Develop Reference

Sending mail with (docx)attachment using python

I have been trying to send a mail via python with a Docx attachment
I'm able to get a mail but with no attachment to it, below is the code I used for attaching a file
And I didn't get any error while attaching a file
import smtplib, ssl
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.base import MIMEBase
from email import encoders
sender_email = email
receiver_email = toemail
password = password
message = MIMEMultipart("alternative")
message["Subject"] = Subject
message["From"] = sender_email
message["To"] = receiver_email
message.attach(htmlmessage)
attach_file = open(attach_file_name, 'rb') # Open the file as binary mode
payload = MIMEBase('application', 'octet-stream')
payload.set_payload((attach_file).read())
encoders.encode_base64(payload)
#encode the attachment
#add payload header with filename
payload.add_header('Content-Disposition', "attachment; filename= %s" % attach_file)
message.attach(payload)
context = ssl.create_default_context()
with smtplib.SMTP_SSL("smtp.gmail.com", 465, context=context) as server:
server.login(sender_email, password)
server.sendmail(
sender_email, receiver_email, message.as_string()
)

Mime types are to be respected. The type multipart/alternative should be used for messages containing the same information in plain text and in HTML. The mail reader can then choose which representation it can use.
On the other hand, multipart/mixed should be used when the message contains multiple different parts, said differently to transport attachements.
So, provided htmlmessage is a valid email.mime.text.MIMEText, your code should not declare "alternative":
...
message = MIMEMultipart()
...
Furthermore, you should avoid to directly use MIMEBase and instead rely on the defaults for MIMEApplication:
payload = MIMEApplication(attach_file.read(),
'vnd.openxmlformats-officedocument.wordprocessingml.document')
payload.add_header('Content-Disposition',
"attachment; filename= %s" % attach_file)
message.attach(payload)
But I must acknowledge that this last point is mainly a matter of taste...

Excel email comes in a different format unable to open Python pandas

The goal is to send an email with excel attachment.
I found an example online but not written for Excel format.
It sends attachment but not like typical excel spreadsheet, so I am unable to open it.
Is it something I can modify in a code in order to receive .xlsx file?
# libraries to be imported
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
fromaddr = "From#gmail.com"
toaddr = "To#gmail.com"
# instance of MIMEMultipart
msg = MIMEMultipart()
# storing the senders email address
msg['From'] = fromaddr
# storing the receivers email address
msg['To'] = toaddr
# storing the subject
msg['Subject'] = "Sending Attachement"
# string to store the body of the mail
body = "Hello, This is Oleg and my attached file"
# attach the body with the msg instance
msg.attach(MIMEText(body, 'plain'))
# open the file to be sent
filename = "FileName"
attachment = open("C:\\Mylocation\\FileName.xlsx", "rb")
# instance of MIMEBase and named as p
p = MIMEBase('application', 'octet-stream')
# To change the payload into encoded form
p.set_payload((attachment).read())
# encode into base64
encoders.encode_base64(p)
p.add_header('Content-Disposition', "attachment; filename= %s" % filename)
# attach the instance 'p' to instance 'msg'
msg.attach(p)
# creates SMTP session
s = smtplib.SMTP('smtp.gmail.com', 587)
# start TLS for security
s.starttls()
# Authentication
s.login(fromaddr, "password")
# Converts the Multipart msg into a string
text = msg.as_string()
# sending the mail
s.sendmail(fromaddr, toaddr, text)
# terminating the session
s.quit()

There is just a small error in your code! change your filename variable to "FileName.xlsx" instead of just "FileName"
I noticed that your file didn't have an extension, and since your filename variable didn't have an extension - that is how I quickly came to this conclusion. The documentation for add_header() seems to use the file extensions as well.

Python - send bulk emails

I've been tasked with sending around 250 emails with around 30kb attachments per email. Each attachment is unique to the recipient. My below code works, although I feel it's too slow, it sends an email around every 7 seconds which across 250 emails will take 29 mins. Obviously parallelising it would help move things along however, I'm curious as to whether my code can be improved. Please note that I haven't yet implemented the targeted attachment and emails as that shouldn't cause such a large performance hit.
import os,datetime
def send_mail(recipient, subject, message, files=None):
import smtplib,email,os
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.application import MIMEApplication
from os.path import basename
username = "myemail"
password ="mypass"
mailServer = smtplib.SMTP('smtp-mail.outlook.com', 587)
mailServer.ehlo()
mailServer.starttls()
mailServer.ehlo()
mailServer.login(username, password)
for i in range(1,15):
try:
msg = MIMEMultipart()
msg['From'] = username
msg['To'] = recipient
msg['Subject'] = subject
msg.attach(MIMEText(message))
for f in files or []:
with open(f, "rb") as fil:
part = MIMEApplication(
fil.read(),
Name=basename(f)
)
part['Content-Disposition'] = 'attachment; filename="%s"' % basename(f)
msg.attach(part)
print('sending mail to ' + recipient + ' on ' + subject)
mailServer.sendmail(username, recipient, msg.as_string())
except error as e:
print(str(e))
mailServer.close()
print(datetime.datetime.now())
send_mail('recipent, 'Sent using Python', 'May the force be with you.',["colours.xls"])
print(datetime.datetime.now())

You should profile your code to see what is consuming the most of time.
I would recommend using cProfile + snakeviz.
python -m cProfile -o program.prof my_program.py
snakeviz program.prof

Send video file via python

I need to figure out how to make a script that scans for new files in a directory, and when there is a new one, sends the file via email.
Someone keeps stealing bikes in my apartment building! First it was my fault (I for got to lock it), now the crook upgraded by cutting chains. I had it after the crook stole my second bike by cutting 1/2 inch airplane wire.
Anyway, using a raspberry pi as a motion activated security camera, I want it to send me a video file as soon as the video program finishes recording it. This is incase they steal the pi.
I am looking at these examples, but I can't figure how to make the script run continuously (every minute) or how to make it scan a folder for a new file.
How do I send attachments using SMTP?
OK
I got it down to scanning and then trying to email. It fails when trying to attach the video file. Can you help? Here is the revised code:
The failure is:
msg = MIMEMultipart()
TypeError: 'LazyImporter' object is not callable, line 38
import time, glob
import smtplib
import email.MIMEMultipart
from email.MIMEBase import MIMEBase
from email.MIMEText import MIMEText
from email.Utils import COMMASPACE, formatdate
from email import Encoders, MIMEMultipart
import os
#Settings:
fromemail= "Jose Garcia <somerandomemail#gmail.com>"
loginname="somerandomemail#gmail.com"
loginpassword="somerandomepassword"
toemail= "Jose Garcia <somerandomemail#gmail.com>"
SMTPserver='smtp.gmail.com'
SMTPort=587
fileslocation="/Users/someone/Desktop/Test/*.mp4"
subject="Security Notification"
def mainloop():
files=glob.glob(fileslocation) #Put whatever path and file format you're using in there.
while 1:
new_files=glob.glob(fileslocation)
if len(new_files)>len(files):
for x in new_files:
if x in files:
print("New file detected "+x)
print("about to call send email")
sendMail(loginname, loginpassword, toemail, fromemail, subject, gethtmlcode(), x, SMTPserver, SMTPort)
files=new_files
time.sleep(1)
def sendMail(login, password, to, frome, subject, text, filee, server, port):
# assert type(to)==list
# assert type(filee)==list
msg = MIMEMultipart()
msg['From'] = frome
msg['To'] = COMMASPACE.join(to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach( MIMEText(text) )
# #for filee in files:
part = MIMEBase('application', "octet-stream")
part.set_payload( open(filee,"rb").read() )
Encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="%s"'
% os.path.basename(filee))
msg.attach(part)
smtp = smtplib.SMTP(SMTPserver, SMTPort)
smtp.sendmail(frome, to, msg.as_string() )
server.set_debuglevel(1)
server.starttls()
server.ehlo()
server.login(login, password)
server.sendmail(frome, to, msg)
server.quit()
def gethtmlcode():
print("about to assemble html")
html = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" '
html +='"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml">'
html +='<body style="font-size:12px;font-family:Verdana"><p>A new video file has been recorded </p>'
html += "</body></html>"
return(html)
#Execute loop
mainloop()

I finally got it working. I had to use python 2.5 to get rid of the LazyImporter error. Every time a new file is added to the security folder, it gets emailed to me. Logging is broken.
import time, glob
import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEMultipart import MIMEBase
from email.MIMEText import MIMEText
from email.Utils import COMMASPACE, formatdate
import datetime
from email import Encoders
import os
import sys
#Settings:
fromemail= 'RaspberryPI Security Camera <someone>'
loginname='someone#gmail.com'
loginpassword='something'
toemail= 'Jose Garcia < someone#gmail.com>'
SMTPserver='smtp.gmail.com'
SMTPort=587
fileslocation='/Users/someone/Desktop/Test/*.*'
subject="Security Notification"
log='logfile.txt'
def mainloop():
files=glob.glob(fileslocation) #Put whatever path and file format you're using in there.
while 1:
f = open(log, 'w')
sys.stdout = Tee(sys.stdout, f)
new_files=glob.glob(fileslocation)
if len(new_files)>len(files):
for x in new_files:
if x in files:
print(str(datetime.datetime.now()) + "New file detected "+x)
sendMail(loginname, loginpassword, toemail, fromemail, subject, gettext(), x, SMTPserver, SMTPort)
files=new_files
f.close()
time.sleep(1)
def sendMail(login, password, send_to, send_from, subject, text, send_file, server, port):
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = COMMASPACE.join(send_to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach( MIMEText(text) )
part = MIMEBase('application', "octet-stream")
part.set_payload( open(send_file,"rb").read() )
Encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="%s"' % os.path.basename(send_file))
msg.attach(part)
smtp = smtplib.SMTP(SMTPserver, SMTPort)
smtp.set_debuglevel(1)
smtp.ehlo()
smtp.starttls()
smtp.login(login, password)
smtp.sendmail(send_from, send_to, msg.as_string() )
smtp.close()
def gettext():
text = "A new file has been added to the security footage folder. \nTime Stamp: "+ str(datetime.datetime.now())
return(text)
class Tee(object):
def __init__(self, *files):
self.files = files
def write(self, obj):
for f in self.files:
f.write(obj)
#Execute loop
mainloop()

It looks like the email module has been refactored over time. This fixed the 'LazyImporter' object not callable error for me on Python 2.7:
from email.mime.text import MIMEText
Noteably it was not happy with (what I thought were) synonyms like import email; email.mime.text.MIMEText(...)

I use python3 and I could not for the life of me get any of these examples to work, but I was able to come up with something that works and is a whole lot simpler.
import smtplib
from email.message import EmailMessage
from email.mime.base import MIMEBase
from email import encoders
# Defining Objects and Importing Files ------------------------------------
# Initializing video object
video_file = MIMEBase('application', "octet-stream")
# Importing video file
video_file.set_payload(open('video.mkv', "rb").read())
# Encoding video for attaching to the email
encoders.encode_base64(video_file)
# creating EmailMessage object
msg = EmailMessage()
# Loading message information ---------------------------------------------
msg['From'] = "person_sending#gmail.com"
msg['To'] = "person_receiving#gmail.com"
msg['Subject'] = 'text for the subject line'
msg.set_content('text that will be in the email body.')
msg.add_attachment(video_file, filename="video.mkv")
# Start SMTP Server and sending the email ---------------------------------
server=smtplib.SMTP_SSL('smtp.gmail.com',465)
server.login("person_sending#gmail.com", "some-clever-password")
server.send_message(msg)
server.quit()

Just put your script in a loop and have it sleep for 60 seconds. You can use glob to get a list of files in the directory. in is pretty useful for seeing what is in a list (i.e. the list of files in the directory).
import time, glob
files=glob.glob("/home/me/Desktop/*.mp4") #Put whatever path and file format you're using in there.
while 1:
new_files=glob.glob("/home/me/Desktop/*.mp4")
if len(new_files)>len(files):
for x in new_files:
if x not in files:
print("New file: "+x) #This is where you would email it. Let me know if you need help figuring that out.
files=new_files
time.sleep(60)

Reliably force Return-Path with Python

I'm a Python junior, so keep that in mind. In a Python script, I need to set a Return-Path address that is different than the sender's address. (I'm using Gmail as SMTP server.)
I've done lots of searching on this question and found plenty of "answers", but no solutions. I tried this link Setting Return-Path with Python sendmail for a MIME message but it's not working for me at all. I can change the "To:" address that the email recipient sees, but when they click "Reply", it's back to the sending email address again.
This is the function that I'm trying to write. It works well enough, except that I need to force a different Return-Path.
#!/usr/bin/python
import smtplib
import os
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email.MIMEText import MIMEText
from email.Utils import COMMASPACE, formatdate
from email import Encoders
import sap_mailserverdata as sf
def send_mail(sent_to, subject, body_text, sent_from_addr='', sent_from_name='', files=[], cc=[], bcc=[]):
"""Send emails with or without attachments."""
assert type(sent_to)==list
assert type(files)==list
assert type(cc)==list
assert type(bcc)==list
message = MIMEMultipart()
message['From'] = sent_from_addr
message['To'] = COMMASPACE.join(sent_to)
message['Date'] = formatdate(localtime=True)
message['Subject'] = subject
message['Cc'] = COMMASPACE.join(cc)
message.preamble = 'You need a MIME enabled mail reader to see this message.\n'
message.attach(MIMEText(body_text, 'html'))
for f in files:
part = MIMEBase('application', 'octet-stream')
part.set_payload(open(f, 'rb').read())
Encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="%s"' % os.path.basename(f))
message.attach(part)
addresses = []
for x in sent_to:
addresses.append(x)
for x in cc:
addresses.append(x)
for x in bcc:
addresses.append(x)
mail_server = smtplib.SMTP(sf.server, sf.server_port)
mail_server.ehlo()
mail_server.set_debuglevel(1)
mail_server.starttls()
mail_server.login(sf.username, sf.password)
mail_server.sendmail(sent_from_addr, addresses, message.as_string())
mail_server.quit()
What am I missing with this function to be able to reliably specify a different replyto Return-Path?

Reply-to and return path are two distinct beasts. See the RFC.
You can set Reply-to with:
msg['reply-to'] = 'smith#acme.com'
The return-path is set by the MTA to the address that receives bounces. It is controlled by the server administrator, so unless you work for Google I don't think this is under your control.
Most of the time one is after "Reply-to"; if you really need to change the return path you must use a SMTP server under your control and google for how to do this for the specific MTA you are using - many will have a white list of users and/or hosts that can override the return path.