Develop Reference

OpenCV cv2.rectangle output binary image

I have been trying to draw rectangle on a black image, uscv2.rectangle.Here is my code : (It is just a sample, in actual code there is a loop i.e values x2,y2,w2,h2 changes in a loop)
heir = np.zeros((np.shape(image1)[0],np.shape(image1)[1]),np.uint8);
cv2.rectangle(heir,(x2,y2),(x2+w2,y2+h2),(255,255,0),5)
cv2.imshow("img",heir);
cv2.waitKey()
It is giving the following output:
Why the image is like that? Why the boundaries are not just a line a width 5.
I have tried, but I am not able to figure it out.

Can't post this in a comment, but it's a negative answer: the same operations work for me on Windows/python 2.7.8/opencv3.1
import numpy as np
import cv2
heir = np.zeros((100,200),np.uint8);
x2=10
y2=20
w2=30
h2=40
cv2.rectangle(heir,(x2,y2),(x2+w2,y2+h2),(255,255,0),5)
cv2.imshow("img",heir);
cv2.waitKey()

Because you are loading the image to be tagged (draw rectangles) in grayscale, thats why when you are adding rectangles/bounding boxes the colors are being converted to grayscale.
To fix the issue, open image in "color" format. Since, you didn't included that part of code, here is the proposed solution:
tag_img = cv2.imread(MYIMAGE,1)
Pay attention to the second parameter here, which is "1" and means load image as color. Read more about reading images here: https://docs.opencv.org/3.0-beta/doc/py_tutorials/py_gui/py_image_display/py_image_display.html

RGB Values Being Returned by PIL don't match RGB color

I'm attempting to make a reasonably simple code that will be able to read the size of an image and return all the RGB values. I'm using PIL on Python 2.7, and my code goes like this:
import os, sys
from PIL import Image
img = Image.open('C:/image.png')
pixels = img.load()
print(pixels[0, 1])
now this code was actually gotten off of this site as a way to read a gif file. I'm trying to get the code to print out an RGB tuple (in this case (55, 55, 55)) but all it gives me is a small sequence of unrelated numbers, usually containing 34.
I have tried many other examples of code, whether from here or not, but it doesn't seem to work. Is it something wrong with the .png format? Do I need to further code in the rgb part? I'm happy for any help.

My guess is that your image file is using pre-multiplied alpha values. The 8 values you see are pretty close to 55*34/255 (where 34 is the alpha channel value).
PIL uses the mode "RGBa" (with a little a) to indicate when it's using premultiplied alpha. You may be able to tell PIL to covert the to normal "RGBA", where the pixels will have roughly the values you expect:
img = Image.open('C:/image.png').convert("RGBA")
Note that if your image isn't supposed to be partly transparent at all, you may have larger issues going on. We can't help you with that without knowing more about your image.

Python PIL: Convert RGBA->P - ValueError: image has wrong mode [duplicate]

I would like to convert a PNG32 image (with transparency) to PNG8 with Python Image Library.
So far I have succeeded converting to PNG8 with a solid background.
Below is what I am doing:
from PIL import Image
im = Image.open("logo_256.png")
im = im.convert('RGB').convert('P', palette=Image.ADAPTIVE, colors=255)
im.save("logo_py.png", colors=255)

After much searching on the net, here is the code to accomplish what I asked for:
from PIL import Image
im = Image.open("logo_256.png")
# PIL complains if you don't load explicitly
im.load()
# Get the alpha band
alpha = im.split()[-1]
im = im.convert('RGB').convert('P', palette=Image.ADAPTIVE, colors=255)
# Set all pixel values below 128 to 255,
# and the rest to 0
mask = Image.eval(alpha, lambda a: 255 if a <=128 else 0)
# Paste the color of index 255 and use alpha as a mask
im.paste(255, mask)
# The transparency index is 255
im.save("logo_py.png", transparency=255)
Source: http://nadiana.com/pil-tips-converting-png-gif
Although the code there does not call im.load(), and thus crashes on my version of os/python/pil. (It looks like that is the bug in PIL).

As mentioned by Mark Ransom, your paletized image will only have one transparency level.
When saving your paletized image, you'll have to specify which color index you want to be the transparent color like this :
im.save("logo_py.png", transparency=0)
to save the image as a paletized colors and using the first color as a transparent color.

This is an old question so perhaps older answers are tuned to older version of PIL?
But for anyone coming to this with Pillow>=6.0.0 then the following answer is many magnitudes faster and simpler.
im = Image.open('png32_or_png64_with_alpha.png')
im = im.quantize()
im.save('png8_with_alpha_channel_preserved.png')

Don't use PIL to generate the palette, as it can't handle RGBA properly and has quite limited quantization algorithm.
Use pngquant instead.

Python Image Library: clean Downsampling

I've been having trouble trying to get PIL to nicely downsample images. The goal, in this case, is for my website to automagically downsample->cache the original image file whenever a different size is required, thus removing the pain of maintaining multiple versions of the same image. However, I have not had any luck. I've tried:
image.thumbnail((width, height), Image.ANTIALIAS)
image.save(newSource)
and
image.resize((width, height), Image.ANTIALIAS).save(newSource)
and
ImageOps.fit(image, (width, height), Image.ANTIALIAS, (0, 0)).save(newSource)
and all of them seem to perform a nearest-neighbout downsample, rather than averaging over the pixels as it should Hence it turns images like
http://www.techcreation.sg/media/projects//software/Java%20Games/images/Tanks3D%20Full.png
to
http://www.techcreation.sg/media/temp/0x5780b20fe2fd0ed/Tanks3D.png
which isn't very nice. Has anyone else bumped into this issue?

That image is an indexed-color (palette or P mode) image. There are a very limited number of colors to work with and there's not much chance that a pixel from the resized image will be in the palette, since it will need a lot of in-between colors. So it always uses nearest-neighbor mode when resizing; it's really the only way to keep the same palette.
This behavior is the same as in Adobe Photoshop.
You want to convert to RGB mode first and resize it, then go back to palette mode before saving, if desired. (Actually I would just save it in RGB mode, and then turn PNGCrush loose on the folder of resized images.)

This is over a year old, but in case anyone is still looking:
Here is a sample of code that will see if an image is in a palette mode, and make adjustments
import Image # or from PIL import Image
img = Image.open(sourceFile)
if 'P' in img.mode: # check if image is a palette type
img = img.convert("RGB") # convert it to RGB
img = img.resize((w,h),Image.ANTIALIAS) # resize it
img = img.convert("P",dither=Image.NONE, palette=Image.ADAPTIVE)
#convert back to palette
else:
img = img.resize((w,h),Image.ANTIALIAS) # regular resize
img.save(newSourceFile) # save the image to the new source
#img.save(newSourceFile, quality = 95, dpi=(72,72), optimize = True)
# set quality, dpi , and shrink size
By converting the paletted version to RGB, we can resize it with the anti alias. If you want to reconvert it back, then you have to set dithering to NONE, and use an ADAPTIVE palette. If there options aren't included your result (if reconverted to palette) will be grainy. Also you can use the quality option, in the save function, on some image formats to improve the quality even more.

Python PIL: How to FIll a Image with a copyright logo like this?

I need to protect my photos by filling them with copyright logos. My OS is Ubuntu 10.10 and Python 2.6. I intend to use PIL.
Supposed I have a copyright logo like this (You can do this in Photoshop easily):
and a picture like this:
I want to use PIL to get copyrighted pictures like the following (Fill the original pic with pattern):
and Final Result by altering the opacity of logos:
Is there any function in PIL that can do this? Any hint?
Thanks a lot!

PIL is certainly capable of this. First you'll want to create an image that contains the repeated text. It should be, oh, maybe twice the size of the image you want to watermark (since you'll need to rotate it and then crop it). You can use Image.new() to create such an image, then ImageDraw.Draw.text() in a loop to repeatedly plaster your text onto it, and the image's rotate() method to rotate it 15 degrees or so. Then crop it to the size of the original image using the crop() method of the image.
To combine it first you'll want to use ImageChops.multiply() to superimpose the watermark onto a copy of the original image (which will have it at 100% opacity) then ImageChops.blend() to blend the watermarked copy with the original image at the desired opacity.
That should give you enough information to get going -- if you run into a roadblock, post code showing what you've got so far, and ask a specific question about what you're having difficulty with.

Just a sample：
#!/usr/bin/python
# -*- coding: utf-8 -*-
from PIL import Image
def fill_watermark():
im = Image.open('a.jpg').convert('RGBA')
bg = Image.new(mode='RGBA', size=im.size, color=(255, 255, 255, 0))
logo = Image.open('logo.png') # .rotate(45) if you want, bg transparent
bw, bh = im.size
iw, ih = logo.size
for j in range(bh // ih):
for i in range(bw // iw):
bg.paste(logo, (i * iw, j * ih))
im.alpha_composite(bg)
im.show()
fill_watermark()