My program generates a series of windows using the following code:
def display(img, name, fun):
global clicked
cv.NamedWindow(name, 1)
cv.ShowImage(name, img)
cv.SetMouseCallback(name, fun, img)
while cv.WaitKey(33) == -1:
if clicked == 1:
clicked = 0
cv.ShowImage(name, img)
cv.DestroyWindow(name)
I press "q" within the gui window to close it. However, the code continues to the next call of the display function and displays a second gui window while not closing the first. I'm using a Mac with OpenCV 2.1, running the program in Terminal. How can I close the gui windows? Thanks.
You need to run cv.startWindowThread() after opening the window.
I had the same issue and now this works for me.
Hope this helps for future readers. And there is also a cv2 binding (I advise to use that instead of cv).
This code works for me:
import cv2 as cv
import time
WINDOW_NAME = "win"
image = cv.imread("ela.jpg", cv.CV_LOAD_IMAGE_COLOR)
cv.namedWindow(WINDOW_NAME, cv.CV_WINDOW_AUTOSIZE)
initialtime = time.time()
cv.startWindowThread()
while (time.time() - initialtime < 5):
print "in first while"
cv.imshow(WINDOW_NAME, image)
cv.waitKey(1000)
cv.waitKey(1)
cv.destroyAllWindows()
cv.waitKey(1)
initialtime = time.time()
while (time.time() - initialtime < 6):
print "in second while"
The same issue happens with the C++ version, on Linux:
Trying to close OpenCV window has no effect
There are a few peculiarities with the GUI in OpenCV. The destroyImage call fails to close a window (atleast under Linux, where the default backend was Gtk+ until 2.1.0) unless waitKey was called to pump the events. Adding a waitKey(1) call right after destroyWindow may work.
Even so, closing is not guaranteed; the the waitKey function is only intercepted if a window has focus, and so if the window didn't have focus at the time you invoked destroyWindow, chances are it'll stay visible till the next destroyWindow call.
I'm assuming this is a behaviour that stems from Gtk+; the function didn't give me any trouble when I used it under Windows.
Sayem2603
I tried your solution and it worked for me - thanks! I did some trial and error and discovered that looping 4 times did the trick for me... or posting the same code 4 times just the same..
Further, I drilled down to:
cv2.destroyAllWindows()
cv2.waitKey(1)
cv2.waitKey(1)
cv2.waitKey(1)
cv2.waitKey(1)
or simply calling DestroyAllWindows and then looping the waitKey() code 4 times:
cv2.destroyAllWindows()
for i in range (1,5):
cv2.waitKey(1)
Worked as well. I am not savvy enough to know why this works exactly, though I assume it has something to do with the interruption and delay created by looping that code(?)
Matthäus Brandl said, above, that the third waitKey() worked for him, so perhaps it is slightly different on each system? (I am running Linux Mint with 3.16.1 kernel and python 2.7)
The delay, alone, doesn't explain it, as simply increasing the delay time on the waitKey() does not do the trick. (Also looped print("Hello") 1000 times instead of using wiatKey() just to see if the delay that created helped any - it did not.) Must have something more to do with how waitKey() interacts with window events.
OpenCV Docs say: "This function is the only method in HighGUI that can fetch and handle events, so it needs to be called periodically for normal event processing unless HighGUI is used within an environment that takes care of event processing."
Perhaps it creates an interrupt of sorts in the GUI display that allows the destroyAllWindows() action to process?
J
Here is what worked for me:
cv2.namedWindow("image")
cv2.imshow('image', img)
cv2.waitKey(0) # close window when a key press is detected
cv2.destroyWindow('image')
cv2.waitKey(1)
This solution works for me (under Ubuntu 12.04 with python open in the shell):
Re-invoke cv.ShowImage after the window is 'destroyed'.
If you are using Spyder ( Anaconda Package ) there is the problem.
None of the solutions worked for me.
I discovered that the problem wasn't the functions, but a problem on Spyder really. Try to use a texteditor plus running on terminal and you be fine using simply:
WINDOW_NAME = "win"
image = cv.imread("foto.jpg", 0)
cv.namedWindow(WINDOW_NAME, cv.CV_WINDOW_AUTOSIZE)
cv.startWindowThread()
cv.imshow(WINDOW_NAME, image)
cv.waitKey()
cv.destroyAllWindows()
I solved the problem by calling cv2.waitKey(1) in a for loop, I don't know why it worked but gets my job done, so I didn't bother myself further.
for i in range(1,10):
cv2.destroyAllWindows()
cv2.waitkey(1)
you are welcome to explain.
It seems that none of the above solutions worked for me if I run it on Jupyter Notebook (the window hangs when closing and you need to force quit Python to close the window).
I am on macOS High Sierra 10.13.4, Python 3.6.5, OpenCV 3.4.1.
The below code works if you run it as a .py file (source: https://www.learnopencv.com/read-write-and-display-a-video-using-opencv-cpp-python/). It opens the camera, records the video, closes the window successfully upon pressing 'q', and saves the video in .avi format.
import cv2
import numpy as np
# Create a VideoCapture object
cap = cv2.VideoCapture(0)
# Check if camera opened successfully
if (cap.isOpened() == False):
print("Unable to read camera feed")
# Default resolutions of the frame are obtained.The default resolutions are system dependent.
# We convert the resolutions from float to integer.
frame_width = int(cap.get(3))
frame_height = int(cap.get(4))
# Define the codec and create VideoWriter object.The output is stored in 'outpy.avi' file.
out = cv2.VideoWriter('outpy.avi',cv2.VideoWriter_fourcc('M','J','P','G'), 10, (frame_width,frame_height))
while(True):
ret, frame = cap.read()
if ret == True:
# Write the frame into the file 'output.avi'
out.write(frame)
# Display the resulting frame
cv2.imshow('frame',frame)
# Press Q on keyboard to stop recording
if cv2.waitKey(1) & 0xFF == ord('q'):
break
# Break the loop
else:
break
# When everything done, release the video capture and video write objects
cap.release()
out.release()
# Closes all the frames
cv2.destroyAllWindows()
Fiddling around with this issue in the python console I observed the following behavior:
issuing a cv2.imshow after cv2.destroyWindow sometimes closes the window. Albeit the old window pops up again with the next highgui call, e.g., cv2.namedWindow
the third call of cv2.waitKey after cv2.destroyWindow closed the window every time I tried. Additionally the closed window remained closed, even when using cv2.namedWindow afterwards
Hope this helps somebody.
(I used Ubuntu 12.10 with python 2.7.3 but OpenCV 2.4.2 from the 13.04 repos)
After searching aroung for some time, none of the solutions provided worked for me so since there's a bug in this function and I did not have time to fix it, I did not have to use the cv2 window to show the frames. Once a few frames have been saved, you can open the file in a different viewer, like VLC or MoviePlayer ( for linux ).
Here's how i did mine.
import cv2
threadDie = True # change this to false elsewhere to stop getting the video
def getVideo(Message):
print Message
print "Opening url"
video = cv2.VideoCapture("rtsp://username:passwordp#IpAddress:554/axis-media/media.amp")
print "Opened url"
fourcc = cv2.cv.CV_FOURCC('X','V','I','D')
fps = 25.0 # or 30.0 for a better quality stream
writer = cv2.VideoWriter('out.avi', fourcc,fps, (640,480),1)
i = 0
print "Reading frames "
while threadDie:
ret, img = video.read()
print "frame number: ",i
i=i+1
writer.write(img)
del(video)
print "Finished capturing video"
Then open the file with a different viewer, prabably in a nother function, like if you like vlc, you can start it and pass the saved file as a parameter. On the terminal, i would do this
vlc out.avi #out.avi is my video file being saved by the function above.
This worked for me on arch linux.
I had the same issue. The problem is that while(cap.isOpened()): loop does not finish so that I added below structure. When video has no frame in the following part, it returns ret values as False. Normally, I put destroyAllWindows command out of loop but I moved it into the loop. It works in my code properly.
while(cap.isOpened()):
ret, frame = cap.read()
if ret == False:
cap.release()
cv2.waitKey(1)
cv2.destroyAllWindows()
cv2.waitKey(1)
This worked for me in spyder :
import cv2 as cv
cv.namedWindow("image")
img = cv.imread("image_name.jpg")
cv.imshow("image",img)
cv.waitKey(5000) # 5 sec delay before image window closes
cv.destroyWindow("image")
Remember use only cv.waitKey(positive Integer) for this to work
cv2.imshow("the image I want to show ",img)
cv2.waitKey(0)
cv2.destroyAllWindows()
cv2.waitKey(1) # to close the window.
The above code worked well for me.
I'm using Mac and python 3.7 .
Close the terminal, later close the window, it worked for me in Visual Studio Code in Windows; I made a task to compile and run the executable in the terminal, the program used my webcam to capture video and display it in a QT window, when I clicked the close button it didn't close, it reopened itself again and continued with the program until I closed the terminal and later could close the program window without it reopening again.
Related
When I am trying to start videocapuring with opencv and python, it simply does not load. Does not show any problems, does not return anything. NOTHING!!!
The code is the simpliest one:
import cv2
import sys
video_capture = cv2.VideoCapture(0)
while True:
ret, frame = video_capture.read()
cv2.imshow('Video', frame)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
video_capture.release()
cv2.destroyAllWindows()
This is the result of running this program
if I run code line by line, this is where it gets stuck
If I press Ctrl+C during execution of last line this is what it tells me:
Trying to dispose element pipeline0, but it is in PAUSED instead of the NULL state.
You need to explicitly set elements to the NULL state before
dropping the final reference, to allow them to clean up.
This problem may also be caused by a refcounting bug in the
application or some element.
Maybe not really a solution, but a 0-effort thing to try is specify the video backend like this:
video_capture = cv2.VideoCapture(0, CAP_V4L2)
I try start my code, but process finishes on step with method cv2.namedWindow (without
any errors).
Do you have any suggestions, why it could be so?
import cv2
image_cv2 = cv2.imread('/home/spartak/PycharmProjects/python_base/lesson_016/python_snippets/external_data/girl.jpg')
def viewImage(image, name_of_window):
print('step_1')
cv2.namedWindow(name_of_window, cv2.WINDOW_NORMAL)
print('step_2')
cv2.imshow(name_of_window, image)
print('step_3')
cv2.waitKey(0)
print('step_4')
cv2.destroyAllWindows()
cropped = image_cv2
viewImage(cropped, 'Cropped version')
P.S.:
Also I erased UBUNTU , and installed Fedora.
Instead Pycharm, check programm on VS code.
But nothing changes.
I changed location for picture (girl.jpg) to directory with python document.
But program stops on step1 and waiting something.
I find out the problem.
I started this code in virtual environment.
Apparently, in virtual environment on UBUNTU/FEDORA, opencv have restrictions.
The code completes all 4 steps for me
I think there is a problem with the image path which you took
The function cv2.namedWindow creates a window that can be used as a placeholder for images and trackbars. Created windows are referred to by their names If a window with the same name already exists, the function does nothing.
I do think the function
cv2.destroyAllWindows
This function is deallocating some needed gui elements, I would guess.
So calling this multiple times will produce some trouble.
import cv2
image_cv2 = cv2.imread('foo.jpg')
def viewImage(image, name_of_window):
print('step_1')
cv2.namedWindow(name_of_window)
print('step_2')
cv2.imshow(name_of_window, image)
print('step_3')
cv2.waitKey(0)
#print('step_4')
#cv2.destroyAllWindows()
cropped = image_cv2
viewImage(cropped, 'Cropped version')
#e.g. better usage at the end of the code or section
cv2.destroyAllWindows()
I'm on lubuntu 16.04, using OpenCV 3.2.0, Python 2.7 and encountering this error after a brief moment of imshow() displaying a window with my camera stream.
This error occurs randomly - the stream can run fine for half a minute before this happens, or it can happen right at the start when I first run the script.
ASSERT: "false" in file qasciikey.cpp, line 495
Aborted (core dumped)
My code appended below:
import numpy as np
import cv2
redcross_cascade = cv2.CascadeClassifier('rcrosscascade.xml')
cap = cv2.VideoCapture(2)
cv2.namedWindow('Haar', cv2.WINDOW_NORMAL)
while 1:
ret, img = cap.read()
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
redcross = redcross_cascade.detectMultiScale(gray, 50, 50)
for (x,y,w,h) in redcross:
cv2.rectangle(img,(x,y),(x+w,y+h),(255,255,0),2)
cv2.imshow('Haar',img)
key = cv2.waitKey(1) & 0xff
if key == 27:
break
cap.release()
cv2.destroyAllWindows()
Would appreciate any assistance on this matter, thank you!
EDIT: I have identified the trigger for this error - movement from my usb optical mouse. Disconnecting the mouse prevents the error from resurfacing but I've yet to find a reason for this occurrence.
I was receiving this error when I was running my python program (which used cv2) via an SSH terminal. When I ran the program from the machine itself, the error went away. I assume this is due to some X11 issue.
I was receiving this error before. Different webcam has different performance.
My method is to write the cv2.waitKey function after cv2.imshow function.
I have encountered the same issue. My app is similar to yours. None of the fixes suggested here have worked for me. I found that if I start single stepping in debug mode through the cap.read(), I can continue running a full speed and the problem will go away, although this is not a good fix.
I'm working with Python OpenCV to a project that as an initial step involves capturing an image from a webcam; I tried to automate this process by using capture = cv2.VideoCapture and capture.read(), but the camera's video mode activation and its subsequent self-adjusting are too slow for what I want to achieve in the end.
Is there a more direct method of automatically capturing a screenshot with Python (and OpenCV)? If not, do you have any alternative suggestion?
Thanks
If you want your camera screenshot function to be responsive, you need to initialize the camera capture outside of this function.
On the following code snippet, the screenshot function is triggered by pressing c:
import cv2
def screenshot():
global cam
cv2.imshow("screenshot", cam.read()[1]) # shows the screenshot directly
#cv2.imwrite('screenshot.png',cam.read()[1]) # or saves it to disk
if __name__ == '__main__':
cam = cv2.VideoCapture(0) # initializes video capture
while True:
ret, img = cam.read()
cv2.imshow("cameraFeed", img) # a window is needed as a context for key capturing (here, I display the camera feed, but there could be anything in the window)
ch = cv2.waitKey(5)
if ch == 27:
break
if ch == ord('c'): # calls screenshot function when 'c' is pressed
screenshot()
cv2.destroyAllWindows()
To clarify: cameraFeed window is only here for the purpose of the demo (where screenshot is triggered manually). If screenshot is called automatically in your program, then you don't need this part.
Hope it helps!
Basically you need to do 3 things:
#init the cam
video_capture = cv2.VideoCapture(0)
#get a frame from cam
ret, frame = video_capture.read()
#write that to disk
cv2.imwrite('screenshot.png',frame)
of course, you should wait a while before, if not you could save a weird black screen (or just the 1st thing the camera got :-) )
For my image processing algorithm I'm using python / OpenCV. The output of my algorithm shall be updated im the same window over and over again.
However sometimes the window freezes and doesn't update at all, but the algorithm is still running and updated the picture a multiple times in the meantime. The window turns dark gray on this Ubuntu machine.
Here is an excerpt of the involved code:
for i in range(0,1000):
img = loadNextImg()
procImg = processImg(img)
cv2.imshow("The result", procImg)
cv2.waitKey(1)
N.B.: processImg() takes about 1-2 s for its procedures. The line cv2.imshow(procImg) creates the window in first instance (i.e. there is no preceding invocation)
My suggestion is to use Matplotlib pyplot for displaying the image. I do it the following way.
import matplotlib.pyplot as plt
# load image using cv2....and do processing.
plt.imshow(cv2.cvtColor(image, cv2.BGR2RGB))
# as opencv loads in BGR format by default, we want to show it in RGB.
plt.show()
I know it does not solve the problem of cv2.imshow, but it solves our problem.
Increasing the wait time solves this issue. However in my opinion this is unnecessary time spent on sleeping (20 ms / frame), even though it's not much.
Changing
cv2.waitKey(1)
to
cv2.waitKey(20)
prevents the window from freezing in my case. The duration of this required waiting time may vary on different machines.
Just add cv2.destroyAllWindows() just after cv2.waitKey()
I have the very same issue and I noticed that the fps the window is updated is getting slower and slower until it freezes completely.
Increasing the waitKey(x) to something higher just extends the duration where the images are updated but when the time that cv2.imshow() needs to calculate exceeds the time from wait(Key) it just stops updating.
(Skip this complainment:)
I think the cv2.imshow() with waitKey() combination is a complete design error, why isn't imshow() just blocking until the UI is updated? That would make life so much easier without having to call waitKey() everytime...
P.S.: There is a possibility to start an own thread for opencv windows inside opencv:
import cv2
img = cv2.imread("image.jpg")
cv2.startWindowThread()
cv2.namedWindow("preview")
cv2.imshow("preview", img)
source: cv2.imshow command doesn't work properly in opencv-python
Well this doesn't work for me because I always get this errors when I run it:
(python3:1177): GLib-GObject-CRITICAL **: g_object_unref: assertion 'G_IS_OBJECT (object)' failed
Attempt to unlock mutex that was not locked
Aborted
Maybe you could try it and report if it is working for you?
Edit:
Okay I solved the problem for me by creating a separate script imshow.py:
import cv2
import os.path
while True:
if os.path.exists("image.pgm"):
image = cv2.imread("image.pgm")
if not image is None and len(image) > 0:
cv2.imshow("Frame", image)
cv2.waitKey(20)
And I am writing the image out in my other program with: cv2.imwrite("image.pgm", image)
And I am calling the script like this:
import subprocess
subprocess.Popen(["python3", "imshow.py"])
Although this is creating some dirty reads sometimes it is sufficient enough for me, a better solution would be to use pipes or queues between the two processes.
So what I think is going on here is that the window,(an element of the highGUI) which is still active after the first call to imshow, is waiting for some sort of response from your waitKey function, but is becoming inactive since the program is stuck calculating in either the processImg of loadNextImg functions. If you don't care about a slight waste of efficiency (i.e. you're not running on an embedded system where every operation counts), you should just destroy the window after waitKey, and recreate before imshow. Since the window no longer exists during the time you are processing and loading images, the highGUI wont get stuck waiting for a call from waitKey, and it won't become unresponsive.
If your window is going grey then it might be take more processing power. So try to resize image into smaller size image and execute. Sometimes times it freezes while running in ipython notebooks due to pressing any key while performing operation. I had personally executed your problem but I didn't get grey screen while doing it. I did executing directly using terminal. Code and steps are shown below.
import argparse
import cv2
import numpy as np
# construct the argument parser and parse the arguments
ap = argparse.ArgumentParser()
ap.add_argument("-i", "--image", required=True, help="Path to the image")
args = vars(ap.parse_args())
# load the image, grab its dimensions, and show it
image = cv2.imread(args["image"])
(h, w) = image.shape[:2]
cv2.imshow("Original", image)
cv2.waitKey(0)
for i in range(0,1000):
image = cv2.imread(args["image"])
cv2.imshow("The result",image);
cv2.waitKey(0)
Run it in terminal:
source activate env_name
python Filename.py --image Imagename.png
This will get to your result in one window only(updating each time) without freezing and if you want seperate image in every new window then add .format(i) as given below. But Remember to run in terminal only not in jupyter notebooks.
You can check using terminal commands in this video link
https://www.youtube.com/watch?v=8O-FW4Wm10s
for i in range(0,1000):
image = cv2.imread(args["image"])
cv2.imshow("The result{}".format(i),image);
cv2.waitKey(0)
This may help to get you 1000 images separately.
try:
import cv2
except:
print("You need to install Opencv \n Run this command \n pip install python-opencv")
exit()
print('Press q to quit frame')
def viewer(name,frame):
while True:
cv2.imshow(name,frame)
if cv2.waitKey(10) & 0xff ==ord('q'):
break
return
cv2.destroyWindow(name)
Save this program and from now onwards, import this and use the function viewer to display any frame/image and your display windows will not hang or crash.
Add the following two lines of code after cv2.imshow() function,
cv2.waitKey()
cv2.destroyAllWindows()
You can use while loop to take burst images without freezing. Here is an example for taking 10 images. You can also try to increase waitkey number and sleep time in while loop. This work for me.
key = cv2.waitKey(1)
webcam = cv2.VideoCapture(0)
sleep(1)
while True:
try:
check, frame = webcam.read()
cv2.imshow("Capturing", frame)
key = cv2.waitKey(1)
img_counter = 0
if key & 0xFF == ord('s'): #press s to take images
while img_counter < 10:
check, frame = webcam.read()
cv2.imshow("Capturing", frame)
key = cv2.waitKey(1)
path = 'F:/Projects/' #folder path to save burst images
img_name = "burst_{}.png".format(img_counter)
cv2.imwrite(os.path.join(path, img_name), img=frame)
print("Processing image...")
img_ = cv2.imread(img_name, cv2.IMREAD_ANYCOLOR) #save as RGB color format
print("{} written!".format(img_name))
img_counter += 1
sleep(0.2)
webcam.release()
cv2.destroyAllWindows()
break
elif key == ord('q'): #press q to quit without taking images
webcam.release()
cv2.destroyAllWindows()
break
except(KeyboardInterrupt):
print("Turning off camera.")
webcam.release()
print("Camera off.")
print("Program ended.")
cv2.destroyAllWindows()
break
This is an old thread but in case someone else encounters it, normally the issue happen when you update opencv/opencv-contrib versions with pip and still some of their dependencies are unmet (for example you might have numpy already installed so it wont reinstall it and this causes it to crash in the back).
Simply do
pip install opencv-python opencv-contrib-python --no-cache --force-reinstall
Version 4.5.2.52 is working fine on ubuntu 20.04 and 18.04 with python > 3.8