I have been trying to create a web service out some python scripts, and haven't seemed to have had much luck. I am new to web services in general, but would really like to get this figured out. I'm on Windows 7 and use IIS7. The service also needs to be SOAP.
I've read through most posts that have anything to do with python and SOAP and tried out pretty much all the different libraries, but most of them just seem over my head (especially ZSI/SOAPpy). The Ladon Library seems like it would be best (and simplest) for what I need, but the tutorial http://www.youtube.com/watch?v=D_JYjEBedk4&feature=feedlik loses me at 5:10 when he brings it to the server. When I type the ladon2.6ctl in the cmd, it seems like windows gets quite confused. I'm guessing it is a little different because he is running on Linux and using Apache.
With that, any tips on how to get a python web service running on Microsoft 'stuff' would be greatly appreciated, as I have been trying to figure this stuff out for way too long.
One thing to note is the reason things are so specific (and seemingly strange) is because the scripts I have do a lot of geoprocessing with ESRI's "arcpy".
--Addition--
Traceback on localhost:8080/TestService:
Traceback (most recent call last):
<br>File "c:\Python26\ArcGIS10.0\lib\site-packages\ladon-0.5.1-py2.6.egg\ladon\server\wsgi_application.py", line 229, in __call__
exec("import %s" % ','.join(self.service_list))
File "<string>", line 1, in <module>
File "c:\Users\r\workspace\ladon\src\testspace.py", line 3, in <module>
class TestService2(object):
File "c:\Users\r\workspace\ladon\src\testspace.py", line 4, in TestService2
#ladonize(int,int,rtype=int)
File "c:\Python26\ArcGIS10.0\lib\site-packages\ladon-0.5.1-py2.6.egg\ladon\ladonizer\decorator.py", line 87, in decorator
ladon_method_info = global_service_collection().add_service_method(f,*def_args,**def_kw)
File "c:\Python26\ArcGIS10.0\lib\site-packages\ladon-0.5.1-py2.6.egg\ladon\ladonizer\collection.py", line 119, in add_service_method
sinfo = self.source_info(src_fname)
File "c:\Python26\ArcGIS10.0\lib\site-packages\ladon-0.5.1-py2.6.egg\ladon\ladonizer\collection.py", line 79, in source_info
a = ast.parse(src)
File "c:\Python26\ArcGIS10.0\lib\ast.py", line 37, in parse
return compile(expr, filename, mode, PyCF_ONLY_AST)
File "<unknown>", line 1
from ladon.ladonizer import ladonize
^
SyntaxError: invalid syntax
sample code:
from ladon.ladonizer import ladonize
class TestService2(object):
#ladonize(int,int,rtype=int)
def sum(self,a,b):
'''add two numbers<br>
param a: number 1
param b: number 2
rtype: sum of result
'''
return a+b
I must admit I normally use Linux for almost everything and I haven't tried Ladon on Windows for a while. I will spin up my windows installation later today and see if there is any trouble.
You wrote that ladon2.6ctl get's confused. Do you have an exception Traceback?
To summarize the fix for anyone else interested, delete the "syslog import" from these 3 ladon modules: ladon/interfaces/jsonwsp.py - line 6
ladon/dispatcher/dispatcher.py - line 7
ladon/server/wsgi_application.py - line 37
Then, you need to change the linefeed from window's default of /r/n to /n. In Eclipse, go to Window -> Preferences -> General, then select (not drop down) the Workspace tab. On the bottom right, select "other" under New text file line delimiter and change it to Unix.
Related
So i have a problem, whenever i try to use Pyinstaller with Pygame, it won't work, instead after a second, it says that it stopped working. I ran a test program before (consisting of a block moving up and down and a block following your cursor) and it worked just fine. However, i tried implementing some text using pygame.font.Font function and suddenly it stopped working. I tried using a try function to see if it could catch it, and nothing. I tried using no font, nothing. This also works as a regular .py file as well, just not as an executable. I'll include further info as needed if need be.
Thanks in advance!
EDIT:i was able to produce an error thanks to kaktus_car letting me know that there was an update to pygame, here it is:
Traceback (Most recent call last):
"test.py", line 20, in <module>
File "site-packages\pygame\pkgdata.py", line 50, in getResource
File "site-packages\pkg_resources\__init__.py", line 1134, in resource_exists
File "site-packages\pkg_resources\__init__.py", line 1404, in has_resource
File "site-packages\pkg_resources\__init__.py", line 1472, in _has
NotImplementedError: Can't perform this operation for unregistered loader type
[1276] Failed to execute script test
So, i managed to figure it out! What i did was i instaed used a different application than pyinstaller. Instead, i used cx_Freeze. If you are having this kind of problem as well, the link is Here the directions are rather clear and you have the option to include files, so if you have a game with made graphics, it can include them.
I'm trying to locally minimize a complicated function using scipy.optimize.minimize. Since I require good gradients in order for the local optimization to be smoothily performed, but the function is so very much complicated in order for the derivatives to be written by hand, I decided to use Autoptim as the middle-man to handle my optimization using the automatic differentiation package Autograd to obtain the gradients.
After I installed the package (as well as Autograd), I opened my python terminal in order to run a few preliminary tests to check whether the installation and the package integration between scipy, autograd and autoptim went smoothily. Then Autoptim raised an error immediately upon import (at the line import autoptim). Since the interpreter gives the full stack of Exceptions raised, I went to the deeper layers to see what line initiated the cascade that halted the interpreter.
The line I found was line 88 of autoptim.py:
87. optim_vars = _convert_to_tuple(optim_vars)
88. precon_optim_vars = precon_fwd(*optim_vars,*args)
89. n_args = len(args)
Python interpreter raised an Invalid Syntax Exception, which means that something in that line is not written "in Python". I checked to see whether there was some unclosed parenthesis and that was not the case. I am using Python 3 so I figured that maybe something on that line was written in Python 2 syntax and it registers wrong for a Python 3 interpreter but as I understand it, the differences between the two versions is quite small and there is some (although not complete) retrocompatibility between the two.
So what gives? What am I missing here?
What is wrong with that line?
Here is the traceback of the import line in the python interpreter
>>> import autoptim
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python3.4/dist-packages/autoptim/__init__.py", line 6, in <module>
from .autoptim import minimize # noqa
File "/usr/local/lib/python3.4/dist-packages/autoptim/autoptim.py", line 95
return objective_function(*optim_vars, *args)
^
SyntaxError: invalid syntax
The syntax being used wasn't introduced until Python 3.5 (see PEP 448). You are using Python 3.4.
As a workaround, you could explicitly build the required list to unpack:
return objective_function(*list(optim_vars + args))
I am trying to connect to a SQL Anywhere database via python. I have created the DSN and I can use command prompt to connect to the database using dbisql - c "DNS=myDSN". When I try to connect through python using con = sqlanydb.connect(DSN= "myDSN")
I get
`Traceback (most recent call last):
File "<pyshell#5>", line 1, in <module>
con = sqlanydb.connect(DSN= "RPS Integration")
File "C:\Python27\lib\site-packages\sqlanydb.py", line 522, in connect
return Connection(args, kwargs)
File "C:\Python27\lib\site-packages\sqlanydb.py", line 538, in __init__
parent = Connection.cls_parent = Root("PYTHON")
File "C:\Python27\lib\site-packages\sqlanydb.py", line 464, in __init__
'libdbcapi_r.dylib')
File "C:\Python27\lib\site-packages\sqlanydb.py", line 456, in load_library
raise InterfaceError("Could not load dbcapi. Tried: " + ','.join(map(str, names)))
InterfaceError: (u'Could not load dbcapi. Tried: None,dbcapi.dll,libdbcapi_r.so,libdbcapi_r.dylib', 0)`
I was able to resolve the problem. I was never able to use the sqlanydb.connect. I ended up using pyodbc. So my final connection string was con = pydobc.connect(dsn="myDSN"). I think that sqlanydb is only fully functional with sqlanydb 17 and I was using a previous version.
Depending on how Sybase is locally installed, it could also be that the Python module really cannot find the (correct) library when looking up dbcapi.dll in your PATH. A quick fix for that is to create a new SQLANY_API_DLL environment variable (that's the initial None in the names the error message says it tried using; it takes priority over all the others) containing the correct path, usually something like %SQLANY16%\Bin64\dbcapi.dll depending on what version you have installed (Sybase usually creates an environment variable pointing to its installation folder on a per version basis).
One way to encounter the backtrace shown by the OP is running 64-bit Python interpreter, which is unable to load the 32-bit dbcapi.dll. Try launching with "py -X-32" to force a 32-bit engine, or reinstall using a 32-bit python engine.
Unfortunately sqlanydb's code that tries to be smart about finding dbcapi also ends up swallowing the exceptions thrown during loading. The sqlanydb author probably assumed that failure to load implies file not found, which isn't always the case.
I was stoked in this same problem, both windows system32 and 64.
I'm using Python 3.9 and I found that since Python 3.8 the cdll.LoadLibrary function does no longer search PATH to find library files.
To fix this, I created the enviroment variable SQLANY_API_DLL pointing to the route of sqlanywhere installation, in my case version 17, bin32 or bin64 depending on your system.
I started using it on one of my programs a while back. Ever since, whenever I type the tab key on a console (cmd.exe instance) with python running, I get a readline internal error. Full traceback is as follows (note I haven't imported the cmd module in this context or even imported a script using it. I've simply started python, pressed tab and voila an exception):
<pre>
Traceback (most recent call last):
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\lib\site-packages\pyreadline\console\console.py", line 768, in hook_wrapper_23
res = ensure_str(readline_hook(prompt))
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\lib\site-packages\pyreadline\rlmain.py", line 571, in readline
self._readline_from_keyboard()
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\lib\site-packages\pyreadline\rlmain.py", line 536, in _readline_from_keyboard
if self._readline_from_keyboard_poll():
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\lib\site-packages\pyreadline\rlmain.py", line 556, in _readline_from_keyboard_poll
result = self.mode.process_keyevent(event.keyinfo)
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\lib\site-packages\pyreadline\modes\emacs.py", line 243, in process_keyevent
r = self.process_keyevent_queue[-1](keyinfo)
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\lib\site-packages\pyreadline\modes\emacs.py", line 286, in _process_keyevent
r = dispatch_func(keyinfo)
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\lib\site-packages\pyreadline\modes\basemode.py", line 257, in complete
completions = self._get_completions()
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\lib\site-packages\pyreadline\modes\basemode.py", line 200, in _get_completions
r = self.completer(ensure_unicode(text), i)
File "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\Lib\rlcompleter.py", line 80, in complete
readline.redisplay()
AttributeError: module 'readline' has no attribute 'redisplay'
</pre>
Before u ask, I installed python to the directory "C:\SP_CI_PROGRAMS\Languages\Python\3.6.1". It's accessible from the path variable. Also any scripts I design I place in a directory u can also access from the path variable (including one using the cmd module for python).
This may not seem like a pressing concern, especially seeing as I can just type 4 spaces instead, however using tabs is something I've become especially accustomed to and the second I type the tab key, anything I've written in a previous block is immediately lost as the traceback is printed. Please, can someone tell me how to fix this.
Edit: This is only within the python interpreter. Typing tab within a running program or something else doesn't pose any problems.
Tested solution for Windows 10 (17 January 2020)
Copy last traceback file path C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\Lib\rlcompleter.py
Open it with any text editor
If has VsCode use cmd and copy this
code C:\SP_CI_PROGRAMS\Languages\Python\3.6.1\Lib\rlcompleter.py
Look the line 80 which traceback tell us
Change these line (starts 79) like bellow and It will works
There will no error message and unnecessary tab more
...
if _readline_available: ## The old one is ##
if hasattr(readline, 'redisplay'): # if _readline_available:
readline.insert_text('\t') # readline.insert_text('\t')
readline.redisplay() # readline.redisplay()
return '' # return ''
...
Do not forget to relaunch your python terminal
Seems to be a continuing issue for Windows machines as seen on Github. A workaround seems to be uninstalling the pyreadline package.
Stop using pyreadline. It's been abandoned. What you're seeing is a known issue, but unless someone takes over pyreadline development, it's unlikely to ever be fixed.
pyreadline can be uninstalled by typing pip uninstall pyreadline in the command prompt. I was experiencing the same issue, but after uninstalling pyreadline, Tab key is working for me.
NOTE: To see the installed packages, type pip list in command prompt.
Well if you don't have permission on the machine. You won't be able to do those uninstall solutions.
So set the completer function. It will solve the problem and won't have weird behaviors. But the auto-completion won't work anymore. If you want it to work have a look at the documentation and implement it.
readline.set_completer(lambda t, s: [None][s])
What has worked for me (while the others did not for some unbeknownst reason) is the following:
In line 78:
if _readline_available:
if hasattr(readline, 'redisplay'):
readline.insert_text('\t')
readline.redisplay()
return ' ' * 4
My goal is to automate configuring firewalls on CentOS 7 machines using Python.
The OS comes with firewalld, so that's what I'm using. I looked into it and found that it uses dbus (I've never heard of or dealt with any of this - please correct me if anything I say is incorrect.)
I found this documentation for how to control dbus processes using Python:
http://dbus.freedesktop.org/doc/dbus-python/doc/tutorial.txt
I checked and the version of Python that comes with the OS includes the dbus module, so it seems like a promising start.
That document suggests that I needed to learn more about what firewalld exposes via the dbus interface. So I did some more research and found this:
https://www.mankier.com/5/firewalld.dbus
The first document says I need to start out with a "well-known name". Their example for such a thing was org.freedesktop.NetworkManager. The second document is titled firewalld.dbus, so I figured that was as good a name as any to try since the document doesn't explicitly give a name anywhere else.
The first document also says I need a name for an object path. Their example is /org/freedesktop/NetworkManager. The second document has an object path of /org/fedoraproject/FirewallD1.
I put those together and tried using the first method the first document suggested, SystemBus's get_object():
>>> from dbus import SystemBus
>>> bus = SystemBus()
>>> proxy = bus.get_object('firewalld.dbus', '/org/fedoraproject/FirewallD1')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib64/python2.7/site-packages/dbus/bus.py", line 241, in get_object
follow_name_owner_changes=follow_name_owner_changes)
File "/usr/lib64/python2.7/site-packages/dbus/proxies.py", line 248, in __init__
self._named_service = conn.activate_name_owner(bus_name)
File "/usr/lib64/python2.7/site-packages/dbus/bus.py", line 180, in activate_name_owner
self.start_service_by_name(bus_name)
File "/usr/lib64/python2.7/site-packages/dbus/bus.py", line 278, in start_service_by_name
'su', (bus_name, flags)))
File "/usr/lib64/python2.7/site-packages/dbus/connection.py", line 651, in call_blocking
message, timeout)
dbus.exceptions.DBusException:
org.freedesktop.DBus.Error.ServiceUnknown:
The name firewalld.dbus was not provided by any .service files
I also gave org.fedoraproject.FirewallD1 a try as the first parameter but ended up with a similar error message.
Why are these not working? Is there some way I can discover what the proper names are? It mentions ".service files" at the end of the error message... where would such a file be located?
Edit: Found several ".service files" by using find / -name *.service. One of them is at /usr/lib/systemd/system/firewalld.service... seems pretty promising so I'll check it out.
Edit 2: It's a rather short file... only about 10 lines. One of them says BusName=org.fedoraproject.FirewallD1. So I'm not sure why it said the name was not provided by any .service files... unless it's not using this file for some reason?
If the unit file says:
BusName=org.fedoraproject.FirewallD1
Then maybe you should try using that as your bus name:
>>> import dbus
>>> bus = dbus.SystemBus()
>>> p = bus.get_object('org.fedoraproject.FirewallD1', '/org/fedoraproject/FirewallD1')
>>> p.getDefaultZone()
dbus.String(u'FedoraWorkstation')
I figured this out based on the fact that this:
>>> help(bus.get_object)
Says that the get_object call looks like:
get_object(self, bus_name, object_path, introspect=True, follow_name_owner_changes=False, **kwargs)