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Issue with parsing csv from Django web form

I was hoping someone could help me with this. I'm getting a file from a form in Django, this file is a csv and I'm trying to read it with Python's library csv. The problem here is that when I apply the function csv.reader and I turn that result into a list in order to print it, I find out that csv.reader is not splitting correctly my file.
Here are some images to show the problem
This is my csv file:
This my code:
And this is the printed value of the variable file_readed:
As you can see in the picture, it seems to be splitting my file character by character with some exceptions.
I thank you for any help you can provide me.

If you are pulling from a web form, try getting the csv as a string, confirm in a print or debug tool that the result is correct, and then pass it to csv using StringIO.
from io import StringIO
import csv
csv_string = form.files['carga_cie10'].file_read().decode(encoding="ISO-88590-1")
csv_file = StringIO(csv_string)
reader = csv.reader(csvfile, delimiter=',', quotechar='"')
for row in reader:
print(row)
Another thing you can try is changing the lineterminator argument to csv.reader(). It can default to \r\n but the web form might use some other value. Inspect the string you get from the web form to confirm.

that CSV does not seem right: you got some lines with more arguments than others.
The acronym of CSV being Comma Separated Values, you need to have the exact same arguments separated by commas for each line, or else it will mess it up.
I see in your lines you're maybe expecting to have 3 columns, instead you got lines with 2, or 4 arguments, and some of them have an opening " in one argument, comma, then closing " in the second argument
check if your script works with other CSVs maybe

Most likely you need to specify delimiter. Since you haven't explicitly told about the delimiter, I guess it's confused.
csv.reader(csvfile, delimiter=',')
However, since there are quotations with comma delimiter, you may need to alter the default delimiter on the CSV file's creation too for tab or something else.

The problem is here:
print(list(file_readed))
'list' is causing printing of every element within the csv as an individual unit.
Try this instead:
with open('carga_cie10') as f:
reader = csv.reader(f)
for row in reader:
print(" ".join(row))
Edit:
import pandas as pd
file_readed = pd.read_csv(file_csv)
print(file_readed)
The output should look clean. Pandas is highly useful in situations where data needs to be read, manipulated, changed, etc.

Reading a tab separated file with Python Pandas

I have encountered a problem reading a tab separated file using Pandas.
All the cell values have double quotations but for some rows, there is an extra double quotation that breaks the whole procedure. For instance:
Column A Column B Column C
"foo1" "121654" "unit"
"foo2" "1214" "unit"
"foo3" "15884""
The error I get is: Error tokenizing data. C error: Expected 31 fields in line 8355, saw 58
The code I used is:
csv = pd.read_csv(file, sep='\t',  lineterminator='\n', names=None)
and it works fine for the rest of the files but not for the ones where this extra double quotation appears.

If you cannot change the buggy input, the best way would be to read the input file into a io.StringIO object, replacing the double quotes, then pass this file-like object to pd.read (it supports filenames and file-like objects)
That way you don't have to create a temporary file or to alter the input data.
import io
with open(file) as f:
fileobject = io.StringIO(f.read().replace('""','"'))
csv = pd.read_csv(fileobject, sep='\t', lineterminator='\n', names=None)

You can do the preprocessing step to fix the quotation issue:
with open(file, 'r') as fp:
text = fp.read().replace('""', '"')
with open(file, 'w') as fp:
fp.write(text)

Generating CSV and blank line

I am generating and parsing CSV files and I'm noticing something odd.
When the CSV gets generated, there is always an empty line at the end, which is causing issues when subsequently parsing them.
My code to generate is as follows:
with open(file, 'wb') as fp:
a = csv.writer(fp, delimiter=",", quoting=csv.QUOTE_NONE, quotechar='')
a.writerow(["Id", "Builing", "Age", "Gender"])
results = get_results()
for val in results:
if any(val):
a.writerow(val)
It doesn't show up via the command line, but I do see it in my IDE/text editor
Does anyone know why it is doing this?
Could it be possible whitespace?

Is the problem the line terminator? It could be as simple as changing one line:
a = csv.writer(fp, delimiter=",", quoting=csv.QUOTE_NONE, quotechar='', lineterminator='\n')
I suspect this is it since I know that csv.writer defaults to using carriage return + line feed ("\r\n") as the line terminator. The program you are using to read the file might be expecting just a line feed ("\n"). This is common in switching file back and forth between *nix and Windows.
If this doesn't work, then the program you are using to read the file seems to be expecting no line terminator for the last row, I'm not sure the csv module supports that. For that, you could write the csv to a StringIO, "strip()" it and then write that your file.
Also since you are not quoting anyting, is there a reason to use csv at all? Why not:
with open(file, 'wb') as fp:
fp.write("\n".join( [ ",".join([ field for field in record ]) for record in get_results()]))

Using Python's CSV library to print an array as a csv file

I have a python list as such:
[['a','b','c'],['d','e','f'],['g','h','i']]
I am trying to get it into a csv format so I can load it into excel:
a,b,c
d,e,f
g,h,i
Using this, I am trying to write the arary to a csv file:
with open('tables.csv','w') as f:
f.write(each_table)
However, it prints out this:
[
[
'
a
'
,
...
...
So then I tried putting it into an array (again) and then printing it.
each_table_array=[each_table]
with open('tables.csv','w') as f:
f.write(each_table_array)
Now when I open up the csv file, its a bunch of unknown characters, and when I load it into excel, I get a character for every cell.
Not too sure if it's me using the csv library wrong, or the array portion.
I just figured out that the table I am pulling data from has another table within one of its cells, this expands out and messes up the whole formatting

You need to use the csv library for your job:
import csv
each_table = [['a','b','c'],['d','e','f'],['g','h','i']]
with open('tables.csv', 'w') as csvfile:
writer = csv.writer(csvfile)
for row in each_table:
writer.writerow(row)

As a more flexible and pythonic way use csv module for dealing with csv files Note that as you are in python 2 you need the method newline='' * in your open function . then you can use csv.writer to open you csv file for write:
import csv
with open('file_name.csv', 'w',newline='') as csvfile:
spamwriter = csv.writer(csvfile, delimiter=',')
spamwriter.writerows(main_list)
From python wiki: If newline='' is not specified, newlines embedded inside quoted fields will not be interpreted correctly, and on platforms that use \r\n linendings on write an extra \r will be added. It should always be safe to specify newline='', since the csv module does its own (universal) newline handling.

Python csv writer : "Unknown Dialect" Error

I have a very large string in the CSV format that will be written to a CSV file.
I try to write it to CSV using the simplest if the python script
results=""" "2013-12-03 23:59:52","/core/log","79.223.39.000","logging-4.0",iPad,Unknown,"1.0.1.59-266060",NA,NA,NA,NA,3,"1385593191.865",true,ERROR,"app_error","iPad/Unknown/webkit/537.51.1",NA,"Does+not",false
"2013-12-03 23:58:41","/core/log","217.7.59.000","logging-4.0",Win32,Unknown,"1.0.1.59-266060",NA,NA,NA,NA,4,"1385593120.68",true,ERROR,"app_error","Win32/Unknown/msie/9.0",NA,"Does+not,false
"2013-12-03 23:58:19","/core/client_log","79.240.195.000","logging-4.0",Win32,"5.1","1.0.1.59-266060",NA,NA,NA,NA,6,"1385593099.001",true,ERROR,"app_error","Win32/5.1/mozilla/25.0",NA,"Could+not:+{"url":"/all.json?status=ongoing,scheduled,conflict","code":0,"data":"","success":false,"error":true,"cached":false,"jqXhr":{"readyState":0,"responseText":"","status":0,"statusText":"error"}}",false"""
resultArray = results.split('\n')
with open(csvfile, 'wb') as f:
writer = csv.writer(f)
for row in resultArray:
writer.writerows(row)
The code returns
"Unknown Dialect"
Error
Is the error because of the script or is it due to the string that is being written?
EDIT
If the problem is bad input how do I sanitize it so that it can be used by the csv.writer() method?

You need to specify the format of your string:
with open(csvfile, 'wb') as f:
writer = csv.writer(f, delimiter=',', quotechar="'", quoting=csv.QUOTE_ALL)
You might also want to re-visit your writing loop; the way you have it written you will get one column in your file, and each row will be one character from the results string.
To really exploit the module, try this:
import csv
lines = ["'A','bunch+of','multiline','CSV,LIKE,STRING'"]
reader = csv.reader(lines, quotechar="'")
with open('out.csv', 'wb') as f:
writer = csv.writer(f)
writer.writerows(list(reader))
out.csv will have:
A,bunch+of,multiline,"CSV,LIKE,STRING"
If you want to quote all the column values, then add quoting=csv.QUOTE_ALL to the writer object; then you file will have:
"A","bunch+of","multiline","CSV,LIKE,STRING"
To change the quotes to ', add quotechar="'" to the writer object.

The above code does not give csv.writer.writerows input that it expects. Specifically:
resultArray = results.split('\n')
This creates a list of strings. Then, you pass each string to your writer and tell it to writerows with it:
for row in resultArray:
writer.writerows(row)
But writerows does not expect a single string. From the docs:
csvwriter.writerows(rows)
Write all the rows parameters (a list of row objects as described above) to the writer’s file object, formatted according to the current dialect.
So you're passing a string to a method that expects its argument to be a list of row objects, where a row object is itself expected to be a sequence of strings or numbers:
A row must be a sequence of strings or numbers for Writer objects
Are you sure your listed example code accurately reflects your attempt? While it certainly won't work, I would expect the exception produced to be different.
For a possible fix - if all you are trying to do is to write a big string to a file, you don't need the csv library at all. You can just write the string directly. Even splitting on newlines is unnecessary unless you need to do something like replacing Unix-style linefeeds with DOS-style linefeeds.
If you need to use the csv module after all, you need to give your writer something it understands - in this example, that would be something like writer.writerow(['A','bunch+of','multiline','CSV,LIKE,STRING']). Note that that's a true Python list of strings. If you need to turn your raw string "'A','bunch+of','multiline','CSV,LIKE,STRING'" into such a list, I think you'll find the csv library useful as a reader - no need to reinvent the wheel to handle the quoted commas in the substring 'CSV,LIKE,STRING'. And in that case you would need to care about your dialect.

you can use 'register_dialect':
for example for escaped formatting:
csv.register_dialect('escaped', escapechar='\\', doublequote=True, quoting=csv.QUOTE_ALL)