I have written an html form and am trying to incorporate a python cgi script with it. I have already configured my apache server to execute cgi scripts from the cgi-bin directory. Here's the html form:
<html>
<body>
<form name="input" action="c:/xampp/cgi-bin/test2.py" method="post">
<input type="text" name="qry" />
<input type="submit" value="GO!" />
</form>
</body>
</html>
And here's the test2.py cgi script:
#!c:/Python27/python.exe -u
import cgi
import cgitb
cgitb.enable()
form = cgi.FieldStorage()
qry = form["qry"].value
print "Content-Type: text/html"
print
print "<html"
print "<body>"
print qry
print "</body>"
print "</html>"
The html page is located in my htdocs folder and the cgi script is in the cgi-bin directory. However, when I enter something into the form and submit, firefox returns an error message saying: "Firefox doesn't know how to open this address, because the protocol (c) isn't associated with any program". Why is this error occurring? Does it have something to do with my path to the cgi script in my html page? Thanks in advance!
You are correct: it has something to do with the path to the CGI script on the HTML page. The form's action attribute should refer to the path where the CGI script is getting interpreted on the server, e.g., /cgi-bin/test2.py.
Since you made this mistake, I'm assuming you are new to web development. Consider using mod_wsgi and a framework like Django instead of CGI, especially if you expect a lot of traffic or you are making a web application and not just handling a single form.
Related
I have created html form with text box and button
enter ur search keyword
My requirement is to pass the text box value in to my test.py code, is there any way to do it.
Please suggest me how do it.
in the form action form action="", put the location of your cgi script and the value of the textbox will be passed to the cgi script.
eg.
<form name="search" action="/cgi-bin/test.py" method="get">
Search: <input type="text" name="searchbox">
<input type="submit" value="Submit">
</form>
in your test.py
import cgi
form = cgi.FieldStorage()
searchterm = form.getvalue('searchbox')
thus you will get the key word entered in search text box in searchterm variable in python.
I had the problem with getting the code in browser. Installed python and xampp.
I put the .py script in cgi-bin and I called it from an html page like that
<form name="input" action="../cgi-bin/name_of_script.py" method="get">
Put the html page in htdocs of xampp.
In the httd.conf find the line
AddHandler cgi-script .cgi .pl .asp
and change it to
AddHandler cgi-script .cgi .pl .asp .py
In the script add the version of the python you have
for example I added
#!C:\Python27\python.exe
because I have installed python27 in the above directory.
Also if you print something in python put this line on top of the script
print "Content-Type: text/html; charset=utf-8\n\n";
The above script of the searchbox it worked fine for me.
My operating system is Windows really torchered me, I searched and searched for the above solution.
I have an Apache web server. I have an html file and a Python script located at var/www/myfolder. I am submitting a form through the html file which is handled by my Python script (when the submit button is clicked). But once handling the form, my Python script executes an external command. (see the following code)
webpage.html
<!DOCTYPE html>
<html>
<head>
<title>Webform</title>
</head>
<body>
<h3>Webform</h3>
<form action="myscript.py" method="POST">
<p>Name: <input type="text" name="name"></p>
<input type="submit" value="Submit">
</form>
</body>
</html>
myscript.py
#!/usr/bin/python -W
import cgi, cgitb
import sys
import os
# Get data from fields
form = cgi.FieldStorage()
name = form.getvalue('name')
print "Content-type:text/html\r\n\r\n"
print '<html>'
print '<head>'
print '<title>Hello Word - First CGI Program</title>'
print '</head>'
print '<body>'
print '<h2>Hello Word! This is my first CGI program</h2></br></br>'
print '<p>Name: %s</p>' % (name)
print '</body>'
print '</html>'
os.system("./other_script.py") # gives me an error with permission
On my server I am user007 but I know that when I click submit on the html file, the Python script is executed as apache2 user. The problem is I don't know the password for this user (can't us sudo). Are the two ideas possible:
1) change from apache2 to user007 when trying to execute other_script.py from myscript.py
2) I know that you can change users using suEXEC but I have no idea how to use it.
Any suggestions?
I should let you know that locally both the python scripts are executing fine.
Edit 1:
I get this message before the error occurs: WARNING: HOME is not set, using root: /
I am trying to run a standard python os.system call from a cgi python script.
This is part of a tutorial so the script is quite simple. I am trying to take a picture with the Raspberry Pi camera and display it in a webpage.
import os, sys
os.system('raspistill -o /var/www/images/image.jpg')
print "Content-type:text/html\r\n\r\n"
print '<html>'
print '<head>'
print '<title>Hello Word - First CGI Program</title>'
print '</head>'
print '<body>'
print '<h2>Hello Word! This is my first CGI program</h2>'
print '<img src="/var/www/images/image.jpg"/>'
print '</body>'
print '</html>'
The error I get when running the system command (opening in a browser) is:
* failed to open vchiq instance"
I have seen another question on this and it said something about the http deamon running as the wrong user, but I am not sure what that meant.
The scripts runs fine when I am running it as the standard user.
Most web servers run with a user for the webserver. Apache2 runs as www-data, for instance.
All files in the computer have ownership and permission data for them that would allow or disallow certain operations from different users - for instance only the superuser (root) can run the poweroff application to turn off the computer.
What you should do is locate the executable you're trying to run which raspistill. This will return the location of the executable file. Next you should check the file permissions using ls -l `which raspistill` and see the owner data and file permissions which are displayed as -rwxr-xr-- (This is a common permission set, yours might vary). The 1st 3 represent Read-Write-eXecute permissions for the file owner, the next 3 chars represent only Read and eXecute permissions for the user group and the last 3 chars represent only Read permissions for the "other" users.
If the owner of the file is not www-data you could do several things such as change the ownership information for the file using chown <user> <file> which I don't recommend or adding execution privileges to the "other" user set with chmod o+x `which raspistill`.
If the problem is indeed with the permissions - this should solve your problem.
Additional information:
http://www.computerhope.com/unix/uchmod.htm
http://www.ss64.com/bash/chmod.html
I fixed it.
The web server had access to the raspistill command, but that command used a video device that it did not have access to. I added the www-data user to the video and the audio group so I could both play audio and take pictures. I also had to change some groups for some folders in my web-directory.
The last thing I had to fix was that the os.system() call returned something and that gave the browser some problems with displaying the webpage. It only displayed text. I now use the subprocess module and the initial code seems to work. My simple test code is here:
import os, sys
import subprocess
#output = subprocess.check_output("raspistill -o /var/www/images/image.jpg", shell=True)
#os.system('raspistill -v -o /var/www/images/image.jpg')
# Import modules for CGI handling
import cgi, cgitb
# Create instance of FieldStorage
form = cgi.FieldStorage()
output = ""
output2 = ""
# Get data from fields
if form.getvalue('speak_en'):
output = subprocess.check_output("espeak \"%s\"" % (form.getvalue('speak')), shell=True)
if form.getvalue('picture'):
output2 = subprocess.check_output("raspistill -o /var/www/images/image.jpg", shell=True)
print """\
Content-type:text/html\n
<html>
<head>
<title>Hello Word - First CGI Program</title>
</head>
<body>
<h2>Select photo or speak</h2>
<form action=\"/cgi-bin/hello.py\" method=\"post\">
<input type=\"checkbox\" name=\"speak_en\" value=\"on\" />
Speak: <input type=\"text\" name=\"speak\"><br />
Take picture:
<input type=\"checkbox\" name=\"picture\" value=\"on\" />
<br />
<input type=\"submit\" value=\"Submit\" />
</form>
<img src=\"../images/image.jpg\" width=640 height=480>
<p>Speak output: %s</p>
<p>Picture output: %s</p>
</body>
</html>
""" % (output, output2)
I'm trying to use Python and HTML together. What I'm trying to do is create an HTML Form that will submit data to a python file and that python file will then handle the data. But I'm not getting it to work.
Here is my python code:
form = cgi.FieldStorage() # instantiate only once!
name = form['Sample Name'].value
and this is my HTML code:
<form method='POST' action='/functionGen.py'>
Name: <input type='text' name='Sample Name'>
<input type='submit' value='Begin Storing'>
</form>
What ends up happening is I just see my python code in the browser, the file doesn't begin handling the data.
What can I do?
You should know, that you are getting plain python source document via http protocol now. If you want to use CGI mechanism, you should place youre .py in cgi-enabled directory. It means that you need http server.
related questions
How to run Python CGI script
How do I set up a Python CGI server?
form.html:
<form action="p.py" method="post">
<input type="text" id="id_text" name="name_text" />
<input type="submit" id="id_submit" name="name_submit" />
</form>
p.py:
#!/usr/bin/python
#what to write here...
Both files are put in /var/www/ , now from http://example.com/form.html, if I click the submit button would I execute the p.py and how can I get the value of textbox?
It's apache/httpd webserver installed on computer.
1st, to make p.py run by apache, you need to check:
1, config apache site for a python script, you may choose: cgi/fastcgi
such as: ScriptAlias /cgi-bin/ /usr/local/xxxxxx/cgi-bin/
2, make sure your p.py file is runable, modify by chown/chmod
2nd, to get the value from a form, you need to understand cgi knowleges and get data from environment,
or much easier by using cgi module:
import cgi
form = cgi.FieldStorage()
v = form.getvalue('id_text','')
print """Content-type: text/html
<html>
<body> submit value:%s </body>
</html>""" % (v)
at last, I suggest:
put runable scripts to a separated dir, away from /var/www/
using a web framework for web develop. It's too deep to use cgi level technology in 2012.