I use GtkAboutDialog and everything works fine except the close button of this widget. All other buttons works fine, I don't know how but all buttons have default callbacks and they create and destroy the windows.
But the "Close" button of GtkAboutDialog widget does not work. I can not even see it's widget. So, can I access it?
[CLARIFICATION] What you're looking at is gtk.AboutDialog — popup window displaying information about an application (new in PyGTK 2.6). This window contains the 'close' button widget which is contained in a GtkHButtonBox widget. The GtkHButtonBox widget is the highest level widget I am able to access for some. Any ideas on how to get to the "close" button and connect a handler for a callback signal?
You don't conenct signals in the same way for a dialog as you do for a window. I made the same mistake when learning PyGTK.
The most basic form of a dialog is you display and run the dialog with:
aboutdialog.run()
Often you will then immediately call:
aboutdialog.destroy()
The .run() line is a loop, which runs until something happens within the dialog.
There is a working example here.
The gtk.AboutDialog is just a gtk.Dialog, and you handle responses from it in the same way. Instead of connecting to the clicked signal of the buttons, the dialog code handles that for you and returns a reponse from your run() call. You can check the value of the response returned to figure out what button was clicked.
If you're trying to override some behaviour instead, you can connect to the response signal of gtk.Dialog.
This is an old question, but since it's one of the first hits from google, I thought I'd throw in the solution that I found. You need an event handler to show the about dialog and one to close it. The first will likely be connected to your help->about menuitem's activate signal. The latter should be connected to the response signal of the about dialog. The two handlers will look something like this:
def on_menuitemHelpAbout_activate(self, *args):
self.builder.get_object('aboutdialog').show()
def on_aboutdialog_response(self, *args):
self.builder.get_object('aboutdialog').hide()
In the example above, I'm using the GtkBuilder to find my about dialog because I've constructed the interface with glade. Note that I'm using .show() over .run() because I don't see the sense in pausing program execution until the dialog is closed. Finally, the response handler can be made to take whatever action depending upon the response, but I'm ignoring it here.
Related
I have some objects in a PyQt GUI that I wish to be hidden when the program runs until a button is pressed that shows them. So far all my attempts have failed, I have experimented with Signals/Slots but I can't seem to find a way of calling a function without an action (e.g. a button press). I would like to know if it is possible to call hide() on an object in this way, and if so, how.
To Close:
QtCore.QObject.connect(self.closeWidget, QtCore.SIGNAL(_fromUtf8("activated()")), widgetName.close)
To Show:
QtCore.QObject.connect(self.actionShow, QtCore.SIGNAL(_fromUtf8("activated()")), widgetName.show)
In other words, widgets inherit a close() and show() method.
See http://pyqt.sourceforge.net/Docs/PyQt4/qwidget.html
Also, some example code: http://www.saltycrane.com/blog/2007/06/more-pyqt-example-code/
I have a Qt program with many buttons, user-interactable widgets, etc.
At one stage in the program, I would like all the widgets to temporarily 'stop working'; stop behaving to mouse clicks and instead pass the event on to one function.
(This is so the User can select a widget to perform meta operations. Part explanation here: Get variable name of Qt Widget (for use in Stylesheet)? )
The User would pick a widget (to do stuff with) by clicking it, and of course clicking a button must not cause the button's bound function to run.
What is the correct (most abstracted, sensible) method of doing this?
(which doesn't involve too much new code. ie; not subclassing every widget)
Is there anything in Qt designed for this?
So far, I am able to retrieve a list of all the widgets in the program (by calling
QObject.findChildren(QtGui.QWidget)
so the solution can incorporate this.
My current horrible ideas are;
Some how dealing with all the applications events all the time in one
function and not letting through the events when I need the
application to be dormant.
When I need dormancy, make a new transparent widget which recieves
mouse clicks and stretch it over the entire window. Take coordinates
of click and figure out the widget underneath.
Somehow create a new 'shell' instance of the window.
THANKS!
(Sorry for the terrible write-up; in a slight rush)
python 2.7.2
PyQt4
Windows 7
You can intercept events send to specific widgets with QObject::installEventFilter.
graphite answered this one first so give credit where credit is due.
For an actual example in PySide, here's an example you might draw some useful code from:
my_app.py
from KeyPressEater import KeyPressEater
if __name__ == "__main__":
app = QApplication(sys.argv)
eater = KeyPressEater()
app.installEventFilter(eater)
KeyPressEater.py
class KeyPressEater(QObject):
# subclassing for eventFilter
def eventFilter(self, obj, event):
if self.ignore_input:
# swallow events
pass
else:
# bubble events
return QObject.eventFilter(self,obj,event)
Python 2.7, PyQt4.8.5
I want to have a main app window and then a second pop up window to display com port settings. This window should always be on top of the parent window until either the ok or the cancel button is clicked; closing the child window. (sort of like a required answer i.e. cant process until you choose the settings from the child window)
Is there a Python Qt command to do this?
Apologies if this has been asked/answered before, my search returned nothing useful.
You want a modal dialog. For example:
dialog = QInputDialog()
dialog.exec_()
You can either implement your own dialog widget (by subclassing QDialog) or use one of the several available.
With wxPython, how does one trigger an event whenever the whole window goes into/out of focus?
To elaborate, I'm building a serial terminal GUI and would like to close down the connection whenever the user doesn't have my application selected, and re-open the connection whenever the user brings my app back into the foreground. My application is just a single window derived from wx.Frame.
The correct answer for this case is to use an EVT_ACTIVATE handler bound to the frame. There will be an event whenever the frame is activated (brought into the foreground relative to other windows currently open) or deactivated. You can use the event object's GetActive method to tell which just happened.
as WxPerl programmer i know there is
EVT_SET_FOCUS(
EVT_KILL_FOCUS(
if you initialize this event by listening to the frame as first parameter it should work as in Perl since the API is almost the same
Interesting article at http://www.blog.pythonlibrary.org/2009/08/27/wxpython-learning-to-focus/
Gist of it: wx.EVT_KILL_FOCUS works fine, but wx.EVT_SET_FOCUS behaves a little oddly for any panel containing widgets (the child's set-focus prevents the panel's set-focus event from firing as expected?)
In addition to what these fellows are saying, you might also want to try EVT_ENTER_WINDOW and EVT_LEAVE_WINDOW. I think these are fired when you move the mouse into and out of the frame widget, although I don't think the frame has to be in focus for those events to fire.
# Hugh - thanks for the readership!
As explained here, I have a simple tray icon using PyGTK.
Being very new to GTK, it appears to me that gtk.main() is synchronous, blocking any further processing until the respective UI is closed.
So how can I periodically (e.g. every 5 seconds) update/refresh StatusIcon's icon - do I have to resort to Twisted et al. for this?
You can use gobject.timeout_add() to add periodical tasks. The first parameter is the interval in seconds, the second parameter is the callback you want to be called. The callback is called as long as it returns something that evaluates to True when used as a bool.
See also section 20 of the PyGTK FAQ, in particular question 20.7.
You can't refresh easily the tray icon , take it from some one that did already try this and failed (Actually i just drop it for the reason that "If the implementation is hard to explain, it's a bad idea.") ,
but here is what i have so far, to refresh the Status Icon you will have to set your status icon using gtk.status_icon_new_from_gicon() method, from the doc :
Creates a status icon displaying a
gio.Icon(). If the icon is a themed
icon, it will be updated when the
theme changes.
So if you want to refresh the Status Icon you will have to create your icon using gio themed icon , and now you can update directly your themed icon and this change will be shown directly in the tray status.
Now about your question :
Yes gtk.main() block waiting for signal, so you just have to bind a signal to an action and when this signal is triggered the action can be executed , for your case in your action callback you can put the code that will refresh your Status Image.
Hope i did help you here.