I'm still republishing a python 2.x script in 3.x.
at some point, the script must replace the "print" function with "disp" (equivalent in TI basic language) except that it no longer works because of parentheses. anyone have an idea to fix it?
The code :
elif (line.find("print ")==idepth(line)):
line = replace(line,"print ","Disp ")
if (line[-1] == ","):
line = line[:-1].rstrip() # Trailing , not legal for ti basic
thanks in advance
Edit: full code :
import sys
import os
import re
#GUI:
import tkinter as tk
from tkinter import filedialog
import tkinter.simpledialog
import tkinter.messagebox
GUI_MODE = False
TAB_REPLACE = " "
def main():
args = sys.argv[1:]
global GUI_MODE
print (args)
if (len(args)==0):
GUI_MODE=True
root = tk.Tk()
root.withdraw()
inp = filedialog.askopenfilename(title="Select a python script to convert")
if (inp==''):
print ("cancelled")
return 0
else:
inp=args[0]
#now input file is known
file=open(inp)
prog = file.read().replace("\r","").split("\n") # Lines of code
#Get a program name:
if (prog[0][:1]=="#" and (prog[0].upper().find("NAME:")>-1 or prog[0].upper().find("PROGRAM:")>-1 )):
outname=prog[0][prog[0].find(":")+1:]
else:
outname=tkinter.simpledialog.askstring("File name","What do you want to name this program?")
fixed = format(prog)
#Write the converted program in this folder:
print ("\n--Converted to TI-Basic code:--")
print (fixed)
print ("")
print ("Making output files: "+outname+".tib, "+outname+".8xp ...")
#Write the converted program in this folder:
outfile=open(outname+".tib","w")
outfile.write(fixed)
outfile.close()
#Write the .8xp program
outfile=open(outname+".8xp","w")
outfile.write(fixed)
outfile.close()
#assuming the compiler tibasic.exe is in this folder:
if (sys.platform[:3]=="win"):
if (os.system('tibasic.exe '+outname+'.tib')): #Returns non-0, error:
errReport("Error trying to run tibasic.exe! Make sure it is in the current folder.")
else:
if (os.system('wine tibasic.exe '+outname+'.tib')): #Returns non-0, error:
errReport("Error trying to run tibasic.exe! Make sure it is in the current folder, and w.i.n.e is installed.\n"+
"(See http://www.winehq.org/ for installer)")
os.remove(outname+".tib")
a=input("Done! Press enter to exit:") #pause
return 0
def format(linesArray): #converts lines from Python to ti-basic.
for i in range(len(linesArray)):
linesArray[i]=linesArray[i].replace("\t",TAB_REPLACE) #Important! see idepth()
i=0;
linesArray.append("") # 0-indent ending so blockAddEnd won't mess up.
while (i<len(linesArray)):
#Convert control blocks (if, for, while) from indented (python) to END (TI)
line = linesArray[i]
if isBlockStart(line,"for "):
linesArray = blockAddEnd(linesArray, i, "End")
elif isBlockStart(line,"if "):
linesArray = blockAddEnd(linesArray, i, "End")
elif isBlockStart(line,"while "):
linesArray = blockAddEnd(linesArray, i, "End")
elif isBlockStart(line,"repeat "): #not in python, but works on TI.
linesArray = blockAddEnd(linesArray, i, "End")
i+=1
# Don't need indentations anymore, do the rest of the conversions:
for i in range(len(linesArray)):
linesArray[i]=convLine(linesArray[i],i+1)
#Remove blanks:
for i in range(linesArray.count("")):
linesArray.remove("")
return "\n".join(linesArray)
def convLine(line,num): #Line by line conversion.
line = line.rstrip().lstrip() #trim indentation.
lnum = "Line "+str(num)+": "
if line.count("#"):
comment = line[line.find("#"):]
if (comment[0:6] == "#no-ti"):
#Does not work on the ti.
return ""
elif (comment[0:4] == "#ti:"):
# Only for ti:
return comment[4:]
else:
line = line[:line.find("#")] # take comment off code
#No imports in ti-basic!
if line.startswith("import ") or (line.count(" import ") and line.startswith("from ")):
return ""
#Errors and warnings:
if (toolong(line)):
print (lnum+"Warning: Text string too long to fit on a TI83/84 screen. The calculator screen is 16 characters wide, 8 characters high.")
if (line.find("\n")>-1):
print (lnum+"Warning: newline \\n is not allowed in TI-Basic.")
if (line.find("'''")>-1):
print (lnum+"Warning: ''' quotes are not allowed, you must use \" quotes on a single line for TI-Basic.")
if (replace(line,"pow(","")!=line):
errReport(lnum+"TI calculators don't have the pow() command, you must use a**b instead of pow(a,b).")
if (replace(line,"import ","")!=line):
print (lnum+"import ignored. No import statements in TI-Basic!")
return "" # ignore import statements!
if (replace(line,"-=","")!=line):
errReport(lnum+"The -= operator is not allowed.\nTry +=- or a=a+-number instead.")
if (replace(line,"def ","")!=line):
errReport(lnum+"Functions are not supported in TI-Basic! However, you can run another program with \"prgmPRGNAME\".")
if (replace(line,"//","")!=line):
print (lnum+"// division converted to / division: For int division, try int(a/b).")
line=replace(line,"//","/")
if (replace(line,"-","")!=line):
print (lnum+"Warning: The - is changed to negative sign on the calculator. If you wanted to subtract, use a+-b instead of a-b.")
if (replace(line,"open(","")!=line):
errReport(lnum+"Error: TI calculators can't use \"open(filename)\" in programs. To store text, try using variables STR0, STR1, ... STR9.")
if (replace(line,"%","")!=line):
errReport(lnum+"Error: TI83/84 calculators don't have Mod.\n Instead of a % b, try (a/b-int(a/b))*b instead.")
# Replace excess spaces, they cause errors in the calculator:
line=replace(line,", ",",")
line=replace(line," + ","+")
line=replace(line," - ","-")
line=replace(line," +- ","+-")
line=replace(line," * ","*")
line=replace(line," / ","/")
line=replace(line," == ","==")
line=replace(line," > ",">")
line=replace(line," < ","<")
line=replace(line," != ","!=")
#TODO: Arrays converted to lists?
line=replace(line,"theta","[theta]") # variable
line=replace(line,"**","^")
line=mathReplace(line)
#round, max, min already works.
line=replace(line,"float(","(")
line=replace(line,"len(","dim(")
line=replace(line,"math.pi","[pi]")
line=replace(line,"math.e","[e]")
line=replace(line,"eval(","expr(")
line=replace(line,"-","[neg]") # use +- instead of - operator.
line=replace(line,"==","=")
line=replace(line," and ","&")
line=replace(line," or ","|")
line=replace(line,"random.random()","rand")
line=replace(line,"random.randint","RandInt")
line=replace(line,"int(","iPart(")
if (replace(line,"input(","") != line):
line=inputConv(line,num)
if isBlockStart(line,"for "):
line=forConv(line,num)
elif (isBlockStart(line,"if ")):
line = replace(line,"if ","If ")
line = replace(line,":",":Then")
elif (isBlockStart(line,"while ")):
line = replace(line,"while ","While ")
line = replace(line,":","")
elif (isBlockStart(line,"repeat")):
line = replace(line,"repeat","Repeat")
line = replace(line,":","")
elif (isBlockStart(line,"else")):
line = replace(line,"else:","Else")
elif isBlockStart(line,"elif"):
errReport(lnum+"""Error: There is no else-if command on the TI83/84. However, you can use this instead:
if <condition>:
...
else:
if <condition>:
...
else:
...""")
elif (line.find("print ")==idepth(line)):
line = re.sub(r"print *\((.+)\)", r"disp \1", line)
if (line[-1] == ","):
line = line[:-1].rstrip() # Trailing , not legal for ti basic
elif (replace(line,"=","")!=line): #assignment is -> on the calculator.
eqspace = line.find("=")
line = line[eqspace+1:].rstrip().lstrip() + "->" + line[:eqspace].rstrip().lstrip() # sto arrow.
line = fixEQ(line)
return replace(line,"+[neg]","-") #lastly, switch back the negative.
def fixEQ(line):
# fix +=, *=, /=.
# A+=1 changes to 1->A+, so fix it now.
if (line[-1]=="+" or line[-1]=="*" or line[-1]=="/"):
line = line[:-1].rstrip()+line[-1] # remove any spaces in "a +" etc
pre = line[line.find("->")+2:]
#pre = pre[:-1].rstrip()+pre[-1]
line= pre + "("+line[:line.find("->")]+")"+ line[line.find("->"):-1]
return line
def inputConv(line,num):
lnum = "Line "+str(num)+": "
if (replace(line,"raw_input(","")!=line and line==replace(line,"=","")):
#raw_input not assigned to variable is like Pause.
return "Pause "
else:
var = line[:line.find("=")].rstrip().lstrip()
if (len(var)>1 and var!="theta"): # might be invalid.
print (lnum+"Warning: Program tries to store to variable \"%s\"." % var)
prompt = line[line.find("input(")+6:]
prompt = prompt[:prompt.find(")")]
# Now return the TI basic input with var spaces removed:
return "Input "+prompt+","+var
def forConv(line,num):
lnum = "Line "+str(num)+": "
# split "for i in range(...):"
var = line[line.find("for ")+4:line.find(" in range")]
#print var
part = line[line.find("in range(")+9:] # only "...) : "
part = part.rstrip(": ")[:-1] # remove extra " " or ":", remove last ).
#print "'"+line+"'"
out = part.split(",")
if len(out)==1:
return "For(%s,0,(%s)-1)" % (var, out[0])
elif len(out)==2:
return "For(%s,(%s),(%s)-1)" % (var, out[0], out[1])
elif len(out)==3:
return "For(%s,(%s),(%s)-1,(%s)" % (var, out[0], out[1], out[2])
else:
errReport(lnum+"Too many commas in for loop!")
return "couldn't convert: "+line
def blockAddEnd(lines, startLine, endText):
# Takes an array, line #, and end text.
# Adds end for that indentation block.
startInd = idepth(lines[startLine])
if idepth(lines[startLine+1]) <= startInd:
errReport("Expected indent after line "+str(startLine+1)+".")
i = startLine+1
#continue searching for the end while it's indented or it's an else line:
while idepth(lines[i]) > startInd or (isBlockStart(lines[i],"else")):
i+=1
# now insert.
lines.insert(i,endText)
return lines
def idepth(text):
# get indentation depth of line.
depth=0
line = text.replace("\t",TAB_REPLACE) #tab is 4 spaces.
while (line[:1]==" "):
line=line[1:]
depth+=1
return depth
def replace(text, changethis, tothis):
# replaces text, but not in quotes.
arr = text.split("\"")
for i in range(0,len(arr),2):
arr[i]=arr[i].replace(changethis, tothis)
return "\"".join(arr)
def toolong(text):
# checks for too long string:
arr = text.split("\"")
for i in range(1,len(arr),2):
#print arr[i]
if (len(arr[i]) > 16):
return True
return False
def parMatch(text,num): # given "(stuff()...()))", returns the parentheses block.
lnum = "Line "+str(num)+": "
for i in range(len(text)):
part = text[:i-1]
if (part.count("(")==part.count(")")):
return part[1:-1] #without outside parentheses.
errReport(lnum+"Invalid parentheses")
def isBlockStart(line, type):
# Check if the line is start of a <type> block.
# checks if it starts with <type>, and ends with ":".
# example: isBlockStart("for i in range(8) : ","for") is true.
return (line.find(type) == idepth(line) and line.rstrip(" ")[-1]==":")
def errReport(text):
print (text)
if (GUI_MODE):
root = tk.Tk()
root.withdraw()
tkinter.messagebox.showerror("Error",text)
sys.exit(1)
def mathReplace(line):
""" Replaces mathematical functions with ti basic functions. """
#Same function in both Python and TI-basic:
same = ["sin", "cos", "tan", "asin", "acos", "atan", "sinh", "cosh", "tanh", "asinh", "acosh", "atanh"]
line=replace(line,"math.sqrt(","[root]^2(")
line=replace(line,"math.fabs(","abs(")
for func in same:
line = replace(line,"math.%s(" % func,func)
line=replace(line,"math.log(","ln(")
line=replace(line,"math.exp(","e^(")
line=replace(line,"math.floor(","int(")
line=replace(line,"math.log10(","log(")
#same, but without "math." They might use
#from math import sqrt etc...
line=replace(line,"sqrt(","[root]^2(")
line=replace(line,"fabs(","abs(")
for func in same:
line = replace(line, "%s(" % func,func)
#(Redundant lines deleted)
line=replace(line,"log(","ln(")
line=replace(line,"exp(","e^(")
line=replace(line,"floor(","int(")
line=replace(line,"log10(","log(")
return line
if __name__ == '__main__': main()
it's the original code with changement propose below
You can use python's regular expression library to perform more advanced string matching and replacement than replace(). Specifically, re.sub(), which functions the same as replace() but takes regular expressions instead of simple strings.
Be sure to first import it with import re. You can then do the following:
elif (line.find("print ")==idepth(line)):
line = re.sub(r"print *\(\"(.+)\"\)", r"disp \1", line)
if (line[-1] == ","):
line = line[:-1].rstrip() # Trailing , not legal for ti basic
This will look for a string of the format "print("&1")" or "print ("&1")" and replace it with "disp &1", where &1 is the contents between the quotes.
Edit: You had initially specified that you wanted the output "without the quotes", but it seems you've edited that comment. If you want to include the quotes in the output, use this line instead:
line = re.sub(r"print *\((.+)\)", r"disp \1", line)
I am not sure what I am doing wrong here but I am trying to open a file, trace1.flow, read the header information then throw the source IP and destination IP into dictionaries. This is done in Python running on a Fedora VM. I am getting the following error:
(secs, nsecs, booted, exporter, mySourceIP, myDestinationIP) = struct.unpack('IIIIII',myBuf)
struct.error: unpack requires a string argument of length 24
Here is my code:
import struct
import socket
#Dictionaries
uniqSource = {}
uniqDestination = {}
def int2quad(i):
z = struct.pack('!I', i)
return socket.inet_ntoa(z)
myFile = open('trace1.flow')
myBuf = myFile.read(8)
(magic, endian, version, headerLen) = struct.unpack('HBBI', myBuf)
print "Magic: ", hex(magic), "Endian: ", endian, "Version: ", version, "Header Length: ", headerLen
myFile.read(headerLen - 8)
try:
while(True):
myBuf = myFile.read(24)
(secs, nsecs, booted, exporter, mySourceIP, myDestinationIP) = struct.unpack('IIIIII',myBuf)
mySourceIP = int2quad(mySourceIP)
myDestinationIP = int2quad(myDestinationIP)
if mySourceIP not in uniqSource:
uniqSource[mySourceIP] = 1
else:
uniqSource[mySourceIP] += 1
if myDestinationIP not in uniqDestination:
uniqDestination[myDestinationIP] = 1
else:
uniqDestination[myDestinationIP] += 1
myFile.read(40)
except EOFError:
print "END OF FILE"
You seem to assume that file.read will raise EOFError on end of file, but this error is only raised by input() and raw_input(). file.read will simply return a string that's shorter than requested (possibly empty).
So you need to check the length after reading:
myBuf = myFile.read(24)
if len(myBuf) < 24:
break
Perhaps your have reached end-of-file. Check the length of myBuf:
len(myBuf)
It's probably less than 24 chars long. Also you don't need those extra parenthesis, and try to specify duplicated types using 'nI' like this:
secs, nsecs, booted, exporter, mySourceIP, myDestinationIP = struct.unpack('6I',myBuf)
I'm trying to make a test for checking whether a sys.argv input matches the RegEx for an IP address...
As a simple test, I have the following...
import re
pat = re.compile("\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}")
test = pat.match(hostIP)
if test:
print "Acceptable ip address"
else:
print "Unacceptable ip address"
However when I pass random values into it, it returns "Acceptable IP address" in most cases, except when I have an "address" that is basically equivalent to \d+.
Using regex to validate IP address is a bad idea - this will pass 999.999.999.999 as valid. Try this approach using socket instead - much better validation and just as easy, if not easier to do.
import socket
def valid_ip(address):
try:
socket.inet_aton(address)
return True
except:
return False
print valid_ip('10.10.20.30')
print valid_ip('999.10.20.30')
print valid_ip('gibberish')
If you really want to use parse-the-host approach instead, this code will do it exactly:
def valid_ip(address):
try:
host_bytes = address.split('.')
valid = [int(b) for b in host_bytes]
valid = [b for b in valid if b >= 0 and b<=255]
return len(host_bytes) == 4 and len(valid) == 4
except:
return False
You have to modify your regex in the following way
pat = re.compile("^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$")
that's because . is a wildcard that stands for "every character"
regex for ip v4:
^((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$
otherwise you take not valid ip address like 999.999.999.999, 256.0.0.0 etc
I came across the same situation, I found the answer with use of socket library helpful but it doesn't provide support for ipv6 addresses. Found a better way for it:
Unfortunately, it Works for python3 only
import ipaddress
def valid_ip(address):
try:
print (ipaddress.ip_address(address))
return True
except:
return False
print (valid_ip('10.10.20.30'))
print (valid_ip('2001:DB8::1'))
print (valid_ip('gibberish'))
You are trying to use . as a . not as the wildcard for any character. Use \. instead to indicate a period.
def ipcheck():
# 1.Validate the ip adderess
input_ip = input('Enter the ip:')
flag = 0
pattern = "^\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}$"
match = re.match(pattern, input_ip)
if (match):
field = input_ip.split(".")
for i in range(0, len(field)):
if (int(field[i]) < 256):
flag += 1
else:
flag = 0
if (flag == 4):
print("valid ip")
else:
print('No match for ip or not a valid ip')
import re
ipv=raw_input("Enter an ip address")
a=ipv.split('.')
s=str(bin(int(a[0]))+bin(int(a[1]))+bin(int(a[2]))+bin(int(a[3])))
s=s.replace("0b",".")
m=re.search('\.[0,1]{1,8}\.[0,1]{1,8}\.[0,1]{1,8}\.[0,1]{1,8}$',s)
if m is not None:
print "Valid sequence of input"
else :
print "Invalid input sequence"
Just to keep it simple I have used this approach.
Simple as in to explain how really ipv4 address is evaluated.
Checking whether its a binary number is although not required.
Hope you like this.
str = "255.255.255.255"
print(str.split('.'))
list1 = str.split('.')
condition=0
if len(list1)==4:
for i in list1:
if int(i)>=0 and int(i)<=255:
condition=condition+1
if condition!=4:
print("Given number is not IP address")
else:
print("Given number is valid IP address")
If you really want to use RegExs, the following code may filter the non-valid ip addresses in a file, no matter the organiqation of the file, one or more per line, even if there are more text (concept itself of RegExs) :
def getIps(filename):
ips = []
with open(filename) as file:
for line in file:
ipFound = re.compile("^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$").findall(line)
hasIncorrectBytes = False
try:
for ipAddr in ipFound:
for byte in ipAddr:
if int(byte) not in range(1, 255):
hasIncorrectBytes = True
break
else:
pass
if not hasIncorrectBytes:
ips.append(ipAddr)
except:
hasIncorrectBytes = True
return ips
re.sub('((25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9][0-9]|[0-9])\\.){3}(25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9][0-9]|[0-9])', '--', '127.0.0.1')
With this regular expression, only numbers from 0 to 255 could compose the address. It also handles leading zeros, so 127.00.0.1 would no pass.
IP address uses following authentication :
255 ---> 250-255
249 ---> 200-249
199 ---> 100-199
99 ---> 10-99
9 ---> 1-9
import re
k = 0
while k < 5 :
i = input("\nEnter Ip address : ")
ip = re.match("^([1][0-9][0-9].|^[2][5][0-5].|^[2][0-4][0-9].|^[1][0-9][0-9].|^[0-9][0-9].|^[0-9].)([1][0-9][0-9].|[2][5][0-5].|[2][0-4][0-9].|[1][0-9][0-9].|[0-9][0-9].|[0-9].)([1][0-9][0-9].|[2][5][0-5].|[2][0-4][0-9].|[1][0-9][0-9].|[0-9][0-9].|[0-9].)([1][0-9][0-9]|[2][5][0-5]|[2][0-4][0-9]|[1][0-9][0-9]|[0-9][0-9]|[0-9])$",i)
k = k + 1
if ip:
print ("\n=====================")
print ("Valid IP address")
print ("=====================")
break
else :
print ("\nInvalid IP")
else :
print ("\nAllowed Max 5 times")
Reply me if you have doubt?
import re
st1 = 'This is my IP Address10.123.56.25 789.356.441.561 127 255 123.55 192.168.1.2.3 192.168.2.2 str1'
Here my valid IP Address is only 192.168.2.2 and assuming 10.123.56.25 is not a valid one as it is combined with some string and 192.168.1.2.3 not valid.
pat = r'\s(((25[0-5]|2[0-4][0-9]|[01]?[0-9]?[0-9])\.){3}((25[0-5]|2[0-4][0-9]|[01]?[0-9]?[0-9])\s|$))'
match = re.search(pat,st1)
print match.group()
================ RESTART: C:/Python27/Srujan/re_practice.py ================
192.168.2.2
This will grep the exact IP Address, we can ignore any pattern look like an IP Address but not a valid one. Ex: 'Address10.123.56.25', '789.356.441.561' '192.168.1.2.3'.
Please comment if any modifications are required.
This works for python 2.7:
import re
a=raw_input("Enter a valid IP_Address:")
b=("[0-9]+"+".")+"{3}"
if re.match(b,a) and b<255:
print "Valid"
else:
print "invalid"
""" regex for finding valid ip address """
import re
IPV4 = re.fullmatch('([0-2][0-5]{2}|\d{2}|\d).([0-2][0-5]{2}|\d{2}|\d).([0-2][0-5]{2}|\d{2}|\d).([0-2][0-5]{2}|\d{2}|\d)', '100.1.1.2')
if IPV4:
print ("Valid IP address")
else:
print("Invalid IP address")