path[-1])
if __name__=='__main__':
print get_method_from_file('abc.def.ghi.jkl.myfile.mymethod'.split('.'))
I am wondering if the importing individual modules is required at all.
Edit: I am using Python version 2.6.5.
From Python 2.7 you can use the importlib.import_module() function. You can import a module and access an object defined within it with the following code:
from importlib import import_module
p, m = name.rsplit('.', 1)
mod = import_module(p)
met = getattr(mod, m)
met()
You don't need to import the individual modules. It is enough to import the module you want to import a name from and provide the fromlist argument:
def import_from(module, name):
module = __import__(module, fromlist=[name])
return getattr(module, name)
For your example abc.def.ghi.jkl.myfile.mymethod, call this function as
import_from("abc.def.ghi.jkl.myfile", "mymethod")
(Note that module-level functions are called functions in Python, not methods.)
For such a simple task, there is no advantage in using the importlib module.
For Python < 2.7 the builtin method __ import__ can be used:
__import__('abc.def.ghi.jkl.myfile.mymethod', fromlist=[''])
For Python >= 2.7 or 3.1 the convenient method importlib.import_module has been added. Just import your module like this:
importlib.import_module('abc.def.ghi.jkl.myfile.mymethod')
Update: Updated version according to comments (I must admit I didn't read the string to be imported till the end and I missed the fact that a method of a module should be imported and not a module itself):
Python < 2.7 :
mymethod = getattr(__import__("abc.def.ghi.jkl.myfile", fromlist=["mymethod"]))
Python >= 2.7:
mymethod = getattr(importlib.import_module("abc.def.ghi.jkl.myfile"), "mymethod")
from importlib import import_module
name = "file.py".strip('.py')
# if Path like : "path/python/file.py"
# use name.replaces("/",".")
imp = import_module(name)
# get Class From File.py
model = getattr(imp, "classNameImportFromFile")
NClass = model() # Class From file
It's unclear what you are trying to do to your local namespace. I assume you want just my_method as a local, typing output = my_method()?
# This is equivalent to "from a.b.myfile import my_method"
the_module = importlib.import_module("a.b.myfile")
same_module = __import__("a.b.myfile")
# import_module() and __input__() only return modules
my_method = getattr(the_module, "my_method")
# or, more concisely,
my_method = getattr(__import__("a.b.myfile"), "my_method")
output = my_method()
While you only add my_method to the local namespace, you do load the chain of modules. You can look at changes by watching the keys of sys.modules before and after the import. I hope this is clearer and more accurate than your other answers.
For completeness, this is how you add the whole chain.
# This is equivalent to "import a.b.myfile"
a = __import__("a.b.myfile")
also_a = importlib.import_module("a.b.myfile")
output = a.b.myfile.my_method()
# This is equivalent to "from a.b import myfile"
myfile = __import__("a.b.myfile", fromlist="a.b")
also_myfile = importlib.import_module("a.b.myfile", "a.b")
output = myfile.my_method()
And, finally, if you are using __import__() and have modified you search path after the program started, you may need to use __import__(normal args, globals=globals(), locals=locals()). The why is a complex discussion.
This website has a nice solution: load_class. I use it like this:
foo = load_class(package.subpackage.FooClass)()
type(foo) # returns FooClass
As requested, here is the code from the web link:
import importlib
def load_class(full_class_string):
"""
dynamically load a class from a string
"""
class_data = full_class_string.split(".")
module_path = ".".join(class_data[:-1])
class_str = class_data[-1]
module = importlib.import_module(module_path)
# Finally, we retrieve the Class
return getattr(module, class_str)
Use importlib (2.7+ only).
The way I tend to to this (as well as a number of other libraries, such as pylons and paste, if my memory serves me correctly) is to separate the module name from the function/attribute name by using a ':' between them. See the following example:
'abc.def.ghi.jkl.myfile:mymethod'
This makes the import_from(path) function below a little easier to use.
def import_from(path):
"""
Import an attribute, function or class from a module.
:attr path: A path descriptor in the form of 'pkg.module.submodule:attribute'
:type path: str
"""
path_parts = path.split(':')
if len(path_parts) < 2:
raise ImportError("path must be in the form of pkg.module.submodule:attribute")
module = __import__(path_parts[0], fromlist=path_parts[1])
return getattr(module, path_parts[1])
if __name__=='__main__':
func = import_from('a.b.c.d.myfile:mymethod')
func()
How about this :
def import_module(name):
mod = __import__(name)
for s in name.split('.')[1:]:
mod = getattr(mod, s)
return mod

How to dynamically load a Python class

Given a string of a Python class, e.g. my_package.my_module.MyClass, what is the best possible way to load it?
In other words I am looking for a equivalent Class.forName() in Java, function in Python. It needs to work on Google App Engine.
Preferably this would be a function that accepts the FQN of the class as a string, and returns a reference to the class:
my_class = load_class('my_package.my_module.MyClass')
my_instance = my_class()
From the python documentation, here's the function you want:
def my_import(name):
components = name.split('.')
mod = __import__(components[0])
for comp in components[1:]:
mod = getattr(mod, comp)
return mod
The reason a simple __import__ won't work is because any import of anything past the first dot in a package string is an attribute of the module you're importing. Thus, something like this won't work:
__import__('foo.bar.baz.qux')
You'd have to call the above function like so:
my_import('foo.bar.baz.qux')
Or in the case of your example:
klass = my_import('my_package.my_module.my_class')
some_object = klass()
EDIT: I was a bit off on this. What you're basically wanting to do is this:
from my_package.my_module import my_class
The above function is only necessary if you have a empty fromlist. Thus, the appropriate call would be like this:
mod = __import__('my_package.my_module', fromlist=['my_class'])
klass = getattr(mod, 'my_class')
If you don't want to roll your own, there is a function available in the pydoc module that does exactly this:
from pydoc import locate
my_class = locate('my_package.my_module.MyClass')
The advantage of this approach over the others listed here is that locate will find any python object at the provided dotted path, not just an object directly within a module. e.g. my_package.my_module.MyClass.attr.
If you're curious what their recipe is, here's the function:
def locate(path, forceload=0):
"""Locate an object by name or dotted path, importing as necessary."""
parts = [part for part in split(path, '.') if part]
module, n = None, 0
while n < len(parts):
nextmodule = safeimport(join(parts[:n+1], '.'), forceload)
if nextmodule: module, n = nextmodule, n + 1
else: break
if module:
object = module
else:
object = __builtin__
for part in parts[n:]:
try:
object = getattr(object, part)
except AttributeError:
return None
return object
It relies on pydoc.safeimport function. Here are the docs for that:
"""Import a module; handle errors; return None if the module isn't found.
If the module *is* found but an exception occurs, it's wrapped in an
ErrorDuringImport exception and reraised. Unlike __import__, if a
package path is specified, the module at the end of the path is returned,
not the package at the beginning. If the optional 'forceload' argument
is 1, we reload the module from disk (unless it's a dynamic extension)."""
import importlib
module = importlib.import_module('my_package.my_module')
my_class = getattr(module, 'MyClass')
my_instance = my_class()
If you're using Django you can use import_string.
Yes i'm aware OP did not ask for django, but i ran across this question looking for a Django solution, didn't find one, and put it here for the next boy/gal that looks for it.
# It's available for v1.7+
# https://github.com/django/django/blob/stable/1.7.x/django/utils/module_loading.py
from django.utils.module_loading import import_string
Klass = import_string('path.to.module.Klass')
func = import_string('path.to.module.func')
var = import_string('path.to.module.var')
Keep in mind, if you want to import something that doesn't have a ., like re or argparse use:
re = __import__('re')
def import_class(cl):
d = cl.rfind(".")
classname = cl[d+1:len(cl)]
m = __import__(cl[0:d], globals(), locals(), [classname])
return getattr(m, classname)
Here is to share something I found on __import__ and importlib while trying to solve this problem.
I am using Python 3.7.3.
When I try to get to the class d in module a.b.c,
mod = __import__('a.b.c')
The mod variable refer to the top namespace a.
So to get to the class d, I need to
mod = getattr(mod, 'b') #mod is now module b
mod = getattr(mod, 'c') #mod is now module c
mod = getattr(mod, 'd') #mod is now class d
If we try to do
mod = __import__('a.b.c')
d = getattr(mod, 'd')
we are actually trying to look for a.d.
When using importlib, I suppose the library has done the recursive getattr for us. So, when we use importlib.import_module, we actually get a handle on the deepest module.
mod = importlib.import_module('a.b.c') #mod is module c
d = getattr(mod, 'd') #this is a.b.c.d
OK, for me that is the way it worked (I am using Python 2.7):
a = __import__('file_to_import', globals(), locals(), ['*'], -1)
b = a.MyClass()
Then, b is an instance of class 'MyClass'
If you happen to already have an instance of your desired class, you can use the 'type' function to extract its class type and use this to construct a new instance:
class Something(object):
def __init__(self, name):
self.name = name
def display(self):
print(self.name)
one = Something("one")
one.display()
cls = type(one)
two = cls("two")
two.display()
Python has an inbuilt library importlib to get the job done. :, How to access module method and class method dynamically bypassing package name as a param. An example is given below.
Module 1:
def get_scenario_data():
return "module1 scenario data"
class Module1:
def module1_function1(self):
return "module1_function"
def module1_function2(self):
return "module2_function"
Module 2:
def get_scenario_data():
return "module2 scenario data"
class Module2:
def module2_function1(self):
return "module2_function1"
def module2_function2(self):
return "module2_function2"
ModuleTest:
Will access the module methods dynamically based on the package name as param
Will access the class methods dynamically based on the package name as param.
ModuleTest
import importlib
module = importlib.import_module('pack1.nestedpack1.module1')
print(module.get_scenario_data())
modul1_cls_obj = getattr(module, 'Module1')()
print(modul1_cls_obj.module1_function1())
print(modul1_cls_obj.module1_function2())
module = importlib.import_module('pack1.nestedpack1.module2')
modul2_cls_obj = getattr(module, 'Module2')()
print(modul2_cls_obj.module2_function1())
print(modul2_cls_obj.module2_function2())
print(module.get_scenario_data())
Results
module1 scenario data
module1_function
module2_function
module2_function1
module2_function2
module2 scenario data
PyPI module autoloader & import
# PyPI imports
import pkg_resources, subprocess, sys
modules = {'lxml.etree', 'pandas', 'screeninfo'}
required = {m.split('.')[0] for m in modules}
installed = {pkg.key for pkg in pkg_resources.working_set}
missing = required - installed
if missing:
subprocess.check_call([sys.executable, '-m', 'pip', 'install', '--upgrade', 'pip'])
subprocess.check_call([sys.executable, '-m', 'pip', 'install', *missing])
for module in set.union(required, modules):
globals()[module] = __import__(module)
Tests:
print(pandas.__version__)
print(lxml.etree.LXML_VERSION)
Adding a bit of sophistication to the existing answers....
Depending on the use case, it may be somewhat inconvenient to have to explicitly specify the full path (E.g. package.subpackage.module...) of the class/method you want to import. On top of importlib, we can leverage __init__.py to make things even cleaner.
Let's say I have a python package, like so:
├── modes
│ ├── __init__.py
│ ├── bar.py
│ ├── foo.py
│ ├── modes.py
foo.py, say, have some class/functions we'd like to use somewhere else in our program:
from modes.modes import Mode
class Foo(Mode):
def __init__(self, *arg, **kwargs):
super(Foo, self).__init__(*arg, **kwargs)
def run(self):
self.LOG.info(f"This is FOO!")
With a command line argument, I can pass an argument that corresponds to a mode that I want to run. I'd like to be able to so something like this:
def set_mode(mode):
""" """
import importlib
module = importlib.import_module('modes.foo')
getattr(module, mode)().run()
which outputs:
>> set_mode("Foo")
>> engine_logger:INFO - This is FOO!
That works fine, however what we'd REALLY want to get at is this:
def set_mode(mode):
""" """
import importlib
module = importlib.import_module('modes') # only import the package, not modules explicitely
getattr(module, mode)().run()
Which raises an error:
>> set_mode("Foo")
>> AttributeError: module 'modes' has no attribute 'Foo'
However, we can add the following to /modes/__init__.py:
from .foo import Foo
from .bar import Bar
Then, we can do:
>> set_mode("Foo")
>> engine_logger:INFO - This is FOO!
>> set_mode("Bar")
>> engine_logger:INFO - This is BAR!
In other worlds, all sub modules/functions/classes we import in init.py will be found directly with importlib.import_module(...), without having to specify the full path from outside.
In Google App Engine there is a webapp2 function called import_string. For more info see here:https://webapp-improved.appspot.com/api/webapp2.html
So,
import webapp2
my_class = webapp2.import_string('my_package.my_module.MyClass')
For example this is used in the webapp2.Route where you can either use a handler or a string.
module = __import__("my_package/my_module")
the_class = getattr(module, "MyClass")
obj = the_class()

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