I'm trying to use httplib to send credit card information to authorize.net. When i try to post the request, I get the following traceback:
File "./lib/cgi_app.py", line 139, in run res = method()
File "/var/www/html/index.py", line 113, in ProcessRegistration conn.request("POST", "/gateway/transact.dll", mystring, headers)
File "/usr/local/lib/python2.7/httplib.py", line 946, in request self._send_request(method, url, body, headers)
File "/usr/local/lib/python2.7/httplib.py", line 987, in _send_request self.endheaders(body)
File "/usr/local/lib/python2.7/httplib.py", line 940, in endheaders self._send_output(message_body)
File "/usr/local/lib/python2.7/httplib.py", line 803, in _send_output self.send(msg)
File "/usr/local/lib/python2.7/httplib.py", line 755, in send self.connect()
File "/usr/local/lib/python2.7/httplib.py", line 1152, in connect self.timeout, self.source_address)
File "/usr/local/lib/python2.7/socket.py", line 567, in create_connection raise error, msg
gaierror: [Errno -2] Name or service not known
I build my request like so:
mystring = urllib.urlencode(cardHash)
headers = {"Content-Type": "text/xml", "Content-Length": str(len(mystring))}
conn = httplib.HTTPSConnection("secure.authorize.net:443", source_address=("myurl.com", 443))
conn.request("POST", "/gateway/transact.dll", mystring, headers)
to add another layer to this, it was working on our development server which has httplib 2.6 and without the source_address parameter in httplib.HTTPSConnection.
Any help is greatly appreciated.
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EDIT:
I can run it from command line. Apparently this is some sort of permissions issue. Any ideas what permissions I would need to grant to which users to make this happen? Possibly Apache can't open the port?
As an (obvious) heads up, this same error can also be triggered by including the protocol in the host parameter. For example this code:
conn = httplib.HTTPConnection("http://secure.authorize.net", 80, ....)
will also cause the "gaierror: [Errno -2] Name or service not known" error, even if all your networking setup is correct.
gaierror: [Errno -2] Name or service not known
This error often indicates a failure of your DNS resolver. Does ping secure.authorize.net return successful replies from the same server that receives the gaierror? Does the hostname have a typo in it?
The problem ultimately came down to the fact that selinux was stopping apache from getting that port. Disabling selinux fixed the problems. I had an issue later where i didn't have /var/www/.python-eggs/, so MySQLdb was hosing on import. But after a mkdir, it was fixed.
pass the port separately from the host:
conn = httplib.HTTPSConnection("secure.authorize.net", 443, ....)
Related
i have a simple code that uses proxy to submit a "GET" request to google .
import httplib2
http = httplib2.Http(proxy_info = httplib2.ProxyInfo(proxy_type=3,proxy_host=myProxy, proxy_port=myPort))
resp, content = http.request("http://google.com", "GET")
print(resp)
print(content)
For some reason i get a Timeout error :
resp, content = http.request("http://google.com", "GET")
File "C:\Python35\lib\site-packages\httplib2\__init__.py", line 1322, in requ
st
(response, content) = self._request(conn, authority, uri, request_uri, meth
d, body, headers, redirections, cachekey)
File "C:\Python35\lib\site-packages\httplib2\__init__.py", line 1072, in _req
est
(response, content) = self._conn_request(conn, request_uri, method, body, h
aders)
File "C:\Python35\lib\site-packages\httplib2\__init__.py", line 995, in _conn
request
conn.connect()
File "C:\Python35\lib\http\client.py", line 849, in connect
(self.host,self.port), self.timeout, self.source_address)
File "C:\Python35\lib\socket.py", line 711, in create_connection
raise err
File "C:\Python35\lib\socket.py", line 702, in create_connection
sock.connect(sa)
TimeoutError: [WinError 10060] A connection attempt failed because the connecte
party did not properly respond after a period of time, or established connecti
n failed because connected host has failed to respond
I'm using a valid proxy, but this module doesn't works, Does anybody knows why this happened?
Win Error 10060 means that no connection can be made and that either the host or the connection(proxy) is at fault. Since google is virtually never down we can narrow down the problem to the proxy configuration.
Since you seemingly configured the proxy correctly (assuming you pass the right types and arugments ) you might want to check what SOCKS protocol the server additionally supports.
Either your're not passing valid values as a proxy configuration or it is the server's fault.
You could also try to diagnose with wireshark to see if any packets even make it to the server.
I am trying to write on HDFS from Python.
Right now, I am using https://hdfscli.readthedocs.io/en/latest/quickstart.html
but for large file I get back:
File "/home/edge7/venv-dev/local/lib/python2.7/site-packages/hdfs/client.py", line 400, in write
consumer(data)
File "/home/edge7/venv-dev/local/lib/python2.7/site-packages/hdfs/client.py", line 394, in consumer
auth=False,
File "/home/edge7/venv-dev/local/lib/python2.7/site-packages/hdfs/client.py", line 179, in _request
**kwargs
File "/home/edge7/venv-dev/local/lib/python2.7/site-packages/requests/sessions.py", line 465, in request
resp = self.send(prep, **send_kwargs)
File "/home/edge7/venv-dev/local/lib/python2.7/site-packages/requests/sessions.py", line 573, in send
r = adapter.send(request, **kwargs)
File "/home/edge7/venv-dev/local/lib/python2.7/site-packages/requests/adapters.py", line 415, in send
raise ConnectionError(err, request=request)
requests.exceptions.ConnectionError: ('Connection aborted.', gaierror(-2, 'Name or service not known'))
My code for writing is pretty simple:
client = InsecureClient('http://xxxxxxx.co:50070', user='hdfs')
client.write("/tmp/a",stringToWrite)
Anyone can suggest a decent package to write on HDFS?
Cheers
For the stacktrace, it seems to be security related. Are you sure you need to use the InsecureClient and not the Kerberos one?. Also, remember that library is just a binding for HttpFs, so doing a manual test with Postman or CURL would let you debug any issue cluster-side.
I'm trying to send an http get request via the httplib, but I'm facing issues.
conn = httplib.HTTPConnection("10.30.111.13/View")
conn.request("GET", "/Default.aspx")
res = conn.getresponse()
if res.status == 200:
print(res.status)
else:
print("Something went terribly wrong")
I get the following error:
TypeError (cannot concatenate 'str' and 'int' objects).
If put the next line of codes, it works no problem:
conn = httplib.HTTPConnection("www.google.com")
conn.request("GET", "/")
EDIT, here is a more detailed log I managed to pull out of my third party software (it restricts me in turn of python usability):
File "<string>", line 3248, in initialization
File "C:\python22\lib\httplib.py", line 701, in request
self._send_request(method, url, body, headers)
File "C:\python22\lib\httplib.py", line 723, in _send_request
self.endheaders()
File "C:\python22\lib\httplib.py", line 695, in endheaders
self._send_output()
File "C:\python22\lib\httplib.py", line 581, in _send_output
self.send(msg)
File "C:\python22\lib\httplib.py", line 548, in send
self.connect()
File "C:\python22\lib\httplib.py", line 516, in connect
socket.SOCK_STREAM):
gaierror: (7, 'getaddrinfo failed')
I'm not someplace where I can test this now, but here's what I think:
You're passing only an IP address to a host field that's expecting a DNS address, not an IP address. That's why your second error listing says 'getaddrinfo' failed.
That said, I'm not sure how to use an IP address with httplib. Maybe try "http://10.30.111.13" instead. A good way to test it would be to replace your IP address above with Google's and see if you still get the error.
Maybe this will help -- sorry I can't say more!
I have changed the IP address for a DNS address. I also removed any path/URI that were in the HTTPConnection() parameter. Now it works. Sorry for such an obvious question guys.
Hi I am new to Python...
I am trying to use YQL using Python.
I installed httplib2-0.7.0, oauth2 and then installed yql package
For this sample code :
import yql
y = yql.Public()
query = 'select * from flickr.photos.search where text="panda" limit 3';
result = y.execute(query)
print result
I got the following error message.
Please help!!
Traceback (most recent call last):
File "test.py", line 4, in
result = y.execute(query)
File "C:\Python27\lib\site-packages\yql-0.7-py2.7.egg\yql__init__.py", line 306, in execute
resp, content = self.http.request(url, http_method)
File "C:\Python27\lib\site-packages\httplib2__init__.py", line 1436, in request
(response, content) = self._request(conn, authority, uri, request_uri, method, body, headers, redirections, cachekey
)
File "C:\Python27\lib\site-packages\httplib2__init__.py", line 1188, in _request
(response, content) = self._conn_request(conn, request_uri, method, body, headers)
File "C:\Python27\lib\site-packages\httplib2__init__.py", line 1123, in _conn_request
conn.connect()
File "C:\Python27\lib\site-packages\httplib2__init__.py", line 890, in connect
self.disable_ssl_certificate_validation, self.ca_certs)
File "C:\Python27\lib\site-packages\httplib2__init__.py", line 76, in _ssl_wrap_socket
cert_reqs=cert_reqs, ca_certs=ca_certs)
File "C:\Python27\lib\ssl.py", line 344, in wrap_socket
ciphers=ciphers)
File "C:\Python27\lib\ssl.py", line 119, in init
ciphers)
ssl.SSLError: [Errno 185090050] _ssl.c:336: error:0B084002:x509 certificate routines:X509_load_cert_crl_file:system lib
When I tried to use the *twitter python wrapper, I ended up getting the same SSL error.*
Please tell me what to do
I can see two likely issues:
SSL Certificate
I'm not familiar with Python or that library you're using, but the error sounds like it can't verify the SSL certificate. (Possibly because there is no suitable local SSL certificate bundle for authentication.) You may be able to configure it to skip the SSL certificate verification.
YQL Flickr Query
The YQL query is not correct and gives an error in the YQL console:
select * from flickr.photos.search where text="panda" limit 3
Actually, given the age of this question, it may have worked in June 2011. Now the Flickr tables require an API key as well, so the working query would look like:
select * from flickr.photos.search where text="panda" and api_key="insert-your-key-here" limit 3
I'm getting a getaddress error and after doing some sleuthing, it looks like it might be my corporate intranet not allowing the connection (I'm assuming due to security, although it is strange that IE works but won't allow Python to open a url). Is there a safe way to get around this?
Here's the exact error:
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
b = urllib.urlopen('http://www.google.com')
File "C:\Python26\lib\urllib.py", line 87, in urlopen
return opener.open(url)
File "C:\Python26\lib\urllib.py", line 203, in open
return getattr(self, name)(url)
File "C:\Python26\lib\urllib.py", line 342, in open_http
h.endheaders()
File "C:\Python26\lib\httplib.py", line 868, in endheaders
self._send_output()
File "C:\Python26\lib\httplib.py", line 740, in _send_output
self.send(msg)
File "C:\Python26\lib\httplib.py", line 699, in send
self.connect()
File "C:\Python26\lib\httplib.py", line 683, in connect
self.timeout)
File "C:\Python26\lib\socket.py", line 498, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
IOError: [Errno socket error] [Errno 11001] getaddrinfo failed
More info: I also get this error with urllib2.urlopen
You probably need to fill in proxy information.
import urllib2
proxy_handler = urllib2.ProxyHandler({'http': 'http://yourcorporateproxy:12345/'})
proxy_auth_handler = urllib2.HTTPBasicAuthHandler()
proxy_auth_handler.add_password('realm', 'host', 'username', 'password')
opener = urllib2.build_opener(proxy_handler, proxy_auth_handler)
opener.open('http://www.stackoverflow.com')
Check you are using the correct proxy.
You can get the proxy information by using urllib.getproxies (note: getproxies does not work with dynamic proxy configuration, like when using PAC).
Update As per information about empty proxy list, I would suggest using an urlopener, with the proxy name and information.
Some good information about how use proxies urlopeners:
Urllib manual
Michael Foord's introduction to urllib
Possibly this is a DNS issue, try urlopen with the IP address of the web server you're accessing, i.e.
import urllib
URL="http://66.102.11.99" # www.google.com
f = urllib.urlopen(URL)
f.read()
If this succeeds, then it's probably a DNS issue rather than a proxy issue (but you should also check your proxy setup).
Looks like a DNS problem.
Since you are using Windows, you can try run this command
nslookup www.google.com
To check if the web address can be resolved successfully.
If not, it is a network setting issue
If OK, then we have to look at possible alternative causes
I was facing the same issue.
In my system the proxy configuration is through a .PAC file.
So i opended that file, took out the default proxy url, for me it was http://168.219.61.250:8080/
Following test code worked for me :
import urllib2
proxy_support = urllib2.ProxyHandler({'http': 'http://168.219.61.250:8080/'})
opener = urllib2.build_opener(proxy_support)
urllib2.install_opener(opener)
response = urllib2.urlopen('http://python.org/')
html = response.read()
print html
You might need to add some more code, if your proxy requires authentication
Hope this helps!!