I've been trying to create a python script that edits a file, but if the file is not already there, it has an error like this:
Traceback (most recent call last):
File "openorcreatfile.py", line 56, in <module>
fileHandle = (pathToFile, 'w')
IOError: [Errno 2] No such file or directory: '/home/me/The_File.txt'
It works fine if the file exists. I've also tried this:
fileHandle = (pathToFile, 'w+')
But it comes up with the same error. Do I need to explicitly check if the file is there? If so, how do I create the file?
EDIT: Sorry, I realized the folder was missing. I'm an idiot.
The error says "No such file or directory."
Since you're trying to create a file, that must not be what's missing. So you need to create the /home/me/ directory.
See os.makedirs.
fo = open("myfile.txt", "wb")
fo.write('blah')
fo.close()
That's it, this will do the job.
myfile = open('test.txt','w')
myfile.write("This is my first text file written in python\n")
myfile.close()
To check if the file is there you can do:
import os.path
os.path.isfile(pathToFile)
so you can handle it, only if it exists:
if os.path.isfile(pathToFile):
fileHandle = (pathToFile, 'w')
else:
pass #or other thing
There are several ways to create a file in python, but if you want to create a text file, take a look at numpy.savetxt, which I think is one of the easiest and most effective ways
with open("filename.txt", "w") as f:
f.write("test")
Related
Goal = Open file, encrypt file, write encrypted file.
Trying to use the PyPDF2 module to accomplish this. I have verified theat "input" is a file type object. I have researched this error and it translates to "file not found". I believe that it is linked somehow to the file/file path but am unsure how to debug or troubleshoot. and getting the following error:
Traceback (most recent call last):
File "CommissionSecurity.py", line 52, in <module>
inputStream = PyPDF2.PdfFileReader(input)
File "build\bdist.win-amd64\egg\PyPDF2\pdf.py", line 1065, in __init__
File "build\bdist.win-amd64\egg\PyPDF2\pdf.py", line 1660, in read
IOError: [Errno 22] Invalid argument
Below is the relevant code. I'm not sure how to correct this issue because I'm not really sure what the issue is. Any guidance is appreciated.
for ID in FileDict:
if ID in EmailDict :
path = "C:\\Apps\\CorVu\\DATA\\Reports\\AlliD\\Monthly Commission Reports\\Output\\pdcom1\\"
#print os.listdir(path)
file = os.path.join(path + FileDict[ID])
with open(file, 'rb') as input:
print type(input)
inputStream = PyPDF2.PdfFileReader(input)
output = PyPDF2.PdfFileWriter()
output = inputStream.encrypt(EmailDict[ID][1])
with open(file, 'wb') as outputStream:
output.write(outputStream)
else : continue
I think your problem might be caused by the fact that you use the same filename to both open and write to the file, opening it twice:
with open(file, 'rb') as input :
with open(file, 'wb') as outputStream :
The w mode will truncate the file, thus the second line truncates the input.
I'm not sure what you're intention is, because you can't really try to read from the (beginning) of the file, and at the same time overwrite it. Even if you try to write to the end of the file, you'll have to position the file pointer somewhere.
So create an extra output file that has a different name; you can always rename that output file to your input file after both files are closed, thus overwriting your input file.
Or you could first read the complete file into memory, then write to it:
with open(file, 'rb') as input:
inputStream = PyPDF2.PdfFileReader(input)
output = PyPDF2.PdfFileWriter()
output = input.encrypt(EmailDict[ID][1])
with open(file, 'wb') as outputStream:
output.write(outputStream)
Notes:
you assign inputStream, but never use it
you assign PdfFileWriter() to output, and then assign something else to output in the next line. Hence, you never used the result from the first output = line.
Please check carefully what you're doing, because it feels there are numerous other problems with your code.
Alternatively, here are some other tips that may help:
The documentation suggests that you can also use the filename as first argument to PdfFileReader:
stream – A File object or an object that supports the standard read
and seek methods similar to a File object. Could also be a string
representing a path to a PDF file.
So try:
inputStream = PyPDF2.PdfFileReader(file)
You can also try to set the strict argument to False:
strict (bool) – Determines whether user should be warned of all
problems and also causes some correctable problems to be fatal.
Defaults to True.
For example:
inputStream = PyPDF2.PdfFileReader(file, strict=False)
Using open(file, 'rb') was causing the issue becuase PdfFileReader() does that automagically. I just removed the with statement and that corrected the problem.
with open(file, 'rb') as input:
inputStream = PyPDF2.PdfFileReader(input)
This error raised up because of PDF file is empty.
My PDF file was empty that's why my error was raised up. So First of all i fill my PDF file with some data and Then start reeading it using PyPDF2.PdfFileReader,
And it solved my Problem!!!
Late but, you may be opening an invalid PDF file or an empty file that's named x.pdf and you think it's a PDF file
I am totally new to python.
I was trying to read a file which I already created but getting the below error
File "C:/Python25/Test scripts/Readfile.py", line 1, in <module>
filename = open('C:\Python25\Test scripts\newfile','r')
IOError: [Errno 2] No such file or directory: 'C:\\Python25\\Test scripts\newfile
My code:
filename = open('C:\Python25\Test scripts\newfile','r')
print filename.read()
Also I tried
filename = open('C:\\Python25\\Test scripts\\newfile','r')
print filename.read()
But same errors I am getting.
Try:
fpath = r'C:\Python25\Test scripts\newfile'
if not os.path.exists(fpath):
print 'File does not exist'
return
with open(fpath, 'r') as src:
src.read()
First you validate that file, that it exists.
Then you open it. With wrapper is more usefull, it closes your file, after you finish reading. So you will not stuck with many open descriptors.
I think you're probably having this issue because you didn't include the full filename.
You should try:
filename = open('C:\Python25\Test scripts\newfile.txt','r')
print filename.read()
*Also if you're running this python file in the same location as the target file your are opening, you don't need to give the full directory, you can just call:
filename = open(newfile.txt
I had the same problem. Here's how I got it right.
your code:
filename = open('C:\\Python25\\Test scripts\\newfile','r')
print filename.read()
Try this:
with open('C:\\Python25\\Test scripts\\newfile') as myfile:
print(myfile.read())
Hope it helps.
I am using VS code. If I am not using dent it would not work for the print line. So try to have the format right then you will see the magic.
with open("mytest.txt") as myfile:
print(myfile.read())
or without format like this:
hellofile=open('mytest.txt', 'r')
print(hellofile.read())
I have this file animallog1.txt which contains information that i would like to use to answer questions using python. How would i import the file to python, which would latter be used
I tried
with open('animallog1.txt', 'r') as myfile
but this is not working and just outputs no such file or directory even though i am pretty sure it exists
animal_names, dates, locations = [], [], []
with open('animallog1.txt', 'r') as myfile:
for line in myfile:
animal_name, date, location = line.strip().split(':')
animal_names.append(animal_name)
dates.append(date)
locations.append(location)
print(animal_names)
print(dates)
print(locations)
so this is the code that i have. animallog1.txt is the name of the file that i want to use.
However my output is
Traceback (most recent call last):
File "None", line 3, in <module>
builtins.FileNotFoundError: [Errno 2] No such file or directory: 'animallog1.txt'
how can i fix this?
Make sure you path is corret or try this:
file = open("sample.txt")
sample.txt is present in the current path, in my ubuntu it works.
I would take a look at this. So modifying your code could be like:
f = open('animal data.txt', 'r+');
f.readline(); //Do this until you've read your questions
f.write('Answer to the questions')
I'm having a problem opening the names.txt file. I have checked that I am in the correct directory. Below is my code:
import os
print(os.getcwd())
def alpha_sort():
infile = open('names', 'r')
string = infile.read()
string = string.replace('"','')
name_list = string.split(',')
name_list.sort()
infile.close()
return 0
alpha_sort()
And the error I got:
FileNotFoundError: [Errno 2] No such file or directory: 'names'
Any ideas on what I'm doing wrong?
You mention in your question body that the file is "names.txt", however your code shows you trying to open a file called "names" (without the ".txt" extension). (Extensions are part of filenames.)
Try this instead:
infile = open('names.txt', 'r')
As a side note, make sure that when you open files you use universal mode, as windows and mac/unix have different representations of carriage returns (/r/n vs /n etc.). Universal mode gets python to handle this, so it's generally a good idea to use it whenever you need to read a file. (EDIT - should read: a text file, thanks cameron)
So the code would just look like this
infile = open( 'names.txt', 'rU' ) #capital U indicated to open the file in universal mode
This doesn't solve that issue, but you might consider using with when opening files:
with open('names', 'r') as infile:
string = infile.read()
string = string.replace('"','')
name_list = string.split(',')
name_list.sort()
return 0
This closes the file for you and handles exceptions as well.
im trying to create a script that opens a file and replace every 'hola' with 'hello'.
f=open("kk.txt","w")
for line in f:
if "hola" in line:
line=line.replace('hola','hello')
f.close()
But im getting this error:
Traceback (most recent call last):
File "prueba.py", line 3, in
for line in f: IOError: [Errno 9] Bad file descriptor
Any idea?
Javi
open('test.txt', 'w').write(open('test.txt', 'r').read().replace('hola', 'hello'))
Or if you want to properly close the file:
with open('test.txt', 'r') as src:
src_text = src.read()
with open('test.txt', 'w') as dst:
dst.write(src_text.replace('hola', 'hello'))
Your main issue is that you're opening the file for writing first. When you open a file for writing, the contents of the file are deleted, which makes it quite difficult to do replacements! If you want to replace words in the file, you have a three-step process:
Read the file into a string
Make replacements in that string
Write that string to the file
In code:
# open for reading first since we need to get the text out
f = open('kk.txt','r')
# step 1
data = f.read()
# step 2
data = data.replace("hola", "hello")
f.close()
# *now* open for writing
f = open('kk.txt', 'w')
# step 3
f.write(data)
f.close()
You've opened the file for writing, but you're reading from it. Open the original file for reading and a new file for writing. After the replacement, rename the original out and the new one in.
You could also have a look at the with statement.