I have a site made in PHP that i need to create a django site of. I've stripped out the PHP code temporary (not much code anyways), but i'm having problems understanding how django works and how to create a simple template to display a page.
I know there's thousands of books and guides out there, but most of them go too deep or doesn't do what i need. I just need two simple pages, page1 and page2, which will be accessed through domain.com/page1 and domain.com/page2.
What is the simplest way to achieve that?
This is what i have in my urls.py file so far, is that correct at least?
from django.conf.urls.defaults import patterns, include, url
urlpatterns = patterns('',
url(r'^$', 'mysite.views.page1', name='home'),
url(r'^$page2', 'mysite.views.page2', name='page2'),
)
It obviously doesn't work now cause the views aren't created.
Any help is greatly appreciated,
// qwerty
I recommend you to walk through tutorial, you will find out everything Django beginner should know.
Try this:
from django.conf.urls.defaults import patterns, include, url
from mysite.yourapp import views
urlpatterns = patterns('',
url(r'^$', 'mysite.views.page1', name='home'),
url(r'^page2/$', 'mysite.views.page2', name='page2'),
)
The r'^page1/$ bit is python regex
in your views.py file define your views:
def page1:
#something
This should help you get started http://docs.djangoproject.com/en/1.3/intro/tutorial01/
Well, i found the most straight-forward way is:
1) urls.py
from django.urls import include, path
from . import views
from django.views.generic import TemplateView
urlpatterns = [
path('test.html', TemplateView.as_view(template_name='main/test.html')),
]
2) templates/test.html
Hello world!
Classic 3-steps:
1) urls.py
from django.urls import include, path
from . import views
urlpatterns = [
path('test.html', views.test, name='test'),]
2) views.py
from django.shortcuts import render
def test(request):
return render(request, 'test.html')
3) templates/test.html
Hello world!
Thats more or less what I use:
urlpatterns = patterns('',
(r'^$', 'news.views.page1'),
(r'^page2/$', 'news.views.page2'),
)
just for your understanding: the beginning of a line is expressed as ^, the end as $. So ^$ stands for an empty line. more about regexp: http://docs.python.org/library/re.html
If you are using older django than direct_to_template generic view is what you need.
from django.views.generic.simple import direct_to_template
urlpatterns = patterns('',
(r'^page1/$', direct_to_template, {'template': 'page1.html'}),
(r'^page2/$', direct_to_template, {'template': 'page2.html'}),
)
Or for newer django 1.3 you need to use class based generic views
from django.conf.urls.defaults import *
from django.views.generic import TemplateView
urlpatterns = patterns('',
(r'^page1/', TemplateView.as_view(template_name="page1.html")),
(r'^page2/', TemplateView.as_view(template_name="page2.html")),
)
P.S. Don't forget to create page1.html and page2.html template files.
Related
I already search for any answer which could help me before write this question, but I haven't found anything that helps.
The thing is that I follow the tutorial and I can't see the view that I created.
Now I'm going to share my code:
project urls.py:
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('polls/', include('polls.urls')),
path('admin/', admin.site.urls),
]
polls urls.py:
from django.urls import path
from . import views
urlpatterns = [
path(" ", views.index, name='index'),
#127.0.0.1/polls/
]
polls views.py
from django.http import HttpResponse
from django.shortcuts import render
# Create your views here.
def index(request):
HttpResponse("Welcome to de Polls Universe Index")
OK I ALREADY KNOW WHATS GOING ON:
I forgot the RETURN before de HttpResponse.
There are two issues with your code:
The path for the index view contains a blank, which must be removed
The view function must return a response object. Please add return in front of the last line.
first of I want to apologize if I use the wrong terms or words in my question. I'm completely new to Django and got only a few months of experience with python. I hope you can understand my question anyways. I also want to acknowledge the fact that I'm using some imports that are not needed here and might not be relevant to the latest version of Django, I'm starting to get lost in all the things I've tried from other threads to solve my problem.
I'm having some problems with showing a page from apps url.
I'm getting redirected to my homepage when trying to reach localhost:8000/articles (because /articles gives 404 error)
I'm not sure exactly what code I need to include here, so bear with me.
articles/urls.py and articles/views.py
from django.conf.urls import url
from django.urls import include, path
from django.conf.urls import include, url
from django.urls import path
from .import views
urlpatterns = [
path('^$', views.article_list),
]
from django.shortcuts import render
from django.http import HttpResponse
# views
def article_list(request):
return render(request, "articles/article_list.html")
The project's urls.py and project's views.py
from django.contrib import admin
from django.urls import path
from django.conf.urls import url, include
from django.urls import include, path
from django.conf.urls import include, url
from django.urls import path, re_path
from .import views
urlpatterns = [
path('admin/', admin.site.urls),
path('articles/', include('articles.urls')),
path('about/', views.about),
re_path('^.*$', views.homepage)
]
from django.http import HttpResponse
from django.shortcuts import render
#Views
def homepage(request):
# return HttpResponse('homepage')
return render(request, "homepage.html")
def about(request):
# return HttpResponse('about')
return render(request, "about.html")
Im getting no errors or such.
So, my question is - does anybody have a clue why /articles generate 404 error?
Thank you in advance.
Firstly, don't use ^$ with path(). You only use regular expressions with re_path.
path('', views.article_list),
Usually, /articles will be redirected to /articles/ with a trailing slash.
However, in your case, you have a catch-all pattern:
re_path('^.*$', views.homepage)
This matches /articles, so you see the home page. Note it's not redirected as you say in your answer, the browser bar will still show /articles.
Unless you have a really good reason to have the catch all, I suggest you remove it and change it to
re_path('^$', views.homepage),
or
path('', views.homepage),
That way, you'll see the homepage for localhost:8000, localhost:8000/articles will be redirected to localhost:8000/articles/, and you'll get a 404 for pages that don't exist, e.g. localhost:8000/art/
Just using a empty string '' instead of '^$:
urlpatterns = [
path('', views.article_list),
]
Take a look at the last example here: https://docs.djangoproject.com/en/3.1/topics/http/urls/#url-namespaces-and-included-urlconfs
*I don't know what django version are you using, but for regular expressions paths you should use re_path() https://docs.djangoproject.com/en/3.1/ref/urls/#django.urls.re_path
I'm completely new to backend, working through the djangobook tutorial. If I'm missing any vital information, let me know. The first task is to get 'Hello World' to show up on your development server, and it keeps returning 404. The two files in question being the views.py (my hello world file) and urls.py
this is the views.py:
from django.http import HttpResponse
def hello(request):
return HttpResponse("Hello world")
this is the urls.py:
from django.conf.urls import url
from django.contrib import admin
from mysite.views import hello
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^hello/$', hello),
]
I feel like its not finding the views file correctly? This is how there set up, exactly as he said to do it in the tutorial
You need to change the URL's in two places. One in your app like you did, and the other in the django directory. This link has more information on how to do it.
from django.conf.urls import patterns, include, url
urlpatterns = patterns(
'',
url(r'', include('hello.urls')),
)
It was at http://127.0.0.1:8000/hello/, also used HunkDivine's answer as another option
I have the following code in my urls.py:
urlpatterns = patterns('',
(r'^news/', include('news.urls')),
)
When I try to open
http://localhost/news
or
http://localhost/news/
in the browser django shows me 404 page:
Using the URLconf defined in python.urls, Django tried these URL patterns, in this order:
^news/
The current URL, , didn't match any of these.
UPD:
news/urls.py:
from django.conf.urls.defaults import *
from django.views.generic.simple import direct_to_template
urlpatterns = patterns('news.views',
(r'^$', 'news'),
)
There is views.py in news directory and it contains news function.
And news module is added to INSTALLED_APPS.
Why it cannot find news pattern? Any suggestions?
Looks like you forgot the url() function:
Try this instead:
from django.conf.urls import url
urlpatterns = patterns('',
url(r'^news/', include('news.urls')),
)
and news/urls.py:
from django.conf.urls.defaults import *
from django.views.generic.simple import direct_to_template
from django.conf.urls import url
urlpatterns = patterns('news.views',
url(r'^$', 'news'),
)
In which port your application launches? When I see your tries http://locahost/news it might be that you forgot to use the right port.
Try to visit http://localhost:8000/ and http://localhost:8000/news.
I think it may be a problem with your views.py this url on the django docs tells you how to dispatch the urls properley
https://docs.djangoproject.com/en/dev/topics/http/urls/
I have a question about urls.py in Django. I am building a blog from scratch as a way of learning Django myself. In the main urls.py file, I have specified the include path to my app's urls.py.
from django.conf.urls import patterns, include, url
# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
(r'^', include('myblog.urls')),
)
In the app (called myblog), the urls.py reads as follows:
from django.conf.urls.defaults import *
from models import blogmodel
from django.contrib import admin
urlpatterns = patterns('',
(r'^login/', include(admin.site.urls)),
(r'^$', include('myblog.views.getLatest')),
)
where getLAtest is the function in my views.py. The error says No module named getLatest
Here's my views.py,
from django.shortcuts import render_to_response
from myblog.models import blogdb
def getLatest(request):
post = blogdb.objects.all()
sorted_post = post.order_by('-served_date')
return render_to_response('blogs.html', {'posts':sorted_post})
Any help is appreciated. Thanks in advance..
You are using the wrong directive; include() is used to include another package; Django will look for a urls.py within the package myblog.views.getLatest when you use that directive.
You want to name the view itself instead:
urlpatterns = patterns('',
(r'^login/', include(admin.site.urls)),
(r'^$', 'myblog.views.getLatest'),
)
Note: no include() is being used.
Try updating this:
urlpatterns = patterns('',
(r'^login/', include(admin.site.urls)),
(r'^$', include('myblog.views.getLatest')),
)
to this:
urlpatterns = patterns('',
(r'^getLatest/$', 'myblog.views.getLatest'),
)
include is meant to read in another urls.py file, where you you are wanting to execute a specific view function.